Select rownum 1
Hi all
I have table that represent the cam of the job, and a worker's 111222333
other 111222888 are H start holiday (01/06/2015 to 07/06/2015 when workers return to work)
W's when it works.
Question is how calculate on 01/06/2015-07/06/2015 = 6 days holiday (start with H)?
with mydata as
(
Select to_date (June 9, 2015 ',' DD/MM/YYYY ') dt, - 684002410 s, 'W', versus, 111222333 code of dual union all
Select to_date (7 June 2015 ',' DD/MM/YYYY '), - 684050570, 'W', 111222333 of double union all
Select to_date (7 June 2015 ',' DD/MM/YYYY '), - 684050570, 'W', 111222888 of double union all
Select to_date (June 6, 2015 ',' DD/MM/YYYY '), - 684150570, 'W', 111222888 of double union all
Select to_date (5 June 2015 ',' DD/MM/YYYY '), - 684190570, 'W', 111222888 of double union all
Select to_date (June 4, 2015 ',' DD/MM/YYYY '), - 684220570, 'W', 111222888 of double union all
Select to_date (3 June 2015 ',' DD/MM/YYYY '), - 684270570, 'W', 111222888 of double union all
Select to_date (2 June 2015 ',' DD/MM/YYYY '), - 684310570, 'W', 111222888 of double union all
Select to_date (1 June 2015 ',' DD/MM/YYYY '), - 684338692, 'H', 111222333 of double union all
Select to_date (1 June 2015 ',' DD/MM/YYYY '), - 684348692, 'W', 111222333 of double union all
Select to_date (1 June 2015 ',' DD/MM/YYYY '), - 684350570, 'W', 111222888 of double union all
Select to_date (1 June 2015 ',' DD/MM/YYYY '), - 684350841, 'W', 111222333 of double union all
Select to_date (1 June 2015 ',' DD/MM/YYYY '), - 684378694, 'W', 111222888 of double union all
Select to_date (29 may 2015 ',' DD/MM/YYYY '), - 684611322, 'W', 111222333 of double union all
Select to_date (29 may 2015 ',' DD/MM/YYYY '), - 684614272, 'W', 111222888 of double union all
Select to_date (29 may 2015 ',' DD/MM/YYYY '), - 684615003, 'W', 111222333 of double union all
Select to_date (29 may 2015 ',' DD/MM/YYYY '), - 684637550, 'W', 111222888 of double union all
Select to_date (28 may 2015', ' MM/DD/YYYY ' "), - 684694292, 'W', 111222333 of the double
)
Select dt, dry
, to_date (6 February 2037 08:28:17 ',' DD/MM/YYYY hh24:mi:ss') + numtodsinterval(sec,'SECOND') val
, to_date (May 31, 2005 ',' DD/MM/YYYY ') + 0.2789 + numtodsinterval (s + 1000000000, 'SECOND') val2, versus, code
of mydata;
concerning
Gordan
Hello
You can use the function of leader to access the values of the following line as follows
with mydata as
(
Select to_date (June 9, 2015 ',' DD/MM/YYYY ') dt, - 684002410 s, 'W', versus, 111222333 code of dual union all
Select to_date (7 June 2015 ',' DD/MM/YYYY '), - 684050570, 'W', 111222333 of double union all
Select to_date (7 June 2015 ',' DD/MM/YYYY '), - 684050570, 'W', 111222888 of double union all
Select to_date (June 6, 2015 ',' DD/MM/YYYY '), - 684150570, 'W', 111222888 of double union all
Select to_date (5 June 2015 ',' DD/MM/YYYY '), - 684190570, 'W', 111222888 of double union all
Select to_date (June 4, 2015 ',' DD/MM/YYYY '), - 684220570, 'W', 111222888 of double union all
Select to_date (3 June 2015 ',' DD/MM/YYYY '), - 684270570, 'W', 111222888 of double union all
Select to_date (2 June 2015 ',' DD/MM/YYYY '), - 684310570, 'W', 111222888 of double union all
Select to_date (1 June 2015 ',' DD/MM/YYYY '), - 684338692, 'H', 111222333 of double union all
Select to_date (1 June 2015 ',' DD/MM/YYYY '), - 684348692, 'W', 111222333 of double union all
Select to_date (1 June 2015 ',' DD/MM/YYYY '), - 684350570, 'W', 111222888 of double union all
Select to_date (1 June 2015 ',' DD/MM/YYYY '), - 684350841, 'W', 111222333 of double union all
Select to_date (1 June 2015 ',' DD/MM/YYYY '), - 684378694, 'W', 111222888 of double union all
Select to_date (29 may 2015 ',' DD/MM/YYYY '), - 684611322, 'W', 111222333 of double union all
Select to_date (29 may 2015 ',' DD/MM/YYYY '), - 684614272, 'W', 111222888 of double union all
Select to_date (29 may 2015 ',' DD/MM/YYYY '), - 684615003, 'W', 111222333 of double union all
Select to_date (29 may 2015 ',' DD/MM/YYYY '), - 684637550, 'W', 111222888 of double union all
Select to_date (28 may 2015', ' MM/DD/YYYY ' "), - 684694292, 'W', 111222333 of the double
)
Select dt, dry
, to_date (6 February 2037 08:28:17 ',' DD/MM/YYYY hh24:mi:ss') + numtodsinterval(sec,'SECOND') val
, to_date (May 31, 2005 ',' DD/MM/YYYY ') + 0.2789 + numtodsinterval (s + 1000000000, 'SECOND') val2, versus, code
, DECODE (versus, 'H', LEAD(dt, 1) OVER (PARTITION BY code ORDER BY dt) - dt, null) holiday
from mydata by code, dt;
Concerning
Salim
Tags: Database
Similar Questions
-
Hi Master,
I executed the query below... I had the result... then run another query (ofcourse even) but get the diff result set. Please explain to me... !!
SQL > Select rownum from emp;
1
2
3
4
5
6
7
8
9
10
11
12
13
14
14 selected, lines
SQL > select rownum separate from emp;
1
6
11
13
2
14
4
5
8
3
7
9
10
12
14 selected lines.
In the second query... What is going on.. why it does not appear in the order of the CSA? Please explain to me.
Concerning
AR
As Scott and Nick, Oracle uses a unique hash to generate the values of distinct rownum:
SQL > select rownum from scott.emp;
Execution plan
----------------------------------------------------------
Hash value of plan: 3286312482
-------------------------------------------------------------------
| ID | Operation | Name | Lines | Cost (% CPU). Time |
-------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 14. 1 (0) | 00:00:01 |
| 1. COUNTY | | | | |
| 2. INDEX SCAN FULL | PK_EMP | 14. 1 (0) | 00:00:01 |
-------------------------------------------------------------------
SQL > select rownum separate
2 from scott.emp;
Execution plan
----------------------------------------------------------
Hash value of plan: 2421365613
--------------------------------------------------------------------
| ID | Operation | Name | Lines | Cost (% CPU). Time |
--------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 14. 2 (50) | 00:00:01 |
| 1. UNIQUE HASH | | 14. 2 (50) | 00:00:01 |
| 2. COUNTY | | | | |
| 3. INDEX SCAN FULL | PK_EMP | 14. 1 (0) | 00:00:01 |
--------------------------------------------------------------------
Note the UNIQUE HASH in the second plan. Essentially, it's what he does to get unique values (although the hashing used by the ora_hash algorithm seems to be different from the one used internally):
SQL > select rn, ora_hash (rn)
2 from (select rownum scott.emp rn)
3 order by 2;
RN ORA_HASH (RN)
---------- ------------
5 365452098
7 738226831
6 1021760792
10 1237562873
12 1646821573
9 1706589901
2 2064090006
1 2342552567
11 2671099528
3 2706503459
14 2791491783
13 3006123492
4 3217185531
8 3510633070
John
-
Hello!
I have a simple code that selects the fields in a table:
SELECT ROWNUM, question, APEX_ITEM.RADIOGROUP(ROWNUM, YES_SCORE, 2, apex_lang.message('YES'), p_item_id => ROWNUM||'y') yes, APEX_ITEM.RADIOGROUP(ROWNUM, NO_SCORE, 2, apex_lang.message('NO'), p_item_id => ROWNUM||'n') no FROM question q WHERE question.id = :TYPE ORDER BY ORDER_ID,ROWNUM;Now, I had insert an ORDER_ID field in the table to make the admin output lines in certain order and Add ORDER BY line code.
Who messed up the column ROWNUM.
Add column rownum differently to get the line numbers appear in the proper order (1, 2, 3,...)?
IM using APEX 4.2.1.
Hello
You may
SELECT rownum
x.question
APEX_ITEM. RADIOGROUP (rownum
x.yes_score
2
apex_lang.message ('YES')
p_item_id-online rownum | (' y') Yes
APEX_ITEM. RADIOGROUP (rownum
x.no_score
2
apex_lang.message ('NO')
p_item_id-online rownum | ("no) no
FROM (SELECT q.question
q.yes_score
q.no_score
QUESTION q
WHERE q.question.id =: TYPE
ORDER BY q.order_id
) x
;
(I assumed that yes_score and no_score are the 'question' column; suggestion: use the alias for the table names and precede all columns with the corresponding alias)
Best regards
Bruno Vroman
-
You have no lines for the SQL query to select
Dear Sir.
I don't want to choose these lines in the second query, please guide me how to do.
Request-> 1
(SELECT ID_NO, ATTND_DATE FROM ATTND_REGISTER WHERE ATTND_DATE BETWEEN :FD AND :TD ORDER BY ID_NO, ATTND_DATE )AT
A query result.
ID_NO ATTND_DATE E1 FEBRUARY 1, 14 E1 FEBRUARY 2, 14 E1 3 FEBRUARY 14 E1 4 FEBRUARY 14 E1 FEBRUARY 5, 14 E1 FEBRUARY 6, 14 E1 FEBRUARY 7, 14 E1 FEBRUARY 8, 14 E1 FEBRUARY 9, 14 E1 10 FEBRUARY 14 E1 FEBRUARY 11, 14 E1 FEBRUARY 12, 14 E1 FEBRUARY 13, 14 E1 14 FEBRUARY 14 E1 15 FEBRUARY 14 E1 16 FEBRUARY 14 E1 17 FEBRUARY 14 E1 18 FEBRUARY 14 E1 19 FEBRUARY 14 E1 20 FEBRUARY 14 E4 FEBRUARY 1, 14 E4 FEBRUARY 2, 14 E4 3 FEBRUARY 14 E4 4 FEBRUARY 14 E4 FEBRUARY 5, 14 Request-> 2
: VALUE OF THE VARIABLE FD = 1 FEBRUARY 14
: VALUE OF THE VARIABLE TD = FEBRUARY 28, 14 '
SELECT A.ID_NO,B.DATES,A.EMP_NAME, A.DESG_NAME FROM ( SELECT ROWNUM - 1 + TO_DATE(:FD, 'DD/MM/RR') DATES FROM ALL_OBJECTS WHERE ROWNUM < TO_DATE(:TD, 'DD/MM/RR') - TO_DATE(:FD, 'DD/MM/RR') + 2 )B, ( SELECT ID_NO, INITCAP(FL_NAME) AS EMP_NAME, INITCAP(UBN.DESG_NAME(DESG_ID)) AS DESG_NAME FROM PERSONAL WHERE (STATUS = 'A') AND (COMPANY_CODE = :COMPANY_CODE)---COMPANY CODE=6 AND (ID_NO = :ID_NO OR :ID_NO IS NULL) )A ORDER BY A.ID_NO,B.DATES;
Solved
I changed in the second query with using the first query.
in Where Clause
WHERE B.DATES | A.ID_NO NOT IN (SELECT ATTND_DATE |) NBI ID_NO. ATTND_REGISTER
WHERE ATTND_DATE BETWEEN: FD AND: TD)
Thank you Allah (SWT).
-
Hi all
Could you please help me understand how calculated on the last column of the first and the last line?
SQL> select rownum,rownum-1,rownum-2,rownum||rownum-1||rownum-2 from dual connect by level < 11; ROWNUM ROWNUM-1 ROWNUM-2 ROWNUM||ROWNUM-1||ROWNUM-2 ---------- ---------- ---------- -------------------------- 1 0 -1 99 2 1 0 210 3 2 1 321 4 3 2 432 5 4 3 543 6 5 4 654 7 6 5 765 8 7 6 876 9 8 7 987 10 9 8 100908 10 rows selected.
-
Dear friends
Given an array of simple employees with the names of employees and wages.
for this query:
Select rownum, salary
from (select name, salary
employees
salary desc order)
.. I am able to see the number of lines like 1,2,3,4,5...
and the names of the employees and wages in descending order,
However if I try to use:
Select rownum, salary
from (select name, salary
employees
salary desc order)
where rownum = 2
Why didn't he give me the second highest salary?
In the case of:
Select rownum, salary
from (select name, salary
employees
salary desc order)
where rownum = 1
.. I am able to see the highest salary.
Thanks for your help...
BestRownum is assigned to the lines of recoveries, so it always starts with 1. So query with ROWNUM = N where N > 1 will return all the lines. Use:
select first_name, salary from ( select first_name, salary, rownum rn from ( select first_name, salary from employees order by salary desc ) ) where rn = 2 /Or better:
select first_name, salary from ( select first_name, salary, row_number() over(order by salary desc) rn from employees ) where rn = 2 /And don't forget, your query (identical to the ones I posted above) does not return second highest salary. Then, they return more employee paid.
SY.
-
How to order by working with rownum
Oracle worm: 11g
Hi all
I have 2 cases here, with external control by one and another without external by command.
I see no difference in the results for the moment.
Case 1:
Case 2:/* Formatted on 4/30/2013 2:12:28 PM (QP5 v5.240.12305.39446) */ SELECT * FROM ( SELECT ROWNUM rn, id FROM (SELECT 9 AS id FROM DUAL UNION ALL SELECT 1 FROM DUAL UNION ALL SELECT 14 FROM DUAL UNION ALL SELECT 7 FROM DUAL UNION ALL SELECT 5 FROM DUAL UNION ALL SELECT 6 FROM DUAL UNION ALL SELECT 13 FROM DUAL UNION ALL SELECT 8 FROM DUAL UNION ALL SELECT 2 FROM DUAL UNION ALL SELECT 4 FROM DUAL UNION ALL SELECT 19 FROM DUAL UNION ALL SELECT 3 FROM DUAL) ORDER BY id) WHERE rn BETWEEN 1 AND 6;
I added the command by external clause in this case
But I want to make sure if I really need to have the order of outer query by here.
Thank you/* Formatted on 4/30/2013 2:12:28 PM (QP5 v5.240.12305.39446) */ SELECT * FROM ( SELECT ROWNUM rn, id FROM (SELECT 9 AS id FROM DUAL UNION ALL SELECT 1 FROM DUAL UNION ALL SELECT 14 FROM DUAL UNION ALL SELECT 7 FROM DUAL UNION ALL SELECT 5 FROM DUAL UNION ALL SELECT 6 FROM DUAL UNION ALL SELECT 13 FROM DUAL UNION ALL SELECT 8 FROM DUAL UNION ALL SELECT 2 FROM DUAL UNION ALL SELECT 4 FROM DUAL UNION ALL SELECT 19 FROM DUAL UNION ALL SELECT 3 FROM DUAL) ORDER BY id) WHERE rn BETWEEN 1 AND 6; ORDER BY id;
Rod.Hey, Rod,
SamFisher wrote:
... I see no difference in the results for the moment.You can not, but you are not sure that you will never see a difference. There may be a difference if you change versions, or if you add more data, or for no apparent reason.
If there is an ORDER BY clause in the main query (as in query 2) then the output is guaranteed to be in that order.
Is there no ORDER BY clause in the main query (as in the query 1), then there is no guarantee that the lines will be in a particular order. If Oracle finds it convenient to display rows in order by one of the columns (for example, rn) then she will do. You can't count on it always does the same thing, unless there is an ORDER BY clause.You should check the ROW_NUMBER analytic function. It is much more useful and easier to understand, as ROWNUM. (In this example, it maybe not simple, however.)
-
Is it possible to use the ROWNUM in a subquery?
I wonder if it is legal to use rownum (for example, a generator of line) in a subquery. I have not found, it is illegal. But it doesn't seem to work without danger
Case of work
Case does notSQL> with v as (select rownum r from (select 1 from dual union all select 2 from dual)) select t1.r t1, t2.r t2 from v t1, v t2 T1 T2 ---------- ---------- 1 1 1 2 2 1 2 2
Published by: Laurent Schneider on March 26, 2013 13:12SQL> create table t(x) as select 1 from dual union all select 2 from dual Table created. SQL> with v as (select rownum r from t) select t1.r t1, t2.r t2 from v t1, v t2 T1 T2 ---------- ---------- 1 1 1 2 3 1 3 2
version 11.2.0.3 on aixI would say that there certainly is a glitch in the way that Oracle treats...
SQL> with v as (select rownum r from t) select t1.r t1, t2.r t2 from v t1, v t2 2 / T1 T2 ---------- ---------- 1 1 2 2 3 1 3 2 SQL> with v as (select /*+ MATERIALIZE */ rownum r from t) select t1.r t1, t2.r t2 from v t1, v t2 2 / T1 T2 ---------- ---------- 1 1 1 2 2 1 2 2 SQL> ed Wrote file afiedt.buf 1 select t1.r t1, t2.r t2 2* from (select rownum r from t) t1, (select rownum r from t) t2 SQL> / T1 T2 ---------- ---------- 1 1 1 2 2 1 2 2Something to do with the subquery factoring.
The explain command plans look identical, so perhaps a trace would be something appear.
-
Save the implementation of counter as 1,2,3,4,5,1,2,3,4,5,1,2... use of rownum
Hello
Need to set up a check-in counter. the meter should be increased from 1 to 5, and then start return of 1. Thus, the record counter must be 1,2,3,4,5,1,2,3,4,5,1,2...
Currently I use "select rownum meter, Id SurveyId in PB_SURVEY_USER_TEST;"
How I can use rownum to get a record count as 1,2,3,4,5,1,2,3,4,5,1,2...
Need help here...MOD (rownum-1, 5) + 1?
Edited by: bencol February 1, 2013 12:04
-
Select SQL statement - See all the value of the range of month of entry
Hi all
I have a vision that is a union of other views
But the description of the view is as below
-current data in the viewdesc dashboard_monthly_view Name Null Type ------------------------------ ---- ------------ MONTHS VARCHAR2(17) NUM_DEPENDENT_IN_ASSESSMENT NUMBER NUM_REFERRED_AODTC NUMBER NUM_AT_DETERMINATION_HEARING NUMBER NUM_ACCEPTED NUMBER NUM_NOT_ACCEPTED NUMBER NUM_EXITED_SUCCESS NUMBER AVERAGE_DAY_TO_EXIST NUMBER NUM_EXITED_UNSUCCESS NUMBER AVERAGE_DAY_TO_EXIST_UNSUCCESS NUMBER COURT_NAME VARCHAR2(9)
-My select query isMONTHS NUM_DEPENDENT_IN_ASSESSMENT NUM_REFERRED_AODTC NUM_AT_DETERMINATION_HEARING NUM_ACCEPTED NUM_NOT_ACCEPTED NUM_EXITED_SUCCESS AVERAGE_DAY_TO_EXIST NUM_EXITED_UNSUCCESS AVERAGE_DAY_TO_EXIST_UNSUCCESS COURT_NAME ----------------- --------------------------- ---------------------- ---------------------------- ---------------------- ---------------------- ---------------------- ---------------------- ---------------------- ------------------------------ ---------- AUG 2012 1 0 0 0 0 0 0 0 0 AAA OCT 2012 8 1 3 1 1 1 44 1 4 AAA SEP 2012 2 0 2 2 0 0 0 0 0 AAA *UNDEFINED* 0 11 7 1 1 0 0 1 0 AAA NOV 2012 0 0 0 0 0 0 0 1 54 BBB OCT 2012 4 1 2 1 1 1 9 0 0 BBB SEP 2012 1 0 0 0 0 1 14 0 0 BBB *UNDEFINED* 0 5 4 1 0 0 0 1 0 BBB AUG 2012 1 0 0 0 0 0 0 0 0 COMBINED NOV 2012 0 0 0 0 0 0 0 1 54 COMBINED OCT 2012 12 2 5 2 2 2 26.5 1 4 COMBINED SEP 2012 3 0 2 2 0 1 14 0 0 COMBINED *UNDEFINED* 0 16 11 2 1 0 0 2 0 COMBINED 13 rows selected
- And the result isDEFINE startmonth = "Aug 2012"; DEFINE endmonth = "Nov 2012"; with all_months as ( select to_char(which_month, 'MON YYYY') month from (select add_months(to_date('&startmonth','MON YYYY'), rownum-1) which_month from all_objects where rownum <= months_between(to_date(NVL('&endmonth', '&startmonth'),'MON YYYY'), add_months(to_date('&startmonth','MON YYYY'), -1)) order by which_month ) ) select nvl(months, '**ALL**') AS "MONTHS", TO_DATE(MONTHS, 'MON YYYY') AS MONTH_SORT , sum(num_dependent_in_assessment) AS num_dependent_in_assessment , sum(num_referred_aodtc) AS num_referred_aodtc , sum(num_at_determination_hearing) as num_at_determination_hearing , sum(num_accepted) AS num_accepted , sum (num_not_accepted) AS num_not_accepted , sum(num_exited_success) as num_exited_success , sum(average_day_to_exist) as average_day_to_exist , sum(num_exited_unsuccess) as num_exited_unsuccess , sum (average_day_to_exist_unsuccess) as average_day_to_exist_unsuccess from DASHBOARD_MONTHLY_VIEW right outer join all_months on DASHBOARD_MONTHLY_VIEW.months = all_months.month --where months in (select month from all_months) and upper(court_name) like 'AAA' group by (months) order by month_sort
-The requirement of results I have to produce isMONTHS MONTH_SORT NUM_DEPENDENT_IN_ASSESSMENT NUM_REFERRED_AODTC NUM_AT_DETERMINATION_HEARING NUM_ACCEPTED NUM_NOT_ACCEPTED NUM_EXITED_SUCCESS AVERAGE_DAY_TO_EXIST NUM_EXITED_UNSUCCESS AVERAGE_DAY_TO_EXIST_UNSUCCESS ----------------- ------------------------- --------------------------- ---------------------- ---------------------------- ---------------------- ---------------------- ---------------------- ---------------------- ---------------------- ------------------------------ AUG 2012 01/08/12 1 0 0 0 0 0 0 0 0 SEP 2012 01/09/12 2 0 2 2 0 0 0 0 0 OCT 2012 01/10/12 8 1 3 1 1 1 44 1 4 **ALL**
On the tota (* EVERYTHING *) l, I tried to use the rollup but he total average too, which is not correct. I think the reason because he cannot read the form that was used to calculate the column.MONTHS MONTH_SORT NUM_DEPENDENT_IN_ASSESSMENT NUM_REFERRED_AODTC NUM_AT_DETERMINATION_HEARING NUM_ACCEPTED NUM_NOT_ACCEPTED NUM_EXITED_SUCCESS AVERAGE_DAY_TO_EXIST NUM_EXITED_UNSUCCESS AVERAGE_DAY_TO_EXIST_UNSUCCESS ----------------- ------------------------- --------------------------- ---------------------- ---------------------------- ---------------------- ---------------------- ---------------------- ---------------------- ---------------------- ------------------------------ AUG 2012 01/08/12 1 0 0 0 0 0 0 0 0 SEP 2012 01/09/12 2 0 2 2 0 0 0 0 0 OCT 2012 01/10/12 8 1 3 1 1 1 44 1 4 NOV 2012 01/11/12 0 0 0 0 0 0 0 0 0 **ALL**
How can I fix this, should I create, select another below one, with the sum of each column and the average for the other columns.
Also, the business analyst want to show all the months between the start and end of the month.
I used the right outer join, but apparently does not produce the right result.
If anyone of you have any ideas, please advise.
We use Oracle 11 g, it is a select statement for an Oracle APEX report.
The APEX version is 4.0.2. I'm a junior developer of the APEX and I still have to learn a lot about SQL Oracle analytic function.
Thank you very much in advance.
AnnHi, Ann.
Ann586341 wrote:
... I created a table to contain a simplified version of this viewThank you. It is much easier to work with.
... My query is
DEFINE startmonth = "Aug 2012"; DEFINE endmonth = "Nov 2012"; with all_months as ( select to_char(which_month, 'MON YYYY') month from (select add_months(to_date('&startmonth','MON YYYY'), rownum-1) which_month from all_objects where rownum <= months_between(to_date(NVL('&endmonth', '&startmonth'),'MON YYYY'), add_months(to_date('&startmonth','MON YYYY'), -1)) order by which_month ) ) , tbl_dashboard_active as ( select * from tbl_dashboard_monthly where months != '**UNDEFINED**' ) select tbl.months AS "MONTHS" --, TO_DATE(tbl.MONTHS, 'MON YYYY') AS MONTH_SORT , tbl.num_hearing , tbl.num_exited_success , tbl.avg_day_success_exist , tbl.num_exited_unsuccess , tbl.avg_day_unsuccess_exist from tbl_dashboard_active tbl right outer join all_months am on tbl.months = am.month and upper(tbl.court_name) like 'BBB' UNION ALL select 'ALL' AS "TOTAL" , SUM(tbl.num_hearing) , SUM(tbl.num_exited_success) , round(AVG(tbl.avg_day_success_exist),2) , SUM(tbl.num_exited_unsuccess) , round(AVG(tbl.avg_day_unsuccess_exist),2) --order by to_date(am.month,'MON YYYY') from tbl_dashboard_monthly tbl right outer join all_months am on tbl.months = am.month and upper(tbl.court_name) like 'BBB'- And the result I got
MONTHS NUM_HEARING NUM_EXITED_SUCCESS AVG_DAY_SUCCESS_EXIST NUM_EXITED_UNSUCCESS AVG_DAY_UNSUCCESS_EXIST ----------------- ----------- ------------------ --------------------- -------------------- ----------------------- AUG 2012 1 0 0 0 0 OCT 2012 1 0 0 2 35 SEP 2012 1 0 0 0 0 ALL 3 0 0 2 11.67I don't know why even I already filter all lines that the month is undefined, I still have a blank line in the result set.
This is the line for November. You do an outer join, in order to ensure that each value of am.month is displayed, even if it does not match what anyone in tbl. When it does not match anything, then all the columns tbl is supposed to provide will be NULL. You decide to view tbl. months, which is one of the following columns will be NULL. You should display mod. monmth instead.
But if I run for handset Court, I don't see this problem. The reason is that the Court combined have given for all four months?
When you say "on behalf of the combined Court", do you mean the unconditional "upper (tbl.court_name) as"BBB "?
If Yes, that would explain it.Also is it possible to list all the months between the start and end month assuring the user even if the statistics are 0.
Once again, in the case of lines that are present, even if they do not have the status of outer join, all of these columns will be NULL. Use NVL to map these nulls to 0.
and how to sort the month
GROUP OF two expressions, which depend on each other: one for sorting and the other for display.
For the sort expression, you can use months as a DATE. (It seems that you have tried this, but commented on the ORDER BY clause in your query is before the FROM clause.) The ORDER BY clause is always at the end of the query, after the FROM clause.)
Another expression of sorting is the number you used to generate the first month. That's what I used below.Here's a way to get the results you requested:
WITH got_months AS ( SELECT TO_DATE ('&startmonth', 'Mon YYYY') AS startmonth_dt , TO_DATE ( NVL ( '&endmonth' , '&startmonth' ) , 'Mon YYYY' ) AS endmonth_dt FROM dual ) , all_months AS ( SELECT rownum AS month_num , TO_CHAR ( ADD_MONTHS ( m.startmonth_dt , ROWNUM - 1 ) , 'MON YYYY' ) AS months FROM got_months m CROSS JOIN all_objects WHERE ROWNUM <= 1 + MONTHS_BETWEEN ( m.endmonth_dt , m.startmonth_dt ) ) SELECT NVL ( am.months , 'All' ) AS months , SUM (NVL (tbl.num_hearing, 0)) AS num_hearing , SUM (NVL (tbl.num_exited_success, 0)) AS num_exited_success , AVG (NVL (tbl.avg_day_success_exist, 0)) AS avg_day_success_exist , SUM (NVL (tbl.num_exited_unsuccess, 0)) AS num_exited_unsuccess , AVG (NVL (tbl.avg_day_unsuccess_exist, 0)) AS avg_day_unsuccess_exist FROM all_months am LEFT OUTER JOIN tbl_dashboard_monthly tbl ON am.months = tbl.months AND UPPER (tbl.court_name) = 'BBB' GROUP BY GROUPING SETS ( (am.month_num, am.months) , () ) ORDER BY am.month_num ;Again, I used two GROUP BY expressions: one for sorting, the other for display. These depend on each other, that is, given one, you could derive from each other, and it is not sensible to dependent ROLLUP GROUP BY expressions like that, so I used GROUPING SETS ROLLUP instead, so it would be only 1 rank of great aggregate (in other words, 'all').
Output:
` AVG_ AVG_ NUM_ DAY_ NUM_ DAY_ NUM_ EXITED_ SUCCESS EXITED_ UNSUCCESS MONTHS HEARING SUCCESS _EXIST UNSUCCESS _EXIST --------- ------- ------- ---------- --------- ---------- AUG 2012 1 0 0 0 0 SEP 2012 1 0 0 0 0 OCT 2012 1 0 0 2 35 NOV 2012 0 0 0 0 0 All 3 0 0 2 8.75 -
Dear all,
Under query running perfectly
SELECT ROWNUM AS RANK, name, SALARY, HIRE_DATE (HIRE_DATE SELECT first name, SALARY FROM EMPLOYEE ORDER BY SALARY desc, DESC HIRE_DATE)
WHERE
ROWNUM < = 3
But when I try to find the third line of salary with the following query, then it returns null. Can someone tell me why it returns null and give me the same query.
SELECT ROWNUM AS RANK, name, SALARY, HIRE_DATE (HIRE_DATE SELECT first name, SALARY FROM EMPLOYEE ORDER BY SALARY desc, DESC HIRE_DATE)
WHERE
ROWNUM = 3Try this
select * from (select first_name,salary,hiredate,row_number() over(order by salary desc) rn from employee) Where rn=3Not tested.
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How to select the lines/odd table...
How to select lines / odd in a table?
Help, please.
Published by: vaibhav on May 7, 2012 05:30This can be done by using the function mod like this:
For even rows
Select * from (select rownum rn, nom_table.* from tableName) where mod (rn, 2) = 0;For the odd lines
Select * from (select rownum rn, nom_table.* from tableName) where mod (rn, 2) = 1; -
SELECT - MODELING maybe clause can help?
Hello world
It's me again with another hierarchical statement. This time, my problem is quite complex. We have a scenario to explain the problem:
Examples of previous data is a single hierarchical table with a tree of the organization. A high level organization has no parent id and an organization is linked to its parent by parent_id. So far, nothing weird and very frequent structure.DROP TABLE organisations; CREATE TABLE organisations ( org_id NUMBER(10), organ_name VARCHAR2(255), parent_id NUMBER(10) ); INSERT INTO organisations VALUES(1, 'TOP', NULL); INSERT INTO organisations VALUES(3, 'TOP2', NULL); INSERT INTO organisations VALUES(11, 'HR', 1); INSERT INTO organisations VALUES(12, 'Recruitment', 11); INSERT INTO organisations VALUES(19, 'Payroll', 11); INSERT INTO organisations VALUES(23, 'Evaluations', 12); INSERT INTO organisations VALUES(35, 'IT', 1); INSERT INTO organisations VALUES(39, 'Software', 35); INSERT INTO organisations VALUES(222, 'Windows', 39); INSERT INTO organisations VALUES(228, 'Linux', 39); INSERT INTO organisations VALUES(223, 'Mac OS', 39); INSERT INTO organisations VALUES(118, 'Applications', 39); INSERT INTO organisations VALUES(119, 'Photoshop', 118); INSERT INTO organisations VALUES(119, 'Microsoft Office 2010', 118); INSERT INTO organisations VALUES(29, 'Hardware', 35); INSERT INTO organisations VALUES(99, 'Helpdesk', 35); COMMIT;
The SELECT statement returns the complete structure of the organizational tree.
Here is the result:SELECT org_id, parent_id, LPAD(' ', LEVEL*2) || organ_name as indented_name FROM organisations START WITH parent_id IS NULL CONNECT BY PRIOR org_id = parent_id;
I would like to have a result like this:1 TOP 11 1 HR 12 11 Recruitment 23 12 Evaluations 19 11 Payroll 35 1 IT 29 35 Hardware 39 35 Software 118 39 Applications 119 118 Photoshop 119 118 Microsoft Office 2010 222 39 Windows 223 39 Mac OS 228 39 Linux 99 35 Helpdesk 3 TOP2
Rules to build this result are simple (yet complex to be implemented using SQL). Whenever a node descendant nodes, I need to have duplicate and the other must have exactly the same name with the suffix. GROUP. If a node is a terminal leaflet, it shouldn't have one. GROUP check-in. A top-level (TOP & TOP2) node does not take into account for this.1 TOP 11 1 HR 11 1 HR.GROUP 12 11 Recruitment 12 11 Recruitment.GROUP 23 12 Evaluations -- no descendants, so no .GROUP node. 19 11 Payroll 35 1 IT 35 1 IT.GROUP 29 35 Hardware 39 35 Software 39 35 Software.GROUP 118 39 Applications 118 39 Applications.GROUP 119 118 Photoshop 119 118 Microsoft Office 2010 222 39 Windows 223 39 Mac OS 228 39 Linux 99 35 Helpdesk 3 TOP2
No idea how we can implement this using SQL? I use 10g (so I can use the TYPE clause if it helps)
Thank you guysOr use GROUP BY with GROUPING SETS:
WITH t AS ( SELECT ROWNUM rn, level lvl, org_id, parent_id, LPAD(' ', LEVEL*2) || organ_name as indented_name, CONNECT_BY_ISLEAF leaf FROM organisations START WITH parent_id IS NULL CONNECT BY PRIOR org_id = parent_id ) SELECT max(org_id) org_id, max(parent_id) parent_id, max(indented_name) || case grouping(lvl) when 1 then '.GROUP' end indented_name FROM t GROUP BY GROUPING SETS((rn),(rn,lvl)) HAVING grouping(lvl) = 0 OR ( max(lvl) != 1 and max(leaf) = 0 ) ORDER BY rn, grouping(lvl) / ORG_ID PARENT_ID INDENTED_NAME ---------- ---------- ------------------------------- 1 TOP 11 1 HR 11 1 HR.GROUP 12 11 Recruitment 12 11 Recruitment.GROUP 23 12 Evaluations 19 11 Payroll 35 1 IT 35 1 IT.GROUP 29 35 Hardware 39 35 Software ORG_ID PARENT_ID INDENTED_NAME ---------- ---------- ------------------------------- 39 35 Software.GROUP 118 39 Applications 118 39 Applications.GROUP 119 118 Photoshop 119 118 Microsoft Office 2010 222 39 Windows 223 39 Mac OS 228 39 Linux 99 35 Helpdesk 3 TOP2 21 rows selected. SQL>SY.
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Insert select with the id auto incream
CREATE TABLE LOG
(NUMBER OF 'ID',
VARCHAR2 (30 BYTE) "ROLEUSER."
VARCHAR2 (30 BYTE) "ROLENAME",.
"studentId" VARCHAR2 (11 BYTE)
)
then I insert in the newspaper (ROLEUSER, ROLENAME, studentID) (select ROLEUSER, ROLENAME, studentID of table a, b).
where a.userid = buserid)
I want to get every row I insert the id auto insert with number of automatic increasethen I have insert into Log(ROLEUSER, ROLENAME, studentID)( select ROLEUSER, ROLENAME, studentID from table a, bUse
insert into Log(ID, ROLEUSER, ROLENAME, studentID)( select ROWNUM, ROLEUSER, ROLENAME, studentID from table a, b where a.userid=buserid) -
Number of rows returned by Rownum
Hello
When I run this code I get 8 rows where I see that the rownum is repeated twice. Why the rownum is repeats and if yes why alone2 times?
This is the result I get:set serveroutput on ; begin for item in ( select rownum as r, first_name||' '||last_name as full_name,salary*10 as dream_salary from employees where rownum <5 ) loop dbms_output.put_line(item.full_name||'dreams having'||item.dream_salary||' '||item.r); end loop; end; /
I have 107 lines.Steven King dreams having 264600 1 Neena Kochhar dreams having 170000 2 Lex De Haan dreams having 170000 3 Alexander Hunold dreams having 90000 4 Bruce Ernst dreams having 60000 5 Steven King dreams having 264600 1 Neena Kochhar dreams having 170000 2 Lex De Haan dreams having 170000 3 Alexander Hunold dreams having 90000 4
Employees of the table contains the following columns
When I use-desc employees Name Null Type -------------- -------- ------------ EMPLOYEE_ID NOT NULL NUMBER(6) FIRST_NAME VARCHAR2(20) LAST_NAME NOT NULL VARCHAR2(25) EMAIL NOT NULL VARCHAR2(25) PHONE_NUMBER VARCHAR2(20) HIRE_DATE NOT NULL DATE JOB_ID NOT NULL VARCHAR2(10) SALARY NUMBER(8,2) COMMISSION_PCT NUMBER(2,2) MANAGER_ID NUMBER(6) DEPARTMENT_ID NUMBER(4) LEFT_DATE DATE
I get 5 rows with the correct rownums.select rownum as r, first_name||' '||last_name as full_name,salary*10 as dream_salary from employees where rownum <=5
Thank you in advance
Published by: to_learn on December 2, 2011 07:47My guess is that you initially run it without defining the serveroutput on. If the results of the two rounds.
Published by: Lacotte Renaud on December 2, 2011 07:54
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