Select the condition of list view

Similar Questions

• Select the value of list view

  Hi all
  Does anyone know how to make a ReadOnly list select and display the display value not the return value when you change the data? I made the list select a text field, text box, etc... but the return value is displayed and not the display value. I don't want my end users to edit the article, but I don't want to show them the value of display. Ideas and help is appreciated, thanks.

  Hello

  As you do not want your users to change the item, could you not use one of these 'View text (based on LOV)' instead?

  Andy

• Align the text in list view

  Hi, how can I align text in list view? I tried with:-fx-text-align: center; in css
  and setTextAlignment (TextAlignment.CENTER); in the code, but without success.
  Can anyone help?

  In an external style sheet, follow these

  .list-cell {
       -fx-alignment: center ;
  }
  

  In Java, you can call

  setAlignment(Pos.CENTER);
  

  on the ListCell (not the ListView). you usually won't have access to the ListCell if you already provide a custom cell.

• Select the item of list apex

  Hi all,
  
  I have a report (created using elements of the apex region). In this report a single column of region's selection list.
  Here's the sql select query in the Source of the region. here in this column in the select list, I have to show more than two values in the selection list.but im get two values(cu_and_cu1).i have tried has given more than two values, but it shows only two values in the drop-down list.
  
  How to solve it?
  

  select .,.,.,apex_item.SELECT_LIST(4,'cu','cu1') from <table_name>;

  Thank you in advance

  Hello

  the format of your selection is wrong. Take a look at the documentation: http://download.oracle.com/docs/cd/E23903_01/doc/doc.41/e21676/apex_item.htm#CHDHJJAB

  It should be like this:

  APEX_ITEM.SELECT_LIST(4,'cu','cu;cu,cu1;cu1,cu2;cu2,cu3;cu3')
  

  Kind regards
  Dirk

• Limit of characters displayed in the Web application list view

  Hello

  I would like to know if the {tag_body, 100} principle can appear on the {tag_description} to list items Web App to limit the total number of characters.

  I prefer this method or an alternaitive to the {tag_description, preview} because it offers more control over what is displayed.

  Your help would be greatly appreciated.

  Thank you

  
  Don

  Hello

  Yes, you can use the same {tag_description, 100} or in the layout to work.

  Kind regards

• Microsoft Silverlight cannot be activated. There is no option to select only activate because it is impossible to select the drop-down list even if it is the most recent version

  I can't activate Microsoft Silverlight. I've attached a screenshot of control. This is the only plugin that says "disabled" next to him. I've updated to the latest version and there is no option on the page of the plugins to acivate because he says 'never activate' and no other selection is selectable.

  Unfortunately, your screenshot is not come through. You can link it to a reply in this thread if you wish.

  If you exit Firefox and it starts again since installing Silverlight, please try this in case a file is locked.

  Can also see you in the editor preferences as follows:

  (1) in a new tab, type or paste Subject: config in the address bar and press ENTER. Click on the button promising to be careful.

  (2) in the search above the list box, type or paste the npc and make a pause so that the list is filtered

  (3) If you find a preference for the plugin.state.npctrl preparing to something other than one, try to double click on it and set it to 1. For reference:

  • 0 = > never activate
  • 1 = > ask to activate
  • 2 = > always activate

  If the preference has a different status from 'the user game' as 'locked', which would indicate a different problem.

• Remove the server from list view Server Admin

  I'm trying to find out how to remove a server listed in the list of servers in admin mode I added a replica server earlier but blew it distance trying to diagnose a separate problem. This server appears in the list of servers to view within the Administration console even if it no longer exists. How can I remove this? Thank you.

  Here is an article on how to remove replica servers, http://kb.vmware.com/selfservice/microsites/search.do?cmd=displayKC&docType=kc&externalId=1010153&sliceId=1&docTypeID=DT_KB_1_1&dialogID=87374507&stateId=0 0 103631102.   You will find yourself using the vdmadmin command to remove the server.

  "C:\Program View\Server\bin\vdmadmin.exe VMware s - r s if you have found this device or any other useful post please consider the use of buttons useful/correct for award points.

• Dynamic action to set the value to select the text box list

  Hello
  
  I want the value in the list box select text box i.e list selection with 5 static values and on the user's selection, this value must be added in a box.
  
  I am using dynamic measurements. I tried with dynamic action and created the change list box select evnent but now how to set the value of the selection list to
  text box that I don't know.
  
  Help, please.
  
  Thanks in advance

  Hello

  I changed the dynamic on this page action to make it work now. I changed the "value Type" action 'Set value' 'Expression JavaScript' and "JavaScript Expression" do the following:

  $v(this.triggeringElement)
  

  This example gets the value of the page element 'DESPROGES', bypassing the server for nothing, as you did before.

  I hope this helps. Let us know if you have any other questions.

  Kind regards
  Anthony

• How to select the condition based on column A, but instead Act state based on column B

  Sorry if the title of the discussion is not clear. I had some difficulty with a brief explanation/question.

  I have a table as follows:

  col1 |  col2 . COL3

  "sfg" | "hfd" | 5

  "XXX" | "jhg | 3

  "dfg" | "tyr" | 9

  "XXX" | "lkh | null

  I'm trying to

  If col3 = null look col1 and select all items except where col1 = 'xxx '.

  The result of select should look as follows:

  col1 |  col2 . COL3

  "sfg" | "hfd" | 5

  "dfg" | "tyr" | 9

  How to do this? I tried with a grouping, group, on (partition by xxx)... It feels like I'm close, but I still do not find this one. You please give me a hint.

  Just the way you are trying

  [code]

  SELECT col1, col2, col3

  FROM (SELECT A.*, SUM (NVL2 (col3, 0, 1)) OVER (PARTITION BY col1) sm

  FROM table_name A)

  WHERE DMS = 0;

  [/ code]

  PS: The new layout of the oracle forums of hatred.

• Capture - list of database selection based on query or view

  Hi all

  I create a field that is a value type list. The list comes from a choice of database list. Now the list of database of choice, I want to show all the data of any column. I want to show the column data depends on certain conditions. I thought of a solution but not successful:

  1. I did see and try to get the view values. But the list of database of choice, I would not find any view. I can't get the tables...

  2. the time of execution, so we can send any query and get the value. But no option.

  I don't want to not view database look-up because I want a list of type value.

  Can someone tell me how I can make it happen?

  Thanks in advance.

  Kind regards

  Shad

  The ability to list views of the database in addition to the Tables has been corrected in an update.  On My Oracle Support, please install the latest patch (currently the Patch 19363640).

• Select the string table drop-down list box.

  Hi all

  I want to select the combo box list based on a string in the entry, I don't know how to do this. I have a drop-down list box and the value comes from a database, what I want to do is I want to change the value of the selected box based on the existing value in the database drop-down list. for example, A, B, C D I strings in the drop-down list box, and then in my database, I have a field with the string C, I want to change the C to A. I can't enter the value of C in a string format, but I don't know how to be the first position of the drop-down list box in so the order of channels combo box will be C, A, B, d., the value of C

  Thank you

  Then just write a new array of strings, with the elements of the new agenda, to the "[] strings" - property.

  Either you must code something that allows you to create an array of strings with the elements in the order that you want them to be. If there is a reorganization only, you could do something like:

  -Get the array of strings [] from the drop-down list using a property node box.

  -Find the position of the element you want to place first and use "delete from table", which returns the new array and the element removed.

  -Build a new table 1 d of the deleted item and table remaining. Move to the second combobox Strings [] property of a node property.

• Script to check if the user selected item from downdown list or not

  I have a script that runs when the form user leaves a drop-down list object after you make a selection. I don't want the script runs if the drop-down list object is empty (the user does not have a selection). I need to create an if statement to test if the user makes a selection in the drop-down list. All the items in the drop-down list are 4 digits.  I prefer the stated case is in the Exit event. The following script is correct?

  If (dropdown1.isNull | dropdown1.rawValue.length! = 4) {}

  xfa.host.messageBox ("you must make a selection, the drop-down list name");

  }

  else {}

  set the script to execute here

  }

  It seems that your script is generally good, but you try to do something more in the message box? Did you mean to carry the name of the drop-down list in the title or as part of the message?

  If you are not allowing the custom entry, you only need the null control. Of course, we only talk about one millisecond, or to check the length of your string. So, you are not asking all devices to perform intense processing.

  If I were asked to do, this is what my script would look like.

  

  

  If you allow custom entries, you must specify what the problem is for the user.

  

  

• How can we change the visibility of the drop-down list after its creation?

  I create a QML document with three drop-down lists.  Depending on how "trans_type" is selected, only to drop Extra should be displayed.  If the option "account" is selected, the drop-down list is visible and the DD category is hidden.  The reverse is true if the 'category' option is selected.

  Here's how I build my QML document:

  void Testing::updateFields()
  {
      if (m_form.isNull())
          return;
  
      // Clear all fields from the form
      m_form->removeAll();
  
      // Clear the internal mapping
      m_fields.clear();
  
      //get the transaction page ready
      QmlDocument *qml = QmlDocument::create("asset:///transaction.qml").parent(this);
  
      DropDown* trans_type = qml->createRootObject();
      trans_type = DropDown::create().title("Transaction Type");
      trans_type->add(Option::create().text("Accounts").value("0"));
      trans_type->add(Option::create().text("Categories").value("1"));
      trans_type->setSelectedIndex(0);
      connect(trans_type, SIGNAL(selectedIndexChanged (int)), this, SLOT(onDDChange(int)));
      m_form->add(trans_type);
  
      DropDown* account_dd = qml->createRootObject();
      account_dd = DropDown::create().title("Account");
      account_dd->add(Option::create().text("No Account").value("0"));
      //... code to populate account drop down here...
      account_dd->setSelectedIndex(0);
      m_form->add(account_dd);
  
      DropDown* category_dd = qml->createRootObject();
      category_dd = DropDown::create().title("Category").visible(false);
      category_dd->add(Option::create().text("No Category").value("0"));
      //... code to populate category drop down here...
      category_dd->setSelectedIndex(0);
      m_form->add(category_dd);
  
  }
  

  Everything is displayed properly on the page.  onDDChange is called and it shows a Toast that the option has been selected.  Here is what I currently have in onDDChange:

  void Testing::onDDChange(const int &info)
  {
      QString msg = "Switched To: ";
      if(info == 0) {
          msg = msg + "Account";
      } else if(info==1) {
          msg = msg + "Category";
      } else {
          msg = msg + "Unrecognized";
      }
      showToast(msg);
  }
  

  I can't figure out how to get the drop down lists to be visible/hidden depending on the needs.  There is a function "setVisible()" for the drop, but I can not understand how to operate without the app crashing.  http://developer.BlackBerry.com/Cascades/reference/bb__cascades__dropdown.html#function-setVisible-v...

  My questions are:

  1. How can I change the visibility of the appropriate dropdown lists in a different function when the status of the main drop-down list is changed?

  2. is there a way to define an id for drop-down lists?  If not, how am I supposed to go into the drop-down lists in a variable later so I can receive their value or change the visibility?

  Any help would be great.  I've been struggling with this for a while.

  There are a number of methods you could use signals and slots between your code and the QML or something simple is assign "objectName" as a property, then this search in C++.

  http://developer.BlackBerry.com/Cascades/documentation/dev/integrating_cpp_qml/

  Something like

  DropBox db = mRootContainer->findChild("dropboxname");
  db->setVisible(true);
  

• When I hit a link to a page in my directory in code view and I click on the link using live view, it does not to this page.  But if I saw in a browser, it works very well.

  When I hit a link to a page in my directory in code view and I click on the link in live mode view, it does nothing.  When I then go to preview in a browser, it works fine.  Can anyone help?

  To follow links in Live View mode, hold down the CTRL on Windows or the command key on a Mac key, and then click the link. Clicking on without using the Ctrl/Cmd key simply selects the link in Live View mode.

• Appeal of pages based on the value of list of choices

  Hello
  I use jdev11.1.2.1.0
  
  
  I created the page with a list of simple choices and 3 buttons.
  
  in the list of choices, all selected items are static only. I created 3 items selected in the list of choices.
  
  and I created 9 jsff fragments.
  
  Now these 9 jsff called regions in the page when I select the value of list of choices and button.
  
  How can I achieve this?
  
  
  
  Thank you..

  try to set a value for variable1 in the constructor.