Select distinct uber several Spalten und eine Ausgabe der nicht ads. Kann mir refer someone help?

Similar Questions

• Textumfluss: Internal uber several Spalten

  Hallo,

  ID CC: habe ein Dokument mit 2 Spalten wo ich eine breite table column 1 sharp Tabelle und einfuge bis in the second column-handed.
  In the second column ignoriert nun der Textumfluss und der Text im der Tabelle background so sharp. Kann man das nur damit losen, indem man die tab in einen extrigen Rahmen packt?

  Beste Grüße
  Andreas

  Nein, internal können keinen Textumfluss process, sie ignorieren auch die Rahmengrenzen own.

  JA, kann man die Tabelle in einen own Textrahmen packen und diesem Textumfluss/Konturfuhrung Encoder. These Textrahmen kann man auch verankern, dass er mit dem text mitfliesst.

  BESSER ware are, wenn deutschsprachige questions im deutschen und nicht im English U2U Forum von Adobe stellst. Die meisten, die yesterday unterwegs sind, verstehen kein deutsch.

• Wie kann ich several Spurkeyframes/alle eines auf once löschen, ohne alle produktdarstellung anzuwahlen Clips

  Hallo zusammen,

  die ist eigtl quite simpel (die Antwort wahrschnl like) question, ich komm nur einfach nicht is... und langsam bin am verzweifeln :/

  Like several spurkeyframes möchte ICH in der chronology anwahlen, z.B. mit Strg + A oder mit der Maj-snack einen Bereich von zwischen zwei markieren, um auf zu entfernen once sharp Keyframes keyframe. ICH schaffe're aber jeden individual Keyframe nacheinander anzuwahlen active, was mir bei meiner Spurkeyframes Anzahl der viel zu aufwendig und zeitfressend ist...

  Kann mir yesterday someone help?

  ICH euch sehr thankful ware!

  Vielen Dank schon once und liebe Grüße,

  Alex

  Using the Pentool and catch the keyframes.

• SELECT DISTINCT alternative

  It's the kind of related to another issue that is posted on this forum.

  As a temporary solution, I try to have my sweater page results in a bunch of products of a table. .

  I have another table of warnings that are joined by the product ID

  The table of warnings will have several elements with the same part number (different warning IDs)

  Then, when I pull in products, get multiples of the same products

  I tried a number of different methods to get this not not to shoot in multiples:

  I tried SEPARATE just on products

  I tried a subquery using SEPARATE the WHERE statement

  SEPARATE does not work, and I read that it isn't exactly the best way to to do.

  If not, how can I do?

  Below is basically how I tried to do.

  SELECT P.ID, HAZ. PID, HAZ.hazardID
  FROM tblProducts P
  LEFT OUTER JOIN tblHazard HAZ on P.ID is HAZ. NEST
  WHERE (HAZ. PID IN (SELECT DISTINCT PID FROM tblHazard sHAZ))

  > All that I really need to know isBob and Frank have children.

  OK, so you may want to the result to be something like:

  Children of the employee

  Yes Bob

  Frank Yes

  Jim No.

  Fix?

  Assuming that it is a standard database, we would have 2 tables - used and the child. An inner join of employee for child returns only employees with children. An outer join of the used for child where the child value = Null returns employees without children. Using a UNION, we can combine the two to get the results above.

  Now, what you want in your query?

• Get the number of DISTINCT from several columns

  How can I get the number of DISTINCT from several columns?
  

  SQL> select count(distinct ename) from emp;
  
  COUNT(DISTINCTENAME)
  --------------------
                    14
  
  SQL> select count(distinct ename, job) from emp;
  select count(distinct ename, job) from emp
         *
  ERROR at line 1:
  ORA-00909: invalid number of arguments

  Hello

  select count(distinct ename || job) from emp;
  

  Kind regards

• Microsoft SQL Server 2014 (SP1 - CU4) (KB3106660) query failed with error ORDER BY items must appear in the select list if SELECT DISTINCT is specified.

  Hello
  I use Microsoft SQL Server 2014 (SP1 - CU4) (KB3106660) Enterprise Edition (64-bit) on Windows NT 6.1 (Build 7601: Service Pack 1)

  SELECT DISTINCT A.PI_LOOKUP_CATEGORY_ID,
  REPLACE (REPLACE (UPPER (A.LOOKUP_CATEGORY_NAME), ' ', '_'), '-', '_') AS CATEGORY_TECH_NAME,
  A.LOOKUP_CATEGORY_NAME,
  A.LOOKUP_CATEGORY_DESCR,
  COUNT (B.PI_LOOKUP_CATEGORY_ID) AS USAGE_COUNT
  FROM [PI_LOOKUP_CATEGORY] A LEFT OUTER JOIN B [PI_INSIGHT_COLUMN] WE
  A.PI_LOOKUP_CATEGORY_ID = B.PI_LOOKUP_CATEGORY_ID
  A.PI_LOOKUP_CATEGORY_ID GROUP,
  REPLACE (REPLACE (UPPER (A.LOOKUP_CATEGORY_NAME), ' ', '_'), '-', '_').
  A.LOOKUP_CATEGORY_NAME,
  A.LOOKUP_CATEGORY_DESCR
  ORDER TO REPLACE (REPLACE (UPPER (A.LOOKUP_CATEGORY_NAME), ' ', '_'), '-', '_')

  above request is failed with error ' ORDER BY items must appear in the select list if SELECT DISTINCT is specified. " Microsoft SQL Server (SP1 - CU4) 2014 (KB3106660)

  same query works fine with older versions of SQL servers like (2008R2, or 2012)

  Please let me know the resolution of this problem...

  Thank you
  Touria

  Ask here:

  MSDN - SQL Server - Microsoft forums

• Explain plan for select distinct

  I got 1 of the online test and there the question has been asked. I have already answered but curious to cross-check my response with your advice...

  Question

  Explain what information plan if the show room in SQL indicates that a separate select statement is made in the SQL.

  
  

  The choices are:

  Sort by a join

  b sort by

  c single fate

  d sort aggregate

  group e - sort by

  My answer

  I gave aggregates of SORT but it seems that his unique kind, because when I run explain plan then I see (unique) hash. Please guide

  
  

  SEPARATE will identify unique rows. So in the given choice it would be KIND of UNIQUE. But oracle could go other plans as UNIQUE HASH or same INDEX FULL SCAN.

  Look at the oracle does not SORT.

  SQL> select distinct ename from emp;
  ENAME
  ------
  SMITH
  BLAKE
  CLARK
  KING
  ADAMS
  TURNER
  ALLEN
  SCOTT
  JONES
  MARTIN
  WARD
  11 rows selected.
  SQL> select * from table(dbms_xplan.display_cursor);
  PLAN_TABLE_OUTPUT
  ---------------------------------------------------------------------------------
  SQL_ID  6b32yqumjmp9b, child number 0
  -------------------------------------
  select distinct ename from emp
  Plan hash value: 984151148
  ---------------------------------------------------------------------------
  | Id  | Operation          | Name | Rows  | Bytes | Cost (%CPU)| Time     |
  ---------------------------------------------------------------------------
  |   0 | SELECT STATEMENT   |      |       |       |     3 (100)|          |
  |   1 |  HASH UNIQUE       |      |    11 |    66 |     3  (34)| 00:00:01 |
  |   2 |   TABLE ACCESS FULL| EMP  |    11 |    66 |     2   (0)| 00:00:01 |
  ---------------------------------------------------------------------------
  
  14 rows selected.
  

  Let me make an explicit ORDER BY for her to performa SORT.

  SQL> select distinct ename from emp order by 1;
  ENAME
  ------
  ADAMS
  ALLEN
  BLAKE
  CLARK
  JONES
  KING
  MARTIN
  SCOTT
  SMITH
  TURNER
  WARD
  11 rows selected.
  SQL> select * from table(dbms_xplan.display_cursor);
  PLAN_TABLE_OUTPUT
  -------------------------------------------------------------------------------
  SQL_ID  f72vjx5rmm0z4, child number 0
  -------------------------------------
  select distinct ename from emp order by 1
  Plan hash value: 725351111
  ---------------------------------------------------------------------------
  | Id  | Operation          | Name | Rows  | Bytes | Cost (%CPU)| Time     |
  ---------------------------------------------------------------------------
  |   0 | SELECT STATEMENT   |      |       |       |     4 (100)|          |
  |   1 |  SORT UNIQUE       |      |    11 |    66 |     3  (34)| 00:00:01 |
  |   2 |   TABLE ACCESS FULL| EMP  |    11 |    66 |     2   (0)| 00:00:01 |
  ---------------------------------------------------------------------------
  
  14 rows selected.
  SQL>
  

  Version - 10.2.0.5.0

• Stay instant, wie eins und eins oder t-online e-mail system. ICH will be arbeiten und nicht standig Unbrauchbares shopping und wieder löschen. Digestive tube Nun

  Habe die monthly cloud creative so bzw. gemietet, erhalte aber nur In Design variant, also kein Phot-Shop. Kein Illustrator usw. Es ist mehr als schwierig, sich zwischen der zerschmetternden HILFEN zu netscheiden oder zurechtzufinden allen. Was kostet was, so was geht die ist wie guidance durch Sprache, so ein remark EIB deutscher Rahmensprache auf English videos. DAS Problem beginnt schon Windows 8.1 so, please geklickt APP mit dem Verweis auf Adobe, which man, aber alles sonst bleibt im Rechner und wird sofort aktiv. As das muss eine klare Linie Geld him. Stay instant, wie eins und eins oder t-online e-mail system. ICH will be arbeiten und nicht standig Unbrauchbares shopping und wieder löschen. Digestive tube Nun

  Please check that your computer meets the minimum requirements for creative cloud and each CC program you want to install. Programs will not for installation if the system does not support: system requirements | Creative cloud.

  If you continue to have difficulties, please contact our support staff at the following link: https://helpx.adobe.com/contact.html

  (be sure to connect to adobe.com with your Adobe ID first)

  Click on the still need help? option in the blue box below, then choose the cat.

• Select distinct optimization

  Hello!

  Is it possible to force the optimizer to use a non-unique index for qurey below?

  select distinct id from t1
   union all 
   select distinct id from t2;
  

  
  I'm usung 11.2.0.3

  Thank you and best regards,
  Pavel

  So declare them non-null. Unless you do this, you cannot use an index.

• Select distinct performance

  Hello
  I have the following problem. A table with appox 650 000 rows and 200 columns queried to distinct values in a column (SN) of type VARCHAR2 (200 Bytes).
  
  The query returns the 40 distinct values in 30 seconds. I would like to shoot this day here.
  
  The original DBA had created a unique index on two columns (SN, DN). Column DN's NUMBER (10.0).
  
  When I run the query with autotrace on I see that the index is not used and a full table scan.
  
  I tried to create an index on just SN, i.e. being not used.
  
  Any suggestions?
  
  Thank you.

  natet wrote:
  John,
  The column definition for the two shows like 'Yes' nullable columns, but the data itself have no nulls for the column.

  You know that the data have no null values and now, I know as well, but does not know that the optimizer and may not know that without you say things as well.

  Add a predicate to your query sn is not null, and it should start to use the index given that sn is the leading column of the index.

  Please note should in the sentence that precedes, the opitimizer may still decide that a full analysis is the way to go, but if you query is of the form:

  select distinct sn from table
  where sn is not null
  

  My bet would be that it will use an index.

  John

• Select distinct cardno how ti implement in owb

  Hello world
  
  I'm quiet new to owb and I want to know how to use the separate in owb...
  
  my query is
  
  Select distinct Caron, brand_edesc
  table tlog where
  edesc = 'AAAA '.
  and tmonth > = 200807 and tmonth < = 200809
  
  so my question is
  
  to find out where the clause I now use the filter operator, I want to know in owb which carrier we use to select distinct?
  
  Thank you very much

  You can use Deduplicator operator.
  Drag the Deduplicator operator and pass cardno, brand_edesc to it.

  See you soon
  Katia

• Select distinct slow on a single column

  Oracle 10.2.0.4
  Linux
  
  I have two requests on the same table.
  
  Select distinct month_id from ABC; --> Uses indexes not even if the index/Index_ffs flag is used. Takes 12 minutes to complete.
  
  Select distinct cost_center from ABC; - > use indexes and runs much faster. Full within minutes.
  

  SQL> select Distinct month_id from abc;
  
  Execution Plan
  ----------------------------------------------------------
  Plan hash value: 1358216387
  
  -------------------------------------------------------------------------------------------------------
  | Id  | Operation           | Name            | Rows  | Bytes | Cost (%CPU)| Time     | Pstart| Pstop |
  -------------------------------------------------------------------------------------------------------
  |   0 | SELECT STATEMENT    |                 |    22 |    66 |   144K  (6)| 00:33:40 |       |       |
  |   1 |  HASH UNIQUE        |                 |    22 |    66 |   144K  (6)| 00:33:40 |       |       |
  |   2 |   PARTITION LIST ALL|                 |    36M|   104M|   139K  (3)| 00:32:37 |     1 |     5 |
  |   3 |    TABLE ACCESS FULL| abc           |    36M|   104M|   139K  (3)| 00:32:37 |     1 |     5 |
  -------------------------------------------------------------------------------------------------------
  
  SQL> select distinct cost_center from abc;
  
  Execution Plan
  ----------------------------------------------------------
  Plan hash value: 37945703
  
  --------------------------------------------------------------------------------------------------------------------
  | Id  | Operation           | Name                 | Rows  | Bytes |TempSpc| Cost (%CPU)| Time     | Pstart| Pstop |
  --------------------------------------------------------------------------------------------------------------------
  |   0 | SELECT STATEMENT    |                      |  8778 | 52668 |       | 80860   (6)| 00:18:53 |       |       |
  |   1 |  HASH UNIQUE        |                      |  8778 | 52668 |   420M| 80860   (6)| 00:18:53 |       |       |
  |   2 |   PARTITION LIST ALL|                      |    36M|   209M|       |  5421   (2)| 00:01:16 |     1 |     5 |
  |   3 |    INDEX FULL SCAN  | abc_idx2          |    36M|   209M|       |  5421   (2)| 00:01:16 |     1 |     5 |
  --------------------------------------------------------------------------------------------------------------------
  
  SQL>

  There are differences in DISTINCT_VALUES and Clustering coefficient for two columns. I would like to know if month_id query can be made to run faster anyway.
  There is an index on the month_id column abc_idx5.
  Let me know if you need more information.
  

  INDEX_NAME     INDEX_TYPE     BLEVEL     LEAF_BLOCKS     DISTINCT_KEYS     CLUSTERING_FACTOR     NUM_ROWS     SAMPLE_SIZE
  abc_IDX2     NORMAL     2     53390     21543     3386600     34762540     3476254
  abc_IDX5     NORMAL     2     32320     22     5279502     36667820     36667820

  Published by: HAP on September 30, 2009 10:22
  
  Published by: HAP on September 30, 2009 10:26

  I guess that month_id is optional and cost_center is mandatory:

  SQL> create table t as select level v1, mod(level,10) v2, mod(level,100) v3, mod(level,1000) v4 from dual connect by level <= 100000;
  
  Tabel is aangemaakt.
  
  SQL> desc t
   Naam                                      Null?    Type
   ----------------------------------------- -------- ----------------------------
  
   V1                                                 NUMBER
   V2                                                 NUMBER
   V3                                                 NUMBER
   V4                                                 NUMBER
  
  SQL> create index t4 on t (v4);
  
  Index is aangemaakt.
  
  SQL> analyze table t compute statistics;
  
  Tabel is geanalyseerd.
  
  SQL> select distinct v4 from t;
  
  Uitvoeringspan
  ----------------------------------------------------------
     0      SELECT STATEMENT Optimizer=CHOOSE (Cost=159 Card=1000 Bytes=
            3000)
  
     1    0   SORT (UNIQUE) (Cost=159 Card=1000 Bytes=3000)
     2    1     TABLE ACCESS (FULL) OF 'T' (Cost=29 Card=100000 Bytes=30
            0000)
  
  SQL> alter table t modify v4 not null;
  
  Tabel is gewijzigd.
  
  SQL> select distinct v4 from t;
  
  Uitvoeringspan
  ----------------------------------------------------------
     0      SELECT STATEMENT Optimizer=CHOOSE (Cost=152 Card=1000 Bytes=
            3000)
  
     1    0   SORT (UNIQUE) (Cost=152 Card=1000 Bytes=3000)
     2    1     INDEX (FAST FULL SCAN) OF 'T4' (NON-UNIQUE) (Cost=22 Car
            d=100000 Bytes=300000)
  

  Oracle is unable to use the index to determine if there are null values in the month_id column. I know three alternatives:

  1. Add a clause not null to the query if you are not interested in null values

  SQL> alter table t modify v4 null;
  
  Tabel is gewijzigd.
  
  SQL> select distinct v4 from t where v4 is not null;
  
  Uitvoeringspan
  ----------------------------------------------------------
     0      SELECT STATEMENT Optimizer=CHOOSE (Cost=152 Card=1000 Bytes=
            3000)
  
     1    0   SORT (UNIQUE) (Cost=152 Card=1000 Bytes=3000)
     2    1     INDEX (FAST FULL SCAN) OF 'T4' (NON-UNIQUE) (Cost=22 Car
            d=100000 Bytes=300000)
  

  2. use a union, but this query will take 12 minutes if all rows have a month_id

  SQL> select distinct v4 from t where v4 is not null
    2  union
    3  select v4 from t where v4 is null and rownum = 1
    4  ;
  
  Uitvoeringspan
  ----------------------------------------------------------
     0      SELECT STATEMENT Optimizer=CHOOSE (Cost=183 Card=1001 Bytes=
            3003)
  
     1    0   SORT (UNIQUE) (Cost=183 Card=1001 Bytes=3003)
     2    1     UNION-ALL
     3    2       INDEX (FAST FULL SCAN) OF 'T4' (NON-UNIQUE) (Cost=22 C
            ard=100000 Bytes=300000)
  
     4    2       COUNT (STOPKEY)
     5    4         TABLE ACCESS (FULL) OF 'T' (Cost=29 Card=1 Bytes=3)
  

  3. create an index that contains a constant to the first position; This index includes all rows with null values

  SQL> create index t4_2 on t ( 1, v4 );
  
  Index is aangemaakt.
  
  SQL> select distinct v4 from t;
  
  Uitvoeringspan
  ----------------------------------------------------------
     0      SELECT STATEMENT Optimizer=CHOOSE (Cost=134 Card=1000 Bytes=
            3000)
  
     1    0   SORT (UNIQUE) (Cost=134 Card=1000 Bytes=3000)
     2    1     INDEX (FAST FULL SCAN) OF 'T4_2' (NON-UNIQUE) (Cost=4 Ca
            rd=100000 Bytes=300000)
  

  The fourt solution to change month_id not NULL :)

• Need help with select distinct in group by

  RDBMS 10 g 2
  
  I have tried what a separate select statement with an order by and having looked on the internet and try different examples, I was unsuccessful.
  
  Here is the code work (not tri - I want to sort by pps.last_name but I can't seem to make it work).
  

  select distinct pps.last_name || ', ' ||pps.first_name || ' ' ||pps.middle_initial || '.' d, 
         emple_no r
    from cobr.vw_pps_payroll pps,
         projman pm
   where term_date is null
     and department = '0004400000'
     and pm.eid != pps.emple_no

  Given that the family name is the leading role or your concatenated column 1, how about this:

  select distinct pps.last_name || ', ' ||pps.first_name || ' ' ||pps.middle_initial || '.' d,
         emple_no r
    from cobr.vw_pps_payroll pps,
         projman pm
   where term_date is null
     and department = '0004400000'
     and pm.eid != pps.emple_no
  order by 1
  

• Corrupt mail? My new gmail address mail went down fine. Then I lost a large part of it in the box in. Sent mail seems to reproduce several times in my project. Also in the trash without my help. Help appreciated. Thank you.

  Corrupt mail?

  My new gmail address mail went down fine. Then I lost a large part of it in the box in.

  Sent mail seems to reproduce several times in my project. Also in the trash without my help. Help appreciated. Thank you.

  Yosemite of OS X running.

  Also went to Applications > utilities, disk utility. and 'Repair permissions' restarted when finished. Don't know if this will help future emails.

  To project e-mails, open the preferences Mail account tab select the account gmail and go to the behaviour of the ball. Uncheck the tab where you will store draft messages on the server.

  Give a little more detail on other issues. For the lost emails, they lack also the site of the gmail webmail?

• Wie kann ich mit dem Script ein vorhandenes Signal bearbeiten so, dass ich nur einen Bereich gained bestimmter totalisators ads kann?

  Hallo zusammen,

  ICH habe ein Drehmoment-Signal mit Werten im Datenportal vorliegen 21000.

  Den ich bei diesem erfasse klareren Wert (EIB Index 1000) und den maximum values (EIB Index 20000).

  Nun möchte ich das Signal nur noch zwischen diesen totalisators darstellen, d.h. das sich auf 19000 Werten oder einfach ein neues Signal kurzt Signal mit den Werten ruler remaining.

  Kann mir einer helfen, wie ich dieses problem kann losen?

  Mir die instructions there...

  Viele Grüße

  Hello Bangiz

  Versuche evil den instruction DataBlCopy: Eine description visit of yesterday:

  http://zone.NI.com/reference/de-XX/help/370858K-0113/comoff/datablcopy/

  Mit dem instruction kannst einen Bereich aus einem Kanal in einen others copying.

  Winfried