The fastest way to load the flex with complex menus of gui application

Hello

In my current project, I have a few menus. Each menu includes a tabbar with one to five tabs and gui-stuff more or less complex in the NavigatorContent.

Most of the menu must be opened by clicking on a button.

I could implement this by assigning to each menu visible and invisible when someone clicks on a button:

<menu:MyFirstMenu id="first" visible="false" />

<menu:MySecondMenu id="second" visible="false" />

...

<s:Button click="first.visible = true;second.visible=false" />

<s:Button click="first.visible = false;second.visible=true" />

but I'm afraid that it takes some time, when the application is initialized.

or I can add menus after the user has clicked on a button

<s:SkinnableContainer id="menuArea" />

<s:Button click="menuArea.addElement(new MyFirstMenu())" />

<s:Button click="menuArea.addElement(new MySecondMenu())" />

but I'm not so sure, if that's the right way to do it.

(I know I must also remove the other menu when I click on one of the buttons, but you get the idea)

So, what is to be implemented, robust way and good if I want to have my app loaded quickly?

Well Yes, that's what I mean.

Tags: Flex

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