Table Insert data in column 2
Hi Experts,
I have a table control. I created a local variable for the table control and I have A data in column 1 of the table entry. No problem. Easy.
Now the question is, I have B data which I want an entry in column 2 of the same order of table. How do I do that?
Thanks amigo
Build the table, but do it with the 1 d arrays.
Tags: NI Software
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Hi all
I was asked by an interviewer,
I have a table with 10 columns. in this 10 columns, I have data in a single column. Is it possible to know that the name of the column in which the data are with the help of any view data dictionary.
Sorry if I ask a stupid question.
Thank youCollect statistics of the table and use USER_TAB_COLUMNS view datadictionary (or one of the related views)
http://docs.Oracle.com/CD/E11882_01/server.112/e25513/statviews_5465.htm#REFRN26276SQL> create table t 2 (c1 number,c2 number,c3 number,c4 number,c5 number,c6 number,c7 number,c8 number,c9 number,c10 number); Table created. SQL> insert into t (c7) values (42); 1 row created. SQL> begin 2 dbms_stats.gather_table_stats(user, 'T'); 3 end; 4 / PL/SQL procedure successfully completed. SQL> select * from t; C1 C2 C3 C4 C5 C6 C7 ---------- ---------- ---------- ---------- ---------- ---------- ---------- C8 C9 C10 ---------- ---------- ---------- 42 1 row selected. SQL> select table_name 2 , column_name 3 from user_tab_columns 4 where table_name = 'T' 5 and num_nulls = 0; TABLE_NAME COLUMN_NAME ------------------------------ ------------------------------ T C7 1 row selected. -
How oracle inserts data in columns
Hi guys, just a quick question. When we have a primary key on 4 columns, and we have, say 20 million lines, and we want to add an additional line. How oracle checks if the data on the primary key is unique for recording added compared to the 20 million lines. They actually compare recording added to all rows in the table?
Published by: 969224 on May 10, 2013 08:14969224 wrote:
Hi guys, just a quick question. When we have a primary key on 4 columns, and we have, say 20 million lines, and we want to add an additional line. How oracle checks if the data on the primary key is unique for recording added compared to the 20 million lines. They actually compare recording added to all rows in the table?Published by: 969224 on May 10, 2013 08:14
Not the entire line, it compares the 4 columns in the INDEX against the 4 columns in the new row.
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Inserting data block to the SPOUT making varchar2 (150) column with currupted
Hi Chris,
We are facing a problem with the insertion of bulk data on the BEAK in a table
Insert data block to the SPOUT making varchar2 (150) column in a table with the corrupted values.
column of first row inserted correct, but the second line, columns in the new row as null
We had trace OIC just before the insertion, these values are correctly coming
But integration doesn't work properly
Could you suggest, what could be the problem, we use the OIC during the client/server connection, this problem is for a direct connection alsoIn general, please do not post questions forum for questions where you have already opened a SR. This translates simply by duplication of efforts and is unlikely to lead to a faster resolution. If the problem is serious or complex that you opened a SR, it is very likely that anyone in the forum (including me) will have an instant response and it will probably ask a lot of questions and do a lot of research that is already made by Oracle support.
Thank you for your understanding and your cooperation.
Chris
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Insert data according to the length of column in table
Hello
If the length of the characters is more than one defined causes error. It's very embarrassing especially when get data dynamically
and our query does not insert information that we expect.
While trying to find the solution an idea came to my mind that, before insertion, so we check that the next data is greater than the specified length
Take only the amount of characters that can be inserted and ignore the rest.
I thought that the query as follows but failed.
Is it possible to insert data up to the amount this column length defined by ignoring the obsolete characters and if the dataSQL> insert into cvDetails(cv_id,objectives) values(9687,substr("Hello",1,3950)); insert into cvDetails(cv_id,objectives) values(9687,substr("Hello",1,3950)) * ERROR at line 1: ORA-00984: column not allowed here
length is less defined length of column, and then insert it as it is?
Thank you in anticipationHello
Do not use double quotes as the string delimiters:
SQL> create table test_nsa (str varchar2(10)); Table created. Elapsed: 00:00:00.88 SQL> insert into test_nsa values (substr('aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa',1,10)); 1 row created. Elapsed: 00:00:00.08 -
inserting data in a column in an existing table
Hi the gems...
I have an existing table TABLE_1 which has more data in it. This table has no primary key. now, I added a new column 'ID' and want to make it a primary key for this table. currently it is not allowed because the column is null...
so I need to insert data into the column.
now, my plan is to fill the column with the data as well as rownumber.
means that if there are 15 records in this table, then the 'ID' column should contain data from 1 to 15. After that, I'll do the column as a primary key...
the script I wrote for this:
declare
number of v_rownum;
Start
Select max (rownum) in the v_rownum from TABLE_1;
because me in 1.v_rownum
loop
Update t set i = t.id TABLE_1 where rownum = i;
commit;
end loop;
end;
but it refreshes only the first record and the rest of the records are not updated.
Please help... Thanks in advance...Select max (rownum) in the v_rownum from TABLE_1;
How many rows do you think that this query will retrieve?
Why not just
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How can I insert data from another table into a table containing a timestamp column
How you insert data from another table in a table if the target table contains a timestamp column. I tried to set the default value of GETDATE() column in the target table, but it does not work.
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Insert data into the source of destinator Table
Hi all
Need to insert data in sample_table1 table xxc_source_table sample_table2
create table xxc_source_table (DESCRIPTION varchar2 (10));
Insert the table xxc_source_table values('A201.) ABC.4084.GR');
create table sample_table1 (col_1 varchar2 (10), col_2 varchar2 (10), col_3 varchar2 (10), col_4 varchar2 (10));
create table sample_table2 (col_1 varchar2 (10), col_2 varchar2 (10), col_3 varchar2 (10), col_4 varchar2 (10), moved_flag varchar2 (2));
col_1 = A201
col_2 = ABC
col_3 = 4084
col_4 = GR
Note: Insert data into the col_1, the col_3, the col_4 of the xxc_source_table sample_table1
(2) if the next (form xxc_source_table) data is exist in the sample_table2, and then set the moved_flag as Y in this column
3) xxc_source_table has 17000 lines
Thank you.
Post edited by: Rajesh123 please do not consider cross the line message
Hi Renon,
Why you don't want substr and instr? For best performance, you should go with substr and instr instead of regexp_substr. However you asked me to provide the code instead of substr and InStr. Then try the below...
INSERT ALL
IN VALUES sample_table1 (col1, col2, col3, col4)
IN sample_table2 VALUES (col1, col2, col3, col4, 'Y')
SELECT REGEXP_SUBSTR (DESCRIPTION,'[^.] +', 1, 1) col1,.
REGEXP_SUBSTR (DESCRIPTION,'[^.] +', 1, 2) col2.
REGEXP_SUBSTR (DESCRIPTION,'[^.] +' 1, 3) col3.
REGEXP_SUBSTR (DESCRIPTION,'[^.] +' 1, 4) col4
OF xxc_source_table;
Thank you
Ann
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Inserting data in the nested table
I explore the differences between the OBJECT and RECORD.
As I'm still learning, I found that both are structures which essentially brings together different elements of types of different data or columns of data types, one is used in SQL and other is used in PL/SQL, please correct me if I'm wrong in my understanding.
Below, I am trying to insert data into an array of type object, but I can't can you please help.
CREATE OR REPLACE type sam as OBJECT ( v1 NUMBER, v2 VARCHAR2(20 CHAR) ); ---Nested Table--- create or replace type t_sam as table of sam; --Inserting data---- insert into table(t_sam) values(sam(10,'Dsouza'));
Error message:
Error starting at line 22 in command: insert into table(t_sam) values(sam(10,'Dsouza')) Error at Command Line:22 Column:13 Error report: SQL Error: ORA-00903: invalid table name 00903. 00000 - "invalid table name" *Cause: *Action:
Ariean wrote:
So the only purpose of the equivalent concept of SQL types of nested tables is to use one of the data types when you define an actual table?
So-you can certainly use more that a simple "set an actual table. (I'm fairly certain that you can pass a table nested within a procedure, for example - try it, though - I'm not 100% sure on that - it just 'logic'.) If you can define a type, you can use it, pass it around, whatever.).
Ariean wrote:
And this nested table could be a record in SQL or object in PLSQL or simple data type (varchar number, etc.)?
Nested tables are just like any other type of custom data. You can create a nested table of other types of data. You can create a custom of nested tables data type.
Stupidly, he could become... uh, stupid O_0
CREATE TYPE o_myobj1 AS object ( id1 number, cdate1 date ); CREATE TYPE t_mytype1 AS table of o_myobj1; CREATE TYPE o_myobj2 AS object ( id2 number, dumb t_mytype1 ); CREATE TYPE t_dumber AS table of o_myobj2;
O_0
OK, my brain is starting to hurt - I hope you get the idea
Ariean wrote:
Second is my understanding correct any OBJECT & RECORD?
I see no benefit to describe another way.
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Insert data into the same table based on certain conditions
Hello. I'm new to this forum.
I have to write a stored procedure to insert data in a table MYTABLE say, having a structure like:
Col1 Col2 Col3... TotalInstallments CurrentInstallment PaidAmount MonthYear
I have to insert all the data that it is in the same table (MYTABLE) except change some fields based on certain conditions:
1. if PaidAmount > 0 & & CurrentInstallment < TotalInstallment then
CurrentInstallment = CurrentInstallment + 1
2. in the field MonthYear I have data ex. 01/2012, 11/2012 formate(month/year)...
So, I have to insert data by incrementing the month and year. for example:
If currentdata is 11/2012 next data will be 12/2012
But following will be 01, 2013
I have to select all records that belongs to the previous month (across the field MonthYear) and put the audit on each record selected and insert data and then turns them into table (MYTABLE) even.
How to achieve that?
Thank you.978184 wrote:
Hello. I'm new to this forum.
I have to write a stored procedure to insert data in a table MYTABLE say, having a structure like:Col1 Col2 Col3... TotalInstallments CurrentInstallment PaidAmount MonthYear
I have to insert all the data that it is in the same table (MYTABLE) except change some fields based on certain conditions:1. if PaidAmount > 0 & CurrentInstallment
CurrentInstallment = CurrentInstallment + 1
2. in the field MonthYear I have data ex. 01/2012, 11/2012 formate(month/year)...
So, I have to insert data by incrementing the month and year. for example:
If currentdata is 11/2012 next data will be 12/2012
But following will be 01, 2013
I have to select all records that belongs to the previous month (across the field MonthYear) and put the audit & on each of the selected data record and insert then turns them into table (MYTABLE).You can do this way:
This is not tested, but if you can provide the example of table structure and data (IN create table and insert scripts), it can be put to the test.
insert into your_table (col1, col2, col3...current_installment, month_field) select col1, col2, col3.., current_installment + case when paidamount > 0 and current_installment < total_installment then row_number() over ( partition by column1, column2,.. columnn -->You may choose partition if you want the --Increment of Current_installment to reset after particular combination ends order by primary_key -->Order the Increment, you may choose to add more columns to order by ) else 0 --> if condition is not met, then Add 0 end curr_installment, add_months(to_date(month_field, 'MM/YYYY'), 1) nxt_month from your_table; -
Error in SQL syntax when inserting data to the table in the form of values using insert record
Hello
I was hoping that someone could help me. I am creating a form of registration on a website to insert data into a database table. When you try to create the form, I get the following error:
You have an error in your SQL syntax; consult the manual for your version of the MySQL server for the right syntax to use near ' VALUES (name, regno, reason) leave (has ', 1, 'dddd')' at line 1
I checked the syntax, but you don't know what's wrong.
I am running Windows 7 with Dw cs6 and wamp server.
Leave with the names of column (name, regno, reason) is the name of the table.
Thank you for your help and please help me.
The code is as below:
<? php require_once('Connections/connect.php');? >
<? PHP
If (! function_exists ("GetSQLValueString")) {}
function GetSQLValueString ($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "")
{
If (via PHP_VERSION < 6) {}
$theValue = get_magic_quotes_gpc()? stripslashes ($TheValue): $theValue;
}
$theValue = function_exists ("mysql_real_escape_string")? mysql_real_escape_string ($TheValue): mysql_escape_string ($theValue);
Switch ($theType) {}
case 'text ':
$theValue = ($theValue! = "")? « " ». $theValue. "" "": "NULL";
break;
case "long":
case "int":
$theValue = ($theValue! = "")? intval ($TheValue): 'NULL ';
break;
case "double":
$theValue = ($theValue! = "")? doubleVal ($TheValue): 'NULL ';
break;
case "date":
$theValue = ($theValue! = "")? « " ». $theValue. "" "": "NULL";
break;
case "set":
$theValue = ($theValue! = "")? $theDefinedValue: $theNotDefinedValue;
break;
}
Return $theValue;
}
}
$editFormAction = $_SERVER ['PHP_SELF'];
If (isset {}
$editFormAction. = « ? ». htmlentities($_SERVER['QUERY_STRING']);
}
If ((isset($_POST["MM_insert"])) & & ($_POST ["MM_insert"] == "form1")) {}
$insertSQL = sprintf ("INSERT INTO leave (name, regno, reason) VALUES (%s, %s, %s)',
GetSQLValueString ($_POST ['name'], "text").
GetSQLValueString ($_POST ['reg'], "int").
GetSQLValueString ($_POST ['reason'], "text"));
@mysql_select_db ($database_connect, $connect);
$Result1 = mysql_query ($insertSQL, $connect) or die (mysql_error ());
}
? >
< ! DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict / / IN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd" > ""
" < html xmlns =" http://www.w3.org/1999/xhtml ">
< head >
< meta http-equiv = "content-type" content = text/html"; charset = utf-8 "/ >"
< title > online form let < /title >
< name meta = "keywords" content = "" / > "
< name meta = "description" content = "" / > "
< link href = "styless.css" rel = "stylesheet" type = "text/css" media = "screen" / > "
< / head >
< body >
< div id = 'wrapper' >
< div id = "header" >
< div id = 'menu' >
< ul >
< class li = "current_page_item" > < a href = "#" > home < /a > < /li >
< li > < /li >
< li > < /li >
< li > < a href = "#" > on < /a > < /li >
< li > < /li >
< li > < a href = "#" > Contact < /a > < /li >
< /ul >
< / div >
<!-end #menu->
< div id = "Search" >
< / div >
<!-end #search->
< / div >
<!-end #header->
< div id = "logo" >
E - SCHOOL of CHRIST < h1 > < / h1 >
< p > < / p >
< / div >
< hr / >
<!-end #logo->
<! - end #header - wrapper->
< div id = "page" >
< div id = "content" >
< div class = "post" >
< h2 class = "title" > leave application online < / h2 >
< div class = "entry" > < / div >
< / div >
< do action = "<?" PHP echo $editFormAction;? ">" method = "POST" name = "form1" id = "form1" >
< table width = "200" border = "2" cellspacing = "5" cellpadding = "5" >
< b >
< scope th 'row' = > name < /th >
< td > < label for = "name" > < / label >
< input type = "text" name = "name" id = "name" / > < table >
< /tr >
< b >
< scope = "row" th > Reg No. < /th >
< td > < label for = "reg" > < / label >
< input type = "text" name = "reg" id = "reg" / > < table >
< /tr >
< b >
< scope = "row" th > why < /th >
< td > < label for = "reason" > < / label >
< name textarea = 'reason' id = cols 'reason' = "45" rows = "5" > < / textarea > < table >
< /tr >
< b >
< scope = "row" th > < /th >
< td > < input type = "submit" name = "b1" id = "b1" value = "Submit" / > < table >
< /tr >
< /table >
< input type = "hidden" name = "MM_insert" value = "form1" / >
< / make >
< / div >
<!-end #content->
< div id = "sidebar" >
< ul >
< li >
Notice of < h2 > < / h2 >
< p > students must present the appropriate documents supporting the reason for leave within 3 working days. < /p >
< /li >
< li id = "calendar" >
Calendar < h2 > < / h2 >
< div id = "calendar_wrap" >
< table summary = "Calendar" >
< caption >
March 2014
< / legend >
< thead >
< b >
< th abbr = "Monday" scope = "col" title = "Monday" > M < /th >
< th abbr = "Tuesday" scope = "col" title = "Tuesday" > T < /th >
< th abbr = "Wednesday" scope = "col" title = "Wednesday" > W < /th >
< th abbr = "Thursday" scope = "col" title = 'Thursday' > T < /th >
< th abbr = "Friday" scope = "col" title = 'Friday' > F < /th >
< th abbr = "Saturday" scope = "col" title = 'Saturday' > S < /th >
< th abbr = "Sunday" scope = "col" title = 'Sunday' > S < /th >
< /tr >
< / thead >
< tfoot >
< b >
< td abbr = "February" colspan = "3" id = "prev" > < a href = "#" title = "" > & laquo; Feb < /a > < table >
< class td = "pad" > < table >
< td abbr = "April" colspan = "3" id = "next" > < a href = "#" title = "" > Apr & raquo; < /a > < table >
< /tr >
< / tfoot >
< tbody >
< b >
< td colspan = "5" class = "pad" > < table >
< td > < table > 1
< td > < table > 2
< /tr >
< b >
< td > 3 < table >
< td > < table > 4
< td > 5 < table >
< td > < table > 6
< td > < table > 7
< td > < table > 8
< td > < table > 9
< /tr >
< b >
< td > < table > 10
< td id = 'today' > < table > 11
< td > < table > 12
< td > < table > 13
< td > < table > 14
< td > < table > 15
< td > < table > 16
< /tr >
< b >
< td > < table > 17
< td > < table > 18
< td > < table > 19
< td > < table > 20
< td > < table > 21
< td > < table > 22
< td > < table > 23
< /tr >
< b >
< td > < table > 24
< td > < table > 25
< td > < table > 26
< td > < table > 27
< td > < table > 28
< td > < table > 29
< td > < table > 30
< /tr >
< b >
< td > < table > 31
< class td = "pad" colspan = "6" > < table >
< /tr >
< / tbody >
< /table >
< / div >
< /li >
< li > < /li >
< /ul >
< / div >
<!-end #sidebar->
< div style = "" clear: both; "> < / div >"
< / div >
<!-end #page->
< div id = "footer" >
< p > Copyright (c) University of Christ. All rights reserved. < /p >
< / div >
<!-end #footer->
< / div >
< div align = center > < / div > < / body >
< / html >
The LEAVE is a reserved word in MySQL. You can try to quote, but you are better to rename it.
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a simple way to insert data in a table
Hello
I need to know in a simple way on how to transfer data from one table to the other...
First xx_inv_tab1 table has three columns col1, col2, col3 and where as the second xx_inv_tab2 table has five columns col1, col2, col3, col4 col5.
Here col2, col3, col4 are the same columns in table1 xx_inv_tab1...
Now I want to transfer the first data in table in second table... first column of the second table holds a sequence, followed by the first three columns of table data and followed with col4 col5 which will contain NULL values...
In my scenario, I have 70-75 columns in my first table that I want to move to the second table including three new columns (one is the sequence with two other null values)...
All ideas, if do us it in a simpler way, saying rather insert into xx_inv_tab2 (col1, col2, col3, col75) values (seq, col1, col2,... col75, null, null)
Help appreciated...
Thank youEasy
not tested
insert into xx_inv_tab2 t2 (col1,col2,col3,col4) select yourSequence.nextval, t1.col1, t1.col2, t1.col3 from xx_inv_tab1 t1 ;Note that col5 must not be used, since you want to fill with a NULL value.
Use excel or sql developer write you a list of the column names, if you are lazy to write all the columns of 75 by yourself.
Which might also work:
not tested
insert into xx_inv_tab2 t2 select yourSequence.nextval, t1.*, null from xx_inv_tab1 t1 ;Published by: Sven w. on August 31, 2012 16:41
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How to insert data into a BLOB column using sql
Hi all
How to insert data into the BLOB column directly using sql.
Thank youcreate table temp ( a blob, b clob); SQL> / Insert into temp values ('32aasdasdsdasdasd4e32','adsfbsdkjf') ; * ERROR at line 1: ORA-01465: invalid hex number Please help in this.
Prakash PInsert into temporary values (UTL_RAW. CAST_TO_RAW ('32aasdasdsdasdasd4e32'), 'adsfbsdkjf');
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Doubt about inserting data into a table
Hi all, when I try to insert data into a table through an anonymous block, the pl/sql block runs successfully, but the data are not get inserted. Can someone please tell me where I am doing wrong?
Thanks in advance!SQL> DECLARE 2 3 V_A NUMBER; 4 5 V_B NUMBER; 6 7 v_message varchar2(25); 8 9 10 BEGIN 11 12 13 select regal.regal_inv_landed_cost_seq.NEXTVAL into V_A from dual ; 14 15 select regal.regal_inv_landed_cost_seq.currval into V_B from dual ; 16 17 INSERT INTO rcv_transactions_interface 18 ( 19 INTERFACE_TRANSACTION_ID, 20 HEADER_INTERFACE_ID, 21 GROUP_ID, 22 TRANSACTION_TYPE, 23 TRANSACTION_DATE, 24 PROCESSING_STATUS_CODE, 25 PROCESSING_MODE_CODE, 26 TRANSACTION_STATUS_CODE, 27 QUANTITY, 28 LAST_UPDATE_DATE, 29 LAST_UPDATED_BY, 30 CREATION_DATE, 31 CREATED_BY, 32 RECEIPT_SOURCE_CODE, 33 DESTINATION_TYPE_CODE, 34 AUTO_TRANSACT_CODE, 35 SOURCE_DOCUMENT_CODE, 36 UNIT_OF_MEASURE, 37 ITEM_ID, 38 UOM_CODE, 39 EMPLOYEE_ID, 40 SHIPMENT_HEADER_ID, 41 SHIPMENT_LINE_ID, 42 TO_ORGANIZATION_ID, 43 SUBINVENTORY, 44 FROM_ORGANIZATION_ID, 45 FROM_SUBINVENTORY 46 ) 47 48 SELECT 49 regal.regal_inv_landed_cost_seq.nextval, --Interface_transaction_ id 50 V_A, --Header Interface ID 51 V_B, --Group ID 52 'Ship', --Transaction Type 53 sysdate, --Transaction Date 54 'PENDING', --Processing Status Code 55 'BATCH', --Processing Mode Code 56 'PENDING', --Transaction Status Cod e 57 lc.quantity_received, --Quantity 58 lc.last_update_date, --last update date 59 lc.last_updated_by, --last updated by 60 sysdate, --creation date 61 lc.created_by, --created by 62 'INVENTORY', --Receipt source Code 63 'INVENTORY', --Destination Type Code 64 'DELIVER' , --AUT Transact Code 65 'INVENTORY', --Source Document Code 66 msi.primary_uom_code , --Unit Of Measure 67 msi.inventory_item_id, --Item ID 68 msi.primary_unit_of_measure, --UOM COde 69 fnd.user_id, 70 V_A, --Shipment Header ID 71 V_B, --SHipment Line ID 72 82, --To Organization ID 73 'Brooklyn', --Sub Inventory ID 74 81, --From Organization 75 'Vessel' --From Subinventory 76 77 FROM 78 regal.regal_inv_landed_cost_tab lc, 79 fnd_user fnd, 80 mtl_system_items msi 81 82 WHERE 83 lc.organization_id = msi.organization_id 84 AND lc.inventory_item_id = msi.inventory_item_id 85 AND lc.created_by = fnd.created_by; 86 87 commit; 88 v_message := SQL%ROWCOUNT; 89 dbms_output.put_line('v_message'); 90 END; 91 / v_message PL/SQL procedure successfully completed. SQL> select * from rcv_transactions_interface; no rows selectedThere is no problem with inserting data!
Only there is no data! This means that your select statement retrieves no rows.
You can see the output of your program (0). This means that there where no line in the result set.Please check the output of your tax return independently:
SELECT -- regal.regal_inv_landed_cost_seq.nextval, --Interface_transaction_id -- V_A, --Header Interface ID -- V_B, --Group ID 'Ship', --Transaction Type sysdate, --Transaction Date 'PENDING', --Processing Status Code 'BATCH', --Processing Mode Code 'PENDING', --Transaction Status Code lc.quantity_received, --Quantity lc.last_update_date, --last update date lc.last_updated_by, --last updated by sysdate, --creation date lc.created_by, --created by 'INVENTORY', --Receipt source Code 'INVENTORY', --Destination Type Code 'DELIVER' , --AUT Transact Code 'INVENTORY', --Source Document Code msi.primary_uom_code , --Unit Of Measure msi.inventory_item_id, --Item ID msi.primary_unit_of_measure, --UOM COde fnd.user_id, -- V_A, --Shipment Header ID -- V_B, --SHipment Line ID 82, --To Organization ID 'Brooklyn', --Sub Inventory ID 81, --From Organization 'Vessel' --From Subinventory FROM regal.regal_inv_landed_cost_tab lc, fnd_user fnd, mtl_system_items msi WHERE lc.organization_id = msi.organization_id AND lc.inventory_item_id = msi.inventory_item_id AND lc.created_by = fnd.created_by;Published by: hm on 13.10.2011 23:19
I removed the references of the sequence and the variables V_A and YaeUb.
BTW: Why do you want to include V_A and YaeUb in two different columns?The use of sequences in your code seems a bit strange to me. But this has nothing to do with your question.
-
inserting data into a temporary table
I want to do something like session and I decided to use the temporary table. But when I try to insert data that has no past. This is my trigger when-pressed key code:
declare
total_col number (18.0);
varchar (100) of the author.
title varchar (200);
price number (18.0);
Start
Select BOOK_AUTHOR, BOOK_TITLE, BOOK_PRICE by author, title, price from BOOKS where BOOK_ID =: BOOKS. BOOK_ID;
insert into orders_tmp (author, title, price) values (author, title, price);
commit;
Select total in total_col total_amount where t_id = (select max (t_id) total_amount);
: SUB_CATEGORY. AMOUNT: = total_col;
end;
the first line of the selected data of the block, 2nd insert into the temporary table. 4th line selected the last column in a temporary table and dispalying in etiquette. When the trigger is activated, I have an ORA-01403 error.
Help, please.
Edited by: 863470 2011-09-06 06:50I decided to use the temporary table
Can you show how you created your temporary table (ie., show us your DML Table statement)? Without knowing how you have set your temporary table, we can really offer you suggestions. ;)
declaretotal_col number (18.0);
varchar (100) of the author.
title varchar (200);
price number (18.0);
Start
Select BOOK_AUTHOR, BOOK_TITLE, BOOK_PRICE by author, title, price from BOOKS where BOOK_ID =: BOOKS. BOOK_ID;
insert into orders_tmp (author, title, price) values (author, title, price);
commit;Select total in total_col total_amount where t_id = (select max (t_id) total_amount);
: SUB_CATEGORY. AMOUNT: = total_col;
end;This is more work than it should be. A much simpler and more elegant method is:
/* Sample When-Button-Pressed trigger */ BEGIN INSERT INTO orders_tmp (author, title, price) SELECT BOOK_AUTHOR, BOOK_TITLE, BOOK_PRICE FROM BOOKS WHERE BOOK_ID = :BOOKS.BOOK_ID; ... Rest of your code here... END;Hope this helps,
Craig B-)If someone useful or appropriate, please mark accordingly.
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