Round the number to the nearest million

Similar Questions

• number rounded to the nearest integer in Excel

  Hello everyone.

  I use an entry in the file of worksheet to export my Excel (csv format) table, but it rounds the number to the nearest integer.

  

  How can I solve this problem?

  My VI is uploadet

  Thanks in advance

  Orlando

  
  

• Rounded to the nearest whole number text size?

  I had to resize a work of art, but now I find myself with sizes that are 71.68px up, 34.51px up, etc.

  Y at - it a script that will break all the text in a document that it is the closest number integer or decimal 0.1?

  // rounds the size of text in all textFrames in your document
  var aTFrame = app.activeDocument.textFrames;
  
  for ( i = 0; i < aTFrame.length; i++ )
  {
  var fractionSize = aTFrame[i].textRange.characterAttributes.size;
  var RoundedSize = Math.round(fractionSize);
  aTFrame[i].textRange.characterAttributes.size = RoundedSize;
  }
  redraw();
  

  This will make all the text frames. Copy the above, paste it into a text editor or the Adobe ESTK (ExtendScript Toolkit) and save it in a text file with the .jsx extension. Place it in the folder/Applications/Adobe Illustrator CSX / Presets / en_US / Scripts and restart HAVE. Run it by the presence of a document in artificial intelligence and call it from file > Scripts > scriptname.

• How to round to the nearest dollar total?

  I have a form that multiplies the number of items per $6.07 but I need the total to round to the nearest dollar. I formatted the total field to be whole and entire selected tab link, who works to give up the hundred in total, but is not helping round up. I suspect that a script is required to achieve this. How can I write this script?

  Thanks for your help.

  You will want to use the Ceil function, which returns the next higher whole number expression, therefore;

  Ceil (table2. Row8.eight * 6.07)

  Just note that it will be only for positive numbers, if you have to deal with negative numbers (perhaps a refund), then you will need to use the Floor function.

  Concerning

  Bruce

• Question about the BOROUGH a number to the nearest quarter

  Hi all

  Please forgive me if I am not posting this at the appropriate place, but I do not know what area he could enter (script, Javascript, Designer...) and the Acrobat Scripting forum seemed as good one place as any.

  I have the field that allows a user to enter a number with 2 decimal places 2-digit. (i.e. 12.30 or 9.78 until 24.00.) This field corresponds to the hours in a day). What I would like is to "round" the quarter of an hour. As an example, if a person enters:

  22.15 - the field would round up to 22.25

  9.78 - the field would round down to 9.75

  12.10 - the field would round down to 12:00

  .15 - would round up a.25

  .96 - would turn to 1.00

  .01 a.24 - would round up a.25

  Essentially, any number that they take place in this field (until 24:00) would be around in an appropriate manner.

  I looked at the ROUNDING FormCalc function and DATE / hour, but it doesn't look like one of those that would allow me to do what I have to do. I guess, that it should be in JavaScript, but yet again, I'm not sure.

  If someone can point me in the right direction, it would be greatly appreciated, and if all goes well, I explained to him what I want to do it properly.

  Jon

  Here is an example of code that I wrote to round a number (x) to the nearest quarter (nouveaux_x):

  var x = 22.15;
  var rounded_x = Math.floor (x);
  var x_nouveaux;

  If (x-rounded_x<=0.125) new_x="rounded_x;" 0="" -="" 0.125="" round="" down="" to="">
  ElseIf (x-rounded_x<=0.375) new_x="rounded_x+0.25;" 0.125="" -="" 0.375="" round="" to="">
  ElseIf (x-rounded_x<=0.625) new_x="rounded_x+0.5;" 0.375="" -="" 0.625="" round="" to="">
  ElseIf (x-rounded_x<=0.875) new_x="rounded_x+0.75;" 0.625="" -="" 0.875="" round="" to="">
  else x_nouveaux = rounded_x + 1; 0,875 - 1,00 round up to 1

  Edit: improved code...

• How time rounding up to the nearest half an hour?

  Hi all

  I have already received excellent and very competent assistance in these forums and hope to have this problem be solved, so...

  The Setup is a built in Acrobat 9.1.3 Acroform

  This concerns a situation where the user between a 'start' and 'end' time for a given event and the result is calculated in a decimal number - this does not work properly.

  The issue is having the time calculated to round to the nearest half-hour, making the number decimal either x.0 x.5

  Thanks in advance

  / Morten

  In this case, you can use the code in my first post. It does exactly that.

• Round time to the nearest minute of you

  Hello

  Is there a simple way to round off a date/time to the nearest Minute?

  Example: 22/03/2013 10:23:35 rounded to 22/03/2013 10:24

  22/03/2013 10:23:29 rounded to 22/03/2013 10:23

  I could just compare the seconds at 30 and round to the Minute or Minute + 1 but I would have to manage the change of day/month/year

  Thank you

  User

  User79 wrote:

  Hello

  Is there a simple way to round off a date/time to the nearest Minute?

  Example: 22/03/2013 10:23:35 rounded to 22/03/2013 10:24

  22/03/2013 10:23:29 rounded to 22/03/2013 10:23

  I could just compare the seconds at 30 and round to the Minute or Minute + 1 but I would have to manage the change of day/month/year

  Thank you

  User

  Here's a way to do it.

  

  Ben64

• Round stamp to the nearest hour

  Hi all

  I would like to turn stamp to the nearest hour. Example:

  21/01/2015 18:51-> 21/01/2015, 19:00

  21/01/2015 18:21-> 2015-21/01 18:00

  Suggestions how I can make it work properly? Thanks in advance.

  Kind regards

  Niek

  Hi Niek,

  With a Script processor, you can use this:

  var date = input1 [0];

  If (date! = null)

  {

  date.setTime (Math.round (date.getTime () / 3600000) * 3600000);

  Output 1 = date;

  }

  see you soon,

  Nick

• Round the percentage to a whole number

  Hello

  I'm still pretty new to perform calculations of script and thereby an individual seems a bit more complex for me.

  I am trying to determine the difference in percentage between 2 numbers and display the percentage as a whole number. Logically my calculation looks like

  (numericField1 - numericField2 / numericField1 * 100)
  (e.g. 1000-850 / 1000 * 100 = 15%)

  I need help with my math and especially round the % to an integer. I wouldn't have all of the answers posted as 22.66666%

  The code below is somethig I tried

  Event.Value = roundNumber ((this.getField (numericField1) .value - this.getField ("numericField2t") .value) / this.getField (numericField1) .value, 2) + "%";
  
  function roundNumber (num, dec) {}
  var result = Math.round(num*Math.pow(10,dec))/Math.pow(10,dec;)
  return the result;

  Any advice would be great!

  Adobe is actually this really simple for you.  If you use a numeric field to display the result, the display for the field template will control the way number.  You can set a percentage pattern:"num{zzzz9.99%}" to control how many digits will be displayed, and how many digits will be important beyond the decimal point.  If there is more than numbers, Adobe will automatically complement number.  In the attached example, I used the boss

  "{zzzz9 %} num" to ensure that only a whole number will be displayed.  Adobe uses the normal rounding rules: 0-4 rounds down, 5 to 9 rounds.

  In addition, the percentage will automatically multiply the value in the field by 100, so you don't need to do it in your script.

  For the attached example, I added your script FormCalc calculation to Calculate the result field event.  The script is now simply:

  (NumericField1 - NumericField2) / NumericField1

  Adobe takes care of the rest.

• Round numbers to the nearest thousand

  Is there a way to round numbers to the nearest thousand in Livecycle Designer ES?

  EVENT CALCULATE CALCULATE...

  I can try something on formcalc too... Although there is no difference between javascript and formcalc in your case

  Here you go with formcalc:

  Tower of ((SubTotal + OtherCharge1 + OtherCharge2 + OtherCharge3)/1000) * 1000

• Round the question in Double chain

  Hi all

  I am facing a weird problem in rounded to a value of type double. I thought that LabVIEW always rounds up this rule when the digit is truncated is 5 - round to the nearest even integer number offshore

  When I round up to two points of accuracy, I get results.

  489.335-> 489.33

  489.355-> 489.36

  

  Can someone tell me how rounding works in the above cases? Please find the sample VI (2010) attached, if you want to play with him.

  Thank you

  Knockaert

  
  

• How to get figure to the nearest penny?

  I want to calculate the average cost of holiday and then round this number to the nearest cent (or two decimal places). Here is my code to find the average.
  

  select      avg(IT220_HOLIDAYDETAILS.HOLCOST) as "HOLCOST" 
   from      "IT220_HOLIDAYDETAILS" "IT220_HOLIDAYDETAILS"

  It works fine, but the result is 1201.3333333333333
  
  I tried to use the rounded, but he did that take all decimals off of all. I want to round to two decimal places, is there a way to do this?
  
  Thanks in advance!
  
  Published by: Jay on November 17, 2010 04:06

  Hi Jay

  You need this...

  select      round(avg(IT220_HOLIDAYDETAILS.HOLCOST),2) as "HOLCOST"
   from      "IT220_HOLIDAYDETAILS" "IT220_HOLIDAYDETAILS"
  

  Either this...

  select      to_char(avg(IT220_HOLIDAYDETAILS.HOLCOST),'9999.99') as "HOLCOST"
   from      "IT220_HOLIDAYDETAILS" "IT220_HOLIDAYDETAILS"
  

  Caveat even as my previous posting on the use of the TO_CHAR version.

  See you soon

  Ben

  Published by: Munky on November 17, 2010 12:39 - typo!

• Search for the nearest value table

  IM wondering if its possible to find a 1 d table worth, if it is not found, then find the nearest match. IM using the 'double' data type and I need at least an accuracy of 4 decimal point in the research.

  For now, im rounding decimal values to the nearest integers from you, but it is not effective at all. Im getting a lot of unwanted split in the plot. I need to be able to search for the decimal points. I found this function "About Equals.VI" starting from a previous thread. Even that uses the concept of the rounding.

  I enclose 3 screws "0.8 & 0.4.VI" are that I created, rounding decimals nearest digit.

  The "approximately equal" is the one I found online.

  The 3rd is I try to mess with what I can find as close a match.

  Y at - it a trick to work around this problem?

  Thank you

  Eureka

  This VI uses the first type of step 3 in your data.  Since you said that you can get the data, you can drop the in VI.

  At the end where I calculate the slope, you can use a linear adjustment if you have full or professional LabVIEW.

  

  

• Join the nearest date "not used".

  I need to join the following tables by the next date "not previously signed" the nearest:

  start_table:

  st_id	start_dt
  start0	31-dec-2014
  Start1	January 3, 2015
  Start2	January 5, 2015
  start3	January 7, 2015
  Debut4	8 January 2015
  Debut5	January 14, 2015

  end_table:

  end_id	end_dt
  end0	January 1, 2015
  End1	January 2, 2015
  End2	January 13, 2015
  End3	January 15, 2015
  bout4	January 17, 2015
  end5	19 January 2015
  end6	January 20, 2015

  Result:

  st_id	end_id
  start0	end0
  Start1	End2
  Start2	End3
  start3	bout4
  Debut4	end5
  Debut5	end6

  start0 joined end0, because the closer to the date of the next 31-dec-2014 is 1 January 2015

  Start1 joined end2, because the closer to the date of the next January 3, 2015 is January 13, 2015.

  Start2 joined end3, because as well as the date of the next more close January 5, 2015 is 13 January 2015, this is already accompanied Start1, so she joined next January 15, 2015.

  start3 joined bout4, because the date of the next although most close January 7, 2015 is 13 January 2015, this one is already joined by Start1, earliest date is January 15, 2015, but is also already joined by start2, then he joined the next available date January 17, 2015.

  Database: 11g

  Thanks in advance

  [UPDATE: changed line 37 to add "or cnt > = 0".] [This covers cases where there are more departures that ends at first.]

  Jiri.Machotka - Oracle wrote:

  I found a non recursive algorithm for this problem...

  I came up with something similar: no recursion, no joins, each table read only once.

  1. UNION ALL marked times 1 tables, with lines of departure and end marked lines - 1
  2. Order by date (first lines) and get a combination of 1's and - 1's.
     so when there are too many lines to end, the sum is negative.
  3. Get the previous cumulative minimum! Then take that end with a sum running lines, at less than the previous minimum.
  4. The remaining lines will have an end of line for each line of departure. Now number lines starting from 1 to N and the lines at the end of 1 to N, then match lines start and end in pairs. I use PIVOT to do this.

  WITH end_table (end_id, end_dt) AS (
    select 'end0',to_date('01-jan-2015','dd-mon-yyyy') from dual union all
    select 'end1',to_date('02-jan-2015','dd-mon-yyyy') from dual union all
    select 'end2',to_date('13-jan-2015','dd-mon-yyyy') from dual union all
    SELECT 'end3',to_date('15-jan-2015','dd-mon-yyyy') FROM dual UNION ALL
    select 'end4',to_date('17-jan-2015','dd-mon-yyyy') from dual union all
    SELECT 'end5',to_date('19-jan-2015','dd-mon-yyyy') FROM dual UNION ALL
    SELECT 'end6',to_date('20-jan-2015','dd-mon-yyyy') FROM dual
  )
  ,start_table (start_id, start_dt) AS (
    select 'start0',to_date('31-dec-2014','dd-mon-yyyy') from dual union all
    select 'start1',to_date('03-jan-2015','dd-mon-yyyy') from dual union all
    select 'start2',to_date('05-jan-2015','dd-mon-yyyy') from dual union all
    select 'start3',to_date('07-jan-2015','dd-mon-yyyy') from dual union all
    select 'start4',to_date('08-jan-2015','dd-mon-yyyy') from dual union all
    SELECT 'start5',to_date('14-jan-2015','dd-mon-yyyy') FROM dual
  )
  , start_and_end as (
    select -1 rowtype, end_id id, end_dt dt from end_table
    union all
    select 1, s.* from start_table s
  )
  , running_count as (
    select se.*,
      sum(rowtype) over(order by dt, rowtype desc) cnt
    from start_and_end se
  )
  , filtered_ends as (
    select rowtype, id, dt from (
      select rc.*,
        min(decode(rowtype,-1,cnt)) over(
          order by dt, rowtype desc
          rows between unbounded preceding and 1 preceding
        ) mincnt
      from running_count rc
    )
    where cnt >= nvl(mincnt,0) or cnt >= 0
  )
  select * from (
    select rowtype, id,
    row_number() over(partition by rowtype order by dt) rn
    from filtered_ends
  )
  pivot(max(id) for rowtype in(1 st_id, -1 end_id))
  order by rn;
  

  ST_ID END_ID RN

  ---------- ------ ------

  1 start0 end0

  2 Start1 end2

  3 Start2 end3

  4 start3 bout4

  5 debut4 end5

  Debut5 6 end6

• Find the nearest parallel line and ignore perpendicular line

  Hello
  
  We have two sets of linear facilities. We would like to find the nearest line of the other set of geometry, but preference should be given to the parallel lines as the perpendicular ones more.
  
  I was intending to use the suite response I see in this forum.
  extract the parallel roads
  
  Is another way?
  
  Thank you
  Frédéric

  Frederick,

  It really depends on what you're trying to determine from your data. I noticed that you included 'street' in your tags. Are you trying to link Street - axis facades, utilities or the plots?

  If you use buffering as John suggested, get an account for characteristics how target your buffer interacts with. In some cases (say the intersections of streets) where you will get multiple occurrences, you can compare the angles/slopes to identify the one who more parallel.

  Note that line buffering will produce a Cheeto (right, with well rounded rectangle). The Cheeto may interact with more than 1 target function if your buffer is too big and the characteristics of the target are tip-to-tail connected - and each of these objectives can be parallel to your line. If it's a problem, you can calculate distances to your targets and choose Next. You will probably always compare the slopes to eliminate false positives at intersections.

  In support of geocoding, I once to the streets adjacent plots and tried the above approaches and found that they do not have sufficient accuracy to dead end or corner-bulbs bulbs. Instead, I used the rotation value of the parcel labels (always placed perpendicular to the street) to generate features of research at the intersection of the adjacent streets. These search functions have variable length depending on the type of street. There were still a few false positives due to errors of data (e.g., misguidance label type, incorrect of streets, etc.), but little enough to dump a body to.

  Kind regards
  Noel