Query to retrieve the number of transactions in every 1 hour for the end

Similar Questions

• Query to retrieve the latest version

  Hello
  I am trying to create a query that retrieves the latetst of a product version. There are 2 tables I have mark from, we have the product number and we got the version - a varchar2 data type (60). Are versions A, B, c... etc. So, I want to give me a line for each product with its latest version of the application. It's the query I have so far
  
  
  SELECT A0. Prod_num, A0.version
  FROM (SELECT A0B. Prod_num, A0.version
  Of tb_1 A0, tb_2 A0B
  WHERE (A0.tb_1pk = A0B.tb_2pk)) A0
  ranking by A0. Prod_num
  
  Returns duplicate versions and product lines.
  
  Thank you.

  Without seeing sample data...

  SELECT A0B. Prod_num,
  Max (a0.version)
  Of tb_1 A0, tb_2 A0B
  WHERE (A0.tb_1pk = A0B.tb_2pk)
  AO8.prod_num GROUP;

• Query to retrieve the level 2 supervisors

  Hi all
  
  I use the following query to retrieve the people which is under the supervision of a given person_id... Is it possible to modify this query (see below) in order to get two levels of employees? something like:
  
  Supervisor 1
  Employee 1
  Employee 2
  Employee 3
  Supervisor 2
  Employee 4
  Employee 5
  Employee 6
  
  The query works if I pass the person_id 1 for example supervisor that I would get used 1 2 and 3. But if I pass an id of the person who, of higher hierarchy, I will just get supervisor 1 supervisor 2... And I need all the people (just two levels down)
  
  Select distinct *)
  Select distinct ppf.first_name |' '|| PPF.last_name
  ppf.last_name
  fu.user_name
  fu.user_id
  ppf.person_id
  papf.person_id Manager
  pi.image_id
  initcap (hla.description) LOCATION
  pb.NAME pay_basis_name
  pax.grade_id
  haou.name
  employment_category
  ppos.date_start
  of per_assignments_x pax
  per_grade_definitions pgd
  per_people_x WP
  fnd_user fu
  per_all_people_f women's wear
  per_images pi
  hr_locations_all hla
  per_pay_bases pb
  hr_all_organization_units haou
  per_periods_of_service OPP
  where ppf.person_id = pax.person_id
  and trunc (sysdate) between papf.effective_start_date and papf.effective_end_date
  and fu.person_party_id = papf.party_id
  and pax.supervisor_id = papf.person_id
  and pi.parent_id (+) = ppf.person_id
  and pi.table_name (+) = "PER_PEOPLE_F".
  and pax.person_id = ppf.person_id
  and hla.location_id (+) = pax.location_id
  AND ppf.current_employee_flag = 'Y '.
  AND pb.pay_basis_id = pax.pay_basis_id
  AND haou.organization_id = pax.organization_id
  AND ppos.person_id = ppf.person_id
  AND pax.grade_id = pgd.grade_definition_id
  AND papf.person_id =: inPersonId
  UNION ALL
  Select ppf.first_name |' '|| PPF.last_name
  ppf.last_name
  fu.user_name
  fu.user_id
  ppf.person_id
  papf.person_id Manager
  pi.image_id
  initcap (hla.description) LOCATION
  pb.NAME pay_basis_name
  pax.grade_id
  haou.name
  employment_category
  ppos.date_start
  of per_people_x WP
  per_grade_definitions pgd
  fnd_user fu
  per_all_people_f women's wear
  HR_WORKING_PERSON_LISTS HWPL
  per_images pi
  per_assignments_x pax
  hr_locations_all hla
  per_pay_bases pb
  hr_all_organization_units haou
  per_periods_of_service OPP
  where
  trunc (sysdate) between papf.effective_start_date and papf.effective_end_date
  and fu.person_party_id = papf.party_id
  AND HWPL.owning_person_id = papf.person_id
  and hwpl.selected_person_id = ppf.person_id
  AND pi.parent_id (+) = ppf.person_id
  and ppf.current_employee_flag = 'Y '.
  and pax.person_id = ppf.person_id
  AND hla.location_id (+) = pax.location_id
  AND pb.pay_basis_id = pax.pay_basis_id
  AND haou.organization_id = pax.organization_id
  AND ppos.person_id = ppf.person_id
  AND pax.grade_id = pgd.grade_definition_id
  AND papf.person_id =: inPersonId
  ) order of last_name

  Hello Alejandro,

  You can play a little bit with one below with what you find most comfortable.

  / * multi level * /.
  Select the level
  assignment_number
  assignment_id
  Manager
  , (select full_name from per_people_x where person_id = pax.person_id)
  , sys_connect_by_path ((sélectionnez employee_number dans per_people_x où person_id = pax.person_id), '-->')
  of per_assignments_x pax
  where primary_flag = 'Y '.
  connect by prior person_id = Manager
  Start by person_id = 1523

  / * level 2 only * /.
  Select (select full_name from per_people_x where person_id = pax1.person_id)
  , (select full_name from per_people_x where person_id = pax2.person_id)
  of per_assignments_x pax1
  per_assignments_x pax2
  where pax1.supervisor_id = 1523
  and pax1.primary_flag = 'Y '.
  and pax1.person_id = pax2.supervisor_id
  and pax2.primary_flag = 'Y '.

• SQL query to retrieve the same record because no. boxes

  Hi all

  I have a table of Bill XXINV.

  the columns are

  INVH_NO INVH_ITEM_CODE INVH_QTY INVH_BOXES

  1122                XXITEM1                    1                    5

  1123                XXITEM2                     2                   6

  I can do a sql query so that I can retrieve the same records repeated as number INVH_BOXES.

  Select * from XXINV

  where invh_no = 1122

  output:

  INVH_NO INVH_ITEM_CODE INVH_QTY INVH_BOXES

  1122                XXITEM1                    1                    5

  Desired output:

  INVH_NO INVH_ITEM_CODE INVH_QTY INVH_BOXES

  1122                XXITEM1                    1                    5

  1122                XXITEM1                    1                    5

  1122                XXITEM1                    1                    5

  1122                XXITEM1                    1                    5

  1122                XXITEM1                    1                    5

  or

  INVH_NO INVH_ITEM_CODE INVH_QTY INVH_BOXES

  1122 XXITEM1 1 1 of 5

  1122 XXITEM1 1 2 of 5

  1122 1 3 5 XXITEM1

  1122 XXITEM1 1 4 of 5

  1122 XXITEM1 1 5 of 5

  Please suggest. Like I need to print each line in a single page to stick them on boxes so that packaging.

  Kind regards

  Afzal.

  Just add INVH_ITEM_CODE to the connection by the clause.

  Select invh_no

  invh_item_code

  invh_qty

  to_char (, 'fm99') | 'from ' | TO_CHAR (invh_boxes, 'fm99') invh_boxes

  of xxinv

  where invh_no = 1122

  connect

  by level<=>

  and prior invh_item_code = invh_item_code

  and prior sys_guid() is not null

• Query to retrieve the data in a sort of pivot format.

  Hello gurus of PL/SQL,.
  I need to extract the data in a format some tables using the join condition. When I extracted using simple join then it turn around individual records based on condition, but want it in a particular format only.
  
  When run the query-
  
  Select sf. JOIN_DT_KEY, sd. CLS, sd. CLS_STATUS, sf. CLS_QTY, sf. CLS_FEES,
  SF. TOTAL_AMT
  of stud_det_fact sf, sd, cd class_dim stud_tag_dim
  where sf.stud_dim_key = sd.stud_dim_key
  AND sf.alloc_cls_dim_key = d.alloc_cls_dim_key AND sd. CLS_STATUS IN
  ("BA", "BSC", "MA", "MBA", "SMC")
  AND af. JOIN_DT_KEY between 20120404 and 20120410 ORDER BY sd. CLS
  
  That the data is returned in the following format:
  
  JOIN_DT_KEY CC CLS_STATUS CLS_QTY CLS_FEES TOTAL_AMT
  1 20120404 BA 1050000 12 875 WORK
  2 20120404 BA 125 12 150000 CAPITAL
  3 20120404 BA 1050000 12 875 WORK
  4 20120404 BSC 4 10 4000 CAPITAL
  5 20120404 BSC 3 10 3000 CAPITAL
  6 20120404 MY 1050000 12 875 WORK
  7 20120404 MY 1000 12 1200000 WORK
  8 20120404 MBA 1200000 12 1000 ALGO
  9 20120404 MBA 1200000 12 1000 ALGO
  
  But I want to in the format after using query itself.
  
  JOIN_DT_KEY WORK of CLS (Qty) WORK (Amt) CAPITAL (Qty) CAPITAL (Amt) (Qty) ALGO ALGO (Amt) NATURAL (Qty) NATURAL (Amt) GrandTotal (Qty) GrandTotal (Amt)
  20120404 1750 2100000 125 150000 0 0 0 0 1875 2250000 BA
  0 0 7 7000 BSC 0 0 0
  0 7 7000
  MY 1875 2250000 0 0 0 0 0
  0 1875 2250000
  0 0 0 0 2000 2400000 MBA 0
  2400000 2000 0
  3625 total 4350000 132 157000 2000 2400000 0
  0 6907000 of 5757
  
  How to change the query to get the hinge of the sort of result, kindly help me. I appreciate all your help in advance.
  
  Thank you and I really apperciate your help.
  
  Note:-attached, this is the example of excel sheet.
  
  Published by: user555994 on April 26, 2012 03:43

  I suggest that to take advantage of the Oracle version you have.

  To start, I took your first message and created a few sample data. This is not your original tables, but it allows us to compare the results.

  drop table T;
  create table T(JOIN_DT_KEY, CLS, STATUS, QTY, FEES, AMT) as select
  TO_DATE('20120404', 'YYYYMMDD'), 'BA', 'WORKING', 875, 12, 1050000 from dual union all select
  TO_DATE('20120404', 'YYYYMMDD'), 'BA', 'CAPITAL', 125, 12, 150000 from DUAL union all select
  TO_DATE('20120404', 'YYYYMMDD'), 'BA', 'WORKING', 875, 12, 1050000 from dual union all select
  TO_DATE('20120404', 'YYYYMMDD'), 'BSC', 'CAPITAL', 4, 10, 4000 from DUAL union all select
  TO_DATE('20120404', 'YYYYMMDD'), 'BSC', 'CAPITAL', 3, 10, 3000 from dual union all select
  TO_DATE('20120404', 'YYYYMMDD'), 'MA', 'WORKING', 875, 12, 1050000 from DUAL union all select
  TO_DATE('20120404', 'YYYYMMDD'), 'MA', 'WORKING', 1000, 12, 1200000 from DUAL union all select
  TO_DATE('20120404', 'YYYYMMDD'), 'MBA', 'ALGO', 1000, 12, 1200000 from DUAL union all select
  TO_DATE('20120404', 'YYYYMMDD'), 'MBA', 'ALGO', 1000, 12, 1200000 from DUAL;
  

  To test the following against your data, is taken your SELECT in the right place or create a view and plug the display where I have the table "T".

  Now, here's how to get everything except the last line "Total":

  select *
  from (
    select JOIN_DT_KEY, CLS, STATUS, QTY, AMT from t
  )
  PIVOT(SUM(QTY) QTY, SUM(AMT) AMT
  for STATUS in('ALGO' as ALGO,'CAPITAL' as CAPITAL,'DMA' as DMA,'NATURAL' as natural,'WORKING' as WORKING));
  
  JOIN_DT_KEY        CLS ALGO_QTY ALGO_AMT CAPITAL_QTY CAPITAL_AMT DMA_QTY DMA_AMT NATURAL_QTY NATURAL_AMT WORKING_QTY WORKING_AMT
  ------------------ --- -------- -------- ----------- ----------- ------- ------- ----------- ----------- ----------- -----------
  2012/04/04 00:00   BSC                             7        7000
  2012/04/04 00:00   BA                            125      150000                                                1750     2100000
  2012/04/04 00:00   MBA     2000  2400000
  2012/04/04 00:00   MA                                                                                           1875     2250000
  

  To get the latest "Total" line, you need to do another GROUP after the pivot.

  select JOIN_DT_KEY, nvl(CLS, 'Total') cls,
  SUM(ALGO_QTY) ALGO_QTY,
  SUM(ALGO_AMT) ALGO_AMT,
  SUM(CAPITAL_QTY) CAPITAL_QTY,
  SUM(CAPITAL_AMT) CAPITAL_AMT,
  SUM(DMA_QTY) DMA_QTY,
  SUM(DMA_AMT) DMA_AMT,
  SUM(NATURAL_QTY) NATURAL_QTY,
  SUM(NATURAL_AMT) NATURAL_AMT,
  SUM(WORKING_QTY) WORKING_QTY,
  SUM(working_AMT) working_AMT
  from (
    select JOIN_DT_KEY, CLS, STATUS, QTY, AMT from t
  )
  PIVOT(SUM(QTY) QTY, SUM(AMT) AMT
  for STATUS in('ALGO' as ALGO,'CAPITAL' as CAPITAL,'DMA' as DMA,'NATURAL' as natural,'WORKING' as WORKING))
  group by grouping sets((join_dt_key, cls), join_dt_key);
  
  JOIN_DT_KEY        CLS   ALGO_QTY ALGO_AMT CAPITAL_QTY CAPITAL_AMT DMA_QTY DMA_AMT NATURAL_QTY NATURAL_AMT WORKING_QTY WORKING_AMT
  ------------------ ----- -------- -------- ----------- ----------- ------- ------- ----------- ----------- ----------- -----------
  2012/04/04 00:00   BA                              125      150000                                                1750     2100000
  2012/04/04 00:00   MA                                                                                             1875     2250000
  2012/04/04 00:00   BSC                               7        7000
  2012/04/04 00:00   MBA       2000  2400000
  2012/04/04 00:00   Total     2000  2400000         132      157000                                                3625     4350000
  

  Using "grouping sets", you group by join_dt_key and cls (which the PIVOT is already done, but you have to do it again) and then by join_dt_key to get the total line.

  Note: I suppose you want a total by date. If you want just a total general for all dates, then Group Rollup (join_dt_key, cls)).

  I hope it's accurate and useful.

• Query to retrieve the data according to requirement

  Hi team,

  I have the table with the details below and my requirement is when I entered the correct empid then only need to display recording (it's easy) and when I entered the empid that is not listed in the table, then I need to display all the records available in this table. Please give me the query.

  EmpID ename

  7839	KING
  7698	BLAKE
  7782	CLARK
  7566	JONES
  7788	SCOTT
  7902	FORD
  7369	SMITH

  Kind regards

  Anil

  can you please mark it as answered@user575819

• Query to retrieve the average growth rate

  Hi all
  
  10.2.0.5 on solaris
  
  Table script:
  
  DB_SPACE_HIST
  (
  DATE TIME STAMP,
  TOTAL_SPACE NUMBER (8).
  USED_SPACE NUMBER (8).
  FREE_SPACE NUMBER (8).
  PCT_INUSE NUMBER (5.2).
  NUM_DB_FILES NUMBER (5)
  );
  
  Sample data:
  
  
  Timestamp: / 16/2010 12:57:52 AM
  Totak space: 678017
  Used space: 235612
  Free space: 442405
  PCT in use: 34.75
  number of files: 60
  
  
  We have the timestamp stored in the table for more than 3 years. The requirement is that we get the average growth in the database per month.
  
  No idea how I can do this?
  
  Kai

  Start by getting your data used_space by month:

  select
  trunc(timestamp,'MM') mth,
  max(used_space) used_space_end_mth
  from db_space_hist
  group by
  trunc(timestamp,'MM');
  

  Then you can use the analytic function LAG to get used_space_end_mth compared to the month previous for calculating growth:

  select
  mth,
  used_space_end_mth - lag(used_space_end_mth) over (order by mth) growth
  from (
     select
     trunc(timestamp,'MM') mth,
     max(used_space) used_space_end_mth
     from db_space_hist
     group by
     trunc(timestamp,'MM')
  )
  order by
  mth;
  

  And finally, you can simply select the average growth:

  select
  avg(growth) avg_growth
  from (
     select
     mth,
     used_space_end_mth - lag(used_space_end_mth) over (order by mth) growth
     from (
        select
        trunc(timestamp,'MM') mth,
        max(used_space) used_space_end_mth
        from db_space_hist
        group by
        trunc(timestamp,'MM')
     )
  );
  

• Need of a query to retrieve the data

  Hello
  
  I have a table named person. It has two fields A_ID and B_ID. The table does not have a primary key
  The data in the table are the following
  
  A_ID B_ID_ _
  
  1 5
  1 10
  2 5
  2 10
  4 15
  5 20
  
  I need to select A_ID and B_ID data so that when you select a given allocation A_ID or B_ID is not for more choices
  
  For Eg: I select the first pair of 1 and 5. Then 1 and 5 is not in the selection of data from A_ID or B_ID
  
  The output of the query for the data in the table above should be
  
  Output
  
  A_ID B_ID_ _
  
  1 5
  2 10
  4 15
  
  Hope you understand the situation.
  Can someone help me to create a query for me
  
  Thanks in advance
  
  Published by: user599079 on August 12, 2009 21:40

  This done:

  Nope:

  SQL>  with t as (
   select 1 a_id, 5 b_id from dual union all
   select 1, 10 from dual union all
   select 2, 5 from dual union all
   select 2, 10 from dual union all
   select 4, 15 from dual union all
   select 5, 6 from dual union all
   select 6, 9 from dual
  ),
  union_data  as
  (
      select    a_id    as id
      ,    'A'    as col
      ,    row_number () over (order by a_id, b_id)    as r_num
      from   t
  union all
      select    b_id    as id
      ,    'B'    as col
      ,    row_number () over (order by a_id, b_id)    as r_num
      from    t
  )
  ,    grouped_data    as
  (
      select      id
      ,      min (col) keep (dense_rank first order by r_num)    as first_col
      ,      min (r_num)                                     as first_r_num
      ,      row_number () over ( partition by min (col) keep (dense_rank first order by r_num)
                                order by        min (r_num)
                       )                    as out_num
      from      union_data
      group by  id
  )
  select      a.id    as a_id
  ,      b.id    as b_id
  from      grouped_data    a
  join      grouped_data    b    on    a.out_num    = b.out_num
  where      a.first_col    = 'A'
  and      b.first_col    = 'B'
  order by  a.out_num
  /
        A_ID       B_ID
  ---------- ----------
           1          5
           2         10
           4         15
  
  3 rows selected.
  

  I expect him back at the last row too much (like my request).
  In addition to change line 5 - 6 5-25 mess up completely:

        A_ID       B_ID
  ---------- ----------
           1          5
           2         10
           4         15
           6         25
  

• query to retrieve the second highest salary managers

  Select * from employee where salary = (select max (salary) in e employees where employee_id = e.manager_id and salary < (select max (salary) in employees))
  /
  
  It does not run... can someone suggest a new

  987184 wrote:
  our teacher was asked to write without y analytical function.dats.

  1 list of Manager IDs:

  select  manager_id
    from  hr.employees
    where manager_id is not null
  /
  

  2 manager info:

  select  employee_id,
          first_name,
          last_name,
          salary
    from  hr.employees
    where employee_id in (
                          select  manager_id
                            from  hr.employees
                            where manager_id is not null
                         )
  /
  

  3. Manager second highest salary

  with managers as (
                    select  employee_id,
                            first_name,
                            last_name,
                            salary
                      from  hr.employees
                      where employee_id in (
                                            select  manager_id
                                              from  hr.employees
                                              where manager_id is not null
                                           )
                   )
  select  m1.employee_id,
          m1.first_name,
          m1.last_name,
          max(m1.salary) second_highest_salary
    from  managers m1,
          managers m2
    where m1.salary < m2.salary
    group by m1.employee_id,
             m1.first_name,
             m1.last_name
    having count(distinct m2.salary) = 1
  /
  

  And execution:

  SQL> select  employee_id,
    2          first_name,
    3          last_name,
    4          salary
    5    from  hr.employees
    6    where employee_id in (
    7                          select  manager_id
    8                            from  hr.employees
    9                            where manager_id is not null
   10                         )
   11    order by salary desc
   12  /
  
  EMPLOYEE_ID FIRST_NAME           LAST_NAME                     SALARY
  ----------- -------------------- ------------------------- ----------
          100 Steven               King                           24000
          102 Lex                  De Haan                        17000
          101 Neena                Kochhar                        17000
          145 John                 Russell                        14000
          146 Karen                Partners                       13500
          201 Michael              Hartstein                      13000
          108 Nancy                Greenberg                      12008
          205 Shelley              Higgins                        12008
          147 Alberto              Errazuriz                      12000
          114 Den                  Raphaely                       11000
          148 Gerald               Cambrault                      11000
  
  EMPLOYEE_ID FIRST_NAME           LAST_NAME                     SALARY
  ----------- -------------------- ------------------------- ----------
          149 Eleni                Zlotkey                        10500
          103 Alexander            Hunold                          9000
          121 Adam                 Fripp                           8200
          120 Matthew              Weiss                           8000
          122 Payam                Kaufling                        7900
          123 Shanta               Vollman                         6500
          124 Kevin                Mourgos                         5800
  
  18 rows selected.
  
  SQL> with managers as (
    2                    select  employee_id,
    3                            first_name,
    4                            last_name,
    5                            salary
    6                      from  hr.employees
    7                      where employee_id in (
    8                                            select  manager_id
    9                                              from  hr.employees
   10                                              where manager_id is not null
   11                                           )
   12                   )
   13  select  m1.employee_id,
   14          m1.first_name,
   15          m1.last_name,
   16          max(m1.salary) second_highest_salary
   17    from  managers m1,
   18          managers m2
   19    where m1.salary < m2.salary
   20    group by m1.employee_id,
   21             m1.first_name,
   22             m1.last_name
   23    having count(distinct m2.salary) = 1
   24  /
  
  EMPLOYEE_ID FIRST_NAME           LAST_NAME                 SECOND_HIGHEST_SALARY
  ----------- -------------------- ------------------------- ---------------------
          101 Neena                Kochhar                                   17000
          102 Lex                  De Haan                                   17000
  
  SQL> 
  

  As you can see, most high salary 24000 is won by the King. Second highest salary is 17000 and is won by two managers: Kochhar and De Haan.

  SY.

• Cannot retrieve the data by binary storage by default for XML 11 g

  Oracle 11.2
  
  All,
  
  As someone mentioned in another post, I got I should use binary XMLType CLOB rather than 11g because it is more efficient. When I create the XMLType column as binary I can't retrieve the value of the column, but when I use CLOB I am able to extract data on.
  
  -Create table with XMLTYPE column.  Since it is 11.2 storage of the column is automatically binary
  CREATE THE TABLE HR. XMLTABLESTORE (key_id VARCHAR2 (10) PRIMARY KEY, xmlloaddate date, xml_column XMLTYPE);
  
  -Insert the XML into the XML column
  INSERT INTO HUMAN RESOURCES. VALUES XMLTABLESTORE (HR. XMLSEQUENCE. NEXTVAL, SYSDATE, XMLType (bfilename ('XMLDIRX', 'PROD_20110725_211550427_220b.xml'),
  nls_charset_id ('AL32UTF8'))); COMMIT;
  
  -When I do a select I see full XML in the xml_column column
  SELECT * FROM HR. XMLTABLESTORE
  
  -When I run the following query I get the following:
  SELECT extract (xml_column, ' / / MapItem/@ProductNum') ProductNum OF HR. XMLTABLESTORE
  
  ProductNum
  -------------
  XMLType
  
  -When I run the following query on the @, I get the following:
  SELECT extract (xml_column, ' / / MapItem/ProductNum ') ProductNum OF HR. XMLTABLESTORE
  
  ProductNum
  -------------
  Null value
  
  When I run the same SELECT query retrieves (xml_column, ' / / MapItem/@ProductNum') ProductNum OF HR. XMLTABLESTORE and the table is created by CLOB, I get out the expected value of the XML file.
  
  How can I get the query to retrieve the data through a binary file?
  
  I appreciate any help in advance.
  
  Thank you
  Shawn
  
  Published by: 886184 on Sep 20, 2011 15:42

  Probably a problem with your client tool.

  It works for me:

  SQL*Plus: Release 11.2.0.2.0 Beta on Mer. Sept. 21 19:39:55 2011
  
  Copyright (c) 1982, 2010, Oracle.  All rights reserved.
  
  Connected to:
  Oracle Database 11g Express Edition Release 11.2.0.2.0 - Beta
  
  SQL> CREATE TABLE xmltablestore (
    2    key_id VARCHAR2(10) PRIMARY KEY
    3  , xmlloaddate DATE
    4  , xml_column XMLTYPE
    5  );
  
  Table created.
  
  SQL> INSERT INTO xmltablestore
    2  VALUES ('1', sysdate, XMLType(bfilename('TEST_DIR', 'PROD_20110725_211550427_220b.xml'),nls_charset_id('AL32UTF8')))
    3  ;
  
  1 row created.
  
  SQL> commit;
  
  Commit complete.
  
  SQL> SELECT extract(xml_column, '//MapItem/@ProductNum') ProductNum
    2  FROM xmltablestore
    3  ;
  
  PRODUCTNUM
  --------------------------------------------------------------------------------
  63481062975
  
  SQL> SELECT extractValue(xml_column, '//MapItem/@ProductNum') ProductNum
    2  FROM xmltablestore
    3  ;
  
  PRODUCTNUM
  --------------------------------------------------------------------------------
  63481062975
  
  SQL> SELECT xmlcast(
    2          xmlquery('/Entries/Category/MapItem/@ProductNum'
    3           passing t.xml_column
    4           returning content
    5          )
    6          as number
    7         ) ProductNum
    8  FROM xmltablestore t
    9  ;
  
  PRODUCTNUM
  ----------
  6,3481E+10
  
  SQL> SELECT xmlcast(
    2          xmlquery('/Entries/Category/MapItem/@ProductNum'
    3           passing t.xml_column
    4           returning content
    5          )
    6          as varchar2(30)
    7         ) ProductNum
    8  FROM xmltablestore t
    9  ;
  
  PRODUCTNUM
  ------------------------------
  63481062975
  

  BTW, extract and extractvalue functions are deprecated in version 11.2.
  Oracle now recommends using XMLCast/XMLQuery.

• SQL query to represent the data in the graph bar

  Hello

  JDev 11.1.1.5.0

  We must create a dashboard to track the translation. We have created the ADF table with buttons 'Create', 'Update' and 'Delete' to manipulate the table.

  Our DB table structure is

  File_id (PK), File_Name, ToSpanish - ARE (YES/NO), beginning of the ToSpanish, ToChina(YES/No), ToChina-Date... etc.

  Once the translated file required language then user must update the DB table using the button "Update".

  So far, we have implemented the requirement above.

  We need represent the status of the translation in the graph bar with the language as X access and file count get access Ex: Spanish-100 China - 200 files files

  Please suggest the sql query to retrieve the necessary info from the DB table that can be represented in the graph bar. Also, it would be great, if you can provide a pointers to create a bar chart.

  Thanks in advance,

  MSR.

  If you set your major increment and minor than 1, then you won't not show decimal points.  You can try setting these 10 or 100 to reach your goal.

  Subtype = "BAR_VERT_CLUST" >

               

• Need to retrieve the records whose salary is higher than the max of avg salar

  I wrote a query to retrieve the data whose salary exceeds the maximum salary of the avg of all departments
  

  SELECT * FROM EMP WHERE SAL>
  (SELECT MAX(AVG (SAL)) FROM EMP
  GROUP BY DEPTNO)

  I would like to write that this query using the associates.
  
  I tried
  

  SELECT EMPNO,ENAME,SAL FROM EMP E1
  WHERE SAL > ANY( SELECT MAX(AVG(SAL)) FROM EMP E2
  WHERE E1.DEPTNO  = E2.DEPTNO)

  It gives me error that we cannot use a function nested in the collateral.
  
  What is the solution of the present?
  
  Thnks

  This?

  select * from emp a
  where exists
  (select 1 from emp b
  where a.deptno=b.deptno
  and a.sal>(select round(max(avg(sal))) from emp group by deptno));
  

• Error when retrieving the value of the pair name / value

  Hi gentlemen,
  
  I am facing a problem while retrieving the value of the pair name / value in the incoming XML file. I am using an Xpath query to retrieve the value but Jdeveloper gives me
  an invalid expression error.
  
  Please find below the new xml and xquery.
  
  < ebo:QueryItemListEBM xmlns:ebo = "http://xmlns.oracle.com/EnterpriseObjects/Core/EBO/Item/V2" >
  < ebo:DataArea xmlns:aia = "http://www.oracle.com/XSL/Transform/java/oracle.apps.aia.core.xpath.AIAFunctions" xmlns:coreitem = "http://xmlns.oracle.com/EnterpriseObjects/Core/EBO/Item/V2" >
  < ebo:Query >
  < ebo:QueryCode > QUERY_ITEMS < / ebo:QueryCode >
  < corecom:QueryCriteria xmlns:corecom = "http://xmlns.oracle.com/EnterpriseObjects/Core/Common/V2" >
  < corecom:QueryExpression >
  < corecom:ValueExpression >
  < corecom:ElementPath > ItemEBO/Item/InventoryLocation/BusinessComponentID < / corecom:ElementPath >
  < corecom: Value > 82 < / corecom: Value >
  < / corecom:ValueExpression >
  < corecom:ValueExpression >
  < corecom:ElementPath > ItemEBO/Item/ItemIdentification/ContextID@OPERATING_UNIT_ID < / corecom:ElementPath >
  < corecom: Value / >
  < / corecom:ValueExpression >
  < corecom:ValueExpression >
  < corecom:ElementPath > ItemEBO/Identification/BusinessComponentID < / corecom:ElementPath >
  < corecom: Value > ba55de86-d8b4-4db1-b599-5aef8424ac3b < / corecom: Value >
  < / corecom:ValueExpression >
  < corecom:ValueExpression >
  < corecom:ElementPath > ItemEBO/Item/ItemIdentification/ContextID@STRUCTURE_NAME < / corecom:ElementPath >
  < corecom: Value > PIM_PBOM_S < / corecom: Value >
  < / corecom:ValueExpression >
  < corecom:ValueExpression >
  < corecom:ElementPath > ItemEBO/Identification/review < / corecom:ElementPath >
  < corecom: Value > 208281 < / corecom: Value >
  < / corecom:ValueExpression >
  < / corecom:QueryExpression >
  < / corecom:QueryCriteria >
  < / ebo:Query >
  < / ebo:DataArea >
  < / ebo:QueryItemListEBM >
  
  I need to retrieve the value 'ba55de86-d8b4-4db1-b599-5aef8424ac3b' on top of xml and xpath expression that I used is:
  
  bpws:.
  
  Please help with your valuable contributions.
  
  Thank you and best regards,
  Vikas marzouk

  829347 wrote:
  Hi Vlad,

  It works quite well. A big thank you to you.

  see you soon,
  Vikas

  Hi Vikas, could you marking my answer as correct then?

  Thank you
  Vlad

• Determine the end of the month and then run the script

  Hi all

  OK, I'm stumped. I can get all kinds of data to date... but I did not find a way (or the same example script) that shows how to retrieve the end of the month.

  
  Why?

  
  I have a master script that runs as a scheduled task. It runs every day and call other scripts based on the date. It is great for things like weekly reports that I just used $dow = {get-date}. DayofWeek but I need to run scripts at the end of the month.

  I can something together that gets the day, and then performs a logical ugly pop-based < or > but I don't know there's a smoother way to do.

  As always, any help greatly appreciated.

  See you soon

  Hello, medalklector-

  One way to do it, it is described by RMToups, Jr. at http://activelydirect.blogspot.com/2011/01/determine-last-day-of-month-in.html.  You should be able to set the output to fit your needs.  How does do for you?

• SQL query to retrieve a single record for each employee of the following table?

  Hi all

  Help me on the writing of SQL query to retrieve a single record for each employee of the following table? preferably a standard SQL.

  CREATE TABLE xxc_contact)

  empnum NUMBER,

  alternatecontact VARCHAR2 (100),

  relationship VARCHAR2 (10),

  phtype VARCHAR2 (10),

  Phone NUMBER

  );

  insert into xxc_contact values (123456, 'Rick Grimes', 'SP', 'Cell', 9999999999)

  insert into xxc_contact values (123456, 'Rick Grimes', 'SP', 'Work', 8888888888)

  insert into xxc_contact values (123457, 'Daryl Dixon', 'EN', 'Work', 7777777777)

  insert into xxc_contact values (123457, 'Daryl Dixon', 'EN', 'Home', 3333333333)

  insert into xxc_contact values (123456, 'Maggie Greene', 'CH', 'Cell', 9999999999)

  insert into xxc_contact values (123456, 'Maggie Greene', 'CH', 'Home', 9999999999)

  expected result:

  EmpNum AlternateContact Relationship PhType Phone       

  123456 rick Grimes SP cell 9999999999

  Daryl Dixon EN work 7777777777 123457

  Home 123458 Maggie Greene CH 6666666666

  Thanks in advance.

  994122 wrote:

  Thank you all, that I got a result

  http://www.orafaq.com/Forum/m/620305/#msg_620305

  By Lalit Kumar B...

  Specifically, the two simple solutions provided were:

  1 using the row_number, entitled Oracle ranking based on descending order of the inside telephone each empnum group. And finally selects the lines which has least rank (of least since that order is descending for phone).

  SQL > column alternatecontact format A20;

  SQL >

  SQL > SELECT empnum, alternatecontact, relationship, phtype, phone

  2 from (SELECT a.*, row_number() over r (PARTITION BY empnum ORDER BY phone / / DESC))

  3 FROM xxc_contact one)

  4. WHEN r = 1

  /

  EMPNUM ALTERNATECONTACT RELATIONSHIP PHTYPE PHONE

  ---------- -------------------- ---------- ---------- ----------

  123456 rick Grimes SP cell 9999999999

  Daryl Dixon EN work 7777777777 123457

  Home 123458 Maggie Greene CH 6666666666

  2. with the help of MAX, Oracle automatically assigns the maximum phone for all the rows in each group of empnum. And finally selects the rows with the maximum phone. Order by clause is omitted here intentionally. You can find out why.

  SQL > SELECT empnum, alternatecontact, relationship, phtype, phone

  2 (SELECT a.*, MAX (phone) over (PARTITION BY empnum) rn FROM xxc_contact one)

  3 WHERE phone = rn

  4.

  EMPNUM ALTERNATECONTACT RELATIONSHIP PHTYPE PHONE

  ---------- -------------------- ---------- ---------- ----------

  123456 rick Grimes SP cell 9999999999

  Daryl Dixon EN work 7777777777 123457

  Home 123458 Maggie Greene CH 6666666666

  Kind regards

  Lalit