Display the sum of all salaries of employees @ footer section

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• 20 GB difference between space and the sum of all files

  my c: drive displays of 42.5 GB used space. the sum of all folders on the c: is 22 GB. make all the folders and files not hidden. I just deleted a user account. the files could still be in the cache somewhere? recovery partition is less than 1 GB. Thank you!!

  To study disk space, use download and install Treesize (freeware).
  http://www.Jam-software.com/treesize_free/

  Information about Treesize
  http://www.Jam-software.com/treesize_free/

  When you open Treesize scan select in the Menu and you will see a list of drives. Click on C and it will generate a list of files.

  Display names and 6 larger files sizes and the total at the top of the list.

• SQL query to display the sum of the values of each June and December

  Hello having problems of construction of a query to the list SQL query to display the sum of the values of each June and December each year.

  My Table;

  TABLE name: MONTH_TERM

  Fields with values:

  TERM_KEY	MONTH_ACTUAL	MONTH_DATE
  82	500	01/11/2015 0:00
  82	450	01/12/2015 0:00
  82	405	01/01/2016 0:00
  82	400	01/02/2016 0:00
  82	450	01/03/2016 0:00
  82	425	01/04/2016 0:00
  82	435	01/05/2016 0:00
  82	410	06/01/2016 0:00
  82	409	01/07/2016 0:00
  82	415	01/08/2016 0:00
  82	420	09/01/2016 0:00
  82	422	10/01/2016 0:00
  82	436	11/01/2016 0:00
  82	556	01/12/2016 0:00
  82	568	01/01/2017 0:00
  82	624	02/01/2017 0:00

  What I would like to see in a query result:

  TERM_KEY	MONTH_ACTUAL	MONTH_DATE	Total of 6 months
  82	500	01/11/2015 0:00
  82	450	01/12/2015 0:00	950
  82	405	01/01/2016 0:00
  82	400	01/02/2016 0:00
  82	450	01/03/2016 0:00
  82	425	01/04/2016 0:00
  82	435	01/05/2016 0:00
  82	410	06/01/2016 0:00	2525
  82	409	01/07/2016 0:00
  82	415	01/08/2016 0:00
  82	420	09/01/2016 0:00
  82	422	10/01/2016 0:00
  82	436	11/01/2016 0:00
  82	556	01/12/2016 0:00	2658
  82	568	01/01/2017 0:00
  82	624	02/01/2017 0:00

  ---

  Here's my query:

  Select

  "TERM_KEY,"

  "MONTH_ACTUAL,"

  to_char(MONTH_DATE,'MM/YYYY') MONTH_DATE,

  DEAL to_char (MONTH_DATE, 'MM')

  WHEN '06' THEN (SELECT SUM (MONTH_ACTUAL)

  OF MONTH_TERM

  WHERE the to_char (MONTH_DATE, 'MM') between 1 and 6

  AND term_key = 82)

  WHEN '12' THEN (SELECT SUM (MONTH_ACTUAL)

  OF MONTH_TERM

  WHERE the to_char (MONTH_DATE, 'MM') between 7 and 12

  AND term_key = 82)

  ELSE null

  END as SIX_MO_CUMM,

  of MONTH_TERM

  where term_key = 82

  It's my results:

  TERM_KEY	MONTH_ACTUAL	MONTH_DATE	Total of 6 months
  82	500	01/11/15 0:00
  82	450	01/12/15 0:00	3608
  82	405	01/01/16 0:00
  82	400	01/02/16 0:00
  82	450	01/03/16 0:00
  82	425	01/04/16 0:00
  82	435	01/05/16 0:00
  82	410	01/06/16 0:00	3717
  82	409	01/07/16 0:00
  82	415	01/08/16 0:00
  82	420	01/09/16 0:00
  82	422	10/01/16 0:00
  82	436	01/11/16 0:00
  82	556	01/12/16 0:00	3608
  82	568	01/01/17 0:00
  82	624	01/02/17 0:00

  Any ideas on how to fix would be great

  Select term_key,

  month_actual,

  month_date,

  case mod (to_char (month_date, 'mm'), 6)

  When 0 then sum (month_actual)

  During)

  term_key partition

  order of month_date

  between the previous month '5' interval and the current line

  )

  end '6 MONTHS in TOTAL'

  from tbl

  order of term_key,

  month_date

  /

  TERM_KEY MONTH_ACTUAL MONTH_DAT 6 MONTHS TOTAL
  ---------- ------------ --------- --------------
  82 500 NOVEMBER 1ST, 15TH
  82 450 1 DECEMBER 15 950
  82 405 1 JANUARY 16
  82 400 1 FEBRUARY 16
  82 450 1ST MARCH 16
  82 425 1ST APRIL 16
  82 435 1 MAY 16
  82 410 2525 1 JUNE 16
  82 409 1 JULY 16
  82 415 1ST AUGUST 16
  82 420 16 - SEP - 01

  TERM_KEY MONTH_ACTUAL MONTH_DAT 6 MONTHS TOTAL
  ---------- ------------ --------- --------------
  82 422 1 OCTOBER 16
  82-436 NOVEMBER 1, 16
  82 556 2658 1 DECEMBER 16
  82 568 1 JANUARY 17
  82 624 1 FEBRUARY 17

  16 selected lines.

  SQL >

  SY.

• How to get the last row and the sum of all columns in a query

  Hello

  is there a way to get the last record for a column and the sum of all the Archives to another column in the same query.

  Best regards

  You must set your needs correctly volunteers to help here...

  Your data are not good enough to bring you a precise solution. Purpose, you do not have a column, which draws a distinction between the first and the last entry.

  The solution becomes easy based on your design.

  I introduced a grouping called 'id' column and a time column called 'time_of_insert' (only this way you can say with confidence that you can differentiate between the first and last (also a foolproof solution) - you can possibly use sequence (instead of date but if you say that you can insert two lines at the same time) ((and then likely sequence would be a better choice to differentiate instead of a timestamp field) etc...)

  With your sample data, something like this can be done to get the desired results.

  -----------------------------------------------------------------------------------------------------------------------

  WITH dataset AS

  (SELECT 1 id, 10 used, 8 remain, systimestamp + 1/24 time_of_insert FROM DUAL

  UNION ALL

  SELECT the 1 id, 1, 7, systimestamp + 2/24 FROM DUAL

  UNION ALL

  SELECT the id 1, 2, 5, systimestamp + 3/24 FROM DUAL

  UNION ALL

  SELECT 1 id, 1, 0, systimestamp + 4/24 FROM DUAL

  UNION ALL

  SELECT 1 id, 0, 0, systimestamp + 5/24 FROM DUAL

  UNION ALL

  SELECT the 1 id, 1, 4, systimestamp + 6/24 FROM DUAL)

  SELECT *.

  (SELECT SUM (used) ON sum_all)

  FIRST_VALUE (stay)

  COURSES (PARTITION BY id ORDER BY time_of_insert DESC)

  last_row

  Of THE dataset)

  WHERE ROWNUM = 1;

  Output:

  ------------------------

  SUM_ALL LAST_ROW

  ------------------------------

  15                  4

  See you soon,.

  Manik.

• The sum of all the "ER" element under the service tag

  Hi gurus
  
  I'm trying to add up all the values of Er under the tag of benefits. But tag Er resumes on different tags in my document xml, as shown below. can you help me provide how to create the sum for all these Er values under the tag of benefits. I appreciate your help. Here is my xml document.
  
  
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  < insurance >
  < REIMBURSED >
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  < / REIMBURSED >
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  < < /ee > ee > 65
  < > 1000 < /er > er
  < / dentalinsurance >
  < / insurance >
  < refinementbenefits >
  < socialsecurity >
  < < /ee > ee > 1000
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  < / socialsecurity >
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  < > < /er > 1500 St
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  < / refinementbenefits >
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  < holiday >
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  < > < /er > 2200 St
  < / sick >
  < holiday >
  < ee > < /ee >
  < > < /er > 3000 St
  < / holiday >
  < / timeoffbenefits >
  < mandatedbenefits >
  < fedunemp >
  < ee > < /ee >
  < > < /er > 200 er
  < / fedunemp >
  < stunemp >
  < ee > < /ee >
  < > 1000 < /er > er
  < / stunemp >
  < / mandatedbenefits >
  < specialbenefits >
  < freeparking >
  < ee > < /ee >
  < > 1000 < /er > er
  < / freeparking >
  < cell >
  < ee > < /ee >
  < > 1000 < /er > er
  < / mobile phone >
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  Thank you.

• The sum of all invoices and view total

  Hello

  I do perhaps the hardest way but the case is the following:

  I want to calculate all the Bills of the largeOrders2 collection and collect all the item.totalPrice 'values' in a table and assign a total that I can use on the site, up to now, I have my code as follows:

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  {% for article on largeOrders2.items-%}

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  < span class = "red sumInvoice" > {{invoicetotals}} </span >

  {% endfor}

  < div class = "result" > Total spent on shopping: {capture totalInvoices %} < span class = "totalsum" > < / span > £{% endcapture} {{totalInvoices}} < / div >}

  < script type = "text/javascript" >

  var sum = 0;

  $('.sumInvoice').each (function () {}

  sum += parseFloat ($(this) .text ());  Or this.innerHTML, this.innerText

  $(".totalsum").text (sum);

  });

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  use {{totalInvoices}} in a {% if order_requirement < totalinvoices-%} declaration.

  I'm quite sure, there is an easier way, but I have not found a solution for the sum of an array using liquid and obtaining data from the result instead of text().

  Thank you

  You don't need any JavaScript for this and you just need to sort your liquid.

  Things of importance to note:

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  -You create an entitled 'Total' ready before your loop with a value of 0 is a number

  -You do the following your loop for: {% assign invTotal = invTotal: so: item.totalPrice-%}

  - As you loop your value will be added to each invoice

  -{{invTotal}} will give you your total value.

• try to get the SUM of all of the charges with the having clause

  Hi Oracle users.

  I'm trying to accomplish to get a sum of a series of charges and it should be easy, but I can't get it.

  For example, I have the following.

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   WHERE TIME_REQ > SYSDATE-120
   Group By ACCTLOC
    having (count(ACCTLOC) > 1)
   
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  Philly     15970
  NY          8623
  Tacoma        3
  SanFran     195
  Hartford    5
  Miami       4374
  
    
  

  How can I get the SUM of this group? Do I put this in PL SQL and do a procedure to carry out the selection? Is this the way to go on this?
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  Thank you!

  with

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  (select 'Philly' acctloc, 15970 totalp Union double all the)

  Select "NY", 8623 Union double all the

  Select "Tacoma", 3 double Union all

  Select "SanFran", 195 double Union all

  Select "Hartford", 5 Union double all the

  Select 'Miami', double 4374

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  Philly	15970	29170	4861.66666666666666666666666666666666667	.547480287967089475488515598217346588961
  NY	8623	29170	4861.66666666666666666666666666666666667	.295611930065135413095646211861501542681
  Tacoma	3	29170	4861.66666666666666666666666666666666667	.000102845389098388755570791909496057593
  SanFran	195	29170	4861.66666666666666666666666666666666667	.006684950291395269112101474117243743572
  Hartford	5	29170	4861.66666666666666666666666666666666667	.000171408981830647925951319849160095989
  Miami	4374	29170	4861.66666666666666666666666666666666667	.149948577305450805622214604045251971203

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  Etbin

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  Hello
  I want to get the sum of each Member in a hierarchy.
  The hierarchy is defined in the strdet table:

  create table strdet
  
  (costcenterms varchar2(20),     // parent
  
   costcenterdet varchar2(20),    // child
  
   lev varchar2(1))

  The values for each object/material by costcenter (child) is defined in the details_det table:

  create table details_det
  
  (costcenterms varchar2(20),
  
   eppid varchar2(30) ,
  
   purchcontyear0 number(4,1) )

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  insert into strdet values ('1' , '1.1','2')
  
  /
  
  insert into strdet values ('1' , '1.2','2')
  
  /
  
  insert into strdet values ('1.1' , '1.1.1','3')
  
  /
  
  insert into strdet values ('1.1' , '1.1.2','3')
  
  /
  
  insert into strdet values ('1.2' , '1.2.1','3')
  
  /
  
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  /
  
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  /
  
  insert into strdet values ('1.1.2' , '1.1.2.1','4')
  
  /
  
  insert into strdet values ('1.2.1' , '1.2.1.1','4')
  
  /
  
  insert into strdet values ('1.2.1' , '1.2.1.2','4')
  
  /
  
  COMMIT;

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  --------------             ------
  
  1                        220 
  
  1.1                       55
  
  1.2                     165
  
  1.1.1                    30
  
  1.1.2                    20
  
  1.2.1                  165

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    2        from details_det d , strdet s
  
    3        where s.costcenterdet=d.costcenterms(+)
  
    4        start with s.costcenterms='1'
  
    5             connect by  s.costcenterms = prior s.costcenterdet
  
    6        order by s.costcenterms
  
    7  /
  
   
  
  COSTCENTERMS                                                 SUM(PURCHCONTYEAR0)OVER(PARTIT
  
  ------------------------------------------------------------ ------------------------------
  
  1.2                                                          
  
  1.2.1                                                                                   165
  
  1.1.1                                                                                    30
  
  1.1.2                                                                                    20
  
  1                                                            
  
  1.1                                                          
  
   
  
  6 rows selected

  How should I modify the above sql stmt to get the result you want...?
  
  Note: I use OracleDB 10 g. v.2
  
  Thank you very much
  SIM

  sgalaxy wrote:
  Anyway, since I want to use the sql stmt to define a materialized view, all versions of data of hierarchical queries are not allowed... (oracle ora-30361 error...).

  No error on my:

  Connected to:
  Oracle Database 10g Enterprise Edition Release 10.2.0.1.0 - Production
  With the Partitioning, OLAP and Data Mining options
  
  SQL> create materialized view x_mv
    2  as
    3  select  grp,
    4          sum(purchcontyear0)
    5    from  (
    6           select  connect_by_root s.costcenterms grp,
    7                   d.purchcontyear0
    8             from  strdet s,
    9                   details_det d
   10                   where s.costcenterdet=d.costcenterms(+)
   11                   connect by s.costcenterms = prior s.costcenterdet
   12          )
   13    group by grp
   14  /
  
  Materialized view created.
  
  SQL> select  *
    2    from  x_mv
    3    order by grp
    4  /
  
  GRP                  SUM(PURCHCONTYEAR0)
  -------------------- -------------------
  1                                    215
  1.1                                   50
  1.1.1                                 30
  1.1.2                                 20
  1.2                                  165
  1.2.1                                165
  
  6 rows selected.
  
  SQL> 
  

  SY.

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  842106 wrote:
  Finally, I need to type = MS
  (i) is_flag total count for all periods
  (II) for the period = 20110501 this is the mv_count

  I need to use the unique table time (i.e. outer joins self-join not)
  I tried using the partition by clause, but it will filter the data.

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              (
               case when period = 20110501 then mv_count else 0 end
              ) mv_cnt_for_20110501
  from your_table
  where type = 'MS';
  

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