See the sum of subset question quiz on a blade of results

I want to show the sum of part only of scores question quiz on a blade of results.

I want to still follow and record the scores of questions (acting as a series of tests), but show that the score some of these question marks (final quiz) to the user. I read these steps http://blog.lilybiri.com/intermediate-score-slides but I only need a subset. I'm not getting any summing the scores showing the partition on the slide.

Any suggestions welcome... Michelle

Even if you need only a subset, the workflow is quite similar. I would create a variable used to store the total score for the questions in this subset. After each question to consider, you add the value of the variable cpQuizInfoLastSlidePointsscored of system to the user variable. At the end of these questions (don't forget the last of them), you will have the total score for this subset in this user variable.

Tags: Adobe Captivate

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ORDER BY  department_id, job_id
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           30 PU_CLERK        13900
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           70 PR_REP          10000
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           90 AD_VP           34000
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    Published by: Frank Kulash on May 27, 2013 10:47

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    B.key_code group

    I got this:
    KEY_CODE SUM (A.INVOICE_AMT) SUM (A.PAID_AMT) SUM (B.TOT_AMT) SUM (B.INV_AMT)
    123123 1168182.16 1168182.16 7009092.96 7009092.96

    But I expected this

    KEY_CODE SUM (A.INVOICE_AMT) SUM (A.PAID_AMT) SUM (B.TOT_AMT) SUM (B.INV_AMT)
    123123 1168182.16 1168182.16 1168182.16 1168182.16

    Thus, the last 2 columns must be exactly what is stored in table1? Then either
    b include these columns in the GROUP BY clause and not to use the SUM,
    (b) the GROUP BY on rec_a alone, separately, can't join the results to the rec_b, or
    (c) using MIN or MAX, instead of SUM. (Anyone. Since there is only one value, MIN will be the same as MAX.)

    Here is an example of (a):

    SELECT    B.key_code
,       sum (a.invoice_amt)     AS sum_invlice_amt
,       sum (a.paid_amt),     AS sum_paid_amt
,       b.tot_Amt
,       b.inv_amt
FROM        rec_a          A
,        rec_b          B
WHERE        A.KEY_CODE     = B.KEY_CODE
AND        B.KEY_CODE      in ('123123')
group by  B.key_code
,            b,tot_amt
,       b.inv_amt
;

    I hope that answers your question.
    If not, post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and the results desired from these data.
    Point where the above query is to produce erroneous results, and explain, using specific examples, how you get the right results from data provided in these places.
    Always say what version of Oracle you are using (for example, 11.2.0.2.0).
    See the FAQ forum {message identifier: = 9360002}

  • What type of input parameter is used according to the SUM?

    Hello world
    As we know sum is an oracle function preset. But what these guys here oracle used for input parameters. How did they do that?
    I mean, we can write this sum fuction as many ways as as mentioned below. Please give me some ideas how to do this.
    SELECT SUM(salary) as "Total Salary" FROM employees;

SELECT SUM(DISTINCT salary) as "Total Salary" FROM employees;

SELECT SUM(income - expenses) as "Net Income" FROM gl_transactions;

SELECT SUM(sales * 0.10) as "Commission" FROM order_details;
    Kind regards
    BS2012

    BS2012 wrote:
    Hello world
    As we know sum is an oracle function preset. But what these guys here oracle used for input parameters. How did they do that?
    I mean, we can write this sum fuction as many ways as as mentioned below. Please give me some ideas how to do this.

    SELECT SUM(salary) as "Total Salary" FROM employees;

SELECT SUM(DISTINCT salary) as "Total Salary" FROM employees;

SELECT SUM(income - expenses) as "Net Income" FROM gl_transactions;

SELECT SUM(sales * 0.10) as "Commission" FROM order_details;

    Kind regards
    BS2012

    As others have said, your question is not very clear.

    There are many aspects and angles to look at what you're asking.

    First of all, a level superior, the sum function simply takes a numeric value as it's argument, so all of these examples you gave have expressions that evaluate to a numeric value to be provided to the sum function. (As someone else already mentioned you can have non-numeric data types, just as long as they can be implicitly converted to a numeric value).

    A statement analysis and the point of view of enforcement, the content of the expression inside the brackets is evaluated before being passed to the sum function. It is not the function sum that he himself takes the expression and evaluates it. The sum function is expecting just a single numeric value.

    Internally, what the function sum is the case, is more than just a single... call function and return a value, because it faces several values being passed in the aggregation group. As such, it must have the ability to know if to start in short, is to accept several input values, so he can add them together, you know give up adding entries and pass the result to the back.

    If we write our own defined aggregate function (others have already provided a link to explain this) we can see what is happening internally. In the following example, we'll write a function defined by the user that multiplies the values rather than the amounts...

    create or replace type mul_type as object(
  val number,
  static function ODCIAggregateInitialize(sctx in out mul_type) return number,
  member function ODCIAggregateIterate(self in out mul_type, value in number) return number,
  member function ODCIAggregateTerminate(self in mul_type, returnvalue out number, flags in number) return number,
  member function ODCIAggregateMerge(self in out mul_type, ctx2 in mul_type) return number
  );
/
create or replace type body mul_type is
  static function ODCIAggregateInitialize(sctx in out mul_type) return number is
  begin
    sctx := mul_type(null);
    return ODCIConst.Success;
  end;
  member function ODCIAggregateIterate(self in out mul_type, value in number) return number is
  begin
    self.val := nvl(self.val,1) * value;
    return ODCIConst.Success;
  end;
  member function ODCIAggregateTerminate(self in mul_type, returnvalue out number, flags in number) return number is
  begin
    returnValue := self.val;
    return ODCIConst.Success;
  end;
  member function ODCIAggregateMerge(self in out mul_type, ctx2 in mul_type) return number is
  begin
    self.val := self.val * ctx2.val;
    return ODCIConst.Success;
  end;
end;
/
create or replace function mul(input number) return number deterministic parallel_enable aggregate using mul_type;
/

    For example, our user-defined aggregate function is based on a total object type.
    This object keeps a value ("val" in our example).
    It has an Initialize method, so when the SQL engine indicates that this is the beginning of an aggregation of values it can set its value to an initial value (in this case zero).
    It has an Iterate method, the SQL engine passes the values to it in the context of all grouped values, it can treat them (in our case it multiplies the value of entry with the value already there for this game of aggregations (and takes a value of 1 for the first iteration basis))
    She has a Terminate method, so when the SQL engine indicates that the global set of values is completed, it can return the result.
    The last method there is a merger and is mandatory, so that when the aggregation is done parallel assessment tool (for better performance internally), the results of these parallel executed aggregations can be combined (see http://docs.oracle.com/cd/E11882_01/appdev.112/e10765/ext_agg_ref.htm#ADDCI5132). As we are multiplying numbers, in our case, it is simply a case of the multiplication of one single result with each other.

    And to see that it works...

    SQL> with t as (select 2 as x from dual union all
  2             select 3 from dual union all
  3             select 4 from dual union all
  4             select 5 from dual)
  5  --
  6  select mul(x)
  7  from t;

    MUL(X)
----------
       120

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