The generation of random number in OSB

Similar Questions

• Generation of random number in OSB problem

  I generate a random number using the current timestamp like -.
  
  (fn:current-dateTime()-xs:dateTime("1970-01-01T00:00:00-00:00")) div xdt:dayTimeDuration('PT0.001S')
  
  It gives me desired output, but some times he set a number of 999755859375 on the random number and it looks like this - 1362640884724.999755859375
  
  can someone help me with this?

  Just wrap it with fn:round()

  Kind regards
  Fabio Douek

• Error message: "the temp"e:\random number\cygwin\tmp\"directory is not a valid directory. Cannot install Visual C++ express 2010.

  Original title: cannot install visual c++ express 2010.

  When I ran vc_web.exe, I got this error message: "the temp"e:\random number\cygwin\tmp\"directory is not a valid directory. Implementation cannot continue. "Can help to solve this problem? Thank you.

  Hi moyeh,

  The question you have posted is better suited to the MSDN forums. You can ask your question in the help link.

  http://social.msdn.Microsoft.com/forums/en/Vsexpressvc/threads

  Hope the helps of information.
  Please post back and we do know.

• What is the possibility of obtaining the same repeated random number?

  I would like to generate a random number of 5 digits;
  
  Select round (dbms_random.value (10, 999990)) twice;
  
  The query above seems pretty good, but what is the possibility of obtaining the same repeated random number? I'm fine with repetition until it spreads not less than a second. Is there such a guarantee?
  
  Thank you
  VINET

  983902 wrote:
  I would like to generate a random number of 5 digits;

  Select round (dbms_random.value (10, 999990)) twice;

  On my laptop, I can call trunc (dbms_random.value (0,100000))-which allows a random number to range form 0 to 99 000 - 100 000 times per second. The probability of repetition in a second depends on the number of calls per second, but in my case that the worst cases are a value that appeared 8 times and 18 445 values appeared twice.

  From what you have said so far, I'd probably use a column of date and a sequence in a column number (10) - possibly with a separate strain by table - for a high volume system.

  Concerning
  Jonathan Lewis

• Canvas of generation of random number in the JavaScript link

  When I export my canvas animation it always generates a random number within the index file, as well as in the example of Javascript:

  CBC: images/Bitmap19.jpg? 1462231964024 «»

  < script src = "test.js? 1462321721905" > < / script >

  Anyone know why this is happening? I have the same version of fix in another computer and it never happened.

  Thank you.

  These numbers are added as a cache-buster for the local web server does not display old content when previewing a page.

• Random number generation N

  Hello

  need help with the generation N random numbers... .This is what I did...

  __________________________________________________________________________________

  < mx:Script >
  <! [CDATA]
  
  private void Init(event:MouseEvent):void
  {
  
  var i: int;
  var randomNumber:Array;
  for (i = 0; i < 6; i ++)
  {
  
  NombrAl [i] = randomRange (0, 100);
  test. Text = NombrAl [i];  ------- ISSUE-----------------
  }

  }
  
  public static void randomRange(low:Number,_high:Number):Number
  {
  return Math.floor (Math.random () * (high - low)) + low;
  
  }
  
  []] >
  < / mx:Script >

  __________________________________________________________________________________

  I wanted to check what are the numbers generated, so I tried to put the RandomNumnber table equal to the text property of the text box that we have not option trace in Flex.

  However, nothing is get print...

  someone help me with this...

  Trace output to the debug console.  He is not related to mx.logging. *.

  package that you can use if you want more control over the output.

• How to generate a random number within a specified tolerance and control than tolerance.

  I am trying to simulate data without using a data acquisition device using a random number generator and I want to be able to control the "range" the random number generated well.  On the front panel, the user can enter a nominal number, and the random number generator would generate numbers more or less disponibles.003 this number nominal.  The data would be delayed on a chart.  Someone knows how to do this?  Or if it is still possible?

  Just for the sake of information, the random number is supposed to resemble thickness measures, that's why I want to simulate more and less disponibles.003 because the data might be thinner or thicker than the nominal value.

  Thanks in advance!

  Two ways of approaching the issue.  First of all, for even distribution, you can 'Roll the dice', which is the (0,1) random number function, multiply the result by 0.06 and then add Mean - 0.03 to center around average distribution.  If you simulate a real process, my initial guess would be that the results would follow a normal distribution.  In this case, you can use the VI of white noise Gaussian of the palette of generation of signals with a standard deviation of 0.015 if you wanted 0.03 to be the point of 2 sigma, then add average results.

• Generation of random values

  There is a bug in the continuous Random.vi for the generation of random in a khi-two distribution and Chi-squared Centre-no? When I draw the histogram with high resolution (numerous ferries) successively the h does not vary around the theoretical value as expected for some values of x.

  I posted a note therebug.

  Here is a comparison between the use of tools OR against my own normal random generator (based on Box Muller). As you can see, NEITHER has much more noise with peaks that are always in the same place. That noise is NOT random!

  

• Problem with the generation of multi-sinus wavefrom of random phase using PXI-5412

  Hello

  I am trying to generate random phase multi-sine waveform using the PXI-5412 14 bits 100 M/s AWG on LabVIEW8.0.

  The version of LabVIEW8.0 for the PXI-5412 comes with a sample VI on multi-tone waveform generation. When I tried with a different combination of frequency and amplitude, there is no problem with the sample VI.

  Because I need the phase to be random for each frequency component, I had tore the tone cluster containing 3 elements, i.e. frequency, amplitude and phase, which feeds the generator of signals, and rebundle the cluster with elements of reading a CSV file by using a loop, a fixed value amplititude and a number of random phase of the frequency generated by a random number (formula lournies elements (: pi - 2pi x r). When the waveform multi-sinusoidale generated on the PXI-5112 100 MHz Digital Oscilloscope, it was pointed out that the waveform would change with the tested frequency range.  However, the amplitude of the wave is always ~1.4V (guess that's always default to 1 V x sqrt (2)).  There is no question also when testing the same combination of frequency and amplitude by using sample VI without modification.

  Please find attached the VI of the sample, snatching up to the version and the CSV file I used. Is there something wrong with the table 1 d of the cluster of 3 elements that I built and assembled causing the signal generator to ignore the value of input amplitude and, possibly, the input value of the same phase (as it seems that the amplititude is always set to the default)?

  The other question that I found on the two sample VI and ripped version is on the news of sampling.  The waveforms appear on digital Oscilloscope PXI-5112 always default to 10 cycles no matter how changed the sampling frequency and the number of samples.  For example, if the frequency is 10 Hz, sampling frequency is 1000 Hz, and I put the number of samples to 10000.  I'm supposed to get 10000/100 = 100 cycles.  However, I could see 10 cycles no matter how, I changed.  What should be the correct way to change the number of cycles?

  Really appreiciate your help and advice. Thank you.

  1 phase unit is in degrees (-180 to 180), no - pi pi.
  2 standardize Waveform.vi always normalize your amplitude of the signal. You can remove it to use your desired amplitue, but must make sure that it is not above 5412 spec.

• How to repeat the last random number

  Hi all!

  I have a timer and a random number (var myNumber: number = Math.ceil (Math.random () * 5);).

  I need to repeat the last random number, for example: 3-3, 4-4, 1-1, etc.

  Any suggestions?

  Thank you.

  use:

  kglad wrote:

  use:

   var myNum: Number;
  

  • var mySound: Sound = new Click();
  • var mySound2: Sound = new Sound2();
  • var fl_TimerInstance: timer = new Timer(1000, 30);
  • fl_TimerInstance.addEventListener (TimerEvent.TIMER, fl_TimerHandler);

  1. Count_It.addEventListener (MouseEvent.CLICK, Count_It);
  2. function Contalo(event: MouseEvent): void {}
  3. fl_TimerInstance.reset ();
  4. fl_TimerInstance.start ();
  5. }

  • function fl_TimerHandler(event: TimerEvent): void {}
  • If (event.currentCount % 2 == 1) {}
  • myNum = Math.ceil (Math.random () * 8);
  • trace (MyNum);
  • mySound.play ();
  • } else {}
  • mySound2.play ();
  • trace (MyNum);
  • }
  • }

• 5 digit unique random number based on the year

  Hello
  I need 5 digit unique random number based on the year. If the new year then duplicate random number allowed.
  Thank you

  If only 5-digit numbers are needed you can extract some transformation injective (http://en.wikipedia.org/wiki/Injective_function) and you could easily check for uniqueness:
  substr (to_char (ln (sequence_value)), 10, 5)
  substr (to_char (exp(1 / sequence_value)), 20, 5)
  ...

  Concerning

  Etbin

• How to sort a random number without using the command by

  Hello
  
  How must be sorted, 5 random number without the use of order by in PLSQL
  for example.
  amount of ID
  1 2
  2 9
  3 3
  4 5
  5 7
  
  Edited by: sake1 1-dec-2010 08:16

  I used Altavista and found an example, how is it?

  DECLARE
  
    /* there is no built array in oracle, you must declare
    your own */
    TYPE Numarray IS TABLE OF NUMBER INDEX BY BINARY_INTEGER;
  
    /* the array of numbers - using assoc array because I can start
    with zero like traditional arrays */
    Nums Numarray;
  
    n NUMBER := 0;
  
    Temp NUMBER;
  
  BEGIN
  
    /* load up the array, put 20 random values in the array,
    in array indicies 0 to 19 */
    FOR i IN 0 .. 19
  
     LOOP
      Nums(i) :=  Round(Dbms_Random.Value(1, 1000));
    END LOOP;
  
    /* get the array size */
    n :=  Nums.Count();
  
    /* display the unsorted values - loop through the whole array and
    print out the values */
    Dbms_Output.Put_Line('unsorted:');
    FOR i IN Nums.First .. Nums.Last LOOP
      Dbms_Output.Put_Line(Nums(i));
    END LOOP;
  
    /* bubble sort - using two loops, compare each value with the one
    after it
    if the one after the current one is smaller , then
  
    switch their locations in the array, this is just like standard
    bubble sorts
    in other languages. The only real diff is the syntax.
    */
  
    FOR i IN 0 .. n - 1 LOOP
      FOR j IN 0 .. n - (i + 1) - 1 LOOP
  
        IF (Nums(j) > Nums(j + 1)) THEN
          Temp := Nums(j);
          Nums(j) :=  Nums(j + 1);
          Nums(j + 1) :=  Temp;
        END IF;
  
      END LOOP;
    END LOOP;
  
    /* display the values sorted */
    Dbms_Output.Put_Line('sorted');
    FOR i IN Nums.First .. Nums.Last LOOP
      Dbms_Output.Put_Line(Chr(9) || Nums(i));
    END LOOP;
  END;
  /*
  unsorted:
  155
  909
  795
  977
  942
  214
  105
  269
  283
  820
  108
  594
  784
  921
  856
  736
  802
  457
  951
  411
  sorted
       105
       108
       155
       214
       269
       283
       411
       457
       594
       736
       784
       795
       802
       820
       856
       909
       921
       942
       951
       977
  
  */
  

  In the code the first comment is wrong in fact, I think, this one:
  "There is no table built in oracle, you must declare your own."
  I remember there are some types of collection of the system, if I not mix with something, I remember there was a sort of like they were undocumented, so we can say legally that the comment in the code has always been right.

• Assigning images to the grid according to their value random number cells?

  Hi all!

  I need a good point (or push) in a good way.

  Background

  (With previous assistance from this forum), I created a random number of 12 x 9 grid that scrolls the numbers 1 to 9, a total of twelve times each. Then I created a button that mixes the current grid cells whenever it locks. I now want to use 9 images that I imported as individual symbols in the library (I gave them each their own class called "skin1," 'skin 2',...) "skin9") as the cell labels or equivalent. I also created images as individual video clips (using the.) The class Sprite as extended but base class keeping the real image of class names in line with the name of the object, i.e. the "skin1" image is the class "skin1.as").

  Question

  How can I assign these images for the cells in the grid according to their respective values (from 1 to 9) and ask them to fill the grid, whenever I click on the button 'shuffle'? Thus, for example, in my grid numbers 1 to 9 randomly appear 12 times each. Whenever the number 4 appears in a cell, I want it to be assigned to the picture "4 GB" (which is just a chart that looks like a button and has a fancy number '4' printed top). Here's a piece of code that I use to draw the grid cells with:

  // Creates a grid cell when called by generateGrid().
  private funciton drawCell(_numeral:int):Sprite
  {
       /*
            This is the code I am currently implementing to populate the grids with (although I
            don't want to use text labels as I want to fill each grid with an image according 
            to its numerical value (1 to 9).
       */
       var _label:TextField = new TextField();
       _label.multiline = _label.wordWrap = false;
       _label.autoSize = "center";
       _label.text = String(_numeral);
       // Add numerical label to cell array.
       cellLabels.push(_label);
       var _s:Sprite = new Sprite();
       _s.graphics.lineStyle(2, 0x019000);
       _s.graphics.drawRect(30, 0, cellW, CellH);
       _s.addChild(_label);
       return _s;
  }
  

  
  While what follows is not the labour code, it will show if all goes well I want to reach inside this function so I can't use the code snippet above to the text labels:

  This will create "if all goes well" a table of 9 images by calling their classes.      var _imageArray:Array = [skin1, skin2, skin3, 4 GB, skin5, skin6, skin7, skin8, skin9];      That's what I want to get for each cell using the matrix in the image above: for (i = 0; I < cells; i ++) {if (_numeral == 1) {/ / Insert image skin1 for each instance of #1 in the grid.}}           } If (_numeral == 2) {/ / Insert image skin 2 for each instance of #2 in the grid.}           }... If (_numeral == 9) {/ / Insert image skin9 for each instance of #9 in the grid.}           }      }

  Again, I want not to use text labels. I have a skin graph custom that I want to go over each number on the grid, based on its value (from 1 to 9). Help with this is greatly appreciated!

  :

  // Creates a grid cell when called by generateGrid().
  private funciton drawCell(_numeral:int):Sprite
  {
       /*
            This is the code I am currently implementing to populate the grids with (although I
            don't want to use text labels as I want to fill each grid with an image according
            to its numerical value (1 to 9).
       */
       var _label:TextField = new TextField();
       _label.multiline = _label.wordWrap = false;
       _label.autoSize = "center";
       _label.text = String(_numeral);
       // Add numerical label to cell array.
       cellLabels.push(_label);
       var _s:Sprite = new Sprite();
       _s.graphics.lineStyle(2, 0x019000);
       _s.graphics.drawRect(30, 0, cellW, CellH);
       _s.addChild(_label);
  
  var classRef:Class=Class(getDefinitionByName("skin"+numeral));var image:*=new classRef();_s.addChild(image);      return _s;
  }
  
  

• Random number in the Transformation file

  Hi all
  
  I need to send a number random while the mapping of one xsd to other in the xsl file. The random number must be alphanumeric with 5 characters. I tried using generate - guid (), but it generates 32 characters. How can you I reduce it to 5 characters and still get a random value?
  
  
  Thank you
  MJ

  A way I do this is by using the request db function and I call the following SQL code

  SELECT dbms_random.value (10000, 99999) FROM dual;

  This will generate a random number between 100000 and 99999

  see you soon
  James

• A random number in the range generator please help!

  Hey hope someone can help out me, im sure its a easy:

  var tstArray:Array = new Array (1,2,3);

  for (var a: uint = 0; has < tstArray.length; a ++)

  {

  var x: Number = Math.floor ((Math.random () * tstArray [a]));

  trace (x);

  tstArray.splice (a, 1);

  }

  I have this code but it does not exectply what I want it to do. Im trying to generate a random number of signle click between 1 and 3, and when all numbers have been used upwards, remove this click listener.

  If you can help it will be much appriciated

  THX pavel

  use:

  var fp1:farm_part1 = new farm_part1();

  and when you want to randomize a table use:

  var tstArray:Array = fp1.randomizeF ([1,2,3]);

  package

  {

  * / import flash.utils.Timer;

  import flash.display.Sprite;

  import flash.events.MouseEvent;

  import flash.display.MovieClip;

  import flash.events.Event;

  import flash.events. *;

  import flash.media.Sound;

  import flash.events.TimerEvent;

  import flash.media.SoundChannel;

  import flash.media.SoundTransform;*/

  public class farm_Part1

  {

  public void randomizeF(a:Array):Array

  {

  a.shuffle ();
  return a;
  }

  ///////////////////////////// change nothing below /////////////////////////////////////////

  function shuffle(a:Array)

  {

  var p:int;

  var t: *;

  var ivar:int;

  for (ivar =. Length-1; Ivar > = 0; Ivar-)

  {

  p = Math.Floor ((Ivar+1) * Math.Random ());

  t = a [ivar];

  a [ivar] = a [p];

  a [p] = t;

  }

  }

  } //randomAnimal

  } //class

  } //package