Specific range of numbers
Hello
I have a numeric field, and I want to enter specific numbers in this area; number between 10 and 40.
How can this be achieved?
Please note that I am new to Livecycle Designer.
Thank you in advance,
On the exit event of the field that you need to write code that verifies that the user has entered a number in this range. Something like this javascript here:
If (this.rawValue < 10="" ||="" this.rawvalue=""> 40) {}
App.Alert ("you have entered a number that is outside the acceptable range. It must be between 10 and 40. "Please try again");
xfa.host.setFocus ("insert the name of your domain here");
}
Hope that helps
Paul
Tags: Adobe LiveCycle
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I need a script to list all PO numbers within a specific range of accounting code. The script is used for the assessment of the stock.
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Please, if this answer is late; just ignore it
The following SQL select statement assumes that you know the costs/inv. natural accounts of valuation and natural account segment is 2:
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I have a range of numbers from B2 - B11 until the G2 - G11. For example:
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Repeats = duplicates.
I want to know all the repetitive number and how many times they repeat.
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Hello
Problem of three steps:
- Determine the distinct values
- Count the number of times each appears in the table
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The first step is easily handled by copy separate Automator Service, a Service of Automator, written by SGIII. A link to the file in post June 21 of the SG in this thread: Re: Analyzing column (maybe not the correct wording)
After downloading and installing the service, select the cells containing the numbers, call the service, and then select the first regular (ie. non-header) cell to a new table and the dough.
(The following assumes the new table has a header row, no column header, and you have selected - click - cell A2 before pasting.)
You will get a list of distinct numbers in a single column (A2 - A34, of your sample and support of note).
To count the numbers:
In this example, the existing table is named 'Table 1'
Enter the following formula in B2 the new table, and then fill up to the last line of the column B:
= COUNTIF (Table 1::B:G, A)
Results should be as shown:
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Kind regards
Barry
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Find the number in a specific range
Hello
I have a requirement where I need to check the lower and upper
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Example:
Range:
0.05
0.1
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0.2
0.25
0.3
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So if I am provided number tell 0.29, I must return under
outout
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How can I do this via oracle sql? I tried both options but
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Published by: 1002048 on April 23, 2013 15:00Hello
Welcome to the forum!
Oracle has two very practice of built-in functions, FLOOR and CEIL, that return the nearest integer, no more than not, or not less than a given number. Is there a way that we can take advantage of these features? Yes! They deal with a range of 1.00, and you have the beaches de.05 or 1/20 that size. Thus magnify your numbers by a factor 20, use CEIL and FLOOR and then narrow results by a factor of 20, like this:
SELECT n , FLOOR (n * 20) / 20 AS low_range , CEIL (n * 20) / 20 AS high_range FROM table_x ;
To test this, I created a test table:
CREATE TABLE table_x ( n NUMBER ); INSERT INTO table_x (n) VALUES (.29); INSERT INTO table_x (n) VALUES (.13); COMMIT;
You should post examples of data like this whenever you have a question.
I got these results from these data:
` N LOW_RANGE HIGH_RANGE ---------- ---------- ---------- .29 .25 .3 .13 .1 .15
Moreover, it is better to ask questions like that are on the language SQL, PL/SQL, and SQL
See the FAQ for this forum {message identifier: = 9360002} -
Count cells with a range in numbers
Is it possible to have the numbers read the value in a cell and there is in a given range. For example: count the number of cells that have a value between 85 and 100.
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Hi all.
It is a pleasure to receive your help.
I use Oracle Database 10 g Enterprise Edition Release 10.2.0
I want to leave a string of pairs of numbers (where each pair represents a range) to know if my setting number is between pairs.
Something like the following.
SQL:
declare i pls_integer := 0; s varchar2(100) := '^([74010000-74019999]|[85990000-85990999])'; test1 varchar2(8) := '64010000'; test2 varchar2(8) := '74010000'; begin begin select 1 into i from dual where regexp_like(test1, s); dbms_output.put_line(i); exception when no_data_found then dbms_output.put_line(0); end; begin select 1 into i from dual where regexp_like(test2, s); dbms_output.put_line(i); exception when no_data_found then dbms_output.put_line(0); end; end;
With the expected result below.
Output (It didn't happen):
0 1
Actual output:
1 1
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I'm looking for the literal correct.
I thank in advance
Filippe
No prob
drop table test
CREATE TABLE test
(NUMBER n
);
INSERT INTO test (n) VALUES (64010000);
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with input_data as)
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(Select '74010000; 74019999; 84010000; 84019999; 94010000; 94019999' VAL double) t
connect regexp_substr (t.val, "[^;]") +', 1, level * 2) IS NOT NULL
)
Select
*
of input_data, test
where
n between to_search and end_num
TO_SEARCH END_NUM N
74010000 74019999 74010000
Just to get the whole picture
with input_data as)
Select regexp_substr (t.val, "[^;]") +', 1, level * 2-1) to_search, regexp_substr (t.val, "[^;]") +', 1, level * 2) end_num
(Select '74010000; 74019999; 84010000; 84019999; 94010000; 94019999' VAL double) t
connect regexp_substr (t.val, "[^;]") +', 1, level * 2) IS NOT NULL
)
Select
*
Of
input_data
full outer join
test
on
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TO_SEARCH END_NUM N
74010000 74019999 74010000
84010000 84019999-
94010000 94019999-
-6401000
chris227: the entire image added
be complete it shoul be "n between to_number (start_num) and to_number (end_num)" accuracy
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Help with SELECT - select the range of numbers
Hello
I need assistance with the SELECT statement. I want to choose Dates today and ending 30 days back. If the result would be like:
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Does anyone have an idea?
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