SQL question: horizontally to group by

Similar Questions

• Is there a limitation of length of sql in a record group?

  Record group contains 4 by union funcion sql statement. When this sql statement longer than 4000 characters then the record group do not allow me to add an additional column to another.

  My question is, is there a limitation of length of sql that record the group support?

  Developer 10g suit.

  Thanks in advance.

  As you have discovered that there is a limit in the form designer, on what size the SQL statement may be in the property Query Group Record in your record group.  Unfortunately, the forms for the Query Group property help topic Record does not that there is a limit or the limit.

  If your request does not fit into the Group Record Query property, you can try to use the integrated Create_Group_From_Query() to fill in your group.  Another option would be to create views in your database, and then select the view in the Query property group Record.

  If you opt to try the method of Create_Group_From_Query(), just set your Group Record in the navigation of the object by using a SELECT statement (your column names) twice and then programmatically remove the Group and re-create it with the high - Create_Group_From_Query ().  See the help topic for the function integrated for a code example.

  Craig...

• the basic sql question

  Hi all I have a basic sql question
  Watch below two querries
  

  1.  select 1 from dual where 1 in (select 1 from dual union all select null from dual) 
  
  It gives output  as 1
  
  but below one 
  
  2.   select 1 from dual where 1 not in  (select 2 from dual union all select null from dual)
  
  It gives output as no data found 

  I think as operator will not compare with all the values, but not the outcome it will compare with all values... When comparing with the value null, the result is automatically null
  
  I'm wrong
  Please help me on this
  
  and why performance wise in operator is more better than no of?
  
  Thanks to all in advance

  Thanks for posting your explain plan command

  Execution Plan
  ----------------------------------------------------------
  Plan hash value: 3249215828
  
  -----------------------------------------------------------------------------
  | Id  | Operation        | Name     | Rows  | Bytes | Cost (%CPU)| Time     |
  -----------------------------------------------------------------------------
  |   0 | SELECT STATEMENT |          |     2 |     6 |     4   (0)| 00:00:01 |
  |   1 |  NESTED LOOPS    |          |     2 |     6 |     4   (0)| 00:00:01 |
  |   2 |   FAST DUAL      |          |     1 |       |     2   (0)| 00:00:01 |
  |   3 |   VIEW           | VW_NSO_1 |     2 |     6 |     2   (0)| 00:00:01 |
  |   4 |    SORT UNIQUE   |          |     2 |       |     2   (0)| 00:00:01 |
  |   5 |     UNION-ALL    |          |       |       |            |          |
  |   6 |      FAST DUAL   |          |     1 |       |     2   (0)| 00:00:01 |
  |*  7 |      FILTER      |          |       |       |            |          |
  |   8 |       FAST DUAL  |          |     1 |       |     2   (0)| 00:00:01 |
  -----------------------------------------------------------------------------
  
  Predicate Information (identified by operation id):
  ---------------------------------------------------
  
     7 - filter(NULL IS NOT NULL)
  
  02:12:54 SQL> select 1 from dual where 1 not in  (select 2 from dual union all select null from dual);
  Elapsed: 00:00:00.01
  
  Execution Plan
  ----------------------------------------------------------
  Plan hash value: 3291682568
  
  -----------------------------------------------------------------
  | Id  | Operation        | Name | Rows  | Cost (%CPU)| Time     |
  -----------------------------------------------------------------
  |   0 | SELECT STATEMENT |      |     1 |     4   (0)| 00:00:01 |
  |*  1 |  FILTER          |      |       |            |          |
  |   2 |   FAST DUAL      |      |     1 |     2   (0)| 00:00:01 |
  |   3 |   UNION-ALL      |      |       |            |          |
  |*  4 |    FILTER        |      |       |            |          |
  |   5 |     FAST DUAL    |      |     1 |     2   (0)| 00:00:01 |
  |   6 |    FAST DUAL     |      |     1 |     2   (0)| 00:00:01 |
  -----------------------------------------------------------------
  

• Apex SQL question - weeks of the month

  I have a sql question.
  I want to create a dynamic list.
  
  If the user select may2009, then I want a dynamic list of show
  
  04/27/2009-05/03/2009
  05/04/2009-05/10/2009
  05/11/2009-05/17/2009
  05/18/2009-05/24/2009
  05/25/2009-05/31/2009
  
  If the user selects Jun 2009, then the list will be
  06/01/2009-06/07/2009
  06/08/2009-06/14/2009
  06/15/2009-06/21/2009
  06/22/2009-06/28/2009
  06/29/2009-07/05/2009
  
  Thank you.

  Using this SQL statement, you can get this list:

  SELECT w_start || ' - ' || w_end d, w_start r
    FROM (SELECT     (week_start_list + (LEVEL - 1) * 7) + 1 w_start,
                     week_start_list + (LEVEL) * 7 w_end
                FROM (SELECT TO_CHAR (TRUNC (TO_DATE (:my_date, 'dd.mm.yyyy'),
                                             'mm'
                                            ),
                                      'IW'
                                     ) week_begin,
                             TRUNC (TO_DATE (:my_date, 'dd.mm.yyyy'),
                                    'mm'
                                   ) m_begin,
                             TO_CHAR
                                (TRUNC (TO_DATE (:my_date, 'dd.mm.yyyy'), 'mm'),
                                 'd'
                                ) day_month_begin,
                             TO_CHAR
                                (TRUNC (ADD_MONTHS (TO_DATE (:my_date,
                                                             'dd.mm.yyyy'
                                                            ),
                                                    1
                                                   ),
                                        'mm'
                                       ),
                                 'IW'
                                ) week_end,
                             TRUNC (ADD_MONTHS (TO_DATE (:my_date, 'dd.mm.yyyy'),
                                                1
                                               ),
                                    'mm'
                                   ) m_end,
                             TO_CHAR
                                (TRUNC (ADD_MONTHS (TO_DATE (:my_date,
                                                             'dd.mm.yyyy'
                                                            ),
                                                    1
                                                   ),
                                        'mm'
                                       ),
                                 'd'
                                ) day_month_end,
                               TRUNC (TO_DATE (:my_date, 'dd.mm.yyyy'),
                                      'mm'
                                     )
                             - TO_NUMBER
                                        (TO_CHAR (TRUNC (TO_DATE (:my_date,
                                                                  'dd.mm.yyyy'
                                                                 ),
                                                         'mm'
                                                        ),
                                                  'd'
                                                 )
                                        ) week_start_list,
                               TRUNC
                                  (ADD_MONTHS (TO_DATE (:my_date, 'dd.mm.yyyy'),
                                               1
                                              ),
                                   'mm'
                                  )
                             + TO_NUMBER
                                  (TO_CHAR
                                      (TRUNC
                                            (ADD_MONTHS (TO_DATE (:my_date,
                                                                  'dd.mm.yyyy'
                                                                 ),
                                                         1
                                                        ),
                                             'mm'
                                            ),
                                       'd'
                                      )
                                  )
                             - 1 week_end_list
                        FROM DUAL)
          CONNECT BY LEVEL <=
                        (SELECT   TO_NUMBER
                                     (TO_CHAR
                                         (TRUNC
                                             (ADD_MONTHS (TO_DATE (:my_date,
                                                                   'dd.mm.yyyy'
                                                                  ),
                                                          1
                                                         ),
                                              'mm'
                                             ),
                                          'IW'
                                         )
                                     )
                                - TO_NUMBER
                                        (TO_CHAR (TRUNC (TO_DATE (:my_date,
                                                                  'dd.mm.yyyy'
                                                                 ),
                                                         'mm'
                                                        ),
                                                  'IW'
                                                 )
                                        )
                           FROM DUAL))
  

  It is a question of SQL and has nothing to do with the Apex.

  Denes Kubicek
  -------------------------------------------------------------------
  http://deneskubicek.blogspot.com/
  http://www.Opal-consulting.de/training
  http://Apex.Oracle.com/pls/OTN/f?p=31517:1
  -------------------------------------------------------------------

• SQL help, how to group in column A and then get a higher frequency in column B?

  Assuming that the following table, operation represents each type of operation of transaction
  Employee table operation another column c
  ' < ' id1
  ' < ' id1
  ' < ' id2
  ' *' id3
  id1 ' / '.
  
  question, for each operation, which employee do the most? which employee do the 2nd most?
  I thought I need to group by operation first, then get the frequency of the employee and get top 1, or at the top of page 2 of higher frequency.
  But I'm struct and don't know how to write sql code.

  998408 wrote:
  Assuming that the following table, operation represents each type of operation of transaction
  Employee table operation another column c
  '<'>
  '<'>
  '<'>
  ' *' id3
  id1 ' / '.

  question, for each operation, which employee do the most? which employee do the 2nd most?
  I thought I need to group by operation first, then get the frequency of the employee and get top 1, or at the top of page 2 of higher frequency.
  But I'm struct and don't know how to write sql code.

  Welcome to OTN. OPS! Posted in the wrong forum. Just after in {forum: id = 75}. Before posting it close this thread as answered marking.

  If someone answer is useful or appropriate, please mark accordingly. *

• SQL question to get a top customer of the page

  Hi all
  I'm prasanna. I have a question about SQL, to get a customer based on name of the year and the customer. I wrote the request like this. But I got an error.
  
  Select calendar_year, cust_first_name, max (sum (amount_sold)) in sale, the time the customers where sales.cust_id = customers.cust_id and times.time_id = sales.time_id of the calendar_year group, cust_first_name
  
  The error is like this:
  
  * Error from the 1 in the command line:
  Select calendar_year, cust_first_name, max (sum (amount_sold)) in sale, the time the customers where sales.cust_id = customers.cust_id and times.time_id = sales.time_id of the calendar_year group, cust_first_name
  Error in the command line: 1 column: 7
  Error report:
  SQL error: ORA-00937: not a function of simple-group
  00937 00000 - 'not a single-group function. "
  * Cause:
  Action:
  
  Thank you inadvace
  Kind regards
  Prasanna

  865016 wrote:
  Your response, I had only one top customer with year, name of the client, amount_sold. But I need for each year

  select  calendar_year,
          cust_first_name,
          total_amount_sold max_amount_sold
    from  (
           select  calendar_year,
                   cust_first_name,
                   sum(amount_sold) total_amount_sold,
                   row_number() over(partition by calendar_year order by sum(amount_sold) desc) rn
             from  sales,
                   times,
                   customers
             where sales.cust_id=customers.cust_id
               and times.time_id=sales.time_id
             group by calendar_year,
                   cust_first_name
          )
    where rn = 1
  / 
  

  I will give you a single customer by calendar_year.

  SY.

• Quick dash in Horizontal Alignment group

  Hello Experts,
  
  I have 4 dashboard which are grouped (for a single GO button) invite you... I want all 4 to be aligned horizontally by default it is pronistique.., I can't separate them because users want to have simple click for all 4.
  
  I couldn't find all the options to make them Horizontal.
  
  Is there a way to do this...?
  
  Thank you
  Kiran

  HI Kiran,
  Instead of creating individual guest & add in the dashboard page to create a single prompt for all 4 columns and drag in the dashboard page you will get the prompt horizontally.let know me if any questions...

• A few questions about resource groups

  Oracle documentation says that the creation of Simple Plan of resources automatically adds SYS_GROUP to level 1 of the plan and the OTHER_GROUPS at level 3.
  
  I checked SYS_GROUP and it seems that the SYSTEM is only the default member. What about SYS or SYSMAN or other dba (user) accounts? If a connect as SYS or with my own dba account to do administrative tasks will be to be considered a member of the SYS_GROUP or should I add "admin" users manually including DBSNMP SYS, SYSMAN, and so on...?
  
  Second question. Documentation also indicates that there is, at level 3, OTHER_GROUPS catch-all group. I looked at integrated groups of servers by default and there is no OTHER_GROUPS there! Only four.
  -AUTO_TASK_CONSUMER_GROUP
  -DEFAULT_CONSUMER_GROUP
  -LOW_GROUP
  -SYS GROUP
  
  Where's my OTHER_GROUPS?
  
  Oracle 10.2.0.4, Linux x 86.

  mishomor wrote:
  Oracle documentation says that the creation of Simple Plan of resources automatically adds SYS_GROUP to level 1 of the plan and the OTHER_GROUPS at level 3.

  I checked SYS_GROUP and it seems that the SYSTEM is only the default member. What about SYS or SYSMAN or other dba (user) accounts? If a connect as SYS or with my own dba account to do administrative tasks will be to be considered a member of the SYS_GROUP or should I add "admin" users manually including DBSNMP SYS, SYSMAN, and so on...?

  Although the system is added to the group member, Sys sessions would be a part of it. I'm not sure, but I can't seem to find the note where his indeedmentioned the Sys and System would use it.

  Second question. Documentation also indicates that there is, at level 3, OTHER_GROUPS catch-all group. I looked at integrated groups of servers by default and there is no OTHER_GROUPS there! Only four.
  -AUTO_TASK_CONSUMER_GROUP
  -DEFAULT_CONSUMER_GROUP
  -LOW_GROUP
  -SYS GROUP

  Where's my OTHER_GROUPS?

  Not sure where you looked, but I could find right away in my 11201 running on Win Xp professional.

  SQL> l
    1* select consumer_group from  dba_rsrc_consumer_groups
  SQL> /
  
  CONSUMER_GROUP
  ------------------------------
  DSS_GROUP
  DSS_CRITICAL_GROUP
  AUTO_TASK_CONSUMER_GROUP
  ORA$AUTOTASK_URGENT_GROUP
  BATCH_GROUP
  ORA$DIAGNOSTICS
  ORA$AUTOTASK_HEALTH_GROUP
  ORA$AUTOTASK_SQL_GROUP
  ORA$AUTOTASK_SPACE_GROUP
  ORA$AUTOTASK_STATS_GROUP
  ORA$AUTOTASK_MEDIUM_GROUP
  INTERACTIVE_GROUP
  OTHER_GROUPS                        <<<<<<<<<<<<<<<<<<<<<<<<<<
  DEFAULT_CONSUMER_GROUP
  SYS_GROUP
  LOW_GROUP
  ORA$APPQOS_0
  ORA$APPQOS_1
  ORA$APPQOS_2
  ORA$APPQOS_3
  ORA$APPQOS_4
  ORA$APPQOS_5
  ORA$APPQOS_6
  ORA$APPQOS_7
  ETL_GROUP
  
  25 rows selected.
  
  SQL> select * from V$version;
  
  BANNER
  -------------------------------------------------------------------------------
  Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - Production
  PL/SQL Release 11.2.0.1.0 - Production
  CORE    11.2.0.1.0      Production
  TNS for 32-bit Windows: Version 11.2.0.1.0 - Production
  NLSRTL Version 11.2.0.1.0 - Production
  
  SQL>
  

  HTH
  Aman...

• PL/SQL question (which is wrong)?

  Hello
  I read a book that has of the following statement
  
  -------------------
  
  DECLARE
  type instructor_info is MADE
  (name, instructor.first_name%type,
  instructor.last_name%type last_name,
  number of sections);
  rv_instructor instructor_info;
  BEGIN
  Select rtrim (i.first_name),
  RTrim (i.last_name),
  Count (*)
  the instructor,.
  s section
  in rv_instructor -.first_name, rv_instructor.last_name, rv_intructor.sections
  where i.instructor_id = s.instructor_id
  and i.instructor_id = 102
  I.first_name group, i.last_name;
  dbms_output.put_line (' instructor ' | rv_instructor.first_name |') '|| rv_instructor.last_name |', teaches ' | rv_instructor.sections | 'section (s)');
  
  exception
  When no_data_found then
  dbms_output.put_line ('there no such instructor');
  
  END;
  
  -----------------
  
  And the writer asks:
  
  Explain what is declared in the previous example. Describe what happens to the record and explain how this translates into the output.
  I look at the answers, and he says, that by operating, this example produces the following output:
  Instructor Tom Wojick, teaches 9 item (s).
  
  My question is that when I execute this example, he produced me the following error.
  
  
  ORA-06550: line13, Column2:
  PL/SQL: ORA-00933: SQL not correctly completed command
  ORA-06550: framework8, Column2
  PL/SQL: SQL statement ignored.
  
  
  I tried the following:
  
  Rv_instructor instructor_info % rowtype;
  
  Or
  
  In rv_instructor.first_name, rv_instructor.last_name, rv_intructor.sections
  
  
  But the same error.
  
  What's wrong?
  
  Thank you very much.

  INTO clause would come before FROM clause.

  Pass by ' this doc once...

  http://download.Oracle.com/docs/CD/B19306_01/AppDev.102/b14261/selectinto_statement.htm#LNPLS01345

  Kind regards
  Prazy

• SQL question on natural joins

  I am a newbie to SQL and I studied the book of Fundamentals SQL Server Oracle OCA 12 c, but a section on natural joins to confuse me.

  Basically, the author says:

  SELECT r.region_name, d.department_name, l.city, c.country_name

  DEPARTMENTS d

  NATURAL JOIN places l, c countries, regions r;

  The natural join between DEPARTMENTS and LOCATIONS creates a provisional result, consisting of 27 lines since they are implicitly attached on the column of location_id. This set is then Cartesian-joined to the table of the COUNTRY as a join condition is not implicitly or explicitly specified. 27 interim lines are attached to 25 lines in the COUNTRY table, which gives a new temp results set with 675 (27 × 25) rows and three columns: DEPARTMENT_NAME, CITY and COUNTRY_NAME. This set is then attached to the REGION table. Once more, a Cartesian join occurs because column REGION_ID is absent from any join condition. The final result set contains rows and four columns (675 × 4) 2700.

  I can understand because you evaluate joins from the left. But then he wrote:

  The JOIN... USE and JOIN... ON the syntaxes are better suited to join multiple tables. The following query joins four tables using the natural join syntax:

  SELECT country_id region_id, c.country_name, l.city, d.department_name

  DEPARTMENTS d

  NATURAL JOIN places l

  NATURAL JOIN country c

  NATURAL JOIN region r;

  This query generates correctly 27 lines in the final results set since the required join columns are listed in the SELECT clause. The following query illustrates how the JOIN... CLAUSE is used to extract the same 27 lines. A join condition can reference columns only in its scope. In the following example, the join of DEPARTMENTS slots can not reference columns in the COUNTRIES or REGIONS of tables, but the join between the COUNTRIES and REGIONS may refer to any column of four tables involved in the query.

  This second method of the part of the natural writing joined confuses me. I don't understand the logic behind the 2nd series of States of Natural Join. For me, it seems that the first series and the 2nd set look alike, but they are apparently not.

  Can someone tell me the differences?

  Thank you!!

  Hello

  The more important thing to learn more about NATURAL JOIN is: never use it.  If you add new columns, joins can get different results.  I've never heard of someone uisng NATURAL JOIN apart from a manual or a question like yours.

  There are a lot of things in Oracle that take the time to learn and are useful.  All the time you spend learning things is better spent on them.

• Need to call the PL/SQL Package in the group dynamics of approval class that implements IDynamicApprovalGroup

  Hi all

  This is regarding the approval of invoice AP I need in my project where the user selects the users/people approval when creating the invoice based on logic. There may be any number of users who could be part of the approval group.

  Approval users information is stored in a table with a single Bill.

  When the user initiates invoice approval, approval of the Bill should go to all the people/users selected in the invoice.

  I created the dynamic of approval group which is the result of a java class. This java class implements IDynamicApprovalGroup. (what is the oracle Developer Guide).

  I called PL/SQL to java class package to get all the details of users of custom for the current invoice table.

  I used the DriverManager.getConnection method by hard coding (JDBC URL, Username, Pwd) connection details that works perfectly fine.

  But I don't want to hard-code the connection details because it will change in bodies SIT/UAT/PROD.

  Please ask you to guide me if there is no solution for the information of connection without hard coding it.

  Following code used to get the connection details

  try {}

  Class.forName ("oracle.jdbc.driver.OracleDriver");

  System.out.println ("= class loaded");

  }

  catch (ClassNotFoundException ex) {}

  System.out.println ("= class loading error");

  ex.printStackTrace ();

  }

  Fitting out = null;

  CallableStatement cstmt = null;

  Try

  {

  connection = DriverManager.getConnection ("jdbc:oracle:thin:@xxhostname:1521/SID", "FUSION", "*");

  Connection = GetConnection ();

  System.out.println ("= connection =" + connection);

  prepare the call

  cstmt = connection.prepareCall ("{call XX_AP_INV_DYN_APPROVAL_PKG. {GET_GROUP_PARTICIPANTS (?,?)} ») ;

  cstmt.setString (1, '12345');   ID on invoice

  Exit of the register

  cstmt.registerOutParameter (2, java.sql.Types.VARCHAR);

  Call the stored procedure

  cstmt. Execute();

  System.out.println ("= procedure being executed");

  approvalGroupMembers = cstmt.getString (2).split("#");

  System.out.println ("= output:" + cstmt.getString (2));

  }

  catch (Exception ex) {}

  ex.printStackTrace ();

  }

  Finally

  {

  Try

  {

  If (cstmt! = null)

  close the callable statement

  {

  cstmt. Close();

  cstmt = null;

  }

  System.out.println ("= stmt closed");

  }

  catch (SQLException ex)

  {

  System.out.println ("= stmt close err");

  ex.printStackTrace ();

  }

  Try

  {

  If (connection! = null)

  close the connection

  {

  Connection.Close;

  connection = null;

  }

  System.out.println ("= closed conn");

  }

  catch (SQLException ex)

  {

  System.out.println ("= Close conn err");

  ex.printStackTrace ();

  }

  }

  Thank you

  Dipak.

  HI Dembélé - you should be able to call the provider database from the java class. Documentation is here. However, you need to specify the name of the data provider that is the same in all environments. Do you know what it is? If it's not I'll take a look and get back to you.

  __

  Peter Maurer

  Relationship with the developers of Applications in fusion

  https://blogs.Oracle.com/fadevrel/

• SQL * PLUS connects with SQL &gt; question

  People,

  I'm confused on the command. / sqlplus with Oracle database.

  According to my understanding,. / sqlplus connected with SQL > using option 3: sysdba, sysoper, sysasm.

  I connect with SQL > to run the rel853.sql script to create a table PSOPRDEFN but a field "OPERPSWDSALT" did not appear in the table PSOPRDEFN although it is in the Create Table statement.

  I connect with SQL * in the directory/home/user/OracleDB_Home/bin as below:

  
  $ export SYSTEM_PASS = AccessId/mypass

  $ export ORACLE_HOME = / home/user/OracleDB_Home

  $ export ORACLE_SID = HRCS90

  $. / lsnrctl start LISTENER

  $. / AccessId/mypass sqlplus as sysdba

  SQL > startup

  SQL > @/opt/PT8.53/scripts/rel853.sql

  SQL > select OPERPSWDSALT in the AccessId.PSOPRDEFN;

  It returns: "OPERPSWDSALT": invalid identifier.

  
  I checked the table PSOPRDEFN that the OPERPSWDSALT field did not appear in the table PSOPRDEFN.

  I tried the sysoper option as below:

  $. / sqlplus AccessId/mypass as sysoper

  SQL > startup

  SQL > @/opt/PT8.53/scripts/rel853.sql

  SQL > select OPERPSWDSALT in the AccessId.PSOPRDEFN;

  It returns: "OPERPSWDSALT": invalid identifier.

  The sysoper error is the same thing with sysdba error.

  I tried the sysasm option as below:

  $. / sqlplus AccessId/mypass as sysasm

  He returned: connection refused.

  
  Someone told me this connection as SYS causes this error. If not a sysdba, sysoper, or sysasm, use the command. / sqlplus AccessId/mypass cannot connect with SQL >.

  
  My question is:

  
  First of all, why is what OPERPSWDSALT did not appear in the PSOPRDEFN table while it is in the CREATE TABLE statement?

  
  Seocond, if not use SYS which is one of the 3 options, how to run the command. / sqlplus AccessId/mypass to connect with SQL > so that CREATE TABLE PSOPRDEFN correctly?

  Thank you.
  

  user8860348 wrote:

  People,

  Hello. Thanks much for the reply. I just do the commands below:

  $ export SYSTEM_PASS = AccessId/mypass

  $ export ORACLE_HOME = / home/user/OracleDB_Home

  $ export ORACLE_SID = HRCS90

  $. / lsnrctl start LISTENER

  $. / AccessId/mypass sqlplus as sysdba

  SQL > show user;

  Its release: the USER is "SYS".

  SQL > connect AccessId/mypass

  Its output:

  Error: ORA - 01034:ORACLE not available

  ORA-27101: shared memory realm does not exist

  64 - Linux_x86 error: no such file or directory.

  As we see above, unable to connect to the Oracle database AccessId.

  My question is:

  What to do on AccessId, so that it can connect to the Oracle database?

  Thank you.

  so much for the use that you refuse to actually use COPY it PASTE & so that we can see the whole session.

  In the past, you did

  > SQL > startup

  Maybe the database is out of order & must be started.

  do exactly as below (line by line)

  ID

  sqlplus

  / as sysdba

  startup

  connect AccessId/mypass

  COPY the results from above then PASTE all back here

• Oracle PL SQL Question to get some data to oracle tables descrepancy

  Version of database
  
  Oracle9i Enterprise Edition Release 9.2.0.8.0 - 64 bit Production
  PL/SQL Release 9.2.0.8.0 - Production
  CORE Production 9.2.0.8.0
  AMT for HP - UX: 9.2.0.8.0 - Production Version
  NLSRTL Version 9.2.0.8.0 - Production
  
  created a few sample data
  
  drop table tab1 purge;
  create table tab1 (DEPT_ID COMP, qc_subtype_id char (4), EQUIP_CODE varchar2 (20), create_time date);
  Insert into tab1 values(13,'1026','HEMORYA011',sysdate);
  Insert into tab1 values(13,'1012','HEMORYA011',sysdate);
  Insert into tab1 values(95,'1026','HEMORYA121',sysdate);
  Insert into tab1 values(95,'1012','HEMORYA121',sysdate);
  ----------------------
  Insert into tab1 values(13,'1026','HEMORYA014',sysdate);
  Insert into tab1 values(13,'1012','HEMORYA005',sysdate);
  Insert into tab1 values(13,'1012','HEMORYA013',sysdate);
  Insert into tab1 values(95,'1012','HEMORYA013',sysdate);
  Insert into tab1 values(95,'1012','HEMORYA148',sysdate);
  
  commit;
  
  I need to get a query to get the records of the gap
  
  Dept HEMORYA014 13 lack 1012
  
  HEMORYA005 dept 12 lack 1026
  
  Dept HEMORYA013 13 lack 1026
  
  The dept 95 lack 1026 HEMORYA013
  
  The dept 95 lack 1026 HEMORYA148
  
  I want to show the latter on the report
  
  Thanks in advance.

  Thanks for posting a unit test.
  I hope it will work for you, but maybe you will need to set the WHERE clause (add additional predicates).

  SQL> select equip_code
    2  from ( select equip_code
    3         ,      count(distinct qc_subtype_id)
    4         from   tab1
    5         group by equip_code
    6         having count(distinct qc_subtype_id)<2
    7        )
    8  order by equip_code;
  
  EQUIP_CODE
  --------------------
  HEMORYA005
  HEMORYA013
  HEMORYA014
  HEMORYA148
  

• running of SQL question

  Hi expert,
  
  
  When I ran after SQL, error message reads "table or view does not exist" pointing to the table "dba_tab_cols" and "dba_all_tables". There is no other question for this statement, because if I changed table "user_tab_cols" and "user_all_tables", it works well.
  
  
  declare
  v_old_table DBA_tab_columns.table_name%type;
  v_where Varchar2 (4000);
  Boolean v_first_col: = true;
  type rc is ref cursor;
  c rc;
  v_rowid varchar2 (20);
  Val varchar2 (50): = "Test note";
  
  Start
  for r in)
  Select
  t.*
  Of
  dba_tab_cols t, dba_all_tables a
  where t.table_name = a.table_name
  and t.data_type like '% CHAR % '.
  and a.owner = 'QA'
  order by t.table_name loop)
  
  If v_old_table is null then
  v_old_table: = r.table_name;
  end if;
  
  If v_old_table <>r.table_name then
  v_first_col: = true;
  
  -dbms_output.put_line ('search' | v_old_table);
  
  Open c for ' select rowid from ' ' |. ' v_old_table | '" ' || v_where;
  
  extract the c in v_rowid;
  loop
  When the output c % notfound;
  dbms_output.put_line (' rowid: ' | v_rowid |) "in" | v_old_table);
  extract the c in v_rowid;
  end loop;
  
  v_old_table: = r.table_name;
  end if;
  
  If v_first_col then
  v_where: = 'where ' | r.column_name | "as" %' | Val | '%''';
  v_first_col: = false;
  on the other
  v_where: = v_where | "or" | r.column_name | "as" %' | Val | '%''';
  end if;
  
  end loop;
  end;
  
  
  But if I choose these DBA tables in the toad sql Editor, it works well, I am currently using my own credentials, not the administrator credentials. why he get different effects running in these two ways?
  
  Thank you very much

  >

  Hello

  When I ran after SQL, error message reads "table or view does not exist" pointing to
  Table 'dba_tab_cols' and 'dba_all_tables '. There is no other question for this statement, because

  If I changed table "user_tab_cols" and "user_all_tables", it works well.
  But if I choose these DBA tables in the toad sql Editor, it works well, I am currently using my own
  credentials, not the administrator credentials. why he get different effects running in these two ways?

  You answered your own question - you know that you have the administrator privileges when you
  Open a session under your own credentials - but your id user obviously does TOAD.

  You use SQL * for the query that fails?

  BTW, you do not give us your version of Oracle - you must always tell us what it is

  Please read the forum FAQ and also the thread "sticky" by BluShadow at the top of the list of positions
  on the forum homepage. These forums are an excellent resource - you will get the best out of them if
  you follow the instructions.

  HTH,

  Paul...

  Published by: Paulie July 24, 2012 16:40

• SQL question for a beginner...

  I have the following structure:
  
  NUMBER OF PROCESSING_ITEM_ID
  NUMBER OF PROJECT_ITEM_FK
  START_TIME DATE
  END_TIME DATE
  NUMBER OF WORKSTATION_FK
  
  examples of data
  
  81,23,10-27-2010 08:00, 27/10/2010 10:00, 3
  42,1,10-27-2010 08:00, 27/10/2010 11:00, 1
  22,23,10-27-2010 13:00, 27/10/2010 17:00, 2
  1,23,10-27-2010 15:00, 27/10/2010 16:00, 1
  23,23,10-27-2010 17:00, 27/10/2010 20:00, 2
  
  I'm trying to divide the data into lines of an hour. If this line we would be divided into:
  
  81,23,10-27-2010 08:00, 27/10/2010 09:00, 3
  81,23,10-27-2010 09:00, 27/10/2010 10:00, 3
  
  third row would be divided into:
  
  22,23,10-27-2010 13:00, 27/10/2010 14:00, 2
  22,23,10-27-2010 14:00, 27/10/2010 15:00, 2
  22,23,10-27-2010 15:00, 27/10/2010 16:00, 2
  22,23,10-27-2010 16:00, 27/10/2010 17:00, 2
  
  The statement that is made should display the data in this way...
  
  John Brewer
  City of Seattle

  Question delicate John, you should ask this in the SQL forums

  This is the query

  with temp AS
       (
        SELECT 81 PROCESSING_ITEM_ID,23 PROJECT_ITEM_FK,TO_DATE('10-27-2010 08:00','MM-DD-YYYY HH24:MI') start_date,TO_DATE('10-27-2010 10:00','MM-DD-YYYY HH24:MI') end_date,3 WORKSTATION_FK from dual
        UNION ALL
        SELECT 22 PROCESSING_ITEM_ID,23 PROJECT_ITEM_FK,TO_DATE('10-27-2010 13:00','MM-DD-YYYY HH24:MI') start_date,TO_DATE('10-27-2010 17:00','MM-DD-YYYY HH24:MI') end_date,2 WORKSTATION_FK from dual
        )
      ,time_span AS
      (
       SELECT MAX( TO_NUMBER(TO_CHAR(end_date,'HH24')) - TO_NUMBER(TO_CHAR(start_date,'HH24')) ) TIME_SPAN
       FROM temp
      )
      ,time_period_rows AS
     (
      SELECT level-1 PERIOD FROM time_span connect by level <= TIME_SPAN
     )
  SELECT T.PROCESSING_ITEM_ID,T.PROJECT_ITEM_FK,TO_CHAR(T.start_date+TR.PERIOD/24,'MM-DD-YYYY HH24:MI') start_time,TO_CHAR(T.start_date+(TR.PERIOD+1)/24,'MM-DD-YYYY HH24:MI') end_time ,T.WORKSTATION_FK
  FROM  temp T
       ,time_period_rows TR
  WHERE PERIOD <= TO_NUMBER(TO_CHAR(end_date,'HH24')) - TO_NUMBER(TO_CHAR(start_date,'HH24'))
  ORDER BY T.PROCESSING_ITEM_ID,TR.PERIOD
  

  Output

  PROCESSING_ITEM_ID     PROJECT_ITEM_FK     START_TIME     END_TIME     WORKSTATION_FK
  22     23     10-27-2010 13:00     10-27-2010 14:00     2
  22     23     10-27-2010 14:00     10-27-2010 15:00     2
  22     23     10-27-2010 15:00     10-27-2010 16:00     2
  22     23     10-27-2010 16:00     10-27-2010 17:00     2
  81     23     10-27-2010 08:00     10-27-2010 09:00     3
  81     23     10-27-2010 09:00     10-27-2010 10:00     3
  81     23     10-27-2010 10:00     10-27-2010 11:00     3
  

  I used a view inline as data source ( temp ), you can change this to your table, name (then remove the display online)