Table of the sum of the column of clusters

Similar Questions

• Mark from a table where the column value is a colon-delimited list

  Version: Oracle Database 11 g Enterprise Edition Release 11.2.0.2.0 - 64 bit Production

  Hello

  This is a new query of a query Frank helped me with: https://community.oracle.com/message/12506306#12506306

  Demand is all users to restrict the report based on a multiple selection on the front-end server (application APEX) filter.

  The filter returns that a colon-delimited list and the data in the table can be saved in a delimited by a colon list too. There may be 1 to n values (up to 4000 characters).

  I need a WHERE clause that will allow a match, if it exists, between the data in the column of the Table and the Mult-selection list filter.

  The abbreviated for this post query would be something like:

  SELECT slt_id, slt_item, slt_owner

  OF slt_dashboard

  WHERE slt_owner IN (colon delimited page list);

  The Create Table and Insert statements:

  CREATE TABLE slt_dashboard
  (
    dashboard_id  NUMBER,
    slt_id        VARCHAR2(10),
    slt_item      VARCHAR2(2500),
    slt_owner     VARCHAR2(4000),
    slt_type      VARCHAR2(25),
    slt_year      NUMBER,
    parent_id     NUMBER
  );
  
  --Insert slt_dashboard
  INSERT INTO slt_dashboard(dashboard_id,slt_id,slt_item,slt_owner,slt_type,slt_year,parent_id)
  VALUES (12,'1.1','Implement revenue enhancement initiatives','E15889:JPARISI:BDUR63','Business Commitment',2014,6);
  
  INSERT INTO slt_dashboard(dashboard_id,slt_id,slt_item,slt_owner,slt_type,slt_year,parent_id)
  VALUES (13,'1.2','Strengthen our Energy position','KVROMAN','Business Commitment',2014,6);
  
  
  

  I have a function to separate the list delimited by two points in a table for the IN clause, but because these values can be saved in a delimited list of Colon in the column of the Table, I have a problem, being able to analyze the data in the column, AND the filter data.

  The function is:

  CREATE OR REPLACE FUNCTION get_list( p_string IN VARCHAR2
                                      ,p_delimiter IN VARCHAR2 DEFAULT ':'
                                     )
      RETURN vc_array_1
      PIPELINED
  IS
      l_string VARCHAR2( 32000 );
      l_array wwv_flow_global.vc_arr2;
  BEGIN
      l_array     :=
          APEX_UTIL.string_to_table( p_string
                                    ,p_delimiter
                                   );
  
      FOR i IN l_array.FIRST .. l_array.LAST
      LOOP
          PIPE ROW ( TRIM( l_array( i ) ) );
      END LOOP;
  
      RETURN;
  END;
  
  
  

  The function called in the query in the form (it's just for reference in case someone wanted to know):

  SELECT ...
  FROM ...
  WHERE slt_owner IN (SELECT * FROM TABLE( get_list( :P115_SLT_OWNER ) ));
  

  But I can't use this approach because the data in the Table can be saved in a delimited list of Colon too.

  Desired output:

  If the Mult-Select list filter contains: E15889:JPARISI then

  1.1 implementation of the E15889 revenue improvement initiatives; JPARISI (it's a semicolon between the names)

  If the multiple-selection list filter contains: KVROMAN then

  1.2 strengthen our position of energy KVROMAN

  If the multiple-selection list filter contains: BDUR63:KVROMAN then

  1.1 implementation of the BDUR63 revenue improvement initiatives

  1.2 strengthen our position of energy KVROMAN

  Please let me know if something is not clear.

  Thank you

  Joe

  I went to approach the Table and the Page works perfectly.

  Thank you to everyone!

  Thank you

  Joe

• ALTER TABLE with the column NULL time consuming

  Hello

  I have a table with nearly 2 million documents (about 10 GB size table) when I perform the following change statement its run fast

  ALTER TABLE tbl_1 ADD (DEFAULT col_4 NUMBER 100 NOT NULL);

  but when I do not give the NOT NULL in the alter its taking a long time to complete this i.e tbl_1 of ALTER TABLE ADD (NUMBER col_4 by DEFAULT 100); once I do the column as NOT NULL.

  Can someone explain why is it happening like that regarding the execution point.

  Thanks in advance.

  I can reproduce the effect in 11.2.0.1 - but not in 12.1.0.1.

  drop table tbl_1;

  create table tbl_1

  as

  Select rownum id

  , lpad ('* ', 50,' *') padding

  of the double

  connect by level<=>

  ALTER TABLE tbl_1 ADD (NUMBER col_4 by DEFAULT 100);

  --> slow in 11.2.0.1; fast 12.1.0.1

  ALTER TABLE tbl_1 ADD (DEFAULT col_4 NUMBER 100 NOT NULL);

  --> Quick 11.2.0.1 and 12.1.0.1

  A SQL trace for two operations (11g) shows that the altar slow (without the constraint explicit non-null) made explicit (and tedious) update of any row in the table:

  Update 'TBL_1"set"COL_4"= 100

  call the query of disc elapsed to cpu count current lines

  ------- ------  -------- ---------- ---------- ---------- ----------  ----------

  Parse        1      0.00       0.02          0          1          0           0

  Run 1 11,63 33.56 8336 1016125 2053531 1000000

  Fetch        0      0.00       0.00          0          0          0           0

  ------- ------  -------- ---------- ---------- ---------- ----------  ----------

  Total 2 11,63 33,58 8336 1016126 2053531 1000000

  The other trace file does not contain the explicit Update. I guess in the optimized case that oracle stores somewhere that col_4 has the value 100 and updates only the line of the block after completing DML operations. But that's just a guess.

• How to create the Table using the column Drag and Drop feature

  Hello:
  I'm new to Data Modeler tool Oracle SQL dev and would like to know if there is a way to create a new table by reusing existing columns or groups of columns. The idea is to maintain consistency and save time of table design. If the columns created previously can be reused and require, drag and drop column in the right pane, then only new columns must be created manually.
  
  Any thoughts on this will be appreciated.
  
  Thank you!

  Yes - just change the name of the model table in the script (t_name = "table_template") then save this new transformation for later use.

  I don't know how to apply only some of the tables. Seems like something you could do to a secondary view level?

  Perhaps someone else on the forum can advise how to change the script to work on a subview only instead of the whole model.

• table and the column in the chain

  Hello
  I'll have a column data containing the combination table and the names of columns as
  
  act_hand_table.work_order
  I want the names of table and column separated
  I want to separte. Classified
  
  Please help me
  Kind regards
  Kiran

  I think it'll work

  SELECT
  SUBSTR (COL1, 1, INSTR(COL1,'.',1,1)-1) TABLENAME.
  SUBSTR (COL1, INSTR(COL1,'.',1,1) + 1) COLUMNNAME
  FROM TABLENAME

• Tables set the column width

  I took someone else's code and have problems with the width of the columns in a table for sizing.

  I have a table to create three columns of work. The table is 905px wide and I want column 140, 350, and the rest in width.

  If I put these values < td width = "140"... > etc., while they seem to be neglected, and the three columns are all the same width.

  It seems fine in design mode but not in Live View or published. Can someone help me to overcome this please?

  Thank you very much.

  1. Tables in HTML behave in their own way and you do not guarantee the width of columns
  2. Do not specify the widths of cell via (attributes) HTML).
     The width attribute in thetag is obsolete (the browsers are not required to support or to obey) and it was always a recommendation to the browser in any case, it was never a precise measurement are met.
  3. Learn how to your tables with CSS style

  See

  http://Veerle.Duoh.com/blog/comments/a_css_styled_table/

  http://www.ehow.com/how_2082412_style-table-CSS.html

  the http://www.google.com.au/Search?SourceId=navclient&ie=UTF-8&rlz=1T4ADFA_enAU351AU351&q=sty + tables + with + css

• Table invites the column space question OBIEE 11 g

  Hello

  I have a relationship with the table view and 2 columns in section guests table. When I see the dashboard report 2 invites showing by far. How can I reduce the space between the 2 column guests?

  Any help?

  Thank you

  Prasanna

  I found the solution. The law in the 2nd column of filling. It solves the problem.

• table and the columns in small capitals!

  Dear all,
  
  My database is GR 11, 2 and Linux is the operating system.
  One of my application, whose code I cannot access, he is trying to insert records into the Oracle database. The problem is that the application is case sensitive and try to find the table and columns in small capitals, name while he gets the caps of Oracle and gives error or identifier is not valid.
  
  Y at - it option to create fields and the table with small letters.
  
  Kindly help.
  
  Kind regards
  Imran

  Use "" for the table and columns

  create table "table_test" ( "col_test" number(12));
  

• SQL join on the two tables where the column as another column

  Hi all
  
  
  tried to get the results of a join between two tables where only one column is like another.
  
  Table1 (nameA) examples: black2, green1
  
  Table2 (Name) example: black2.location.uk.com, green1.location.uk.com
  
  so, for example, I want to match all those in table1 with black2 column in table2 that begins with black2 and so of suite, if you see what im trying to get to!
  
  My sql up to now:
  

  select * from  schema.table1 a
  join schema.table2 b 
  on a.nameA like concat('%', b.nameB, '%'); 

  but it errors:
  
  ORA-00909: invalid number of arguments
  00909 00000 - "invalid number of arguments.
  
  Any help or advice would be greatly appreciated, thank you!

  Or any of them should do...

  select * from  schema.table1 a
  join schema.table2 b on a.nameA like '%'||b.nameB||'%';
  

  or

  select * from  schema.table1 a
  join schema.table2 b on instr(b.nameB,a.nameA) > 0
  

• Delete rows in a table when the columns from two tables match

  Hello

  I have following two tables.

  ===========================================

  create the table empbooth as

  (

  Select 1 empid, 1 double cabin Union all the

  Select option 2, Union 1 double all the

  Select 3, Union 1 double all the

  Select option 4, Union 2 double all the

  Select option 5, 2 double

  );

  create the table attsht as

  (

  Select 1 empid, 240 reg, 0 unpaid all double union

  Select option 2, reg 200, 0 unpaid of all the double union

  Select 3, 240 reg, 0 unpaid all double them union

  Select 4 480 reg, 0 unpaid all double union

  Select 5 240 reg, unpaid double 0

  );

  =================================================

  I want to remove rows from attsht where corresponding booth (which is stored in the empbooth table) is 1.

  The condition is 'where attsht.empid = empbooth.empid and empbooth.booth = 1 '.

  I use oracle 10g.

  Help, please

  delete from attsht where a.empid in (select b.empid from empbooth b where b.booth = 1)

  or

  remove from attsht a

  where exists (select null

  of empbooth b

  where b.booth = 1

  and b.empid = a.empid)

• Error when selecting all the columns in the table

  Hi all

  When I write a query by selecting all the columns of the table fromo using * function as well as another new column, I get the error,

  Select *, to_char (hiredate, 'fmday') day

  WCP

  where to_char (hiredate, 'fmday') ('Monday');

  ERROR on line 1:

  ORA-00923: THE KEYWORD not found where expected

  I need all the columns in the table with the column user-defined 'day '. Is there a way I can get the result like this?

  Hello

  padders wrote:

  Alias table to use...

  Or the name of the table, for example

  Select emp.*, to_char (hiredate, "fmday") as day

  WCP

  where to_char (hiredate, 'fmday') ('Monday');

  The bottom line is that * must be qualified (with a table name or alias) when the SELECT clause includes anything else besides *.

• Remove the column from the compressed tables

  NLSRTL	11.2.0.3.0	Production
  Oracle Database 11g Enterprise Edition	11.2.0.3.0	64 bit Production
  PL/SQL	11.2.0.3.0	Production
  AMT for Linux:	11.2.0.3.0	Production

  Hello

  I read on how to do to remove a compressed table column - first set unused and then drop unused columns. However, in the example below on the basis of data, I ran it, it does not work. Please, can you tell me WHEN this approach does not work. What is dependent on - settings or something else. Why can't I drop unused columns?

  And the example and errors:

  create table tcompressed compress in select * from all_users;

  > TCOMPRESSED table created.

  ALTER table tcompressed add x number;

  > table TCOMPRESSED altered.

  ALTER table tcompressed drop the x column;

  >

  Error report:

  SQL error: ORA-39726: unsupported operation column add/drag on compressed tables

  39726 00000 - "operation column add/drop not supported on compressed tables. ''

  * Cause: Not support add/column operation move compressed tables

  elapse.

  * Action: When adding a column, do not specify a default value.

  DELETE column is only supported in a column SET UNUSED

  (remove the column metadata).

  ALTER table tcompressed unused column of the set x;

  > table TCOMPRESSED altered.

  ALTER table tcompressed drop unused columns;

  >

  Error report:

  SQL error: ORA-39726: unsupported operation column add/drag on compressed tables

  39726 00000 - "operation column add/drop not supported on compressed tables. ''

  * Cause: Not support add/column operation move compressed tables

  elapse.

  * Action: When adding a column, do not specify a default value.

  DELETE column is only supported in a column SET UNUSED

  (remove the column metadata).

  As you can see even after changing the table defining the column as unused X I still can't drop by DROP UNUSED COLUMNS.

  Thank you.

  If you enable compression for all operations on a table, you can delete the columns in the table. If you enable compression for the only direct-path inserts, you can't remove columns.

• How to find the name of the column in the tables

  Hello..

  Suppose that there are thousands of table in the database. Out of them a few tables contain the column name as 'ENTRY_BY '.

  I want to know the tables that have columns like "ENTRY_BY".

  ... Please suggest for this query.

  all_tab_cols

  Select * from all_tab_cols

  where column_name like ' % INPUT % ';

  Post edited by: Rajavignesh

• on the column in the table with

  I chose a table cell, the column width

  steady increase, a command can be written

  I tried to do, but does not

  var myStep = 1;  
  var myTables = app.selection[0].stories[0].tables[0].everyItem().getElements();  
  for(var n=0;n<myTables.length;n++){  
   for (i=0; i<myTable.columns.length; i++) 
      if(myTables [n].columns[i].width + myStep<0){myTables [n].columns[i].width= 0; continue};  
      myTables [n].columns[i].width = myTables [n].columns[i].width + myStep;  
  

  Hi hamdifem,

  How ' end this:

  // Table_ColumnsWidthIncreaseByStep.jsx
  
  var myStep = 1;
  var theTables = app.selection[0].tables.everyItem().getElements();
  
  for (n=0; n
  Have fun
  		   

• Ask about the order of the column in a table

  We have a table called EMP in several of our patterns. JOB is the third column in order. But in certain patterns, JOB is not the third column. I'm looking for patterns with EMP table where the column of EMPLOYMENT is not the third column.
  

  SQL > desc emp
   Name                                      Null?    Type
   ----------------------------------------- -------- --------------
   EMPNO                                     NOT NULL NUMBER(4)
   ENAME                                              VARCHAR2(10)
   JOB                                                VARCHAR2(9)
   MGR                                                NUMBER(4)
   HIREDATE                                           DATE
   SAL                                                NUMBER(7,2)
   COMM                                               NUMBER(7,2)
   DEPTNO                                             NUMBER(2)
  
  
  select column_name, column_id from dba_tab_Cols where 
  TABLE_NAME = 'EMP' AND OWNER = 'SCOTT' order by column_id;
  
  COLUMN_NAME                     COLUMN_ID
  ------------------------------ ----------
  EMPNO                                   1
  ENAME                                   2
  JOB                                     3       --------Third column
  MGR                                     4
  HIREDATE                                5
  SAL                                     6
  COMM                                    7
  DEPTNO                                  8

  select
    owner
  from
    dba_tab_Cols
  where
    TABLE_NAME = 'EMP' AND
    OWNER = 'SCOTT' and
    column_id != 3;