simple expression evaluator

Similar Questions

• Simple expression for the nested compositions

  Hi all

  I'm writing a simple expression to map the starting point of the effect of beam with a layer of a model. The result should be the beam from the pink square. The pink square is within a mobile model (model 'Start'). The other end of the beam is already connected in place of the violet (Comp 'end').

  Here is a screenshot, you can download the project here: Microsoft OneDrive - access to files anywhere. Create docs with Office free online.

  

  Thank you!

  simply use a control point dummy expression and plug it with a transformation of the layer space.

  Mother = thisComp.layer ("preComp");

  mPoint = mPre.effect ("Point")("Point");

  mPre.toComp (mPoint)

  Mylenium

• vector expression evaluation

  Hello world
  
  Can someone tell me the following expression evaluation.
  
  int i = 0;
  System.out.println (i ++ + ++ I + ++ i);
  
  
  Please help me...

  Prem says:
  Ok.. Thanks for this knowledge...

  If the operands are evaluated, left right then exit this expression must be of 6 but is 5? How?

  No, it must be exactly what it is. If such was not the case, it would mean that there is a HUGE mistake in a very basic part of Java a beginner like you could find, but who somehow don't get it fixed, despite Java used in thousands of existing applications.

  int i=0;
  System.out.println( i++ + ++i + ++i); 
  

  When we reached the first term (i ++), the value of i is 0. The value of this expression is the value of i, before the increment, if we determine that the value of this expression is 0. Then, we increment I 1. Running so our total is 0 and the value of i is 1.

  When we reached the second term (++ i), we increment all first I between 1 to 2. Then, we determine the value of this expression, which is the new value of i is 2. We have therefore 0 + 2 = 2 for our running total, and the value of i is now 2.

  When we reached the third mandate (++ i once again), we increment all first I have 2-3. Then, we determine the value of this expression, which is the new value of i is 3. So we have 0 + 2 + 3 = 5 for our total and the value of i is 3.

  It's as if we have:

  int i = 0;
  int j = i++; // j  = 0; i = 1;
  int k = ++i; // i = 2; k = 2;
  int m = ++i; // i = 3; m = 3;
  System.out.println(j + k + m); // 0 + 2 + 3
  

  Edited by: jverd May 15, 2012 02:32

• Expression evaluation limits step

  I'm just trying to understand the point at which the step limits expression is evaluated. I'm trying to define the limits of a test of numerical limit based on an expression. I'm passing the context of the sequence for the LabVIEW code module so that the VI may determine the limits to set the colors of parts of pass/fail indicator and for certain other purposes.

  The problem I have is that it resembles the step limits expression has not been evaluated at the time wherever the context of the sequence is passed to the VI, which means that the calculated limits are not available. Is this correct? If so, does anyone have suggestions as to how I might be able to get around this?

  Thank you.

  Adam

  Hi Adam,.

  The following graph shows the order of execution of the teststand steps.

  

  I believe that the evaluation of the expression limited on "steps of numerical limit test" occurs during the evaluation of the expression status (so the last part of the stage).

  Another solution would be to create your own custom step type and include a custom "step first substep for your personalized step step" (I think I just broke the world record for most uses of the word 'no' in a sentence )

  However, I think that you've already found the solution more practice/simple/elegant. Yes, Bravo to you!

  Thanks for your time. I hope that gives a little clarification.

  Best wishes

• Do in Expression evaluation

  Do everything in
  ((

  Val (locals. ((DailySelfCalTimeMsgBoxInputHours)<0&& val(locals.dailyselfcaltimemsgboxinputhours)="">23)). ((Val (Locals.DailySelfCalTimeMsgBoxInputMinutes)<0&& val(locals.dailyselfcaltimemsgboxinputminutes)="">59)). RunState.Sequence.Main ["Message Popup"]. Result.ButtonHit! = "2"

  MSG Box to read at the time of user input
  }

  I have this logic, but do so while the loop was never released.  If I press the button cancel the do while loop is exited.  However, Locals.DailySelfCalTimeMsgBoxInputHours Locals.DailySelfCalTimeMsgBoxInputMinutes meet the requirements above in the Do While expression, the loop never ends.  In the framework of the Expression of Post of Message box, I converted the above string variables of numeric type and display values as expected.  So, I'm not sure why when I try to use Val (String) in the Do While expression, the evaluation does not work as expected.  Can someone shed light on this problem?

  Pseudocode:

  While

  hours < 0="" and="" hours=""> 23

  Or

  minutes < 0="" and="" minutes=""> 59

  Or

  buttonhit <> 2

  end while

  Ok. Hours is never negative and more than 23. Minutes will be never greater than 59 both negative. buttonhit could not be 2. Thus, it seems that you will never get a real on buttonhit.

  I think that either you have you a larger and less reverse, or you need to replace your ANDS by RHA.

  Good luck

  Bob Y.

• Boolean expression evaluation

  Hello

  Flex, 4.0.x

  I came across a strange behavior, by evaluating the following expressions (function):

  public function calculateIsNext():void
  {
       if ( _currentState == "FirstPage" )
       {
            isNext = ((StoreManufacturerCode!='') && hasSelectedProducts);
            dispatchEvent( new Event( "ChangeValidation" ) );
       }
  }
  
  

  the problem lies on the line where the proximity is calculated, whenever I stop here during debugging, the two part of the expression are real and just leave this function after this line, dispatchEvent is not managed.

  I got this line also with if else statements, where proximity = true, never evaluated even the two parts of the expression are ture

  Anyone encountered similar behavior?

  r. sandor

  Sometimes, you will see this, if you are using the old code.  Try to delete the contents of bin-debug and then goes to the project > Clean and the cleaning of your project.  You can also see this in functions that may be related, if the underlying code generated decides that the value has not changed.

  HTH;

  Amy

• Stored as varchar expression evaluation

  Hello
  
  I declared a varchar variable and that data stored in this variable are an expression.
  I need to evaluate the expression.
  Y at - it an option to do so.
  For example
  
  v_s_expression: = '10 + 5';
  
  I need to evaluate and get the value in another variable.
  
  I would get the result 15 in the v_n_result variable.
  
  all methods?
  
  Thanks in advance
  Prasanth

     1  declare v varchar2(30) := '5+10';
    2          i number;
    3  begin
    4    execute immediate 'begin :b0 :='||v||'; end;'
    5    using out i;
    6    dbms_output.put_line(i);
    7* end;
  SQL> /
  15
  

• bind variables and expression evaluation

  Hi friends,

  I was looking at a query that uses a bad plan. DB is 11.2.0.3 with active user bind peeking. It is a simplified version showing the problem:

  Select egp.bsn

  , egp.klantnummer as 'Persoonsnummer '.

  , egp.samengesteldenaam as 'Samengesteldenaam '.

  , egp.geboortedatum as 'Geboortedatum.

  of pr_eigenschappen2 egp

  where

  (egp.bsn =: b1 or: b2 is null)

  and rownum < 51

  EGP. BSN is varchar2 (10) and has a high selectivity (almost unique) and is indexed btree. table and index have adequate statistics.

  When it is run with b1: = 928818 and b2: = 928818 (linked both as varchar2 (10)) a full table scan + filter is used on pr_eigenschappen2.

  If the query is changed to

  Select egp.bsn

  , egp.klantnummer as 'Persoonsnummer '.

  , egp.samengesteldenaam as 'Samengesteldenaam '.

  , egp.geboortedatum as 'Geboortedatum.

  of pr_eigenschappen2 egp

  where

  (= egp.bsn: b1 or 928818 a null value)

  and rownum < 51

  
  

  the index on the bsn is used, and the query does not 3.9 seconds but 1 millisecond.
  

  
  

  If I had a choice, the query would be different. I don't want to talk about the reason for the request, I would like to know why the optimizer does not use the index in the first case.
  

  
  

  
  

  Jan-marten,

  as Hoek wrote: "the optimizer must take into account the fact that the bind peut var be null, and then a full crawl is required...". ». For the bsn = part: b1 a systematic index scan range would be a good idea, but for: b1 is null, there is only one relevant case producing a result: NULL IS NULL and this condition the CBO only a full table scan or a full scan of the index taking into account (after all a complete analysis of the index may also be called 'index range scan across the table' - but that would be contrary to the 'Beach' in its name).

  By the way: I think that the trick of gather_plan_statistics is not very useful in the test case since you do not use display_cursor with allstats format. He might even have a negative impact on performance since statistical rowsource are quite expensive - depending on the timing of your OS routine. I think that Mr. Lewis has written something on this effect, in his notebook.

  Concerning

  Martin

• evaluate the expression error

  Hello

  TestStand 4.1, I'm trying to copy a container of FileGlobals to StationGlobals, based on a name.

  The following works, even if the browser of Expression says that it will cause a runtime error because "error in the call for expression int 'Evaluate'. Unexpected token:... »

  Locals.Name = "Name1"

  StationGlobals.TargetContainer = evaluate ("FileGlobals" + Locals.Name + ".") SourceContainer")

  where StationGlobals.TargetContainer and FileGlobals.Name1.SourceContainer are of the same named type.

  I tried to use EvaluateEx(), but found no construction to make it work. What would be the syntactically correct way to do this?

  Thank you

  Peter

  Peter,

  the reason for the 'mistake' the evaluation of the expression at development time, it's that he is a "stacked" expression

  First, you set Locals.Name a new value. I think in your sequence Locals.Name is by default an empty string. Then use this value in another part of the expression.

  Since there is no SequenceContext (no performance), the value of Locals.Name is not actually modified by the first part of the expression leaving the Evaluate() to search for a "FileGlobals" property... SourceContainer. Since two '.' one after another are illegal for search strings, the entire expression evaluation fails.

  This error does not occur during execution, because the first part of the expression does not actually change Locals.Name (for the SequenceContext) to be "Name1", while the second part will result in Evaluate ("FileGlobals.Name1.SourceContainer").

  hope this helps,

  Norbert

• Expression.Evaluate () - how to use with propertyobject?

  Hello

  I have the code in a reminder of model of process and would like to evaluate an expression in the context of Runstate.Caller.

  I found the method

  Expression. Evaluate (evaluationContext, evaluationOptions is EvalOption_NoOptions)

  That's exactly what I need. However, if I have a CallingStep.Expr, which is an expression, I can't access the Evaluate() function. It is not available, only the functions PropertyObjects are.

  How can I throw it's an Expression, so I can access the function Evaluate?

  I really I could do:

  Runstate.CallingStep.Expr.Evaluate (Runstate.Caller, 0x0)

  This returns the expression evaluated in the context of the appellant as a PropertyObject.

  But this isn't the case, need me something to TS know Runstate.CallingStep.Expr is an Expression... even if I add it to the Panel of the watch, it shows that it is an expression...

  Thank you.

  Hello

  Try to use RunState.Caller. AsPropertyObject. EvaluateEx (xxx)

  Hope this helps

  Jürgen

• Is there any built-in method to calculate mathematical expressions in blackberry?

  Hello

  I want to calculate the input given to for example phrase (25 + 48 * 9 + 69) / 3 in the BIRD rule database and display the result in a text box. So there is a built-in method to calculate data expressions?

  Do you mean a mathematical expression evaluator?

  Maybe you can use this:

  http://javadots.blogspot.com/2008/11/arithemetic-expressions-Solver-in-64.html

  http://Web.archive.org/Web/20070205080726/http://oglimmer.de/Java/mathematical_expression_parser.php

• Custom number Converter:-EL Expression

  Hi all

  I use JDeveloper 11.1.2.4.0.

  I have created a number converter to format number fields.

  I've referenced: Jerry on Java: create a custom converter of JSF 1.2 with the attributes and bunch of Red: tag JSP behavior customer personalized ADF Faces 11.1.1 Articles and created as a component of the taglib.

  I put the model to a numeric field based on a value of fields of wages as below

  #{bindings. Salary.inputValue gt 15000?' # 0.000 ': ' {# 0.00 "}".

  Salary is given as partial trigger deposited number and automatic sending is enabled in the salary field.

  I already pay value deposited. The loading of the page, the expression is used and the correct model is visible.

  But if I change the amount of salary not evaluates the expression and model does not change.

  But when refresh my browser tab then the model will change based on the new amount.

  For default converter I found the expression evaluates according to the change in the value of the wage.

  
  

  What I need to know is why EL Expression was not evaluated in the converter of custom number? I do any extra parameter?
  

  Please help me by providing some valuable links & Suggestions

  Thank you and best regards,

  Gijith

  Hi all

  Finally, I solved the problem of my custom number converter.

  It was that didn't save the handler class in the taglib.xml file. That's why expression evaluation works do not.

  After Manager class regitering everything works fine.

  Thank you dvohra21 for your reply.

  Kind regards

  Gijith.

• Expression of counting number with $-understand how to set breakpoints

  Hello, I am using a phrase that I found on: Expressioneering of Dan Ebberts Design Guide who saved me quiet a bit of frustration since I had to have a comma followed of a character custom at the end of my counting of numbers. But I have a simple question that I can't get out enough instructions on the page and I hope someone here could direct to me.

  
  

  Issue: The numbers count for the first 4 seconds - or what I change too, but I understand not how put my breakpoints number. that is to say, I want to go from 0 to 1 800 break at some point for a few seconds and then count to 6 500 break again and count up and so on. The part I don't understand is, how to start the countdown and stop on a number and then start again the count. I set keyframes for where I want that these numbers are on the timeline in the "Source text" page of Dan, which refers, but it does not work. Thoughts? Direction? Expression is lower and I have attached a picture of my calendar reference. Thank you very much for any direction you can provide

  
  

  Expression:

  numDecimals = 0;

  comma = true;

  dollarSign = true;

  beginCount = 0;

  endCount = 17000;

  hard = 4;

  t = time - inPoint.

  s = linear (t, 0, hard, beginCount, endCount) .toFixed (numDecimals);

  prefix = "";

  Si (s [0] == «- ») {}

  prefix = "-";

  s = s.substr (1);

  }

  the prefix if (dollarSign) += "±";

  If (the comma) {}

  Decimals = "";

  If (numDecimals > 0) {}

  decimals = s.substr (-(numDecimals + 1));

  s = s.substr (0, s.length - (numDecimals + 1));

  }

  outStr = s.substr (-s.length, (s.length-1)%3 + 1);)

  for (i = Math.floor((s.length-1)/3); I > 0; i--) {}

  outStr += "," + s.substr(-i*3,3);

  }

  outStr decimals + prefix;

  } else {}

  prefix + s;

  }

  

  I think I'd just keyframe a with values and the times when you want to stop and use a simpler expression of the text source like that to make the cursor:

  s = Math.round (effect ("Slider Control") ("Slider")) m:System.NET.SocketAddress.ToString ();

  outStr = s.substr (-s.length, (s.length-1)%3 + 1);)

  for (i = Math.floor((s.length-1)/3); I > 0; i--) {}

  outStr += "," + s.substr(-i*3,3);

  }

  outStr + "±";

  Dan

• Missing expression error when cases is used as field

  I tried to write an expression that calculates how many days ago a request and return a value defined by the user if the calculation falls under the criteria in the case statement. The SQL view for the query I use is shown below:

  SELECT A.F_POSN_REQUEST_ID, A.F_REQ_ECP_STATUS, TO_CHAR(A.REQUEST_DTTM,'YYYY-MM-DD-HH24.MI.SS."000000"'), TO_CHAR(A.F_REQ_ST_DT,'YYYY-MM-DD-HH24.MI.SS."000000"'), TO_CHAR(A.F_REQ_ECP_ST_DT,'YYYY-MM-DD-HH24.MI.SS."000000"'), TO_CHAR(A.F_REQ_ECP_PROC_DT,'YYYY-MM-DD-HH24.MI.SS."000000"'), CASE WHEN(sysdate - TO_DATE(SUBSTR( TO_CHAR(A.F_REQ_ST_DT,'YYYY-MM-DD-HH24.MI.SS."000000"'),1,16),'YYYY-MM-DD-HH24.MI'))>60 THEN '>60' ELSE(CASE WHEN(sysdate - TO_DATE(SUBSTR( TO_CHAR(A.F_REQ_ST_DT,'YYYY-MM-DD-HH24.MI.SS."000000"'),1,16),'YYYY-MM-DD-HH24.MI')) >30 AND <=60 THEN '30 - 60' ELSE(CASE WHEN(sysdate - TO_DATE(SUBSTR( TO_CHAR(A.F_REQ_ST_DT,'YYYY-MM-DD-HH24.MI.SS."000000"'),1,16),'YYYY-MM-DD-HH24.MI'))>=15 AND <=30 THEN '15 - 30' ELSE(CASE WHEN(sysdate - TO_DATE(SUBSTR( TO_CHAR(A.F_REQ_ST_DT,'YYYY-MM-DD-HH24.MI.SS."000000"'),1,16),'YYYY-MM-DD-HH24.MI'))<15 THEN 'Less Than 15' ELSE NULL END)END)END)END)) 
    FROM PS_F_POSN_REQUEST A 
    WHERE A.F_REQ_ECP_STATUS IN ('I','O','P') 
    GROUP BY  A.F_POSN_REQUEST_ID,  A.F_REQ_ECP_STATUS,  TO_CHAR(A.REQUEST_DTTM,'YYYY-MM-DD-HH24.MI.SS."000000"'),  TO_CHAR(A.F_REQ_ST_DT,'YYYY-MM-DD-HH24.MI.SS."000000"'),  TO_CHAR(A.F_REQ_ECP_ST_DT,'YYYY-MM-DD-HH24.MI.SS."000000"'),  TO_CHAR(A.F_REQ_ECP_PROC_DT,'YYYY-MM-DD-HH24.MI.SS."000000"')

  When I try to execute the query I get Message = ORA-00936: lack of expression (50 380)
  
  Any suggestions you could provide to help me clarify this error would be greatly appreciated.
  
  Published by: 992737 on March 8, 2013 09:07

  Hi, Peter,.

  Peter Gjelstrup wrote:
  ... OR

  select something,
  case your_expression
         when > 60
  then '>60'
         when > 30
  then '>30'
         when > 10
  then '>10'
  .
  etc.
  end
  something_else
  

  It really works when try you it?

  A CASE of Simple Expression (where you have an expression just after the CASE keyword and before the first WHEN) only check for equality. To use the inequality operators (such as >) you must use an Expression looked for CASES , such as

  CASE
     WHEN  exp > 60  THEN ...
     WHEN  exp > 30  THEN ...
  

  Repeat the expression exp each time.

• Small question about expressions 2 Dimensions

  What I do is probably very simple, but I have never tinkered with simple expressions.

  I have a bulge effect and I want the Center to track an object, so I pickwhip the position of the object to the center of curvature, but he needs to go "up" a few hundred pixels. (say 200) How to SIMPLY change the value y of the Ardennes Center?

  I could move the object anchor point and solve the problem, but I'd rather have this knowledge.

  Something like this is probably the most general way to do it:

  target = thisComp.layer ("target");

  fromComp (target.toComp (target.anchorPoint)) - [0,200]

  Dan