The values are duplicated in Proportion?

Similar Questions

• Why all the results are duplicated when searching in my bookmarks library?

  If I search for "Shell", for example, and then click on the 'name' column, most of the 'results' are duplicated. For example, "Perdido | On Shell"in the"shell"folder Parent is shown twice... same URL and al. I see that the or after the 01/02/2013 added bookmarks are NOT duplicated.

  In my case, the bookmarks ARE actually duplicated. I checked by exporting and by analyzing the HTML code.
  The whole "All bookmarks" hierarchy had somehow been copied into a random location of my favorite tree. This is why all bookmarks except most recent lie twice.
  It looked like this:

  - All Bookmarks
    + Bookmarks Toolbar
    + Bookmarks Menu
       + MY_FOLDER_A
       + MY_FOLDER_B
       - MY_FOLDER_C
         MY_NESTED_FOLDER_A
           - All Bookmarks
              .... older state fully duplicated!!!
  

  I deleted the nested copy of "All bookmarks" and it seems OK now.
  I made this copy by mistake (which I highly doubt) or a bug caused.

  Good to hear that you are not using Firefox Sync (I use it). It would have been a Prime Minister candidate for causing a problem like this. (My bad favorites have been replicated to all of the computers connected with synchronization).

  The copy of "All bookmarks" should have been made over the past months, but I couldn't determine exactly when. The copies have the same ADD_DATE and LAST_MODIFIED timestamp in the HTML file.

• reinstalled itunes on new pc and all the songs are duplicated

  r

  I reinstalled iTunes on new pc and all the songs are duplicated. How can I delete everyone else?

  iTunes can create duplicates if the same content is added several times from outside the media folder when it is about to make copies of everything that is added to the library, or is added from an external drive that hosts the press kit that was disconnected during the launch of iTunes.

  Official notice of Apple on the duplicates is here: find and remove duplicates in your iTunes library. This is a manual process and article fails to explain some of the potential pitfalls such as the lost coast and membership of playlist, or sometimes the same file can be represented by multiple entries in the library as well as a removal and recycling the file will break all the others.

  Use MAJ > display > show items to reproduce exactly to display the duplicates because it is normally a selection more useful. You must manually select all but one of each group to remove. Sort the list by Date added can make easier select appropriate tracks, but it works better when executed immediately after the dupes were created.  If you have several entries in iTunes connected to a same file on the disk hard then don't not send to trash.

  Use my DeDuper script (Windows only) If you are not sure, do not want to do it by hand, or want to maintain ratings, play counts and playlist membership. See this background thread , this post for detailed instructions and Please take note of the warning to back up your library before deduping.

  (If you don't see the menu bar press ALT to temporarily view or CTRL + B to keep displayed.)

  The latest version of the script can put away the dead links as long as there is at least a double live to merge his stats and membership of the playlist and must deal wisely when the same file has been added through multiple paths.

  TT2

• In the column of table when the values are grater that maximum linear axis it does not show the bar

  Hi guys,.

  In the column of table when the values are grater than there maximum linear axis it does not show the Bar.But I want to display the bar up to the maximum limit of the axis is linear without changing the limit max.

  Consider following the example:

  The values are 80 90 200 300

  and here is the result:

  Left: when I don't put maximum property of linear axis.

  Right: when I put in maximum property of linear axis to 200.

  

  Law 4th bar is not visible because the value of this bar is 300 which is excedding maxium. But I want the 4th bar to appear identical to 3 bar.

  How can I do this?

  Thanks in advance.

  Then you should change the value of Y to the maximum value.

  Another option, you should consider is changing the Render item column to reflect that the value is greater than the specified maximum value.

• Search and replace values in the text field before the values are stored in DB

  Hello
  There is a question - answer and text box text field - in my application. Problem is, some of the answers are stored with the apostrophes to the DB and I have a problem while recovering in the DB. I need to replace the single quotes 1 with 2 apostrophes. The values are stored in the DB when you click on the submit button.
  
  So, I'm using the following javascript code:
  italics
  < script type = "text/javascript" >
  function test().
  {
  var str = "& P2_S1.";
  document. Write (Escape (STR));
  }
  < /script >
  italics
  I need to call this javascript function, when the user clicks on the button submit, but BEFORE the values are stored in the DB. How can I get this done?
  
  Please let me know.

  Hi Suzi,

  Just use

  begin
  update test set S1=replace(:P2_S1, '''', '''''') where name=:APP_USER;
  end;
  

  as you did in your SELECT statement.

  But I shake also why you want to do? Where do you have problems with the apostrophe?

  Concerning
  Patrick
  -----------
  My Blog: http://www.inside-oracle-apex.com
  APEX 4.0 Plug-Ins: http://apex.oracle.com/plugins

• After deactivation of elements using Javascript, the values are missing when the...

  .. .page is submitted.
  
  Friends,
  
  I have my page apex in the attribute of the HTML Body with some Javascript functions I wrote to determine the following:
  
  < pre > onLoad = "RadioGroupEnableDisable ('P213_COMPLETED', true); disableStartEndDate(); "< / pre >
  
  
  These disable a group of radio buttons and two text fields and work as expected, the values in the controls, I can't change the values and the values are changed properly when I navigate to the next record.
  
  However
  
  When I try to edit a field that allow entry and try to save the changes when the page is submitted, I have an error message stating that the required fields are null (these are the same fields that I disabled).
  
  Is this expected behavior? or I'm doing something very wrong?
  
  Any help will be very appreciated!

  Hello

  Disabled items are not submitted. It's standard HTML.
  What is your problem

  BR, Jari

• check if the fields in the table are duplicated

  I neeed to check if the unique table fields are duplicated.
  
  I write this
  
  Select IID_DELOVNO_MESTO, IID_DEL_IN_NALOG from ZKET_DELA_IN_NALOGE_DM Z1
  where Z1. IID_DELOVNO_MESTO = (select IID_DEL_IN_NALOG from ZKET_DELA_IN_NALOGE_DM Z2)
  
  but I get
  
  SQL error: ORA-01427: einreihig subquery returns multiple rows
  01427 00000 - "einreihig subquery returns several lines.
  
  so I try with loop
  
  declare @stevec int;
  declare @izpis chain;
  
  Set @stevec = 1;
  While @stevec > 0
  Start
  Set @izpis = (select IID_DELOVNO_MESTO, IID_DEL_IN_NALOG from ZKET_DELA_IN_NALOGE_DM Z1
  where Z1. IID_DELOVNO_MESTO = (select IID_DEL_IN_NALOG from ZKET_DELA_IN_NALOGE_DM I2));
  end
  
  impression izpis
  
  and I get
  
  PLS-00103: encountered the symbol "@" when expecting one of the following values:
  
  begin function package pragma procedure subtype type use
  < an ID > < a double quote delimited identifier > form
  current cursor
  06550 00000 - "line %s, column % s:\n%s".
  * Cause: Usually a PL/SQL compilation error.
  
  and I don't know how to solve this problem.
  
  Published by: senza on Sep 2, 2008 02:08
  
  Published by: senza on Sep 2, 2008 02:17

  It will work, but there are probably more effective ways to do so.
  Note that the actual query starts from select * from sampledata. The front section is the only reason I can repeat your data

  with sampledata
  as
  (
  select 1 ID,12  IID_DELOVNO_MESTO,14 IID_DEL_IN_NALOG from dual union all
  select 2, 17, 15 from dual union all
  select 3, 12, 14 from dual
  )
  select * from sampledata
  where IID_DELOVNO_MESTO||IID_DEL_IN_NALOG in
  (
  select cols
  from
  (
  select IID_DELOVNO_MESTO||IID_DEL_IN_NALOG cols,count(IID_DELOVNO_MESTO||IID_DEL_IN_NALOG) from sampledata
  group by IID_DELOVNO_MESTO||IID_DEL_IN_NALOG
  having count(IID_DELOVNO_MESTO||IID_DEL_IN_NALOG) > 1
  )
  )
  

• If the values are same then post it as a

  Hi all

  item Qty

  -----       ---

  ABCD 2

  ABCD 2

  XYZ 3

  IF the two element is the same then display a (consider as a single value)

  I mean 2 items should display ex :-abcd, xyz

  I'm IN THE LOOP FOR of CURSOR help

  v_tab (i): = c_rec.item_id;

  v_tab. Delete;

  Thank you

  Hi all, found the solution...

  abc heart

  is

  in this added slider group so we get 2 values (1,2) If values are like 1,1,2

  CDE news

  is

  We get 3 values as 1,1,2

  ABC (parameters) FOR loop

  FOR LOOP

  i: = i + 1;

  x_tab (i): = id

  END LOOP;

  .....

  .....

  .....

  x_tab. Delete;

  commit;

  end of loop

  If we did not add internal cursor, what I mean is that it holds (x_tab (i)) 2 first values (either same or not) and the following values is also stored in 2 values, I need 3 values

• The values are not displayed in the user interface

  Hello.
  
  I use jdev 11.1.1.5
  
  I need to refersh tha table
  
  I had created a TPTrialBal EO with corresponding VO. I had dragged and dropped it as an adf:table
  
  I had also created an adf:button named build., when I click on this button, some values are inserted into the TPTrialBal I need to show the value inserted in the user interface.,.
  How can I do this.,.
  
  could someone help me pls

  After update of data in the table add patialTrigger to the table component.
  You can do it by doing this. In the behavior section property table contains call partial property triggers here you
  adjustable from which component partial triggers this component, you can select your command button.

• Displaying an Enum value and the name of the element when the values are not sequential

  Hello

  I use Enum and controls indictators successfully with shared and modbus variables.

  For example:

  Name of the element Value

  Off:                0

  Start 1

  On                2

  Œuvres enum Setup, I don't need to look for a cheat sheet to convert the name of the element in its value, I see the name of the item in my order/indicator.

  My new variables, I'm currently managing look like this:

  Name of the element Value

  Code 0 x 201

  Beginning Code 0 x 202

  Code 0 x 001

  Any ideas how I can display the value and the name of the element on a façade. (for a control and indicator)

  For enumerations, it seems that the item values must go 0,1,2,3,4,5

  I found the solution:

  http://digital.NI.com/public.nsf/allkb/79BA4505AE8C755E86256FB2000140B0

  use a ring of text and deselect the sequential box

• Instead of trigger is running, but the values are not inserted into the view

  I created a view
  create or replace view as select e.department_id, e.last_name, d.department_name employee e, Department d where e.department_id = d.department_id;
  
  create or replace trigger trgg instead of inserting it on vns for each line
  declare
  The CNT number;
  Start
  Select count (*) in the cnt of employees where department_id =:new.department_id;
  If cnt = 0 then
  insert into employees (department_id, last_name) values(11,'nandu');
  end if;
  Select count (*) in the cnt of the Department where department_id =:new.department_id;
  If cnt > 0 then
  insert into dept (department_name) values('wrestling');
  end if;
  end;
  /
  This is the code required. .plz answer the right

  create or replace view
  vns as
  select e.department_id,e.last_name,d.department_name
  from employees e,departments d
  where e.department_id=d.department_id;
  
  create or replace trigger trgg
  instead of insert on vns
  for each row
  declare
  cnt number;
  begin
  select count(*) into cnt from employees where department_id=:new.department_id;
  if cnt=0 then
  --insert into employees(department_id,last_name) values(11,'nandu');
  insert into employees(employee_id,email,hire_date,job_id,department_id,last_name)
                 values(207,'[email protected]',sysdate,'AC_MGR',11,'nandu');   --- Values you have to choose!!
  end if;
  select count(*) into cnt from departments where department_id=:new.department_id;
  if cnt>0 then
  insert into departments(department_id, department_name) values(11, 'wrestling');  -- department_id is needed
  end if;
  end;
  /
  
  -- testing with existing dept id = 10
  
  insert into vns(department_id) values(10);
  
  SQL> select * from departments where department_id = 11;
  
  DEPARTMENT_ID DEPARTMENT_NAME                MANAGER_ID LOCATION_ID
  ------------- ------------------------------ ---------- -----------
             11 wrestling
  

  Requirement, you must be knowing well
  Show you how the trigger must be according to your point of view and logic inside the trigger or you recreate in order to avoid the required values in the trigger body.

  Thank you!

• The elements are duplicated in the left pane of the library.

  When I go to "chrome://browser/content/places/places.xul" items in the left pane seems a copy as in the picture I have attached. Is it possible to fix this before creating a new profile?

  You have never imported an HTML backup?

  For problems with the file places.sqlite (bookmarks, historical) database, you can check in the Firefox profile folder.

  • http://KB.mozillazine.org/Bookmarks_history_and_toolbar_buttons_not_working_-_Firefox
  • https://support.Mozilla.org/KB/bookmarks+not+saved#w_fix-the-bookmarks-file
  • Maintenance: https://addons.mozilla.org/firefox/addon/places-maintenance/

• After the transfer of the library to new Mac, all the songs are duplicated

  I got a new iMac and launched iTunes and signed on my Apple account, where all my music presented themselves as available in iCloud.

  I then transferred the iTunes library to the iMac for my old Mac laptop.  Now each song appears twice, once with the cloud, indicating that it is not on my computer but in the cloud and the cloud is dashed outline, indicating that the path on my computer is awaiting transfer to the cloud.

  I don't know if it's just another bug of iTunes/iCloud or if I messed up the transfer.

  Any suggestions?  Thank you!

  Argelius wrote:

  I then transferred the iTunes library to the iMac for my old Mac laptop.

  How and what exactly did transfer you from the old to the new computer?

• Misssing MSINSTALLER cannot add new software until the values are reset.

  Tried to install new software: IE...    QuickBooks

  Printer drivers / scanner etc...

  HP Pavilion DV5000 w / Windows XP Media edition currently installed (SP n ° 3).

  Has worked with Plumchoice for more than 8 hours online for this problem.  Removed some items that were hidden in my Webroot Spysweeper and all I get is a faster computer.     I had an event log with a missing HKEY, who was replaced by their reimage software but still has problems installation, he was told that the registry needs to be rebuilt or to destroy the operating system and start over...  WHAT CAN I DO?

  Hi DonaldWhite355,

  Follow the steps in the article.

  http://support.Microsoft.com/kb/2438651

• Select only records where the column values are not all equal to zero

  Hi everyone, it seems so easy, but it has left me speechless on the research in a way that is clean, easy to achieve. I know when someone replies, I'm going to kick me. So, let's assume this is what I have:
  

  with mytable as (
  select 'Type 1' as itemtype, 'JAN' as monthname, 0 as theval from dual union all
  select 'Type 1' as itemtype, 'FEB' as monthname, 1 as theval from dual union all
  select 'Type 1' as itemtype, 'MAR' as monthname, 5 as theval from dual union all
  select 'Type 1' as itemtype, 'APR' as monthname, 1 as theval from dual union all
  select 'Type 1' as itemtype, 'MAY' as monthname, 4 as theval from dual union all
  select 'Type 1' as itemtype, 'JUL' as monthname, 0 as theval from dual union all
  select 'Type 1' as itemtype, 'AUG' as monthname, 0 as theval from dual union all
  select 'Type 1' as itemtype, 'SEP' as monthname, 1 as theval from dual union all
  select 'Type 1' as itemtype, 'OCT' as monthname, 7 as theval from dual union all
  select 'Type 1' as itemtype, 'NOV' as monthname, 1 as theval from dual union all
  select 'Type 1' as itemtype, 'DEC' as monthname, 2 as theval from dual union all
  
  select 'Type 2' as itemtype, 'JAN' as monthname, 0 as theval from dual union all
  select 'Type 2' as itemtype, 'FEB' as monthname, 0 as theval from dual union all
  select 'Type 2' as itemtype, 'MAR' as monthname, 0 as theval from dual union all
  select 'Type 2' as itemtype, 'APR' as monthname, 0 as theval from dual union all
  select 'Type 2' as itemtype, 'MAY' as monthname, 0 as theval from dual union all
  select 'Type 2' as itemtype, 'OCT' as monthname, 0 as theval from dual union all
  select 'Type 2' as itemtype, 'NOV' as monthname, 0 as theval from dual union all
  select 'Type 2' as itemtype, 'DEC' as monthname, 0 as theval from dual
  )
  select
    itemtype,
    sum (case monthname when 'JAN' then theval else 0 end) as JAN,
    sum (case monthname when 'FEB' then theval else 0 end) as FEB,
    sum (case monthname when 'MAR' then theval else 0 end) as MAR,
    sum (case monthname when 'APR' then theval else 0 end) as APR,
    sum (case monthname when 'MAY' then theval else 0 end) as MAY,
    sum (case monthname when 'JUN' then theval else 0 end) as JUN,
    sum (case monthname when 'JUL' then theval else 0 end) as JUL,
    sum (case monthname when 'AUG' then theval else 0 end) as AUG,
    sum (case monthname when 'SEP' then theval else 0 end) as SEP,
    sum (case monthname when 'OCT' then theval else 0 end) as OCT,
    sum (case monthname when 'NOV' then theval else 0 end) as NOV,
    sum (case monthname when 'DEC' then theval else 0 end) as DEC
  from mytable
  group by itemtype
  order by itemtype

  I need an external application around it or something which will select only 'Type 1'... that is, if all months are each equal to zero, do not include the record in the result set.
  
  In summary to get a total of zero is not an option, because I could have-15 and + 15 in different columns, in which case, the recording should be displayed.
  
  Something as simple as... 'not the case (oct = 0 and 0 nov and dec = 0...) at the end is all it seems to me necessary. I thought to add a case for each column clause, but that seems not very effective. Ideas?
  
  Thanks in advance!
  Mark
  
  Edit... I know not what follows will work using the MINUS operator, but my actual query is really huge, and I don't want to have to write it twice...
  {code}
  Select
  ItemType,
  sum (case monthname when "JAN" then Val else 0 end) such as JAN,.
  sum (case when monthname 'FEB', then Val 0 otherwise end) by Feb.
  sum (case when monthname 'MAR', then Val 0 otherwise end) like MARS,
  sum (case monthname when "APR" then Val else 0 end) as APR.
  sum (case when monthname 'MAY', then Val else 0 end) either.
  sum (case when monthname "JUN", then Val 0 otherwise end) as JUN.
  sum (case monthname when "JUL" then Val else 0 end) as JUL,.
  sum (case monthname when "AUG" then Val else 0 end) as AUG.
  sum (case monthname when "MS" then Val else 0 end) as MS.
  sum (case monthname when "OCTS" then Val else 0 end) OCT.
  sum (case monthname when "NOV" then Val else 0 end) as NOV.
  sum (case monthname when 'DEC' then Val else 0 end) as DEC
  FROM MyTable
  Group of itemtype
  
  less
  
  Select
  ItemType,
  Jan, Feb, mar, Apr, may, June, July, August, Sept, oct, nov, dec
  de)
  Select
  ItemType,
  sum (case monthname when "JAN" then Val else 0 end) such as JAN,.
  sum (case when monthname 'FEB', then Val 0 otherwise end) by Feb.
  sum (case when monthname 'MAR', then Val 0 otherwise end) like MARS,
  sum (case monthname when "APR" then Val else 0 end) as APR.
  sum (case when monthname 'MAY', then Val else 0 end) either.
  sum (case when monthname "JUN", then Val 0 otherwise end) as JUN.
  sum (case monthname when "JUL" then Val else 0 end) as JUL,.
  sum (case monthname when "AUG" then Val else 0 end) as AUG.
  sum (case monthname when "MS" then Val else 0 end) as MS.
  sum (case monthname when "OCTS" then Val else 0 end) OCT.
  sum (case monthname when "NOV" then Val else 0 end) as NOV.
  sum (case monthname when 'DEC' then Val else 0 end) as DEC
  FROM MyTable
  Group of itemtype
  )
  where (oct = 0 & nov = 0 and dec = 0 and jan = 0 and 0 = Feb and mar = 0
  apr = 0 and may = 0 and = 0 jun and Jul = 0 and aug = 0 and Ms = 0
  )
  order of itemtype
  {code}
  
  Change again... OK, I guess that I am answering my own question here, but I think that by using a WITH to write the main request once clause and then selecting * twice using the MINUS operator between where the second query is where (oct = 0, etc.) is what I need. If anyone has better suggestions, please let me know! Here's the logic of nickname for what I come up with to date...
  
  {code}
  WITH mainquery as (select all)
  Select * from mainquery
  less
  Select * from mainquery where (oct = 0, nov = 0, etc...)
  {code}
  
  Thanks again!
  Mark
  
  Published by: user455268 on March 1, 2012 19:13
  
  Published by: user455268 on March 1, 2012 19:16

  Hello

  You can do it with a HAVING clause:

  select
    itemtype,
    sum (case monthname when 'JAN' then theval else 0 end) as JAN,
    sum (case monthname when 'FEB' then theval else 0 end) as FEB,
    sum (case monthname when 'MAR' then theval else 0 end) as MAR,
    sum (case monthname when 'APR' then theval else 0 end) as APR,
    sum (case monthname when 'MAY' then theval else 0 end) as MAY,
    sum (case monthname when 'JUN' then theval else 0 end) as JUN,
    sum (case monthname when 'JUL' then theval else 0 end) as JUL,
    sum (case monthname when 'AUG' then theval else 0 end) as AUG,
    sum (case monthname when 'SEP' then theval else 0 end) as SEP,
    sum (case monthname when 'OCT' then theval else 0 end) as OCT,
    sum (case monthname when 'NOV' then theval else 0 end) as NOV,
    sum (case monthname when 'DEC' then theval else 0 end) as DEC
  from mytable
  group by itemtype
  HAVING      MIN (theval)     != 0
  OR      MAX (theval)     != 0
  order by itemtype
  ;
  

  If the values are all 0, then the MIN and MAX will be 0.
  If the MIN or MAX is not 0, the values are all 0.

  This assumes that the combination (itemtype, monthname) is unique, because it is in your sample data.
  If this is not the case, start with a subquery that GROUPs BY itemtype, monthname, so that when you get to the main request, this combination will be unique.