SQL count (*) with Group of

Hello

I need help to fix this SQL.

Fields in the table are like that.
ID(PK)
user_id
user_name
login_time(timestamp)
Basically I want the values of user_id, user_name, last time the logged-in user and total number of times the user
select  distinct user_id , user_name, login_date from USER_LOGIN
where login_date in (select max(login_date) from USER_LOGIN group by user_id) 
the above query is to give the result set with user_id, user_name, last time that the user logged on, but how can I include count (*) Group of user_id in the sql above
select  distinct user_id , user_name, login_date, count(*) from USER_LOGIN
where login_date in (select max(login_date) from USER_LOGIN group by user_id)  group by user_id 
the sql above does not work.

can you help me to get the number of records by user_id group.

Thank you
SK

Hello

Looks like you want something like this:

SELECT       user_id
,       user_name
,       MAX (login_time)     AS last_login_time
,       COUNT (*)          AS total_rows
FROM       user_login
GROUP BY  user_id
,            user_name
;

This assumes that user_login is off standard (like him are often seen), such that every row of the same user_id will also have the same user_name.

I hope that this answers your question.
If not, post a small example of data (CREATE TABLE and INSERT statements) and the results desired from these data.

Tags: Database

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