Select the last instruction time need.

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• The latest version of Lr does not work with the last WIN10, I need help

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• By selecting the last row of the table

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  ;
  

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• Select the last 7 days

  How to select the last 7 days of my table, I use the query, but it is the calculation according to sysdate
  

  It is the data of my talble
  DP_DATE
  ---------
  03-APR-10
  21-APR-10
  22-APR-10
  23-APR-10
  26-APR-10
  27-APR-10
  28-APR-10
  29-APR-10
  30-APR-10
  03-MAY-10
  04-MAY-10
  
  11 rows selected.

    select distinct dp_date
    from dailyprice
    where trunc(dp_date) between trunc(sysdate-7) and trunc(sysdate)
  
  this query is returning 
  DP_DATE
  ---------
  29-APR-10
  30-APR-10
  03-MAY-10
  04-MAY-10

  I want to choose last 7 days
  APRIL 26, 10
  APRIL 27, 10
  28 APRIL 10
  APRIL 29, 10
  30 APRIL 10
  MAY 3, 10
  4 MAY 10
  
  kindly Guide
  
  concerning

  Hello

  Use DENSE_RANK() rather than ROW_NUMBER().

  with mytable
  as
  (
  select 'abcFund' FND , to_date('09-MAY-10','dd-mon-rr') dp_date, 10 price from dual union all
  select 'dddFund', to_date('09-MAY-10','dd-mon-rr'), 12 from dual union all
  select 'abcFund', to_date('09-MAY-10','dd-mon-rr'), 12 from dual union all
  select 'edfFund', to_date('09-MAY-10','dd-mon-rr'), 12 from dual union all
  select 'eeeFund', to_date('09-MAY-10','dd-mon-rr'), 12 from dual union all
  select 'dddFund', to_date('08-MAY-10','dd-mon-rr'), 12 from dual union all
  select 'abcFund', to_date('08-MAY-10','dd-mon-rr'), 12 from dual union all
  select 'edfFund', to_date('08-MAY-10','dd-mon-rr'), 12 from dual union all
  select 'eeeFund', to_date('08-MAY-10','dd-mon-rr'), 12 from dual union all
  select 'eeeFund', to_date('08-MAY-10','dd-mon-rr'), 12 from dual union all
  select 'dddFund', to_date('07-MAY-10','dd-mon-rr'), 12 from dual union all
  select 'abcFund', to_date('07-MAY-10','dd-mon-rr'), 12 from dual union all
  select 'edfFund', to_date('07-MAY-10','dd-mon-rr'), 12 from dual union all
  select 'edfFund', to_date('05-MAY-10','dd-mon-rr'), 11 from dual union all
  select 'dddFund', to_date('05-MAY-10','dd-mon-rr'), 12 from dual union all
  select 'eeeFund', to_date('05-MAY-10','dd-mon-rr'), 12 from dual union all
  select 'dddFund', to_date('04-MAY-10','dd-mon-rr'), 12 from dual union all
  select 'abcFund', to_date('04-MAY-10','dd-mon-rr'), 12 from dual union all
  select 'dddFund', to_date('03-MAY-10','dd-mon-rr'), 12 from dual union all
  select 'abcFund', to_date('03-MAY-10','dd-mon-rr'), 12 from dual union all
  select 'edfFund', to_date('03-MAY-10','dd-mon-rr'), 12 from dual union all
  select 'eeeFund', to_date('03-MAY-10','dd-mon-rr'), 12 from dual union all
  select 'dddFund', to_date('01-MAY-10','dd-mon-rr'), 12 from dual union all
  select 'abcFund', to_date('01-MAY-10','dd-mon-rr'), 12 from dual union all
  select 'abcFund', to_date('30-APR-10','dd-mon-rr'), 11 from dual
  )
  select dp_date
        from ( select dp_date
                    , dense_rank() over (order by dp_date desc) rn
                 from mytable
             )
       where rn <= 7;
  

  Courtesy: Rob SQL
  * 009 *.

  Published by: 009 on May 6, 2010 05:01

• Select the last disk in the history table

  How to select the last record in a history table? the example data is
  < p >
  Product EffectiveDate
  
  prod1 01/01/1980
  
  prod1 01/01/1990
  
  prod1 01/01/2000
  
  prod2 02/02/1980
  
  prod2 02/02/2000
  < /p >
  < p >
  
  
  The expected result is
  
  
  
  Product EffectiveDate
  
  prod1 01/01/2000
  
  prod2 02/02/2000
  < /p >
  
  

  Assuming that there is a single line with max (effectivedate) for a given product

  SELECT product, attrib1, attrib2, ... , max_effective_date
    FROM (SELECT product,
                 attrib1,
                 attrib2,
                 ... ,
                 effectivedate,
                 max( effectivedate ) over (partition by product) max_effective_date
            FROM history_table)
   WHERE effectivedate = max_effectivedate
  

  should work.

  Justin

  Published by: Justin cave on October 30, 2008 18:32

  Formatting changes

• Select the last value for each day of the table

  Hello!
  
  I have a table that contains several measures for each day. I need two queries on this table, and I'm not sure how to write them.
  
  The table stores the rows (sample data)
  

  *DateCol1                 Value       Database*
  27.09.2009 12:00:00       100           DB1
  27.09.2009 20:00:00       150           DB1
  27.09.2009 12:00:00       1000          DB2
  27.09.2009 20:00:00       1100          DB2
  28.09.2009 12:00:00       200           DB1
  28.09.2009 20:00:00       220           DB1
  28.09.2009 12:00:00       1500          DB2
  28.09.2009 20:00:00       2000          DB2

  Explanation of the data in the sample table:
  We measure the size of the data files belonging to each database to one or more times a day. The value column indicates the size of the files of database for each database at some point (date in DateCol1 European model).
  
  
  What I need:
  Query 1:
  The query must return to the last action for each day and the database. Like this:

  *DateCol1       Value      Database*
  27.09.2009        150          DB1
  27.09.2009       1100          DB2
  28.09.2009        220          DB1
  28.09.2009       2000          DB2

  Query 2:
  The query should return the average measurement for each day and the database. Like this:

  *DateCol1       Value      Database*
  27.09.2009       125          DB1
  27.09.2009      1050          DB2
  28.09.2009       210          DB1
  28.09.2009      1750          DB2

  Could someone please help me to write these two queries?
  
  Please let me know if you need further information.
  
  Published by: user7066552 on September 29, 2009 10:17
  
  Published by: user7066552 on September 29, 2009 10:17

  Why two queries when it suffice ;)

  SQL> select dt
    2       , db
    3       , val
    4       , avg_val
    5    from (
    6  select dt
    7       , val
    8       , db
    9       , row_number () over (partition by db, trunc (dt)
   10                                 order by dt desc
   11                            ) rn
   12       , avg (val) over (partition by db, trunc (dt)) avg_val
   13    from test)
   14   where rn = 1
   15  order by dt
   16  /
  
  DT        DB           VAL    AVG_VAL
  --------- ----- ---------- ----------
  27-SEP-09 DB2         1100       1050
  27-SEP-09 DB1          150        125
  28-SEP-09 DB2         2000       1750
  28-SEP-09 DB1          220        210
  

• Select the last Date of multicolumn and its value adjustent cust_id

  I have a Table with 5 customer_id and 5 Dates with each belonging to its cust_id.

  I need to take the last, in my example would be CUSTID_5.  I know

  this with the GREATEST who select the CHANGE_DATE_5 (in my example), but

  How to choose the CUSTID_x? that goes along with the winning Date?

  create table test_tbl)

  number of custid_1

  date of change_date_1,

  number of custid_2

  date of change_date_2,

  number of custid_3

  date of change_date_3,

  number of custid_4

  date of change_date_4,

  number of custid_5

  date of change_date_5

  );

  INSERT INTO test_tbl

  (CUSTID_1, CHANGE_DATE_1, CUSTID_2, CHANGE_DATE_2, CUSTID_3, CHANGE_DATE_3, CUSTID_4, CHANGE_DATE_4, CUSTID_5, CHANGE_DATE_5)

  VALUES

  (111, sysdate, 222, sysdate + 1, 333, sysdate + 2, 444, sysdate + 3, 555, sysdate + 4);

  commit;

  Hello

  Here's one way:

  WITH unpivoted_data AS

  (

  SELECT custid, change_date

  , EVALUATE () OVER (ORDER BY change_date DESC) AS r_num

  OF test_tbl

  UNPIVOT ((custid, change_date)

  Label ((custid_1, change_date_1) AS 1)

  , (custid_2, change_date_2) AS 2

  , (custid_3, change_date_3) AS 3

  , (custid_4, change_date_4) AS 4

  , (custid_5, change_date_5) AS 5

  )

  )

  )

  SELECT custid, change_date

  Of unpivoted_data

  WHERE r_num = 1

  ;

  Having several columns for several occurrences of basically the same thing is a bad table.  This problem would be much simpler, but also more effective if each pair custid/change_date has been strored on a separate line.  In addition, you would not be limited to 5 pairs.