Someone remembers Adobe Streamline? Need help for the conversion of drawings to bitmap to vector line.

Years ago and there are probably still more OSs, Adobe had a product called Streamline this linework (well relatively effortless) effortlessly converted to vector. It was easy to sweep the original work, and the user apply settings to get an outline of eigenvector (with a reasonable number of points).  Well, that the program is no longer available and I not being able to achieve something close to perfection from Photoshop/Illustrator CS - which means I create a path to the PS and then hover over the path to Illustrator. I can never get a true vector "copy" of my scanned drawings.  I tried everything, such as upping the resolution (600-800 dpi) in the PS, which of course gives me way too complex a piece of vector, although can be used.  In any case, I'm working on a project now that whereby I really need a more transparent and less "bulky point" conversion of my work in vector contour.  The work of the line are very complex. Any suggestions, anyone?

Mary,

You will probably need a cleaning after Live Trace; Among the options we object > Pat > simplify and add Anchor Points. If you view an image, you will get suggestions.

There are a few ways to apply; one more pretty is the use of closed paths. You can fill and stroke color (or use fill/no STROKE or cerebral vascular accident / no fill).

Tags: Illustrator

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    SPI 2561284360, message ID = 3875463636, a = 0x87D0CFC8

    DEC 20 02:39:26.794: ISAKMP: (2142): removal of spi 2561284360 message ID = 3357871564

    02:39:26.794 20 Dec: ISAKMP: (2142): node-937095732 error suppression REAL reason "remove larval.

    02:39:26.794 20 Dec: ISAKMP: (2142): node-419503660 error suppression FALSE reason 'informational (en) State 1.

    02:39:26.794 20 Dec: ISAKMP: (2142): entry = IKE_MESG_FROM_PEER, IKE_INFO_NOTIFY

    02:39:26.794 20 Dec: ISAKMP: (2142): former State = new State IKE_P1_COMPLETE = IKE_P1_COMPLETE

    02:39:46.798 20 Dec: ISAKMP: (2142): purge the node-1177810765

    02:39:46.798 20 Dec: ISAKMP: (2142): purge the node-138734109

    02:39:56.763 20 Dec: % s-6-IPACCESSLOGRL: the rate limited or missed 2 sachets of access list record

    DEC 20 02:39:56.763: IPSEC (key_engine): request timer shot: count = 2,.

    local (identity) = xx.xx.xx.xx:0, distance = xx.xx.xx.xx:0,

    local_proxy = 0.0.0.0/0.0.0.0/0/0 (type = 4),

    remote_proxy = 0.0.0.0/0.0.0.0/0/0 (type = 4)

    the config is following.

    crypto ISAKMP policy 10

    BA 3des

    preshared authentication

    Group 2

    ISAKMP crypto key xxxxxx address xx.xx.xx.xx

    !

    !

    Crypto ipsec transform-set esp-3des esp-sha-hmac vpnset

    transport mode

    !

    Crypto ipsec tech profile

    Set transform-set vpnset

    !

    !

    my-map 20 ipsec-isakmp crypto map

    defined peer xx.xx.xx.xx

    Set transform-set vpnset

    match address 155

    Hello

    As for your question, you can have more than 1 card crypto on the interface.

    However, you can use the same card encryption for several strategies. You can change the ma-card to vpnmap.
    In this way the two are enabled on the same interface, with one having a higher priority than the other.

    So if a package came from inside, the first crypto ACL interface is checked and then the next and so on. The first match found is chosen for the IPsec negotioation.

  • Need help for the particular case of selection

    Oracle DB 12 c, I think than 12.1.2

    drop table person_tests;

    create table person_tests)

    person_id number,

    test_type_id varchar2 (1).

    date of test_date

    );

    insert into person_tests (person_id, test_type_id, test_date) values (1, 'A', to_date('01012000','MMDDYYYY'));

    insert into person_tests (person_id, test_type_id, test_date) values (1, 'A', to_date('01022000','MMDDYYYY'));

    insert into person_tests (person_id, test_type_id, test_date) values (1, 'B', to_date('01032000','MMDDYYYY'));

    insert into person_tests (person_id, test_type_id, test_date) values (1, 'B', to_date('01042000','MMDDYYYY'));

    insert into person_tests (person_id, test_type_id, test_date) values (1,', to_date('01052000','MMDDYYYY'));

    insert into person_tests (person_id, test_type_id, test_date) values (2,', to_date('01062000','MMDDYYYY'));

    insert into person_tests (person_id, test_type_id, test_date) values (3, 'A', to_date('01072001','MMDDYYYY'));

    insert into person_tests (person_id, test_type_id, test_date) values (3, 'A', to_date('01082000','MMDDYYYY'));

    insert into person_tests (person_id, test_type_id, test_date) values (3, 'B', to_date('01092000','MMDDYYYY'));

    insert into person_tests (person_id, test_type_id, test_date) values (3, 'B', to_date('01102000','MMDDYYYY'));

    insert into person_tests (person_id, test_type_id, test_date) values (3,', to_date('01102000','MMDDYYYY'));

    People as a participant in some of the tests: A, B and C where each event is tagged with a date when finished.

    I need to get out of the only people who have done 2 tests of type A, 2 type tests B and 1 type C. I test have show the type of test and the date of the most recent of these tests. In the above example would output desired

    1 JANUARY 5 C 00

    3. A 7 JANUARY 01

    Hope that this definition of the logical problem

    Hello

    Sorry, I missed the obligation to show the most recent test_type_id.

    Assuming that the date to display is the date, that the minimum conditions were met (if not gratutitous trials came afterwrds), you can do something like this:

    WITH got_r_num AS

    (

    SELECT person_id, test_type_id, test_date

    , ROW_NUMBER () OVER (PARTITION BY person_id, test_type_id)

    ORDER BY test_date

    ) AS r_num

    OF person_tests

    WHERE test_type_id IN ('A', 'B', 'C')

    )

    SELECT person_id

    MIN (test_type_id) DUNGEON (DENSE_RANK LAST ORDER BY test_date) AS last_test_type

    MAX (test_date) AS last_test_date

    OF got_r_num

    WHERE r_num<= case ="">

    WHEN 'A' THEN 2

    WHEN 'B' THEN 2

    WHEN 'C' THEN 1

    END

    GROUP BY person_id

    HAVING COUNT (*) = 5-2 ' A + 2 ' B + 1 'C '.

    ;

    What test_type_id would you like to display tie for the final round?

    I just saw your post by saying that a person with 3 or more 'A' type tests should be excluded.  In this case, my original solution (with = in the WHERE clause) is what you want; only FINALLY used to get past test_type_id.  The solution in this post is for the situation where you don't care if there are 3 or more ' has, but you want to ignore all but the first 2.

  • Need help for the parent data!

    I and the application (app) that launches a window title and load a module (module1). In module1, I have a custom DateChooser component (dateChooser). I have stock introduced in dateChooser that needs to send the data back to module1, but instead it tries to send to app. I tried parent (which comes out wrong) & parentDocument but no luck. Can someone tell me how to get data in module1. Thank you!!

    He solved.

    Moved the event to module1 instead of dateChooser listeners and worked like a champ.

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