Sum of the two columns

Similar Questions

• calculate the sum of the two columns - display the result in the third column

  Hello
  
  I have a report and I want to calculate the sum of the two columns of the report and display the total in the third column.
  
  For example: Sample_My_Report
  
  Col1 Col2 (Col1 and Col2) Total
  
  3-7-10
  
  
  can someone help me with this question.
  
  Thank you.

  Hello:

  If your report is an IR you can use the menu "Tool" to add columns calculated at the State

  CITY

• Combine the two columns of text

  I have two columns of text (say that name is a column and the name is the other)

  I would like to combine the two columns for the text of these two columns are in a column. (First name and last name in the same column)

  Is this possible? If so is there a tutorial somewhere?

  Hi Danielle,

  The & (concatenation operator) is your friend.

  

  Formula in D2 (fill down)

  "B2 &" "& C2.

  & joins elements into a single string.

  "" inserts a space.

  Kind regards

  Ian.

• using outer joins if the two column is null? Use only (+)

  Hi all

  create the table xxc_tr_num (tl_number number, tr_no number tl_no_id);

  insert into xxc_tr_num values (123,100,222);

  insert into xxc_tr_num values (124,100,333);

  create the table xxc_od_tab (tl_number number, tl_id number);

  insert into xxc_od_tab values (123,001);

  insert into xxc_od_tab values (null, null);

  create table xxc_oth_tab (name varchar2 (10), number of tl_id);

  insert into xxc_oth_tab values('abc',,001);

  insert into xxc_oth_tab values (null, null);

  Wait it out put

  tr_no tl_no_id name

  100 222 abc

  100 333

  using outer joins if the two column is null? use only please of outer joins

  And I tried to use outer joins on both tl_id column but not get values and I use have County (tr_no ) > 1

  Rajesh123 wrote:

  Thank you Kiss it is not possible to use having clause?

  You need to understand the functioning of the group. If you will not be asked this question.

  Check this box

  SQL> select tr_no,
    2         tl_no_id,
    3         count(*)
    4    from xxc_tr_num a,
    5         xxc_od_tab b,
    6         xxc_oth_tab c
    7   where a.tl_number = b.tl_number(+)
    8     and b.tl_id = c.tl_id(+)
    9   group
   10      by tr_no
   11       , tl_no_id;
  
       TR_NO   TL_NO_ID   COUNT(*)
  ---------- ---------- ----------
         100        333          1
         100        222          1
  

  See what returns the count? You have grouped according to TR_NO and TL_NO_ID. You must take into consideration the TL_NO_ID just put COUNT (TR_NO) does not increase the NUMBER of the whole group. To get the NUMBER on the whole group, I used the analytical function and did. Like this, see the number of the analytical function here

  SQL> select tr_no,
    2         tl_no_id,
    3         count(*),
    4         count(*) over(partition by tr_no)
    5    from xxc_tr_num a,
    6         xxc_od_tab b,
    7         xxc_oth_tab c
    8   where a.tl_number = b.tl_number(+)
    9     and b.tl_id = c.tl_id(+)
   10   group
   11      by tr_no
   12       , tl_no_id;
  
       TR_NO   TL_NO_ID   COUNT(*) COUNT(*)OVER(PARTITIONBYTR_NO)
  ---------- ---------- ---------- ------------------------------
         100        222          1                              2
         100        333          1                              2
  

  So to answer your question, yes you can't do in the HAVING clause...

• find the cumulative sum of the previous columns

  Hello
  
  How can I get the cumulative sum of a particular column in the preceding lines in the current line.
  e.g. I have a table produced,
  
  Date | Orders
  __________________
  1 JANUARY 10 | 3
  JANUARY 2, 10. 5
  JANUARY 3, 10. 1
  
  I want to select the date and orders between the 1st and the 3rd. Something like...
  Select the Date, the orders for products where Date between to_date('1-JAN-10') and to_date('3-JAN-10')
  
  But I want the output like this...
  
  Date | Orders
  __________________
  1 JANUARY 10 | 0
  JANUARY 2, 10. 3
  JANUARY 3, 10. 8
  
  Similarly, when I select it between 2 and 3, I want the output voltage...
  
  Date | Orders
  _________________
  JANUARY 2, 10. 3
  JANUARY 3, 10. 8
  
  and so on. In the output, orders here are the cumulative sum of the previous columns.
  
  Published by: eric clapton, November 8, 2010 20:45

  Hello

  Use the analytical SUM function.
  You want to filter by date after the cumulative SUM is calculated, so calculate the SUM in a subquery, then filter by date no later than:

  WITH     got_cm_orders     AS
  (
       SELECT     dt
       ,     orders
       ,     SUM (orders) OVER (ORDER BY dt) - orders
                 AS cm_orders
       FROM     products
  )
  SELECT     dt
  ,     orders
  WHERE     dt     BETWEEN     DATE '2010-01-02'
            AND     DATE '2010-01-03'
  ;
  

• Comparing the sum of the two tables and correct by difference of amount in its second t

  Hello guys,.
  
  I have a very difficult task that I can't get my head around.
  The sample data looks like this:
  
  Master table
  Request - booking - debit - credit - MasterAmout
  1------------1----------------D---------------------------------15.3
  1------------2----------------D---------------------------------480.6
  1------------3------------------------------C-------------------496.8
  ------------------------------------------- 0.9
  
  
  The slave table
  Demande---reservation---debit---credit---slaveamout---slavecorrection
  1------------1------------D------------------------------------15.3---------------14.5
  1------------2------------D------------------------------------480.6-------------480.6
  1------------3-----------------------------C-------------------496---------------496
  -------------------------------------------0.1--------------------------------------0.9
  
  
  The reservation have a total amount of 0.1, but must be corrected to 0.9 because the main table has 0.9.
  
  Reservation 1 requires a correction so the slave table also has a total of 0.9 (business rule is, only corrections on the first booking). So we have
  to change the amount of 15.3 to 14.5. I plan my SQL like this:
  
  1 reservations sum of two tables for each claim. Compare the two for each individual claim.
  2. If Captain sum the amount shows a difference between master / slave
  2.1 select top 1 table reservation slave for the specific claim and increase/decrease by the difference of these two amounts.
  
  Who is?

  Hello

  Use MERGE to actually do the UPDATE.
  The ROW_NUMBER analytic function to identify the first booking in slave (unless you can count on which the reservation = 1).

  MERGE INTO     slave     dst
  USING     (
       WITH     master_summary     AS
       (
            SELECT       claim
            ,       SUM ( master_ampount * CASE
                                     WHEN  debit  = 'D'  THEN -1
                                     WHEN  credit = 'C'  THEN  1
                                 END
                       )     AS balance
            FROM       master
            GROUP BY  claim
       )
       SELECT     s.claim
       ,     s.booking
       ,     SUM ( s.slave_amount * CASE
                              WHEN  s.debit  = 'D'  THEN -1
                              WHEN  s.credit = 'C'  THEN  1
                             END
                ) OVER (PARTITION BY  claim) - m.balance     AS diff
       ,     ROW_NUMBER () OVER ( PARTITION BY  claim
                           ORDER BY        booking
                         )     AS r_num
       FROM     master_summary     m
       JOIN     slave          s  ON     m.claim     = s.claim
       )          src
  ON     (     src.claim     = dst.claim
       AND     src.r_num     = 1
       )
  WHEN MATCHED THEN UPDATE
  SET     dst.debit      = CASE
                      WHEN src.diff      <  0 THEN 'D'
                                     ELSE NULL
                   END
  ,     dst.credit      = CASE
                      WHEN src.diff      <  0 THEN NULL
                                     ELSE 'C'
                   END
  ,     dst.slaveamount = ABS (src.diff)
  ;
  

  If you would care to CREATE TABLE and INSERT statements for the sample data (showing the two tables, as they exist before the DML) then I could test this.

  The design of history seems very uncomfortable. Instead of the debit and credit columns, it would be much simpler to have positive and negative amounts. Is it really worth now both not corrected and corrected the amounts in the table on the slave, especially if you keep only versions corrected debit and credit columns?

• How to read the two columns of data in a file of PDM.

  Hi all

  I am reading two data columns for the 2nd of a PDM file two sheets, as shown below.

  

  Two columns of data must then be shared so they can be displayed in a xy chart and also apply a linear adjustment VI. I implemented the graph xy and linear adjustment using a txt file (see below), therefore all the outputs work, however this application with a tdms file turns a little more tax.

  

  

  

  So, essentially, that I don't know how read the correct leaf and therefore the columns in the PDM file and then how to produce the graph xy and linear adjustment of the data types produce. Here's my current attempt, which produces several errors of the type of terminal, as well as not being able to select the exact data in the PDM.

  

  Any help/suggestions/example vi on this asap would be greatly appreciated.

  Thanks in advance,

  Pete

  Also the PDM file viewer. VI helps you easily understand the structure of data files.

• How to read the two columns of data from the Port series

  Hello

  I'm reading two columns of data from the serial port.

  Example:

  52439 52430

  52440 52437

  52209 52214

  51065 51070

  52206 52390

  I use the serial of Visa service and I can read the first column of data from the serial port, but I can't understand how to read the second column.

  I want to both sets of chart data.

  I enclose my VI.

  Thank you for your help.

  The analysis of string function takes a "Format string" on top (with the right button of the function and choose Help, which explains all the entries).  In particular, you can say 'Give me two numbers separated by a tab' and the output will be two numbers (whole or floating, depending on the chosen format).  In particular, %d\t%d specifies a decimal integer, , whole decimal.

• Combine the two columns of the table

  SELECT providerid, Sum OF appdev.usercounts
  WHERE the counttime BETWEEN SYSDATE - 30/1440 AND SYSDATE-15/1440 GROUP BY ORDER BY providerid providerid
  
  697 W
  U 813
  T 143
  S 2
  
  SELECT providerid, Sum OF appdev.usercounts
  WHERE the counttime BETWEEN - 30/1440 AND (SYSDATE-1) - 15/1440 (SYSDATE-1) GROUP BY ORDER BY providerid providerid;
  
  450 W
  U 571
  T 80
  S 2
  
  I want output like
  
  W 697 450
  U 813 571
  143 80 T
  2 2 S
  Help, please
  
  Thank you
  Praveen

  'COUNT', which is the actual column name? It could become very confusing.

  Not tested for obvious reasons, but it should be close:

  SELECT providerid
       , sum(
           case when counttime between sysdate - 30/1440 and sysdate - 15/1440 then count end
         ) as cnt1
       , sum(
           case when counttime between (sysdate-1) - 30/1440 and (sysdate-1) - 15/1440 then count end
         ) as cnt2
  FROM appdev.usercounts
  WHERE ( counttime between sysdate - 30/1440 and sysdate - 15/1440 )
     OR ( counttime between (sysdate-1) - 30/1440 and (sysdate-1) - 15/1440 )
  GROUP BY providerid
  ORDER BY providerid
  ;
  

• Help the release of the two column list

  Hello
  I have two columns from two different tables. How can I write a query to list the information in a column of result?
  
  I have

   TABLE A              TABLE B
  _Column A_          _Column B_
      a                    d
      b                    e                 
      c                    f

  What I want is

  RESULT_COLUMN
        a
        b
        c
        d
        e
        f

  Any help appreciated here
  
  Thank you

  Select column_a table_a
  Union
  Select table_b column_b;

• How to put the two column values in two different colors unique online: MobApp

  Hello
  
  I develop Mobile Application.
  I want to show two values in different columns in single row and first column value in either green or red and the second color the default column value.
  the first value of the column is green when the value is greater than the second value of the column.
  and the first column value in red when the value is less than the second value of the column.
  The code I tried is:
  --------------------------------------------------------------------------------------------
  < tr:panelGroupLayout layout = "vertical" styleClass = 'list' >
  < tr:panelList styleClass = "panelist ul > li > a" >
  
  
  "" < tr:outputText value = "deliver: % #{row.bindings.OccCurr.inputValue},
  inlineStyle = "background-color: #{rank." OccCurr > line. OccFcst? {'Green': 'Red'}; ">
  
  "< tr:outputText value =" OccFcst: #{row.bindings.OccFcst.inputValue} % ">"
  
  < / tr:outputText >
  < / tr:outputText >
  < / tr:panelList >
  < / tr:panelGroupLayout >
  ------------------------------------------------------------------------------------------------
  
  But the code above does not work.
  
  
  Please, someone tell me what I need to do.
  
  
  I apreciate your time and your help.
  
  Sanchez.

  Hi Catherine,

  Exactly, what is not working? Your OccCurr and OccFcst values are printed to the screen? I notice some questions.

  (1) If you want to display two outputText on one line, you can surround them with a panelGroupLayout and set the page layout to horizontal.
  (2) I don't think that you can place an outputText in outputText one another as in the codes that you have provided.
  (3) your EL is inconsistent. What is #{row.bindings.OccCurr.inputValue} or #{line. OccCurr}? If your values are displayed, but the background color does not work, it could be the first.

  Kind regards
  Amélie Chan

• Combine the two columns?

  HI, the problem is this, I have two columns: start_date and end_date
  
  Invite a: start date (for example 08/08/2008)
  Invite two: End Date (for ouvertede 30/04/2009)
  
  so these are two different columns, do you know how get all the data between these two dates.
  If I use the "between the function" I can't get the dates between the same column,
  The start date
  The start date
  
  but I need the end date...
  
  I really appriciate to help
  
  Thank you

  Hello

  Something like:

  SELECT *
  FROM   
  WHERE  start_date BETWEEN TO_DATE('08/08/2008', 'mm/dd/yyyy') AND TO_DATE('04/30/2009', 'mm/dd/yyyy')
  OR     end_date BETWEEN TO_DATE('08/08/2008', 'mm/dd/yyyy') AND TO_DATE('04/30/2009', 'mm/dd/yyyy');
  

  Kind regards

• "How do you build a filter based on the conditions of the two columns?

  Hi all
  
  line desc period Amount1 Amount2
  
  Jan Feb 10 0
  Tue Jan 20 0
  Jan jan 30 0
  Jan - Apr 0 40
  
  
  I have such a report with four columns
  
  Line Descr is a table and other period table and amounts 1 and are 2 respective amounts.
  
  now I need to see the only column in the result i, e. jan jan 30 0
  
  
  I need to write a sql in the formula in the column so that I need to get this result
  
  
  Any suggestions as what sql what I write
  
  Thank you
  
  Xavier.
  
  Published by: Xavier on July 1st, 2011 12:03
  
  Published by: Xavier on July 1st, 2011 12:04
  
  Published by: Xavier on July 1st, 2011 12:05
  
  Published by: Xavier on July 1st, 2011 12:05
  
  Published by: Xavier on July 1st, 2011 12:06
  
  Published by: Xavier on July 1st, 2011 12:07
  
  Published by: Xavier on July 2, 2011 11:37

  OK, so try it this way.

  (1) take another column. Click on the fx, delete the content and enter this:

  CASE WHEN tablename. Line_Desc = tablename. Period THEN put END to 'Y' ELSE ' n

  (2) put a filter on this column = 'Y '.

  It should work.

• Filter the two columns with a variable

  Hi guys!

  I am new to Oracle BI EE and I following the task at hand.

  In my database, I've followed columns:

  ID | VALUE | VALID_FROM | VALID_TO

  The first is the unique ID, the second value I need to show my analysis, the latter two are dates.

  I need to prepare the analysis when user asks values at a time, so I'll have to show all lines where the date selected by the user is greater than VALID_FROM and smaller than VALID_TO (but the user must enter only once).

  I am a complete beginner and have no idea how prepare this analysis? Could you give me some advice?

  Best regards

  Greg

  I did not understand your exact need. A date value, will be user input.

  For example: 01.08.2014, then your analysis will be filtered by;

  01.08.2014 > VALID_FROM and

  01.08.2014<>

  If so, you can create a prompt for dashboard column and give set a presentation for this column. Then, you will use this presentation for valid_from and valid_to columns column.

• Update, one of the two columns based on a condition

  I have this example table:

  Lead_ID	Mailed_Date	Campaign of	Model	MPI	MP2
  100	August 2, 12	Travel_Check	US_Air	null	null
  200	August 2, 12	Travel_Check

  US_Air

  1099

  null

  MP1 and MP2 columns represent mailpiece_IDs (marketing mail that was sent).  MP1 is the first piece in the mail and MP2 is the second room that receives mail. Here Lead_id 100 received no mail and Lead_id 200 received the first piece.

  I want my update to allow me to update MP1 IF MP1 is null, but if MP1 is worth, I want MP2 to update. So if I update with a new post 2000 article ID the result should look like this after the update.  Lead_ID 100 received a piece of mail, and 200 Lead_ID received two parts:

  Lead_ID	Mailed_Date	Campaign of	Model	MPI	MP2
  100	August 2, 12	Travel_Check	US_Air	2000

  null

  200

  August 2, 12

  Travel_Check

  US_Air

  1099

  2000

  I tried this case and I thought that maybe I could choose the field with COALESCE, but which doesn't seem to work.   Can anyone help?

  Hello

  Here's another way to do it:

  UPDATE yourtable

  Mp1 SET = NVL (mp1, 2000)

  mp2 = NVL2 (mp1, mp2 2000)

  WHERE LESS (mp1, mp2) IS NULL

  ;

  In any case, there are 2 columns that could be changed, so you should have 2 columns listed in the SET clause.  It does not matter that one or these columns will be always equal to itself.