Hierarchical data, how to aggregate over levels in hierarchical query?

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  Published by: Vel January 5, 2012 12:20 AM

  Barros says:
  Frank,

  I used the Sub hierarchical query to achieve the result desired, mentioned above,.

  select SYS_CONNECT_BY_PATH(parent,'/') root ,level from some_table
  start with id = 5
  CONNECT BY PRIOR parent =  id;
  
  o/p
  
  /4     1
  /4/2     2
  /4/2/1     3
  /4/2/1/0     4
  

  But please let me know if it is possible to get the details of the hierarchy (using hierarchical queries) of the query node to the root, as the below a node

  1/2/3/4/5 -- root hierarchy for node 5
  

  OK, you had a go, and you're almost there. Now you seem to be saying you want the hierarchy from the top down rather than bottom-up, so you'll need to change around your connection by the clause. Something like that...

  SQL> ed
  Wrote file afiedt.buf
  
    1  with t as (select 1 as ID, 0 as PARENT_ID from dual union all
    2             select 2, 1 from dual union all
    3             select 3, 1 from dual union all
    4             select 4, 2 from dual union all
    5             select 5, 4 from dual union all
    6             select 6, 4 from dual union all
    7             select 100, 0 from dual)
    8  --
    9  -- end of test data
   10  --
   11  select ltrim(SYS_CONNECT_BY_PATH(id,'/'),'/') root
   12  from   t
   13  where connect_by_isleaf = 1
   14  and id = 5
   15  connect by parent_id = prior id
   16* start with parent_id = 0
  SQL> /
  
  ROOT
  -------------------------------------------------------------------
  1/2/4/5
  

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  Hi all

  I have a hierarchical query that I use in an area of tree demand APEX and there are nodes that have no children and I am trying to find a way to not display these nodes. Essentially if the user does not have to develop a lot of knots to know that nothing exists at the most detailed level.

  The data are based on the Oracle Fusion FND tables but for example purposes here is enough data to illustrate my question:

  
  

  create table APPL_TAXONOMY_HIERARCHY (SOURCE_MODULE_ID varchar2(30), TARGET_MODULE_ID varchar2(30));
  create table APPL_TAXONOMY_TL (module_id varchar2(30), description varchar2(100), user_module_name varchar2(30), language varchar2(5));
  create table APPL_TAXONOMY (MODULE_ID    varchar2(30),    MODULE_NAME    varchar2(30), MODULE_TYPE varchar2(10),    MODULE_KEY varchar2(30));
  create table TABLES (table_name varchar2(30), module_key varchar2(30));
  
  

  insert into APPL_TAXONOMY_TL values ('1', null, 'Oracle Fusion', 'US' );
  insert into APPL_TAXONOMY_TL values ('2', null, 'Financials', 'US' );
  insert into APPL_TAXONOMY_TL values ('3', null, 'Human Resources', 'US' );
  insert into APPL_TAXONOMY_TL values ('20', null, 'Accounts Payable', 'US' );
  insert into APPL_TAXONOMY_TL values ('10', null, 'General Ledger', 'US' );
  
  insert into APPL_TAXONOMY_HIERARCHY values ('1', 'DDDDDDDD');
  insert into APPL_TAXONOMY_HIERARCHY values ('2', '1');
  insert into APPL_TAXONOMY_HIERARCHY values ('3', '1');
  insert into APPL_TAXONOMY_HIERARCHY values ('4', '1');
  insert into APPL_TAXONOMY_HIERARCHY values ('10', '2');
  insert into APPL_TAXONOMY_HIERARCHY values ('20', '2');
  
  insert into APPL_TAXONOMY values ('1', 'Fusion', 'PROD', 'Fusion');
  insert into APPL_TAXONOMY values ('2', 'Financials', 'FAMILY', 'FIN');
  insert into APPL_TAXONOMY values ('10', 'GL', 'APP', 'GL');
  insert into APPL_TAXONOMY values ('3', 'Human Resources', 'FAMILY', 'HR');
  insert into APPL_TAXONOMY values ('20', 'AP', 'APP', 'AP');
  
  insert into tables values ('GL_JE_SOURCES_TL','GL');
  insert into tables values ('GL_JE_CATEGORIES','GL');
  

  My hierarchical query is as follows:

  with MODULES as
  (
  SELECT h.source_module_id, b.user_module_name, h.target_module_id
        FROM APPL_TAXONOMY_HIERARCHY H,
        APPL_TAXONOMY_TL B,
  APPL_TAXONOMY VL
  where H.source_module_id = b.module_id
  and b.module_id = vl.module_id
  and vl.module_type not in ('PAGE', 'LBA')
  UNION ALL
  select distinct table_name, table_name,  regexp_substr(table_name,'[^_]+',1,1) 
  from TABLES --needed as a link between TABLES and APPL_TAXONOMY
  union all
  select module_key as source_module_id, module_name as user_module_name, module_id as target_module_id  from appl_taxonomy VL where VL.module_type = 'APP')
  SELECT  case when connect_by_isleaf = 1 then 0
              when level = 1             then 1
              else                           -1
         end as status,
  LEVEL,
  user_module_name as title,
  null as icon,
  ltrim(user_module_name, ' ') as value,
  null as tooltip,
  null as link
        FROM MODULES
        START WITH source_module_id = '1'
        CONNECT BY PRIOR source_module_id = target_module_id
  ORDER SIBLINGS BY user_module_name;
  

  In Oracle APEX, this gives a tree with the appropriate data, you can see here:

  https://Apex.Oracle.com/pls/Apex/f?p=32581:29 (username: guest, pw: app_1000);

  The SQL of the query results are:

  STATUS

  TITLE LEVEL

  VALUE

  ---------- ---------- ------------------------------ ------------------------------

  	1	1 oracle Fusion	Oracle Fusion
  	-1	2 financial tables	Financials
  	-1	3 accounts payable	Accounts payable
  	0	4 AP	AP
  	-1	General Accounting 3	General Accounting
  	-1	4 GL	GL
  	0	5 GL_JE_CATEGORIES	GL_JE_CATEGORIES
  	0	5 GL_JE_SOURCES_TL	GL_JE_SOURCES_TL
  	0	2 human resources	Human resources

  The lowest level is the name of the table to level 5. HR is not any level under level 2, in the same way, "AP" (level 4) has nothing below, i.e. no level 5 and that's why I don't want to show these nodes. Is this possible with the above query?

  Thanks in advance for your suggestions!

  John

  Hello

  The following query will include only the nodes of level = 5 and their ancestors (or descendants):

  WITH modules LIKE

  (

  SELECT h.source_module_id

  b.user_module_name AS the title

  h.target_module_id

  To appl_taxonomy_hierarchy:

  appl_taxonomy_tl b

  appl_taxonomy vl

  WHERE h.source_module_id = b.module_id

  AND b.module_id = vl.module_id

  AND vl.module_type NOT IN ('PAGE', "LBA")

  UNION ALL

  SELECT DISTINCT

  table-name

  table_name

  , REGEXP_SUBSTR (table_name, ' [^ _] +')

  From the tables - required as a link between the TABLES and APPL_TAXONOMY

  UNION ALL

  SELECT module_key AS source_module_id

  AS user_module_name module_name

  module_id AS target_module_id

  Of appl_taxonomy vl

  WHERE vl.module_type = 'APP '.

  )

  connect_by_results AS

  (

  SELECT THE CHECK BOX

  WHEN CONNECT_BY_ISLEAF = 1 THEN 0

  WHEN LEVEL = 1 THEN 1

  OF ANOTHER-1

  The END as status

  LEVEL AS lvl

  title

  -, NULL AS icon

  , LTRIM (title, "") AS the value

  -, NULL as ToolTip

  -, Link AS NULL

  source_module_id

  SYS_CONNECT_BY_PATH (source_module_id - or something unique

  , ' ~' - or anything else that may occur in the unique key

  ) || ' ~' AS the path

  ROWNUM AS sort_key

  Modules

  START WITH source_module_id = '1'

  CONNECT BY PRIOR Source_module_id = target_module_id

  Brothers and SŒURS of ORDER BY title

  )

  SELECT the status, lvl, title, value

  -, icon, tooltip, link

  OF connect_by_results m

  WHEN THERE IS)

  SELECT 1

  OF connect_by_results

  WHERE the lvl = 5

  AND the path AS ' % ~' | m.source_module_id

  || '~%'

  )

  ORDER BY sort_key

  ;

  You may notice that subqueries modules and the connect_by_results are essentially what you've posted originally.  What was the main request is now called connect_by_results, and it has a couple of additional columns that are necessary in the new main request or the EXISTS subquery.

  However, I am suspicious of the 'magic number' 5.  Could you have a situation where the sheets you are interested in can be a different levels (for example, some level = 5 and then some, into another branch of the tree, at the LEVEL = 6, or 7 or 4)?  If so, post an example.  You have need of a Query of Yo-Yo, where you do a bottom-up CONNECT BY query to get the universe of interest, and then make a descendant CONNECT BY query on this set of results.

• How to find the level of oracle objects dependencies...

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  in oracle if we have to find the dependencies we use "all_dependencies", how ever if
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  example as shown below;
  
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  view 1:            v_test using table1
  
  view 2:            v_test2 using v_test
  
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  Published by: W Nicloei on October 7, 2008 19:53

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