Expression evaluation limits step
I'm just trying to understand the point at which the step limits expression is evaluated. I'm trying to define the limits of a test of numerical limit based on an expression. I'm passing the context of the sequence for the LabVIEW code module so that the VI may determine the limits to set the colors of parts of pass/fail indicator and for certain other purposes.
The problem I have is that it resembles the step limits expression has not been evaluated at the time wherever the context of the sequence is passed to the VI, which means that the calculated limits are not available. Is this correct? If so, does anyone have suggestions as to how I might be able to get around this?
Thank you.
Adam
Hi Adam,.
The following graph shows the order of execution of the teststand steps.
I believe that the evaluation of the expression limited on "steps of numerical limit test" occurs during the evaluation of the expression status (so the last part of the stage).
Another solution would be to create your own custom step type and include a custom "step first substep for your personalized step step" (I think I just broke the world record for most uses of the word 'no' in a sentence )
However, I think that you've already found the solution more practice/simple/elegant. Yes, Bravo to you!
Thanks for your time. I hope that gives a little clarification.
Best wishes
Tags: NI Software
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Hello world
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Please help me...Prem says:
Ok.. Thanks for this knowledge...If the operands are evaluated, left right then exit this expression must be of 6 but is 5? How?
No, it must be exactly what it is. If such was not the case, it would mean that there is a HUGE mistake in a very basic part of Java a beginner like you could find, but who somehow don't get it fixed, despite Java used in thousands of existing applications.
int i=0; System.out.println( i++ + ++i + ++i);
When we reached the first term (i ++), the value of i is 0. The value of this expression is the value of i, before the increment, if we determine that the value of this expression is 0. Then, we increment I 1. Running so our total is 0 and the value of i is 1.
When we reached the second term (++ i), we increment all first I between 1 to 2. Then, we determine the value of this expression, which is the new value of i is 2. We have therefore 0 + 2 = 2 for our running total, and the value of i is now 2.
When we reached the third mandate (++ i once again), we increment all first I have 2-3. Then, we determine the value of this expression, which is the new value of i is 3. So we have 0 + 2 + 3 = 5 for our total and the value of i is 3.
It's as if we have:
int i = 0; int j = i++; // j = 0; i = 1; int k = ++i; // i = 2; k = 2; int m = ++i; // i = 3; m = 3; System.out.println(j + k + m); // 0 + 2 + 3
Edited by: jverd May 15, 2012 02:32
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user enters a string like "x * x + dx * dy" or 'x * dx - dy * y' and I Flash on hidden that in an actionscriptline in the code, it looks like:
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OK, thnx, I will follow your advice
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