SQL for the calculation of the salary

Version: 11.2

Permanent employees get monthly salary, contract workers get only commission.
Some permanent employees such as PETER and JOHANN get salary and Commission


I want to find the total amount paid to permanent and non-permanent.

The computation of the total, for employees who receive the salary and Commission as PETER and JOHANN, I want to ignore the Commission and considers that pay them for the calculation of total compensation.
ie. When computing the total amount paid to all these employees

    I want to ignore commision of 400 received by PETER 
    and
    I want to ignore commision of 1000 received by  JOHANN
That is to say. The Total amount paid will be: 18 500

create table pay_master (emp_type varchar2(50) , empname varchar2(50), salary number , comm number );


insert into pay_master values ( 'PERM', 'KAREN' , 2000, 0 );
insert into pay_master values ( 'PERM', 'HANS'  , 3000, 0 );
insert into pay_master values ( 'CONTRACT', 'KEITH'  , 0, 1000 );

insert into pay_master values ( 'CONTRACT', 'ABDUL'  , 0, 2000 );
insert into pay_master values ( 'PERM', 'KRISHNA'  , 1000, 0 );
insert into pay_master values ( 'CONTRACT', 'CHENG'  , 0, 1500 );
insert into pay_master values ( 'PERM', 'PETER'  , 5000, 400 );
insert into pay_master values ( 'PERM', 'JOHANN'  , 3000, 1000 );


col EMP_TYPE format a10
col EMPNAME format a10

SQL> select * From pay_master order by empname;

EMP_TYPE   EMPNAME        SALARY       COMM
---------- ---------- ---------- ----------
CONTRACT   ABDUL               0       2000
CONTRACT   CHENG               0       1500
PERM       HANS             3000          0
PERM       JOHANN           3000       1000           ---------------> Ignore this commision when calculating the total pay
PERM       KAREN            2000          0
CONTRACT   KEITH               0       1000
PERM       KRISHNA          1000          0
PERM       PETER            5000        400           ---------------> Ignore this commision when calculating the total pay

8 rows selected.

SQL> select EMPNAME , salary+comm from pay_master order by empname;

EMPNAME    SALARY+COMM
---------- -----------
ABDUL             2000
CHENG             1500
HANS              3000
JOHANN            4000
KAREN             2000
KEITH             1000
KRISHNA           1000
PETER             5400

8 rows selected.

SQL> select sum(salary+comm) from pay_master;

SUM(SALARY+COMM)
----------------
           19900


Expected output from the SQL with the above mentioned logic is 18500
How can I do this in SQL? I think that I can't use CASE here statement because the CASE statement works only in a single column. Right?

Hello

J.Kiechle wrote:
... I think that I can't use CASE here statement because the CASE statement works only in a single column. Right?

A CASE results in a single value expression. It may depend on any number of columns (that is, of reference): 0, 1, 2, 3 or more.

For example, the following is based on 2 columns, x and y:

CASE
    WHEN  x > y
    THEN  x
    ELSE  y
END

which is just another way to get the same results that

GREATEST (x, y)

You can use either of the foregoing, for your problem (assuming that the salary and the Commission are always 0 or more).

Published by: Frank Kulash, Sep 21, 2012 05:40

Tags: Database

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SQL> VARIABLE variable_name REFCURSOR;
SQL> SET AUTOPRINT ON;
SQL> BEGIN
  2     :variable_name := package_name.function_name_refcursor ('%A%');
  3  END;
  4  /

PL/SQL procedure successfully completed.

COLUMN_NAME
-----------
ALLEN
WARD
MARTIN
BLAKE
CLARK
ADAMS
JAMES

7 rows selected.

SQL> ALTER TABLE table_name ADD (new_column_name VARCHAR2 (1) DEFAULT 'X');

Table altered.

SQL> BEGIN
  2     :variable_name := package_name.function_name_refcursor ('%A%');
  3  END;
  4  /

PL/SQL procedure successfully completed.

COLUMN_NAME NEW_COLUMN_NAME
----------- ---------------
ALLEN       X
WARD        X
MARTIN      X
BLAKE       X
CLARK       X
ADAMS       X
JAMES       X

7 rows selected.

SQL>

  • SQL for the interface of FILES with column headers

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    Thank you
    Patel.

    Hi Pierrot

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    http://odiexperts.com/Oracle-to-flat-file/

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    Concerning
    KK

  • SQL for the datetime type

    Hello

    help me in this.

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    You can change in your date format or add

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  • SQL for the sum of a column while avoiding the repetition of values

    Dear all
    I have this table called Loans_installments that contains the client's loan payments.

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    110 2 222 100 1/1/2013 1 0 50
    110 2 222 100 1/2/2013 2 0 52
    110 2 222 100 1/3/2013 3 0 54
    110 2 222 100 1/4/2013 4 500 90
    110 2 222 100 1/5/2013 5 0 50
    110 2 222 100 1/6/2013 6 0 51
    110 2 222 100 7/1/2013 7 0 50
    110 2 222 100 1/8/2013 8 600 105
    110 2 222 100 1/9/2013 9 0 50
    110 2 222 10 100 1/10 / 2013 0 54
    110 2 222 100 1/11 / 2013 11 0 50
    110 2 222 100 1/12 / 2013 12 700 120



    now what I want to do the sum of int_amt field based on original_inst_amt value (0 or a value) and put the result on the int_amt who has an orig_inst_amt value <>0.

    the result should be like this:


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    110 2 222 100 1/1/2013 1 0 0
    110 2 222 100 1/2/2013 2 0 0
    110 2 222 100 1/3/2013 3 0 0
    110 2 222 100 1/4/2013 4 500 246
    110 2 222 100 1/5/2013 5 0 0
    110 2 222 100 1/6/2013 6 0 0
    110 2 222 100 7/1/2013 7 0 0
    110 2 222 100 1/8/2013 8 600 256
    110 2 222 100 1/9/2013 9 0 0
    110 2 222 100 1/10 / 2013 10 0 0
    110 2 222 100 1/11 / 2013-11 0 0
    110 2 222 100 1/12 / 2013 12 700 274


    any help please.

    With the help of the clause type

    SQL> with t
  2  as
  3  (
  4  select 110 branch, 2 currency, 222 client_id, 100 loan_no, to_date('1/1/2013','mm/dd/yyyy') inst_mat_date, 1  inst_seq, 0   original_inst_amt, 50 int_amt from dual
  5  union all
  6  select 110 branch, 2 currency, 222 client_id, 100 loan_no, to_date('1/2/2013','mm/dd/yyyy') inst_mat_date, 2  inst_seq, 0   original_inst_amt, 52 int_amt from dual
  7  union all
  8  select 110 branch, 2 currency, 222 client_id, 100 loan_no, to_date('1/3/2013','mm/dd/yyyy') inst_mat_date, 3  inst_seq, 0   original_inst_amt, 54 int_amt from dual
  9  union all
 10  select 110 branch, 2 currency, 222 client_id, 100 loan_no, to_date('1/4/2013','mm/dd/yyyy') inst_mat_date, 4  inst_seq, 500 original_inst_amt, 90 int_amt from dual
 11  union all
 12  select 110 branch, 2 currency, 222 client_id, 100 loan_no, to_date('1/5/2013','mm/dd/yyyy') inst_mat_date, 5  inst_seq, 0   original_inst_amt, 50 int_amt from dual
 13  union all
 14  select 110 branch, 2 currency, 222 client_id, 100 loan_no, to_date('1/6/2013','mm/dd/yyyy') inst_mat_date, 6  inst_seq, 0   original_inst_amt, 51 int_amt from dual
 15  union all
 16  select 110 branch, 2 currency, 222 client_id, 100 loan_no, to_date('1/7/2013','mm/dd/yyyy') inst_mat_date, 7  inst_seq, 0   original_inst_amt, 50 int_amt from dual
 17  union all
 18  select 110 branch, 2 currency, 222 client_id, 100 loan_no, to_date('1/8/2013','mm/dd/yyyy') inst_mat_date, 8  inst_seq, 600 original_inst_amt, 105 int_amt from dual
 19  union all
 20  select 110 branch, 2 currency, 222 client_id, 100 loan_no, to_date('1/9/2013','mm/dd/yyyy') inst_mat_date, 9  inst_seq, 0   original_inst_amt, 50 int_amt from dual
 21  union all
 22  select 110 branch, 2 currency, 222 client_id, 100 loan_no, to_date('1/10/201','mm/dd/yyyy') inst_mat_date, 10 inst_seq, 0   original_inst_amt, 54 int_amt from dual
 23  union all
 24  select 110 branch, 2 currency, 222 client_id, 100 loan_no, to_date('1/11/201','mm/dd/yyyy') inst_mat_date, 11 inst_seq, 0   original_inst_amt, 50 int_amt from dual
 25  union all
 26  select 110 branch, 2 currency, 222 client_id, 100 loan_no, to_date('1/12/201','mm/dd/yyyy') inst_mat_date, 12 inst_seq, 700 original_inst_amt, 120 int_amt from dual
 27  )
 28  select branch
 29       , currency
 30       , client_id
 31       , loan_no
 32       , inst_mat_date
 33       , inst_seq
 34       , original_inst_amt
 35       , decode(original_inst_amt, 0, 0, sum(int_amt) over(partition by cnt)) int_amt
 36    from (
 37            select branch
 38                 , currency
 39                 , client_id
 40                 , loan_no
 41                 , inst_mat_date
 42                 , inst_seq
 43                 , original_inst_amt
 44                 , int_amt
 45                 , cnt
 46              from t
 47             model
 48             dimension by
 49             (
 50                inst_seq
 51             )
 52             measures
 53             (
 54                branch, currency, client_id, loan_no, inst_mat_date, original_inst_amt, int_amt, 1 cnt
 55             )
 56             rules
 57             (
 58                 cnt[any] = case
 59                                   when original_inst_amt[cv()-1] > 0 then
 60                                      cnt[cv()-1] + 1
 61                                   else
 62                                      nvl(cnt[cv()-1], cnt[cv()])
 63                               end
 64             )
 65         )
 66  /

    BRANCH   CURRENCY  CLIENT_ID    LOAN_NO INST_MAT_   INST_SEQ ORIGINAL_INST_AMT    INT_AMT
---------- ---------- ---------- ---------- --------- ---------- ----------------- ----------
       110          2        222        100 01-JAN-13          1                 0          0
       110          2        222        100 02-JAN-13          2                 0          0
       110          2        222        100 03-JAN-13          3                 0          0
       110          2        222        100 04-JAN-13          4               500        246
       110          2        222        100 05-JAN-13          5                 0          0
       110          2        222        100 06-JAN-13          6                 0          0
       110          2        222        100 08-JAN-13          8               600        256
       110          2        222        100 07-JAN-13          7                 0          0
       110          2        222        100 09-JAN-13          9                 0          0
       110          2        222        100 11-JAN-01         11                 0          0
       110          2        222        100 10-JAN-01         10                 0          0
       110          2        222        100 12-JAN-01         12               700        274

12 rows selected.

SQL>

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  FROM (SELECT S_NO,
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