The hierarchy tree tutorial
Hello dear,Please someone help me or share a link to the development of the hierarchy tree on a form.
I need the following specifications in development.
that populate database table.
Add a node that will be recorded in table
remove a node that erases the precise recording of table
update a node that update the database table.
I'll be very thank you all in advance.
Kind regards
Zafar Iqbal
Hello
It is a starting point
François
Tags: Oracle Development
Similar Questions
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How to use record group to insert data into the hierarchy tree?
Hello
I had a hierarchical tree in my block and I want to use the record group to display
in the hierarchy tree, call david_tree. He did work for the code I try below
and I think it might be that the create_group_form_query was wrong? or miss an order?
DECLARE
htree;
rg_data RECORDGROUP;
v_ignore NUMBER;
BEGIN
htree: = Find_Item ('tree_block.david_tree');
rg_data: = CREATE_GROUP_FROM_QUERY ('rg_bank',
"select name, short_name".
|| "from css_banks");
-Fill the record with data.
v_ignore: = POPULATE_GROUP (rg_data);
-Transfer the data from the record group to the hierarchical
-tree and bring it to display.
FTREE. SET_TREE_PROPERTY (htree, FTREE. (RECORD_GROUP, rg_data);
END;
Thank you
DavidDavid,
You get an error with your code? Looks like you took your example code help Forms. I don't really see a problem with the code, but the forms example gives an example of how create the record group used by the HTree so the Receiver General may be the cause of the problem. When I used the HTree, I used the FTREE. Procedure ADD_TREE_DATA to fill the tree. When I started working with HTree I created a wrapper package to simplify the process. You can watch how I work with the HTree in a demo that I published called: forms and how to: create a shape of the HIERARCHICAL tree.Hope this helps,
Craig B-)If someone useful or appropriate, please mark accordingly.
-
Order by in the hierarchy tree
HelloW All
My request for the hierarchy tree is
SELECT 1, LEVEL, name. ' ('| to_char (ID) |') ', ", to_char (id)+.
FROM py_emp+.
CONNECT BY PRIOR id = start catagory_id with+.
id in (1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,+)
* 21,22,23,24,25,26,27,28,29,30,31,32,33,34,35, *.
* 36.37.38.39.40.41). *
Its fine to work, but the hierarchy tree is not stopped by Id
What can I do?
2nd I want to start with the id in 1,2,3 do not enter from 1 to 1000 to continue automatically continue
Concerning
Wasim Ismail1. you can use
BROTHERS AND SŒURS ORDER BY ID
2. I do not understand this requirement
-
Colorful of the hierarchy tree
Hello
This is the first thread write. I searched your discussions for 'how to display the hierarchy tree in forms 10g with different colors and different fonts for different nodes weight '. But I found nothing.
Looking forward hopefully to your answers.Hello
Forms provides special not integrated to manage the coloring of a tree.
The only way would be to do it through the Java code.François
-
Fill the table of the hierarchy tree of XML data
Hi experts
I have an XML file and I want to create a hierarchy tree in a single table.
Say the following XML:
< Note >
< to > < /pour > Mary
< from > John < / from >
< title > call < / section >
< body > don't forget me this weekend < / body >
< / note >
Expected to generate these documents:
TAG ID PARENT_ID VALUE
Note 1 null null
2 1 Marie
3 1 John
4 1 position of reminder
5 1 body remember me this weekend
How can I achieve this?
Thanks in advance
OscarHi Oscar,.
These discussions should be of interest to you:
{: identifier of the thread = 2210708}
{: identifier of the thread = 2195072}
-
Is there a way to the highest point in the hierarchy tree darker?
It is the highest point that you see when a field in the tree is selected. The highest point is STILL very low, and the only way to see it is by looking at an angle.
Hello
This came before as the subject last year.
You can change the color of items selected in the hierarchy. However it is a Windows setting in Control Panel.
Have a look here: http://forums.adobe.com/message/2603870#2603870.
Good luck
Niall
-
Best way to display a report of the hierarchy tree to APEX 4.2
I have a hierarchical query spans four levels over two tables. The application works very well and also includes columns hierarchical sum (i.e. the parent displays the sum of all children) using functions.
I wonder what is the best way to view these data for users?
At the moment I think I would have a collection now my connection with the edition special 'show' column. Then I would include HTML to define values correct show/hide and refresh the report when you click on a node. In my view, this would probably work, but may not be the best way.
I disassembled my request for necessary columns (no column of the sum) and the tree APEX regions work well for this. Y at - it a plugin alternative jquery or anything that people with what will give me the directory structure 4.2 native while allowing me to display additional columns with links?
If I need to provide more info let me know!
LSDev wrote:
I'm going to use today to test these ideas, and if they don't work I'll go with the classic report hack, I thought.
AEC: I'll try the plugin and report back on the question if I can get the links to work.
The plugin code is clear and simple. However, the links generated HTML text in the query as:
... '' || apex_escape.html(ename) || '' employee ...
does not work out of the box as the plug-in is escaping in HTML output column values:
-- Render all other columns FOR j IN 3 .. l_value_list.count LOOP sys.htp.p('
' || sys.htf.escape_sc(l_value_list(j)(i)) || ' '); END LOOP;This can be changed to allow the links:
-- Render all other columns FOR j IN 3 .. l_value_list.count LOOP IF l_value_list(j)(i) not like '' || l_value_list(j)(i) || ''); END LOOP;
-
Dear member.
I am a beginner. and want to know about how to make hierarchical form
I use suit developer 10g.
Thank you
Mustafa
Lahore, pakistanMustafa,
the way you marked the node_id and parent_node_id in the two tables, it is at the level of the form. or that it's a bit confusing to me, I have to apply this form of ht to another schema.
Yes, I create Federal Archives which fills the HT in the trigger once - new - form - Instance (WNFI). You can fill a HT of anywhere, but I use the WNFI to ensure that the tree is completed when the form is loaded.
To add a node "Grandson" to your tree, you simply change the trigger WNFI and add a loop for these nodes. Use your data for example, the code in the WNFI might look like this (untested):
DECLARE CURSOR c_comp IS SELEC T compcode, name FRO M company; CURSOR c_div (p_comp NUMBER) IS SELEC T div_id, div_name, dept_id FRO M s_div WHER E compcode = p_comp; CURSOR c_dept (IS SELEC T dept_id, dept_name FRO M s_dept WHER E dept_id = p_dept; n_level NUMBER := 1; n_row NUMBER := 1; rg_id RECORDGROUP; node Ftree.Node; BEGIN Tree_Control.v_item_name := 'MY_TREE_DATA.MY_TREE'; rg_id := Tree_Control.Create_RG; <
> FOR r_comp IN c_comp LOOP -- Add Parent Company Tree_Control.ADD_RG_ROW(rg_id, ftree.collapsed_node, n_row, n_level, r_comp.name, null, r_comp.compcode); n_row := n_row + 1; n_level := n_level + 1; -- Add any child Department records < > FOR r_div IN c_div(r_comp.compcode) LOOP Tree_Control.ADD_RG_ROW(rg_id, ftree.collapsed_node, n_row, n_level, r_div.div_name, null, r_div.div_id); n_row := n_row+1; -- Now, add any Grandchildren < > FOR r_dept IN c_dept(r_div.dept_id) LOOP Tree_Control.ADD_RG_ROW(rg_id, ftree.collapsed_node, n_row, n_level, r_dept.dept_name, null, r_dept.dept_id); END LOOP grandchild; END LOOP child; END LOOP parent; ftree.Add_Tree_Data(Tree_Control.v_item_name, ftree.ROOT_NODE, ftree.PARENT_OFFSET, ftree.LAST_CHILD, ftree.RECORD_GROUD, rg_id); END; You will still need to modify the Create_RG function in the Tree_Control package to support the changes described above, but this code example should help you get started.
Craig...
-
Button gif icon not displayed but the icon of the hierarchy tree.
Developer and oracle 10 g database
I was working on windows Xp and oracle10g on button icon and HTree worked very well.
After that, I installed windows 7 pro, in this icon of the window was not displayed.
now, even once, I installed windows Xp and run my existing form there is a problem I m facing Htree menu does not display icon but button is displayed.
I have set all parameters for the icon (gif file).
I checked again all the icons in the extract with Winrar jar filedefine formsweb jar file recreated jar file *.gif files. Jar -cfv icons.jar *.gif copy jar file into java folder edit registry edit regstry.dat it is record group SELECT -1, LEVEL, NODE, icon,S_ID FROM MENU CONNECT BY PRIOR S_ID=S_NO START WITH S_ID=1 order by to_number(s_id) -1 LEVEL NODE ICON S_ID ---------- ---------- -------------------- -------------------- ----- -1 1 MENU menu 1 -1 2 SETUP profile 2 -1 3 Location location 3 -1 3 Department public 4 -1 3 Designation info 5 -1 3 Shift abc 6 -1 3 Divisions house 7 -1 3 Transporter Trans 8 -1 3 Bank bank 9 -1 3 Leave_Type hospital 10 10 rows selected
Published by: 867210 on February 7, 2013 23:46Edit the Registry.dat file
First edit this default path and stop OJ4J and start and run form. default.icons.iconpath= if not working then try this default.icons.iconpath=icons
concerning
-Ahmed -
Start - and connect SQL to the lowest level in the tree or the hierarchy
Hello
In a tree structure as shown below how can I get all the child (tree) level lowest records as a - E, H, G, and D.
A a B, C, D to level 2
B E and F at level 3, and C G at level 3
F a H level 4
A
| l | l | l
B C D
| l | l | l
E F G
| l
H
I have used start with and coonect by to give all levels of the tree as follows: -.
SELECT task_id, parent_task_id, top_task_id, level
OF pa_tasks
WHERE project =: p
START WITH parent_task_id IS NULL
CONNECT BY PRIOR task_id = parent_task_id
Thank you
Published by: user10648285 on October 17, 2011 23:42
Published by: user10648285 on October 17, 2011 23:42
Published by: user10648285 on October 17, 2011 23:42
Published by: user10648285 on October 17, 2011 23:43Oracle a [url http://download.oracle.com/docs/cd/E11882_01/server.112/e26088/pseudocolumns001.htm#i1009313] nickname for hierarchical queries:
SELECT task_id,parent_task_id, top_task_id,level FROM pa_tasks WHERE project_id = :bind_variable and connect_by_isleaf = 1 START WITH parent_task_id IS NULL CONNECT BY PRIOR task_id = parent_task_id
-
I recently noticed that some of my projects have libraries added in a separate the 'library' of the project tree branch, while in others they are simply registered at the level of the base tree; see these two examples:
There is a practical difference between these two provisions, in addition to aesthetics? Can I get in trouble in the second? I'm actually in many of my projects in the second scenario without apparent problems, so I tend to answer 'no', but who knows?
Hello Roberto,
The hierarchy of the project tree is only to logically organize your files. However, there is no impact on the operation of the program.
You can change the hierarchy to organize your files in the virtual folder that you want.
Starting with 2013 CVI, you can also add subfolders, which was not possible in 2012.
Constantine.
-
Default qualifier to "generate the function tree.
Hello
Since this is my first attempt to use the CVI feature for the creation of a Commission of an include file as I am facing a very basic question...
My problem is that in the popup 'Generate the function Tree', I need to specify a default qualifier. So Far, however, I use no qualifier by default, because one) I didn't need and b) I provide 32-bit and 64-bit software versions. If I understand correctly, I have to choose for 32 bit __stdcall or __fastcall for 64 bit. In other words, a function panel will work for 32-bit or 64-bit programs? I guess it's a misunderstanding
Furthermore, it should be to update the tutorial (from 2014?) to reflect actual contextual Control Panel CVI2013...
You should be able to use the __stdcall in your code, regardless of the number of bits. When you build a 64-bit version of your code, this qualifier is ignored (it will use fastcall instead), but its presence is harmless.
-
Hello
I work with the hierarchy (using start with and plug by front) in order to built a 'tree' of jobs in the application.
For each job, the hirarchy start with LEVEL 1 to the level "n".
In the example below, I built the hirarchy for job number 34461, with 4 levels.
Of curse, I have hundreds of jobs, but for simplicity I shows that the values of a job.
I need your advice with the following problem:
In the case wherever one of the lines return "bz" in mach_name column, I need to return ALL of the hirarchy work (in the example below - all 11 lines)
where "bz" value didn't exists column mach_name - no lines related to the specific job should be returned.
Please notify.
< code >
SQL > fixed line 300
SQL > with all_data as (SELECT X.JOB_NAME, x.joid, LEVEL,
x.box_joid,
mach_name
OF AEDBADMIN.ujo_job x, AEDBADMIN.ujo_job_tree j
WHERE X.JOID = J.JOID
START WITH J.PARENT_JOID = 34461
CONNECT PRIOR X.JOID = J.PARENT_JOID)
Select all_data.*
of all_data;
JOID'ART BOX_JOID LEVEL MACH_NAME JOB_NAME
------------------------------------ ---------- ---------- ---------- ----------
Ys_Crm_Inv_Push_Load_Ctrl_tr_BOX 31596 1 34461
Ys_Crm_Inv_Push_Load_Ctrl_tr 31605 2 31596
Ys_Crm_Inv_BOX 31586 3 31605
Ys_Crm_Inv 31587 4 31586 bz
Auto Ys_Crm_Inv_OK 31588 4 31586
E_Push_Trx_BOX 31594 3 31605
E_Push_Trx 31595 4 31594 cr
E_Push_Trx_OK 31597 4 31594 auto
Ys_Crm_Load_Cntrl_tr_BOX 31599 3 31605
Ys_Crm_Load_Cntrl_tr 31600 4 31599 bz
Ys_Crm_Load_Cntrl_tr_OK 31602 4 31599 auto
11 selected lines.
< code >
Thank you
SELECT DISTINCT *.
de)
SELECT mytest.*
, COUNTY (CASE
WHEN mach_name = "bz".
THEN 1
END
) ON (SCORE OF CONNECT_BY_ROOT joid'art) AS good_cnt
sys_connect_by_path(joid,'/')
OF mytest
START WITH lvl = 1
CONNECT BY box_joid = PRIOR joid'art
) t
ORDER BY road;
-
Getting the name of the top of the hierarchy of the inventory in a VC
When you cross a VC inventory, what is the type of the object at a higher level? I think it's a folder - that's what I'm doing once the connection and I browse the hierarchy correctly.
File fd (sc.rootFolder);
Where sc is the ServiceContent instance I understand well after the connection to the server.
The VC that I use is named STORAGE2 and the top-level object is also named STORAGE2 - but when I ask the name of the object "fd" he gave a name "data centers". When I ask the other folders in the hierarchy down, I make own name except for this one.
Am I wrong in thinking that the top-level of the VC object is a folder? How can I name own derieve for this object?
Thank you
. / Siva.
"Data centers" is the name of the rootFolder. The next type of the object in the tree is defined entities of data center. Take a look at the ServiceInstance object to see the tree in the API documentation.
In the user of the vSphere Client interface, the rootFolder is hidden, and they show rather the name of vCenter. If you want to emulate the appearance of the user interface of vSphere, you need to hide some of the items of base directory, but they are there in the real inventory tree in code.
-
Hierarchy tree Denorm full config
What do we need to turn it on in order to see the specifications of trade that the Formulation of exit are related to, in the run-up to the release of formulation?
When display us the FO tree, we see the spec of formulation and master card, but not the spec of trade to which it is bound. We have tried the config setting but without and success. Thank you
David
You are referencing denorm hierarchy, this service captures all hierarchies so that the data must be in the table.
However, I assume you mean the tool navigator of the hierarchy since you mention a view of the actual production of formula. Hierarchy browser shows that the specifications of the user to the bottom of the hierarchy. Going up the hierarchy is non-deterministic as a single tree, for example, you can use the same formula in several finished products. Where used report will show you the data that you want. It will show you both multiple hierarchies. This report and others who profit from the denorm service will be available shortly after the holiday season.
I hope this helps. Let me know if you have any questions.
Kelly
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