SQL query to retrieve the same record because no. boxes

Similar Questions

• SQL query to retrieve a single record for each employee of the following table?

  Hi all

  Help me on the writing of SQL query to retrieve a single record for each employee of the following table? preferably a standard SQL.

  CREATE TABLE xxc_contact)

  empnum NUMBER,

  alternatecontact VARCHAR2 (100),

  relationship VARCHAR2 (10),

  phtype VARCHAR2 (10),

  Phone NUMBER

  );

  insert into xxc_contact values (123456, 'Rick Grimes', 'SP', 'Cell', 9999999999)

  insert into xxc_contact values (123456, 'Rick Grimes', 'SP', 'Work', 8888888888)

  insert into xxc_contact values (123457, 'Daryl Dixon', 'EN', 'Work', 7777777777)

  insert into xxc_contact values (123457, 'Daryl Dixon', 'EN', 'Home', 3333333333)

  insert into xxc_contact values (123456, 'Maggie Greene', 'CH', 'Cell', 9999999999)

  insert into xxc_contact values (123456, 'Maggie Greene', 'CH', 'Home', 9999999999)

  expected result:

  EmpNum AlternateContact Relationship PhType Phone       

  123456 rick Grimes SP cell 9999999999

  Daryl Dixon EN work 7777777777 123457

  Home 123458 Maggie Greene CH 6666666666

  Thanks in advance.

  994122 wrote:

  Thank you all, that I got a result

  http://www.orafaq.com/Forum/m/620305/#msg_620305

  By Lalit Kumar B...

  Specifically, the two simple solutions provided were:

  1 using the row_number, entitled Oracle ranking based on descending order of the inside telephone each empnum group. And finally selects the lines which has least rank (of least since that order is descending for phone).

  SQL > column alternatecontact format A20;

  SQL >

  SQL > SELECT empnum, alternatecontact, relationship, phtype, phone

  2 from (SELECT a.*, row_number() over r (PARTITION BY empnum ORDER BY phone / / DESC))

  3 FROM xxc_contact one)

  4. WHEN r = 1

  /

  EMPNUM ALTERNATECONTACT RELATIONSHIP PHTYPE PHONE

  ---------- -------------------- ---------- ---------- ----------

  123456 rick Grimes SP cell 9999999999

  Daryl Dixon EN work 7777777777 123457

  Home 123458 Maggie Greene CH 6666666666

  2. with the help of MAX, Oracle automatically assigns the maximum phone for all the rows in each group of empnum. And finally selects the rows with the maximum phone. Order by clause is omitted here intentionally. You can find out why.

  SQL > SELECT empnum, alternatecontact, relationship, phtype, phone

  2 (SELECT a.*, MAX (phone) over (PARTITION BY empnum) rn FROM xxc_contact one)

  3 WHERE phone = rn

  4.

  EMPNUM ALTERNATECONTACT RELATIONSHIP PHTYPE PHONE

  ---------- -------------------- ---------- ---------- ----------

  123456 rick Grimes SP cell 9999999999

  Daryl Dixon EN work 7777777777 123457

  Home 123458 Maggie Greene CH 6666666666

  Kind regards

  Lalit

• SQL query to get the NULL records after the last matching flag

  I have a xx1 table with id and flag columns. So I want the data in this table, after the last flag matched. I want that data to id 7 in the rooms. Even if the id 2,3,5 are null flag 'Y' was at 6. ID so I need a query to get the data of the xx1 table after the last correspondence flag (from 7 to 9 id).

  SQL > create table xx1

  2 (identification number,

  3 flag varchar2 (10));

  Table created.

  SQL > insert into xx1 values (1, 'Y');

  1 line of creation.

  SQL > insert into values xx1 (2, null);

  1 line of creation.

  SQL > insert into values xx1 (3, null);

  1 line of creation.

  SQL > insert into xx1 values (4, 'Y');

  1 line of creation.

  SQL > insert into values xx1 (5, null);

  1 line of creation.

  SQL > insert into xx1 values (6, 'Y');

  1 line of creation.

  SQL > insert into values xx1 (7, null);

  1 line of creation.

  SQL > insert into values xx1 (8, null);

  1 line of creation.

  SQL > insert into values xx1 (9, null);

  1 line of creation.

  SQL > select * from xx1.

  FLAG OF THE ID

  ---------- ----------

  1. IS

  2

  3

  4. IS

  5

  6. IS

  7

  8

  9

  9 selected lines.

  SQL >

  Hello

  user11164339 wrote:

  Hi Frank - when I run the query, I don't see the results data.

  I get

  FLAG OF THE ID

  ----- ----------

  7

  8

  9

  What you do differently?

• SQL query to represent the data in the graph bar

  Hello

  JDev 11.1.1.5.0

  We must create a dashboard to track the translation. We have created the ADF table with buttons 'Create', 'Update' and 'Delete' to manipulate the table.

  Our DB table structure is

  File_id (PK), File_Name, ToSpanish - ARE (YES/NO), beginning of the ToSpanish, ToChina(YES/No), ToChina-Date... etc.

  Once the translated file required language then user must update the DB table using the button "Update".

  So far, we have implemented the requirement above.

  We need represent the status of the translation in the graph bar with the language as X access and file count get access Ex: Spanish-100 China - 200 files files

  Please suggest the sql query to retrieve the necessary info from the DB table that can be represented in the graph bar. Also, it would be great, if you can provide a pointers to create a bar chart.

  Thanks in advance,

  MSR.

  If you set your major increment and minor than 1, then you won't not show decimal points.  You can try setting these 10 or 100 to reach your goal.

  Subtype = "BAR_VERT_CLUST" >

               

• SQL query to find the total number of source based nonsource passangersbetween source and destination station and passenger station on the same chekindate

  Hello

  SQL query to find the total number of source based nonsource passangersbetween source and destination station and passenger station on the same chekindate.

  Please help on this script and let me know if you need more details.

  ---

  You use a SELECT statement.  Let me know if you need more details.

• Insert the same record (same key) in different sessions

  Oracle Database 10g Enterprise Edition Release 10.2.0.5.0 - Prod
  PL/SQL Release 10.2.0.5.0 - Production
  CORE Production 10.2.0.5.0
  AMT for Linux: Version 10.2.0.5.0 - Production
  NLSRTL Version 10.2.0.5.0 - Production
  
  Hello! I am inserting the same record in 2 different sessions without validation using TOAD:
  

  insert into FIFAPPS.TESTES values(3);

  in this table, where ID is a key:
  

  CREATE TABLE FIFAPPS.TESTES
  (
    ID  NUMBER
  )

  In the first session, it goes well, but for the next session... It of just execution and never ends. My question is what happens when I insert the second session? TX in advance.

  You have a unique index or primary key (which will automatically index) on the column?

  Oneself up to the entrance in the first insert your index? Since you insert same value in another session, he waits for the lock on index to be released. If the first session agrees, you will get an error (duplicate). If the first session, second session restorations go...

• How do I install sql 2008 and sql 2008 R2 on the same user account in vista

  I am trying to install sql 2008 and sql 2008 r2 on the same user account and get error message that the account cannot be used. How can I install sql 2008 and sql 2008 r2 on the same user account in vista

  Hello

  try to repost/ask in the SQL Server forums

  http://social.msdn.Microsoft.com/forums/en/category/SQLServer/

• FDMEE 11.1.2.4 - how to load the same record source of 2 different custom in HFM members

  Hi Experts,

  We have the following situation:

  We need download a source document unique member 2 custom end balance as well as two rollforward Member custom movement 2 (additions, for example), the SAME account.

  In our GL, we have separate accounts for the additions, disposals, depreciation, etc.   In HFM, we use custom for these last members.

  I tried the multi-dimensions mappoing member card custom 2 individual based on the story.   It works fine, but when I add another condition by using the same account of source and card balance end Member, he only ended up filling a 2 custom members (according to what has been covered last importing).

  What would be the best way to load a single 2 custom members (same account) source document?

  I wanted to use the accounts of logic since I know that would work, but our financial team do not accept this approach.

  It is even possible to load the same record of 2 different HFM Member?  Even if we loaded the file even a second time in another place, I think that it still would replace what took the first time, instead of loading again to another custom on the same member account.  Even if we loaded to HFM on 'merge '?

  Any ideas at all would be appreciated.

  Thank you
  Mark Smith

  Why your financial team will not accept the approach of the accounts of the logic? He is the obvious solution to your problem. FDM or FDMEE, you can only load on the data at the intersection of a target element. If you want to load the same piece of data at several intersections in the target, then you need to have this piece of data repeated in data sources n then you will need something in the source that could identify how unique each copy so you can map correctly. As noted it is one of the main functions of the accounts of the logic, other approaches are likely to be messy, more prone to error and much harder to verify.

• SQL query to display the sum of the values of each June and December

  Hello having problems of construction of a query to the list SQL query to display the sum of the values of each June and December each year.

  My Table;

  TABLE name: MONTH_TERM

  Fields with values:

  TERM_KEY	MONTH_ACTUAL	MONTH_DATE
  82	500	01/11/2015 0:00
  82	450	01/12/2015 0:00
  82	405	01/01/2016 0:00
  82	400	01/02/2016 0:00
  82	450	01/03/2016 0:00
  82	425	01/04/2016 0:00
  82	435	01/05/2016 0:00
  82	410	06/01/2016 0:00
  82	409	01/07/2016 0:00
  82	415	01/08/2016 0:00
  82	420	09/01/2016 0:00
  82	422	10/01/2016 0:00
  82	436	11/01/2016 0:00
  82	556	01/12/2016 0:00
  82	568	01/01/2017 0:00
  82	624	02/01/2017 0:00

  What I would like to see in a query result:

  TERM_KEY	MONTH_ACTUAL	MONTH_DATE	Total of 6 months
  82	500	01/11/2015 0:00
  82	450	01/12/2015 0:00	950
  82	405	01/01/2016 0:00
  82	400	01/02/2016 0:00
  82	450	01/03/2016 0:00
  82	425	01/04/2016 0:00
  82	435	01/05/2016 0:00
  82	410	06/01/2016 0:00	2525
  82	409	01/07/2016 0:00
  82	415	01/08/2016 0:00
  82	420	09/01/2016 0:00
  82	422	10/01/2016 0:00
  82	436	11/01/2016 0:00
  82	556	01/12/2016 0:00	2658
  82	568	01/01/2017 0:00
  82	624	02/01/2017 0:00

  ---

  Here's my query:

  Select

  "TERM_KEY,"

  "MONTH_ACTUAL,"

  to_char(MONTH_DATE,'MM/YYYY') MONTH_DATE,

  DEAL to_char (MONTH_DATE, 'MM')

  WHEN '06' THEN (SELECT SUM (MONTH_ACTUAL)

  OF MONTH_TERM

  WHERE the to_char (MONTH_DATE, 'MM') between 1 and 6

  AND term_key = 82)

  WHEN '12' THEN (SELECT SUM (MONTH_ACTUAL)

  OF MONTH_TERM

  WHERE the to_char (MONTH_DATE, 'MM') between 7 and 12

  AND term_key = 82)

  ELSE null

  END as SIX_MO_CUMM,

  of MONTH_TERM

  where term_key = 82

  It's my results:

  TERM_KEY	MONTH_ACTUAL	MONTH_DATE	Total of 6 months
  82	500	01/11/15 0:00
  82	450	01/12/15 0:00	3608
  82	405	01/01/16 0:00
  82	400	01/02/16 0:00
  82	450	01/03/16 0:00
  82	425	01/04/16 0:00
  82	435	01/05/16 0:00
  82	410	01/06/16 0:00	3717
  82	409	01/07/16 0:00
  82	415	01/08/16 0:00
  82	420	01/09/16 0:00
  82	422	10/01/16 0:00
  82	436	01/11/16 0:00
  82	556	01/12/16 0:00	3608
  82	568	01/01/17 0:00
  82	624	01/02/17 0:00

  Any ideas on how to fix would be great

  Select term_key,

  month_actual,

  month_date,

  case mod (to_char (month_date, 'mm'), 6)

  When 0 then sum (month_actual)

  During)

  term_key partition

  order of month_date

  between the previous month '5' interval and the current line

  )

  end '6 MONTHS in TOTAL'

  from tbl

  order of term_key,

  month_date

  /

  TERM_KEY MONTH_ACTUAL MONTH_DAT 6 MONTHS TOTAL
  ---------- ------------ --------- --------------
  82 500 NOVEMBER 1ST, 15TH
  82 450 1 DECEMBER 15 950
  82 405 1 JANUARY 16
  82 400 1 FEBRUARY 16
  82 450 1ST MARCH 16
  82 425 1ST APRIL 16
  82 435 1 MAY 16
  82 410 2525 1 JUNE 16
  82 409 1 JULY 16
  82 415 1ST AUGUST 16
  82 420 16 - SEP - 01

  TERM_KEY MONTH_ACTUAL MONTH_DAT 6 MONTHS TOTAL
  ---------- ------------ --------- --------------
  82 422 1 OCTOBER 16
  82-436 NOVEMBER 1, 16
  82 556 2658 1 DECEMBER 16
  82 568 1 JANUARY 17
  82 624 1 FEBRUARY 17

  16 selected lines.

  SQL >

  SY.

• How to return values from the record following instead of in the same record in LOV

  Hi all

  I use Forms 10 G.

  I have a block of details. In what in the 3rd column, I have a LOV.

  My requirement is let say I asked for it from the 1st and 2nd column, and it shows 1 record.

  After that if I pressed F9, then it should display the LOV list and, when I select a value any then it will create a new record with the same value of 1st and 2nd column.

  Example: -.

  Agenda	provider	country
  123	ABC	India

  We here in the column 'Country' LOV. Then when I pressed F9 then Lov should be displayed.

  as below.

  List of countries
  India
  U.S..
  Japan

  It works very well so far.

  Now if I select from the USA in the list then it should create a new record with the values of 1st and 2nd column.

  Agenda	provider	country
  123	ABC	India
  123	ABC	Japan

  How can I do this?

  Besically I need, rather than return the value in the same record, he must return to the next with the exsiting values record.

  The algorithm is:

  -use the KEY-LISTVAL about to 'COUNTRIES '.

  -LOV execution using builtin show_lov

  -store the return value Lov any parameter or a local variable in your trigger code ( vL_dummy_Deger varchar2 (100); )

  -Create registration

  -assign value to any new item you want to

  code like this:

  declare

  vLDummy boolean;

  vL_dummy_Deger varchar2 (100);

  Start

  -lov runs lov ruturns value is assigned to all the dummy elements to store Lov, return value. (no need to display)

  "-" DUMMY "point lets store lov, return value.

  vLDummy: = show_lov ('LOV_ULKE');

  --

  vL_dummy_Deger: =: model;

  create_record;

  : new_item: = vL_dummy_Deger;

  end;

• Query to retrieve the level 2 supervisors

  Hi all
  
  I use the following query to retrieve the people which is under the supervision of a given person_id... Is it possible to modify this query (see below) in order to get two levels of employees? something like:
  
  Supervisor 1
  Employee 1
  Employee 2
  Employee 3
  Supervisor 2
  Employee 4
  Employee 5
  Employee 6
  
  The query works if I pass the person_id 1 for example supervisor that I would get used 1 2 and 3. But if I pass an id of the person who, of higher hierarchy, I will just get supervisor 1 supervisor 2... And I need all the people (just two levels down)
  
  Select distinct *)
  Select distinct ppf.first_name |' '|| PPF.last_name
  ppf.last_name
  fu.user_name
  fu.user_id
  ppf.person_id
  papf.person_id Manager
  pi.image_id
  initcap (hla.description) LOCATION
  pb.NAME pay_basis_name
  pax.grade_id
  haou.name
  employment_category
  ppos.date_start
  of per_assignments_x pax
  per_grade_definitions pgd
  per_people_x WP
  fnd_user fu
  per_all_people_f women's wear
  per_images pi
  hr_locations_all hla
  per_pay_bases pb
  hr_all_organization_units haou
  per_periods_of_service OPP
  where ppf.person_id = pax.person_id
  and trunc (sysdate) between papf.effective_start_date and papf.effective_end_date
  and fu.person_party_id = papf.party_id
  and pax.supervisor_id = papf.person_id
  and pi.parent_id (+) = ppf.person_id
  and pi.table_name (+) = "PER_PEOPLE_F".
  and pax.person_id = ppf.person_id
  and hla.location_id (+) = pax.location_id
  AND ppf.current_employee_flag = 'Y '.
  AND pb.pay_basis_id = pax.pay_basis_id
  AND haou.organization_id = pax.organization_id
  AND ppos.person_id = ppf.person_id
  AND pax.grade_id = pgd.grade_definition_id
  AND papf.person_id =: inPersonId
  UNION ALL
  Select ppf.first_name |' '|| PPF.last_name
  ppf.last_name
  fu.user_name
  fu.user_id
  ppf.person_id
  papf.person_id Manager
  pi.image_id
  initcap (hla.description) LOCATION
  pb.NAME pay_basis_name
  pax.grade_id
  haou.name
  employment_category
  ppos.date_start
  of per_people_x WP
  per_grade_definitions pgd
  fnd_user fu
  per_all_people_f women's wear
  HR_WORKING_PERSON_LISTS HWPL
  per_images pi
  per_assignments_x pax
  hr_locations_all hla
  per_pay_bases pb
  hr_all_organization_units haou
  per_periods_of_service OPP
  where
  trunc (sysdate) between papf.effective_start_date and papf.effective_end_date
  and fu.person_party_id = papf.party_id
  AND HWPL.owning_person_id = papf.person_id
  and hwpl.selected_person_id = ppf.person_id
  AND pi.parent_id (+) = ppf.person_id
  and ppf.current_employee_flag = 'Y '.
  and pax.person_id = ppf.person_id
  AND hla.location_id (+) = pax.location_id
  AND pb.pay_basis_id = pax.pay_basis_id
  AND haou.organization_id = pax.organization_id
  AND ppos.person_id = ppf.person_id
  AND pax.grade_id = pgd.grade_definition_id
  AND papf.person_id =: inPersonId
  ) order of last_name

  Hello Alejandro,

  You can play a little bit with one below with what you find most comfortable.

  / * multi level * /.
  Select the level
  assignment_number
  assignment_id
  Manager
  , (select full_name from per_people_x where person_id = pax.person_id)
  , sys_connect_by_path ((sélectionnez employee_number dans per_people_x où person_id = pax.person_id), '-->')
  of per_assignments_x pax
  where primary_flag = 'Y '.
  connect by prior person_id = Manager
  Start by person_id = 1523

  / * level 2 only * /.
  Select (select full_name from per_people_x where person_id = pax1.person_id)
  , (select full_name from per_people_x where person_id = pax2.person_id)
  of per_assignments_x pax1
  per_assignments_x pax2
  where pax1.supervisor_id = 1523
  and pax1.primary_flag = 'Y '.
  and pax1.person_id = pax2.supervisor_id
  and pax2.primary_flag = 'Y '.

• Query to retrieve the latest version

  Hello
  I am trying to create a query that retrieves the latetst of a product version. There are 2 tables I have mark from, we have the product number and we got the version - a varchar2 data type (60). Are versions A, B, c... etc. So, I want to give me a line for each product with its latest version of the application. It's the query I have so far
  
  
  SELECT A0. Prod_num, A0.version
  FROM (SELECT A0B. Prod_num, A0.version
  Of tb_1 A0, tb_2 A0B
  WHERE (A0.tb_1pk = A0B.tb_2pk)) A0
  ranking by A0. Prod_num
  
  Returns duplicate versions and product lines.
  
  Thank you.

  Without seeing sample data...

  SELECT A0B. Prod_num,
  Max (a0.version)
  Of tb_1 A0, tb_2 A0B
  WHERE (A0.tb_1pk = A0B.tb_2pk)
  AO8.prod_num GROUP;

• Query to retrieve the number of transactions in every 1 hour for the end

  Hello
  
  Could someone help to write a query to retrieve the number of transactions in every hour for the last month.
  
  Case:
  I / P
  
  If Timestamp1
  1 01/01/2008 00:00:01
  CAS2 01/01/2008 00:01:01
  case3 01/01/2008 01:00:01
  1 01/01/2008 01:02:01
  case4 01/01/2008 01:10:01
  Service5 01/02/2008 02:00:01
  Case6 01/02/2008 02:10:01
  case7 2008-02-01 23:00:01
  .............................
  
  .............................
  case... 2008-01-31 00:24:00
  
  
  O/P
  cases of to_time of time
  2008-01-01 00:00:00 01/01/2008 01:00 2
  2008-01-01 01:00:01 01/01/2008 02:00 3
  
  .........................
  .........................
  
  etc.
  
  Any help really appreciated

  We can do this by using analytic functions

  Here's what I did:

  create table timestamp1 (date of ts)

  Select * from timestamp1
  2008-10-30 15:41:13
  2008-10-30 15:41:05
  2008-10-30 15:40:03
  2008-10-30 14:58:26
  2008-10-30 14:29:45
  2008-10-30 13:17:48
  2008-10-30 08:29:50
  2008-10-30 06:05:51
  2008-10-30 03:41:52
  2008-10-30 02:29:54

  Select distinct to_char (ts, 'hh24') frmhrs,
  TO_CHAR (ts, 'hh24') + 1 tohrs, count (ts) OVER (order by to_number (to_char (ts, 'hh24')) RANK BEFORE (1/24))
  of timestamp1
  When trunc (ts) = trunc (sysdate) - I added this just to make sure that I get for data of today
  order of frmhrs

  FRMHRS TOHRS CNT
  1-3-02
  03-4-1
  06 7 1
  1-9-08
  13 14 1
  14 15 2
  15 16 3

  You can customizeas by your need.

• SQL Query to retrieve records in a table with the same records or only one record in a table

  Hello

  Got a curious requirment to extract the Non-distincts records in a table

  Example of

  Account number	Type of account
  12345	SB
  12345	SB
  12346	CR
  12346	SB
  12347	SB
  12348	CR
  12349	SB

  Requrirement is to retrieve the records as follows

  Result must be

  Account number	Type of account
  12345	SB
  12345	SB
  12347	SB
  12348	CR
  12349	SB

  You will notice that 12346 which has two separate lines have been eliminated in the result. I tried several qeries to achieve this result, one or the other had a few mismatch. Can someone give me a request for it.

  Thanks in advance.

  SELECT ACCOUNT_NUMBER,

  ACCOUNT_TYPE

  DE)

  SELECT ACCOUNT_NUMBER,

  ACCOUNT_TYPE,

  COUNT (*) ON CNT_ACC (ACCOUNT_NUMBER PARTITION).

  COUNT (*) ON CNT_NUM_TYP (PARTITION ACCOUNT_NUMBER, ACCOUNT_TYPE)

  FROM T1)

  WHERE CNT_ACC = CNT_NUM_TYP;

  exit;

  12345	SB
  12345	SB
  12347	SB
  12348	CR
  12349	SB

• SQL Query to retrieve records for all after the Max Dates.

  Hello everyone,

  I am trying to retrieve the record more recent, based on the date field ( nextDate ).

  Currently, there are only 4 records in the MC_Maintenance table and two in the Machine table.

  Machine table

  MC_id             EquipID          

  1                      0227

  MC_id EquipID

  2                     0228

  ---------------------------------

  MC_Maintenance table

  Maint_id MC_id Next_maint

  1                      2                      08/25/2010     

  2                      2                      07/01/2010

  3                      1                      2010-11-06

  4                      1                      07/11/2010

  I have am trying to accomplish is,.

  the list of the two machines of the table of the Machine with the MAX (Next_maint) control the list of MC_Maintenance results

  These are the records I want to display.

  Maint_id MC_id Next_maint

  1                      2                      08/25/2010

  4                      1                      07/11/2010                 

  Here is the SQL query

  SELECT

         MC. MC_ID as ID,

  MC.complete_Date completed.

  MC.next_maint as nextDate,.

  MC.maint_notes as noted,.

  MC.facility Facility.

  M.EquipId,.

  $m.name as the name.

  M.SerialNumber SN.

  M.dept as dept.

  M.Freq as freq

  Of MC_Maintenance MC, Machine M

          where  MC. MC_ID = M.MC_ID

  '           Using MAX (nextDate)

  Any ideas would be useful.

  TJ

  I thought it was a simple group of problem?

  SELECT M.EquipID, MC.MC_ID, Max(MC.next_maint)
  FROM MC_Maintenance MC INNER JOIN Machine M ON MC.MC_ID = M.MC_ID
  GROUP BY M.EquipID, MC.MC_ID