SQL query to assign several concurrent programs to the concurrent Manager.

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  Original title: white screen on startup of Windows Vista

  Hello

  I tried tirelessly fix my Sony Vaio computer that is running Windows Vista. After that I entered my password by logging into my account, the screen charge nothing; It is empty. I'm unable to open all programs, even the Task Manager.

  I AM able to start safe mode. I tried MSCONFIG, removing all the programs of cleaning, power off start up programs, but nothing seems to work. Can anyone help? Thank you.

  Hello

  See if that helps you.

  Do a Safe Mode system restore to before the problem started.

  http://bertk.MVPs.org/html/restoresysv.html

  @@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@

  If it doesn't, try a startup repair and / or a system restore using a DVD of Vista from Microsoft

  Manufacturers recovery disks normally do not have Service Options; they are normally a relocation to the factory only settings option.

  Here is the guide to repair Options using a Vista DVD from Microsoft.

  If a friend or a work acquantance of yours has one, you can borrow and use it for repairs.

  http://www.bleepingcomputer.com/tutorials/repair-Windows-with-Windows-Startup-Repair/

  Table of contents

  1. Overview of Windows Vista repair options
  2. How to perform an automatic repair of Windows Vista using Startup Repair
  3. Advanced Tools Overview
  4. Conclusion

  If you do not or can not borrow a Microsoft DVD there is a download of a file ISO of Vista Startup Repair available that you can put on a Bootable floppy to make the above startup repair and that the method is recommended by a large number of posters in these Forums.

  Unfortunately, you have to buy it.

  Here is a link to it:

  http://NeoSmart.net/blog/2011/Windows-Recovery-discs-updated-reinstated/

  See you soon.

• Need for the sql query to have several columns in a single coulumn

  Hi all
  
  I need create the query to have several columns in a single column with several lines.
  
  Select a.customer_trx_id, a.previous_customer_trx_id
  of ra_customer_trx_all one
  where a.customer_trx_id =: customer_trx_id
  
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  a.customer_trx_id a.previous_customer_trx_id
  
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  As
  
  
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  Abdul

  Hello

  You want a way to confirm that what looks like two rows is really a line?

  Here are three ways:

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  WITH  my_original_querry     AS
  (
       select  a.customer_trx_id || CHR(13)
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       from      ra_customer_trx_all     a
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  (2) in SQL * Plus, have SQL * more count them for you:

  SET     FEEDBACK     1
  
  select  a.customer_trx_id || CHR(13)
                   || a.previous_customer_trx_id     as id
  from      ra_customer_trx_all     a
  where      a.customer_trx_id      = 274881;
  

  (3) implicitly count them with the ROWNUM Pseudo-column

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                   || a.previous_customer_trx_id     as id
  ,     ROWNUM
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• SQL Query to retrieve records for all after the Max Dates.

  Hello everyone,

  I am trying to retrieve the record more recent, based on the date field ( nextDate ).

  Currently, there are only 4 records in the MC_Maintenance table and two in the Machine table.

  Machine table

  MC_id             EquipID          

  1                      0227

  MC_id EquipID

  2                     0228

  ---------------------------------

  MC_Maintenance table

  Maint_id MC_id Next_maint

  1                      2                      08/25/2010     

  2                      2                      07/01/2010

  3                      1                      2010-11-06

  4                      1                      07/11/2010

  I have am trying to accomplish is,.

  the list of the two machines of the table of the Machine with the MAX (Next_maint) control the list of MC_Maintenance results

  These are the records I want to display.

  Maint_id MC_id Next_maint

  1                      2                      08/25/2010

  4                      1                      07/11/2010                 

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  SELECT

         MC. MC_ID as ID,

  MC.complete_Date completed.

  MC.next_maint as nextDate,.

  MC.maint_notes as noted,.

  MC.facility Facility.

  M.EquipId,.

  $m.name as the name.

  M.SerialNumber SN.

  M.dept as dept.

  M.Freq as freq

  Of MC_Maintenance MC, Machine M

          where  MC. MC_ID = M.MC_ID

  '           Using MAX (nextDate)

  Any ideas would be useful.

  TJ

  I thought it was a simple group of problem?

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  FROM MC_Maintenance MC INNER JOIN Machine M ON MC.MC_ID = M.MC_ID
  GROUP BY M.EquipID, MC.MC_ID
  

• Stuck on a sql query to search for records that have the same parent child records

  Oracle 10 g 2 Enterprise Edition.
  
  Hello
  
  I'm writing a logic to find records in a parent table, who have the same values in a child table.
  This is part of a larger application, but I am stuck on that part for now, so I have mocked some of the below simplified tables to capture the heart of the
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   id      number primary key,
   name      varchar2(100));
  
  -- child table 
  CREATE TABLE employee (
   id          number primary key,
   name      varchar2(100));
  
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   manager_id          NUMBER, 
   employee_id      NUMBER,
   CONSTRAINT join_table_pk PRIMARY KEY (manager_id, employee_id),
   CONSTRAINT manager_fk FOREIGN KEY (manager_id) REFERENCES manager(id),
   CONSTRAINT employee_fk FOREIGN KEY (employee_id) REFERENCES employee(id) 
   );
  
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  INSERT INTO manager (id, name) VALUES (1, 'John');
  INSERT INTO manager (id, name) VALUES (2, 'Bob');
  INSERT INTO manager (id, name) VALUES (3, 'Mary');
  INSERT INTO manager (id, name) VALUES (4, 'Sue');
  INSERT INTO manager (id, name) VALUES (5, 'Alan');
  INSERT INTO manager (id, name) VALUES (6, 'Mike');
  
  -- Insert some employees 
  INSERT INTO employee (id, name) VALUES (101, 'Paul');
  INSERT INTO employee (id, name) VALUES (102, 'Simon');
  INSERT INTO employee (id, name) VALUES (103, 'Ken');
  INSERT INTO employee (id, name) VALUES (104, 'Kevin');
  INSERT INTO employee (id, name) VALUES (105, 'Jack');
  INSERT INTO employee (id, name) VALUES (106, 'Jennifer');
  INSERT INTO employee (id, name) VALUES (107, 'Tim');
  
  -- Insert the links
  -- John manages Paul, Simon, Ken
  INSERT INTO join_table (manager_id, employee_id) VALUES (1, 101);
  INSERT INTO join_table (manager_id, employee_id) VALUES (1, 102);
  INSERT INTO join_table (manager_id, employee_id) VALUES (1, 103);
  -- Bob manages Paul, Simon, Kevin, Jack
  INSERT INTO join_table (manager_id, employee_id) VALUES (2, 101);
  INSERT INTO join_table (manager_id, employee_id) VALUES (2, 102);
  INSERT INTO join_table (manager_id, employee_id) VALUES (2, 104);
  INSERT INTO join_table (manager_id, employee_id) VALUES (2, 105);
  -- Mary manages Jennifer, Tim
  INSERT INTO join_table (manager_id, employee_id) VALUES (3, 106);
  INSERT INTO join_table (manager_id, employee_id) VALUES (3, 107);
  -- Sue manages Jennifer, Tim
  INSERT INTO join_table (manager_id, employee_id) VALUES (4, 106);
  INSERT INTO join_table (manager_id, employee_id) VALUES (4, 107);
  -- Alan manages Paul, Simon, Ken, Jennifer, Tim
  INSERT INTO join_table (manager_id, employee_id) VALUES (5, 101);
  INSERT INTO join_table (manager_id, employee_id) VALUES (5, 102);
  INSERT INTO join_table (manager_id, employee_id) VALUES (5, 103);
  INSERT INTO join_table (manager_id, employee_id) VALUES (5, 106);
  INSERT INTO join_table (manager_id, employee_id) VALUES (5, 107);
  -- Mike manages Paul, Simon, Ken
  INSERT INTO join_table (manager_id, employee_id) VALUES (6, 101);
  INSERT INTO join_table (manager_id, employee_id) VALUES (6, 102);
  INSERT INTO join_table (manager_id, employee_id) VALUES (6, 103);
  
  -- For sanity
  CREATE UNIQUE INDEX employee_name_uidx ON employee(name);

  If I ask for Manager John, so I want to find other managers who manage the exact list and even employees.
  Answer should be Mike.
  If I ask for Manager of Mary, the answer should be Sue.
  
  This query will give me the list of managers who manage some of the same employees as John, but not the same employees accurate...

  SELECT DISTINCT m.name AS manager
  FROM manager m, join_table jt, employee e
  WHERE m.id = jt.manager_id
  AND jt.employee_id = e.id
  AND e.id IN (
       SELECT e.id
       FROM manager m, join_table jt, employee e
       WHERE m.id = jt.manager_id
       AND jt.employee_id = e.id
       AND m.name = 'John')
  ORDER BY 1;

  I thought about using set operations to find managers with a list of employees less than my employees is null and where my employees under their list of employees is null. But there must be an easier way more elegant.
  Any ideas?
  BTW, I need to run as a batch on tables with > 20 million rows so the efficiency of queries is key.

  What about...

  WITH manager_list AS
  (
   SELECT name,
          LTRIM(MAX(SYS_CONNECT_BY_PATH(id,','))
          KEEP (DENSE_RANK LAST ORDER BY curr),',') AS employees
   FROM   (SELECT m.name,
                  e.id,
                  ROW_NUMBER() OVER (PARTITION BY m.name ORDER BY e.id) AS curr,
                  ROW_NUMBER() OVER (PARTITION BY m.name ORDER BY e.id) -1 AS prev
           FROM   manager m,
                  join_table jt,
                  employee e
    WHERE m.id           = jt.manager_id
    AND   jt.employee_id = e.id
    AND   m.name = :P_MANAGER)
    GROUP BY name
    CONNECT BY prev = PRIOR curr AND name = PRIOR name
    START WITH curr = 1
  ), all_list AS
  (
   SELECT name,
          LTRIM(MAX(SYS_CONNECT_BY_PATH(id,','))
          KEEP (DENSE_RANK LAST ORDER BY curr),',') AS employees
   FROM   (SELECT m.name,
                  e.id,
                  ROW_NUMBER() OVER (PARTITION BY m.name ORDER BY e.id) AS curr,
                  ROW_NUMBER() OVER (PARTITION BY m.name ORDER BY e.id) -1 AS prev
           FROM   manager m,
                  join_table jt,
                  employee e
    WHERE m.id           = jt.manager_id
    AND   jt.employee_id = e.id)
    GROUP BY name
    CONNECT BY prev = PRIOR curr AND name = PRIOR name
    START WITH curr = 1
  )
  SELECT a.*
  FROM   manager_list m,
         all_list a
  WHERE  m.employees = a.employees
  

  Would be easier in 11g, but I do not have a facility here so this is based on 10g.

  See you soon

  Ben

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  Restore points are created automatically every day, and just before the events significant system, such as installing a program or device driver. There is no need for schedule you a task for her through Task Scheduler. However, you can also create a manually restore point.

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