Update, one of the two columns based on a condition

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  Is it possible using a CASE statement to find the rows that are double and one of the two lines was updated so that they are all unique?

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  Hello

  I don't see how a CASE expression would contribute to this problem.

  In your original message, you said you wanted to update the table, in other words, to permanently change some of the values stored in the table.

  In response, #2, looks like you want to change what is in the table, you just want to replace by new values for col2 in this query, without permanently changing table.  You can do this by using the ROW_NUMBER right in the query, when you thought using a CASE expression.

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  Hi all

  create the table xxc_tr_num (tl_number number, tr_no number tl_no_id);

  insert into xxc_tr_num values (123,100,222);

  insert into xxc_tr_num values (124,100,333);

  create the table xxc_od_tab (tl_number number, tl_id number);

  insert into xxc_od_tab values (123,001);

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  using outer joins if the two column is null? use only please of outer joins

  And I tried to use outer joins on both tl_id column but not get values and I use have County (tr_no ) > 1

  Rajesh123 wrote:

  Thank you Kiss it is not possible to use having clause?

  You need to understand the functioning of the group. If you will not be asked this question.

  Check this box

  SQL> select tr_no,
    2         tl_no_id,
    3         count(*)
    4    from xxc_tr_num a,
    5         xxc_od_tab b,
    6         xxc_oth_tab c
    7   where a.tl_number = b.tl_number(+)
    8     and b.tl_id = c.tl_id(+)
    9   group
   10      by tr_no
   11       , tl_no_id;
  
       TR_NO   TL_NO_ID   COUNT(*)
  ---------- ---------- ----------
         100        333          1
         100        222          1
  

  See what returns the count? You have grouped according to TR_NO and TL_NO_ID. You must take into consideration the TL_NO_ID just put COUNT (TR_NO) does not increase the NUMBER of the whole group. To get the NUMBER on the whole group, I used the analytical function and did. Like this, see the number of the analytical function here

  SQL> select tr_no,
    2         tl_no_id,
    3         count(*),
    4         count(*) over(partition by tr_no)
    5    from xxc_tr_num a,
    6         xxc_od_tab b,
    7         xxc_oth_tab c
    8   where a.tl_number = b.tl_number(+)
    9     and b.tl_id = c.tl_id(+)
   10   group
   11      by tr_no
   12       , tl_no_id;
  
       TR_NO   TL_NO_ID   COUNT(*) COUNT(*)OVER(PARTITIONBYTR_NO)
  ---------- ---------- ---------- ------------------------------
         100        222          1                              2
         100        333          1                              2
  

  So to answer your question, yes you can't do in the HAVING clause...

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  I've written a procedure that accepts an input parameter and returns a refcursor.
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  Published by: Sumit Narayan, 11 April 2010 22:00

  I'd be inclined to do something like that to analyze the list separated by commas, that allows you to join without the concatenation of the columns as you do now.

  ME_XE?select
    substr(column_value, 1, 2)            as brand_id,
    substr(column_value, 3, length(column_value))   as site_id
  from table(sys.ODCIVARCHAR2LIST('AA12345','BB45434','HJ89736'));
    2    3    4
  BRAND_ID   SITE_ID
  ---------- ----------
  AA         12345
  BB         45434
  HJ         89736
  
  3 rows selected.
  
  Elapsed: 00:00:00.20
  ME_XE?
  
  ME_XE?select * from v$version;
  
  BANNER
  ----------------------------------------------------------------
  Oracle Database 10g Express Edition Release 10.2.0.1.0 - Product
  PL/SQL Release 10.2.0.1.0 - Production
  CORE  10.2.0.1.0  Production
  TNS for Linux: Version 10.2.0.1.0 - Production
  NLSRTL Version 10.2.0.1.0 - Production
  
  5 rows selected.
  
  Elapsed: 00:00:00.39
  ME_XE?
  

  So for your case...

  Select
    f.Month_name,
    f.Year,
    sum(f.REVPAR),
    Sum(f.ADR)
  from FIS_KPI_TREND f, table(sys.ODCIVARCHAR2LIST('AA12345','BB45434','HJ89736')) t
  where f.Brand_id = t.brand_id
  and   f.SIte_id  = t.site_id
  group by f.Month_name, f.Year;
  

  Published by: Tubby 11 April 2010 22:12