Select the last record of each month

Similar Questions

• use to insert the last day of each month

  Hi, I wrote this code but it did not insert the 20 December and it is January 1, and next time running is 31 January... I would like to work to make this insert every last day of each month...
  

  begin
    sys.dbms_job.submit(job => :job,
                        what => 'INSERT INTO hisrtu 
                                          SELECT rtunum, linked, dbchkd, chaqty, dbvald, ctrltr, meaadj, qtyrtu, month, year, entity, rtunam 
                                          FROM qtyrtu;',
                        next_date => to_date('31-10-2010 01:00:03', 'dd-mm-yyyy hh24:mi:ss'),
                        interval => 'SYSDATE +30');
    commit;
  end;
  /

  I don't know if it's because I assigned the date 31-10... In November it's just but December has not...
  
  Best regards, hope you can help me.
  
  I use oracle 9i

  Hello

  If you want the job to run at 02:00 the last day of the next month, then the desired argument is:

  interval => 'ADD_MONTHS (TRUNC (SYSDATE, ''MONTH''), 2) - (22 / 24)'
  

  In other words, if she finishes running at 02:30 on 31 January, then
  TRUNC (SYSDATE, 'MONTH') will be at 00:00:00 January 1
  ADD_MONTHS (TRUNC (SYSDATE, 'MONTH'), 1) will be March 1st at 00:00:00
  ADD_MONTHS (TRUNC (SYSDATE, 'MONTH'), - 1) (22 / 24) will be 22 hours earlier, i.e. 02:00 on the last day of February.

  logandro wrote:
  I don't know if it's because I assigned the date 31-10... In November it's just but December has not...

  Do you mean this line?

  next_date-online to_date (October 31, 2010 01:00:03 ',' dd-mm-yyyy hh24:mi:ss'),

  I don't think that's a problem. The next_date specifies only when it work baptisms. I guess he ran on October 31; you said it was running well on 30 November, 30 days after that. Something has to happen after November 30.

  Note that the interval argument is relative when the task completes. If a task takes 30 minutes to run, then

  interval => 'SYSDATE +30'
  

  means that, if it turns to
  01:00:03 October 31, then it will run again about
  01:30:03 November 30, around
  02:00:03 on December 30.
  02:30:03 January 29 and so on. If your business does that for a few seconds, it won't matter much.

  If you decide to use LAST_DAY, don't forget not that the hours-minutes-seconds referring LAST_DAY are the same as those of his argument.

• Select the last value for each day of the table

  Hello!
  
  I have a table that contains several measures for each day. I need two queries on this table, and I'm not sure how to write them.
  
  The table stores the rows (sample data)
  

  *DateCol1                 Value       Database*
  27.09.2009 12:00:00       100           DB1
  27.09.2009 20:00:00       150           DB1
  27.09.2009 12:00:00       1000          DB2
  27.09.2009 20:00:00       1100          DB2
  28.09.2009 12:00:00       200           DB1
  28.09.2009 20:00:00       220           DB1
  28.09.2009 12:00:00       1500          DB2
  28.09.2009 20:00:00       2000          DB2

  Explanation of the data in the sample table:
  We measure the size of the data files belonging to each database to one or more times a day. The value column indicates the size of the files of database for each database at some point (date in DateCol1 European model).
  
  
  What I need:
  Query 1:
  The query must return to the last action for each day and the database. Like this:

  *DateCol1       Value      Database*
  27.09.2009        150          DB1
  27.09.2009       1100          DB2
  28.09.2009        220          DB1
  28.09.2009       2000          DB2

  Query 2:
  The query should return the average measurement for each day and the database. Like this:

  *DateCol1       Value      Database*
  27.09.2009       125          DB1
  27.09.2009      1050          DB2
  28.09.2009       210          DB1
  28.09.2009      1750          DB2

  Could someone please help me to write these two queries?
  
  Please let me know if you need further information.
  
  Published by: user7066552 on September 29, 2009 10:17
  
  Published by: user7066552 on September 29, 2009 10:17

  Why two queries when it suffice ;)

  SQL> select dt
    2       , db
    3       , val
    4       , avg_val
    5    from (
    6  select dt
    7       , val
    8       , db
    9       , row_number () over (partition by db, trunc (dt)
   10                                 order by dt desc
   11                            ) rn
   12       , avg (val) over (partition by db, trunc (dt)) avg_val
   13    from test)
   14   where rn = 1
   15  order by dt
   16  /
  
  DT        DB           VAL    AVG_VAL
  --------- ----- ---------- ----------
  27-SEP-09 DB2         1100       1050
  27-SEP-09 DB1          150        125
  28-SEP-09 DB2         2000       1750
  28-SEP-09 DB1          220        210
  

• How can I program a list of Interfaces that will run on the last Sunday of each month...

  Hi can someone help me to achieve this scenario...

  Thanks in advance...

  Hello

  Make the scenario for each interface and expand when the script option is planning.

  Scheduling---> option execution---> select month (day of week)---> monthly date = last & Sunday and schedule accordingly.

  Let me know

  Thank you

• Select the last record

  In the following query, I want only one record for Robert (later) and a record for all peoples in R1. Tried several joins, but do not know why it does not work

  drop table r1;

  create table r1

  (

  index_id NUMBER,

  first name VARCHAR2 (10),

  created DATE by DEFAULT SYSDATE

  );

  Insert into r1 (index_id, name) VALUES (1, 'Joe');

  Insert into r1 (index_id, name) VALUES (2, 'Robert');

  Insert into r1 (index_id, name) VALUES (3, 'John');

  commit;

  drop table r2;

  create table r2

  (

  index_id NUMBER,

  Field1 VARCHAR2 (10),

  VARCHAR2 (10) Field2.

  created DATE by DEFAULT SYSDATE

  );

  Insert into r2 (index_id, Field1, Field2) VALUES (2, "REC1", "OLD");

  Insert into r2 (index_id, Field1, Field2, created) VALUES (2, 'REC1', 'NEW', sysdate + 1);

  commit;

  Select r1.*, r2.* from r1, r2,

  (

  Select f.index_id as ind, f.field1, max (f.created) as last

  R2 f

  F.index_id, f.field1) abc

  where r1.index_id = r2.index_id

  and r2.created = abc.latest

  and r2.index_id = abc.ind (+);

  .

  Like this?

  -------------------------------------------------------

  SELECT *.

  SINCE r1,.

  (SELECT f.index_id AS ind, f.field1, MAX (f.created) AS last

  R2 f

  F.index_id, f.field1) r2

  WHERE r1.index_id = r2.ind (+);

  -------------------------------------------------------

  INDEX_ID	FIRST NAME	CREATED	IND	FIELD1	LATEST
  2	Robert	04/07/2013-06:43	2	REC1	05/07/2013-06:43
  3	John	04/07/2013-06:43
  1	Joe	04/07/2013-06:43

  If not then please post your results

  See you soon,.

  Manik.

• Select the last disk in the history table

  How to select the last record in a history table? the example data is
  < p >
  Product EffectiveDate
  
  prod1 01/01/1980
  
  prod1 01/01/1990
  
  prod1 01/01/2000
  
  prod2 02/02/1980
  
  prod2 02/02/2000
  < /p >
  < p >
  
  
  The expected result is
  
  
  
  Product EffectiveDate
  
  prod1 01/01/2000
  
  prod2 02/02/2000
  < /p >
  
  

  Assuming that there is a single line with max (effectivedate) for a given product

  SELECT product, attrib1, attrib2, ... , max_effective_date
    FROM (SELECT product,
                 attrib1,
                 attrib2,
                 ... ,
                 effectivedate,
                 max( effectivedate ) over (partition by product) max_effective_date
            FROM history_table)
   WHERE effectivedate = max_effectivedate
  

  should work.

  Justin

  Published by: Justin cave on October 30, 2008 18:32

  Formatting changes

• How to select the last 3 records in a table?

  I have a table named HRM_ATTENDANCE
  as follows

  Name         Type         Nullable Default Comments 
  ------------ ------------ -------- ------- -------- 
  LEAVEDATE    DATE                                   
  EMPLOYEECODE VARCHAR2(8)                            
  LEAVETYPE    VARCHAR2(4)                            
  APPROVEDBY   VARCHAR2(8)  Y                         
  FEEDBY       VARCHAR2(8)  Y                         
  FEEDTIME     DATE         Y                         
  REMARKS      VARCHAR2(50) Y 

  the table contains the record of leave of employees as follows

  LEAVEDATE   EMPLOYEECODE LEAVETYPE APPROVEDBY FEEDBY   FEEDTIME    REMARKS
  ----------- ------------ --------- ---------- -------- ----------- --------------------------------------------------
  6/1/2013    00001        CL  
  6/3/2013    00001        EL                                         
  6/5/2013    00001        CPL    
  6/7/2013    00001        SL 
  6/9/2013    00001        CL                                        

  I want to select the last 3 leaves (records) to employeecode "00001" so I don't know the what are the dates of the leave. in easy words I want to choose the folder where leavedate > = 5 June 2013 ", but I don't know any dates."

  Select * from HRM_ATTENDANCE where rownum<=3 order="" by="" leavedate="">

• Select the last 10 records in a table

  Oracle9i. I am trying to select the last 10 numbers in a table with this command series

  select serial from tab_42 where employeecode='00001'  and rownum<=10 order by serial desc;

  but it's not not selecting the most recent serial number 10. How to do?

  The rownum clause is applied before the order by clause, one must use a subquery...

  select * from (select serial from tab_42 where employeecode='00001' order by serial desc) where rownum<=10;
  

• Cursor Oracle return only the last record

  I am a newbie in oracle stored proc. I tried to select data using the slider, but it only return last record. The recording must be greater than 1.
  
  CREATE or REPLACE procedure MySchema.Test (myrefcur on sys_refcursor)
  Is
  
  Begin
  declare
  
  Cursor C1 IS
  
  Select mySerialNum from TableA;
  MyRecord C1% rowtype;
  
  Begin
  Open C1;
  Loop
  Fetch C1 into myrecord;
  When the output C1% NotFound;
  
  Open for Myrefcur
  Select SerialNumB from TableB where SerialNumB = myrecord.mySerialNum;
  
  End loop;
  Close C1;
  End;
  end;
  
  However, it only returns the last record in the list.
  
  Original case *.
  The original code is as below:
  
  1st, I'll need to select a list of ImageSerialNum of ImageSerial
  
  * 1 query:
  Select A.ImageSerialNum from ImageSerial A, ProductionOrder B, Bom C
  Where A.ProductionOrderID = B.ProductionOrderID And B.Assembly_Num = C.Model_Num and
  B.Revision = C.Revision And B.EngRevision = C.EngRevision and
  C.Bom_ID = passInVariable* and C.FactoryID = "7"
  
  2nd, I'll need to check the process of EACH series with the code below:
  
  * Low code a return process for 1 series only.
  
  Select t.processid, t.processname, t.assembly_num, t.revision, t.engrevision of
  (Select p.ProcessID, p.ProcessName, in. Assembly_Num, in. review, in. EngRevision, im.imageserialnum
  Process p, Routesequence rs, Imageserial im, ProductionOrder in.
  Where im. ImageserialNum = SerialNum* and p.ProcessID = rs. ProcessID
  And rs. RouteID = in. RouteID and rs. SequenceID = im. NextRouteSequence
  And in. ProductionOrderID = im. ProductionOrderID AND IM. STATUS OF '0'
  UNION
  SELECT A.REWORKROUTEID AS PROCESSID PROCESSNAME AS B.ROUTENAME, C.ASSEMBLY_NUM, C.REVISION, C.ENGREVISION, a.imageserialnum
  OF IMAGESERIAL A, B OF ROAD, PRODUCTIONORDER C
  WHERE A.REWORKROUTEID = B.ROUTEID AND A.IMAGESERIALNUM = SerialNum*.
  AND A.PRODUCTIONORDERID = C.PRODUCTIONORDERID and a.status = '0') t
  
  After that, I would like to combine the two in 1 stored proc code.

  in this case, you just want to join the two applications to use in the FROM clause
  As I don't have your tables, I created two tables, each representing the results of your queries. Substitute the names of table with your queries

  SQL> drop table master
    2  /
  
  Table dropped.
  
  SQL> drop table details
    2  /
  
  Table dropped.
  
  SQL>
  SQL> create table master
    2  (ImageSerialNum varchar2(25));
  
  Table created.
  
  SQL>
  SQL>
  SQL> insert into master values ('Serial1');
  
  1 row created.
  
  SQL> insert into master values ('Serial2');
  
  1 row created.
  
  SQL> insert into master values ('Serial3');
  
  1 row created.
  
  SQL> insert into master values ('Serial4');
  
  1 row created.
  
  SQL> insert into master values ('Serial5');
  
  1 row created.
  
  SQL>
  SQL> create table details
    2  (ImageSerialNum  varchar2(25)
    3  ,ProcessID  number
    4  ,ProcessName varchar2(25)
    5  );
  
  Table created.
  
  SQL>
  SQL> insert into details values ('Serial1',  1, 'Process1');
  
  1 row created.
  
  SQL> insert into details values ('Serial3',  3, 'Process3');
  
  1 row created.
  
  SQL> insert into details values ('Serial5',  5, 'Process5');
  
  1 row created.
  
  SQL>
  SQL> select m.imageserialnum
    2       , d.processid
    3       , d.processname
    4    from master m
    5    left outer
    6    join details d
    7      on (m.imageSerialnum = d.imageserialnum)
    8   order by m.imageserialnum
    9  /
  
  IMAGESERIALNUM             PROCESSID PROCESSNAME
  ------------------------- ---------- -------------------------
  Serial1                            1 Process1
  Serial2
  Serial3                            3 Process3
  Serial4
  Serial5                            5 Process5
  

  your query will be something like

  select m.imageserialnum
       , d.processid
       , d.processname
    from () m
    left outer
    join (
  

• Find the 2nd Sunday of each month in a report

  Hello

  I have the data of EMP_Name and Join_Date. I have to build a dashboard report where

  1. In the dashboard, there is a command prompt. If I select a year and a month then, the report is expected to show that the data of the respective month.
  2. This report will show the employees who joined the company only after the 2nd Sunday of each month until the end of the month.

  Inputs/suggestions, how to build it?

  Thanks in advance.

  You have a question, Yes... a SQL query... OBIEE do not mean SQL but LSQL, your query will be not really usable like this...

  You're right, it seems that when the first day of the month is a Saturday he jump 1 week...

  The correct formula for the 3rd Friday is:

  TIMESTAMPADD (SQL_TSI_DAY, (14 + 6-CASE WHEN DAYOFWEEK (TIMESTAMPADD (SQL_TSI_DAY, 1-DAYOFMONTH (CURRENT_DATE), CURRENT_DATE)) = 7 THEN 0 END ELSE DAYOFWEEK (TIMESTAMPADD (SQL_TSI_DAY, 1-DAYOFMONTH (CURRENT_DATE), CURRENT_DATE))), TIMESTAMPADD (SQL_TSI_DAY, 1-DAYOFMONTH (CURRENT_DATE), CURRENT_DATE))

  If instead of CURRENT_DATE you want to use your own column date just to replace in the formula and it works.

• Display total records with the last record

  Hi all

  I have the following tables:

  create the table TRY_date_detail

  (

  item_date date,

  number of item_order

  );

  create the table TRY_date_master

  (

  date of master_date,

  number of date_amount

  );

  Insert all

  IN TRY_date_detail values (to_date('01-01-2011','DD-MM-YYYY'), 1)

  IN TRY_date_detail values (to_date('01-01-2011','DD-MM-YYYY'), 2).

  IN TRY_date_detail values (to_date('01-01-2011','DD-MM-YYYY'), 3)

  IN TRY_date_detail values (to_date('01-01-2011','DD-MM-YYYY'), 4)

  IN TRY_date_detail values (to_date('01-01-2011','DD-MM-YYYY'), 5)

  IN TRY_date_master values (to_date('01-01-2011','DD-MM-YYYY'), 6432)

  IN TRY_date_master values (to_date('01-01-2011','DD-MM-YYYY'), 1111)

  IN TRY_date_detail values (to_date('11-08-2012','DD-MM-YYYY'), 11)

  IN TRY_date_detail values (to_date('11-08-2012','DD-MM-YYYY'), 12)

  IN TRY_date_detail values (to_date('11-08-2012','DD-MM-YYYY'), 13)

  IN TRY_date_detail values (to_date('11-08-2012','DD-MM-YYYY'), 14)

  IN TRY_date_master values (to_date('11-08-2012','DD-MM-YYYY'), 8913)

  IN TRY_date_detail values (to_date('09-03-2014','DD-MM-YYYY'), 21)

  IN TRY_date_detail values (to_date('09-03-2014','DD-MM-YYYY'), 22)

  IN TRY_date_detail values (to_date('09-03-2014','DD-MM-YYYY'), 23)

  IN TRY_date_master values (to_date('09-03-2014','DD-MM-YYYY'), 1234)

  IN TRY_date_detail values (to_date('11-03-2014','DD-MM-YYYY'), 33)

  Select * twice;

  -My query is:

  SELECT ITEM_DATE, ITEM_ORDER, DATE_AMOUNT NULL

  OF TRY_date_detail

  WHERE ITEM_DATE IN (SELECT DISTINCT master_date OF TRY_date_master)

  UNION

  SELECT MASTER_DATE, NULL, SUM (DATE_AMOUNT)

  OF TRY_DATE_MASTER

  MASTER_DATE GROUP;

  -My query result:

  ITEM_DATE ITEM_ORDER DATE_AMOUNT

  January 1, 11 12:00:00 AM 1 (null)

  January 1, 11 12:00:00 AM 2 (null)

  January 1, 11 12:00:00 AM 3 (null)

  January 1, 11 12:00:00 AM 4 (null)

  January 1, 11 12:00:00 AM 5 (null)

  January 1, 11 12:00:00 AM (null) 7543

  11 Aug 12 12:00:00 AM 11 (null)

  11 Aug 12 12:00:00 AM 12 (null)

  August 11, 12 noon 13 (null)

  11 Aug 12 12:00 14 (null)

  11 Aug 12 12:00:00 AM (null) 8913

  9 March 14 12:00:00 AM 21 (null)

  9 March 14 12:00:00 AM 22 (null)

  9 March 14 12:00:00 AM 23 (null)

  9 March 14 12:00:00 AM (null) 1234

  -What I need, is to display the Date_amount with the last line of each date as follows:

  ITEM_DATE ITEM_ORDER DATE_AMOUNT

  January 1, 11 12:00:00 AM 1 (null)

  January 1, 11 12:00:00 AM 2 (null)

  January 1, 11 12:00:00 AM 3 (null)

  January 1, 11 12:00:00 AM 4 (null)

  January 1, 11 12:00:00 AM 5 7543

  11 Aug 12 12:00:00 AM 11 (null)

  11 Aug 12 12:00:00 AM 12 (null)

  August 11, 12 noon 13 (null)

  August 11, 12 12 00 14 8913 h

  9 March 14 12:00:00 AM 21 (null)

  9 March 14 12:00:00 AM 22 (null)

  9 March 14 12:00:00 AM 23 1234

  Thank you

  Ferro

  You have to JOIN to the table two

  SQL> select item_date
    2       , item_order
    3       , decode(rno, cnt, date_amount) date_amount
    4    from (
    5          select item_date
    6               , item_order
    7               , date_amount
    8               , row_number() over(partition by item_date order by item_order) rno
    9               , count(*) over(partition by item_date) cnt
   10            from try_date_detail
   11            join (
   12                   select master_date, sum(date_amount) date_amount
   13                     from try_date_master
   14                    group
   15                       by master_date
   16                 )
   17              on item_date = master_date
   18         );
  
  ITEM_DATE           ITEM_ORDER DATE_AMOUNT
  ------------------- ---------- -----------
  01/01/2011 00:00:00          1
  01/01/2011 00:00:00          2
  01/01/2011 00:00:00          3
  01/01/2011 00:00:00          4
  01/01/2011 00:00:00          5        7543
  11/08/2012 00:00:00         11
  11/08/2012 00:00:00         12
  11/08/2012 00:00:00         13
  11/08/2012 00:00:00         14        8913
  09/03/2014 00:00:00         21
  09/03/2014 00:00:00         22
  09/03/2014 00:00:00         23        1234
  
  12 rows selected.
  
  SQL>
  

• How to get the second Monday of each month in a given date range?

  In Oracle forms, how to get the second Monday of each month in a given date range?

  I tried below using the query WITH the Clause, but it seems that WITH Clause does not work in Oracle forms. So is there another way to do this in Oracle forms?

  WITH month_range AS

  (

  SELECT TO_DATE ('Dec 2013', 'Mon YYYY') AS first_month

  , TO_DATE ('Mar 2014', 'Mon YYYY') AS last_month

  OF the double

  )

  SELECT NEXT_DAY (6 + ADD_MONTHS (first_month

  , LEVEL - 1

  )

  , 'MONDAY '.

  ) AS second_monday

  OF month_range

  CONNECTION OF LEVEL < = 1 + MONTHS_BETWEEN (last_month, first_month)

  ;

  Thanks in advance.

  Good fishing, when the first day of the month is Thursday... So I changed the query accordingly... Try the below

  SELECT CASE WHEN TO_CHAR (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'DY') = 'game '.

  THEN NEXT_DAY (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'THU')

  Of OTHER NEXT_DAY (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'Game') + 7

  END AS second_day

  FROM (SELECT SYSDATE startdate,

  SYSDATE + 300 enddate

  THE DOUBLE)

  CONNECT BY LEVEL<=>

• for the 25th day of each month in Date function

  Dear all,
  
  I want to want to get the 25th day of each month
  as.
  Select sysdate from dua.
  
  
  
  Concerning

  SQL> select trunc(sysdate,'MM')+24 "Day" from dual;
  
  Day
  ---------
  25-MAY-13
  

• How to get the date for the first Monday of each month

  Dear members,
  
  How to get the date for the first Monday of each month.
  
  I wrote the following code
  
  SELECT decode (to_char (trunc (sysdate + 30, 'MM'), 'DAY'), 'MONDAY', trunc (sysdate + 30, 'MM'), NEXT_DAY (trunc (sysdate + 30, 'MM'), "LUN")) FROM DUAL
  
  But he looks at complex bith.
  
  Abhishek
  
  Published by: 9999999 on 8 March 2013 04:30

  Use the IW format - it will make independent NLS solution. And all you need is truncated 7^th day of each month using IW:

  select  sysdate current_date,
          trunc(trunc(sysdate,'mm') + 6,'iw') first_monday_the_month
    from  dual
  /
  
  CURRENT_D FIRST_MON
  --------- ---------
  08-MAR-13 04-MAR-13
  
  SQL> 
  

  Here is the list of the first Monday of the month of this year:

  with t as(
            select  add_months(date '2013-1-1',level-1) dt
              from  dual
              connect by level <= 12
           )
  select  dt first_of_the_month,
          trunc(dt + 6,'iw') first_monday_the_month
    from  t
  /
  
  FIRST_OF_ FIRST_MON
  --------- ---------
  01-JAN-13 07-JAN-13
  01-FEB-13 04-FEB-13
  01-MAR-13 04-MAR-13
  01-APR-13 01-APR-13
  01-MAY-13 06-MAY-13
  01-JUN-13 03-JUN-13
  01-JUL-13 01-JUL-13
  01-AUG-13 05-AUG-13
  01-SEP-13 02-SEP-13
  01-OCT-13 07-OCT-13
  01-NOV-13 04-NOV-13
  
  FIRST_OF_ FIRST_MON
  --------- ---------
  01-DEC-13 02-DEC-13
  
  12 rows selected.
  
  SQL> 
  

  SY.

• The line of the last line of each table page is going to be missing.

  Hi Experts,
  In OBIEE 11.1.1.6.0, I have a report contains more than one line. "When I click on" PDF "Print", the last line of each table page line will be missing. " Why?
  Are you facing the same case? How soluve this question? Thank you.

  Hey Kobe,

  The question, looks lke a bug. Here's the work around, change the table view, click the properties of content next to the text "Table" (at the top of the columns and measures) in the layout-> position In Border pane to choose custom and select only the bottom edge (horizontal line). Now export to pdf format, you must see the border for the last row on each page.

  Kind regards
  DpKa