This output on AWR report mean?

Similar Questions

• The main events in AWR report

  Hi all

  11.2.0.1

  AIX 6.1

  I had this big event awr report.

  Can you help me how to interpret this please. Or what is the value of looking here?  Thank you very much

  The main events in AWR report

  I have

  n

  Snap              s       Snap                                                                                                    A

  Snap the t hard event time start Avgwt DB A

  Time event ID # (m) expected grade (s) (ms) % S waiting class

  ------ --------------- --- ---------- ---------------------------------------- ----- -------------- -------------- -------- ------- ------ ---------------

  13902 13/09/16 09:00 1 60.05 os thread start 1 140,00 11.08 79,11 56 0,0 Concurrency

  13902 13/09/16 09:00 60.05 1 CPU time 2 0.00 0.00 9,45 48 0.0 CPU

  13902 13/09/16 09:00 1 60.05 log file parallel write 3 1506.00 1.84 1.22 9 0.0 IO system

  13902 13/09/16 09:00 1 60.05 control file parallel write 4 1291.00 1.41 1.09 7 0.0 IO system

  13902 13/09/16 09:00 1 log file sync 60.05 5 721.00 1.03 1.43 commit 5 0.0

  13903 13/09/16 10:00 1 60.05 os thread start 1 138.00 10.36 75,10 47 0.0 Concurrency

  13903 13/09/16 CPU 60.05 1 10:00 hour 2 0.00 0.00 10,28 47 0.0 CPU

  13903 13/09/16 10:00 1 60.05 log file parallel write 3 1575.00 1.73 1.10 8 0.0 IO system

  13903 13/09/16 10:00 1 60.05 direct path read 3 486.00 1.73 3.56 8 0.0 IO user

  13903 13/09/16 10:00 1 60.05 control file parallel write 4 1285.00 1.51 1.17 7 0.0 IO system

  13903 13/09/16 10:00 1 log file sync 60.05 5 823.00 1.08 1.32 commit 5 0.0

  13904 13/09/16 11:00 60.05 1 CPU time 1 0.00 17,06 0.00 CPU 32 0.0

  13904 13/09/16 11:00 1 60.05 os thread start 2 145.00 10,65 73.46 20 0.0 Concurrency

  Thanks, I just tell the users, there is no problem in the comic book, and the stats is normal and no suspiscious activity and that the problem is in the minds of users only.

• that means the great value of 'Call' recursive % in AWR report?

  Hi all.
  
  I saw "call recursive %: 85%" supported the section profile an awr report.
  --> This could be a problem?
  --> otherwise, depends on the type of application?
  
  ---
  
  From my understanding,.
  
  1. the client calls-> calls DBMS user
  2 recursive calls-> calls for DBMS internal, such as the process of background, function or procedures.
  
  ---
  
  I would like to hear about your experience.
  
  Thanks in advance.
  Best regards.

  a recursive call is a call, for example, which must be completed before the user SQL can be completed.

  Read this to understand what I mean:

  http://it.Toolbox.com/blogs/confessions/how-Oracle-really-works-27-recursive-calls-20300

  Osama...

• Number of processors and cores in AWR report

  Hello

  I have a report AWR to my system and a couple of entries confuse me.

  Q1. It's showing 3 carrots, 2 Sockets and 4 processors. The CPU and the Sockets, I understand that 2 chips with 2 processors per chip so 4 CPU.

  What confuses me, is the fact that it shows 3 carrots. Is that that by CPU cores? Othererwise 3-4 makes no sense?

  Q2. What is the difference between DB, time CPU and CPU DB?

  My understanding is that DB time is the time used by the process, including the time processor and wait time. Because a system can have more than one processor, it is quite natural that DB time may exceed to elapse time - since you have multiple processors that contribute to this time (I guess that DB time cannot be really more time elapse * our processors?)

  In fact, you could say if DB time does not exceed the time to elapse, then you have a Nock idle system?

  My understanding of time CPU, is that it's time where each process actually gets treatment CPU (so it does not time-out). I think that the AWR report confusingly used the term time CPU and CPU DB, to mean the same thing?

  clearly greatly appreciated

  Jim

  
  

  Hi Jimbo,

  Q1. "Nuclei" in the CWA report represents the quantity of physical processor cores and the "processors" takes into account the simultaneous multithreading so in your case, one option could be a CPU Socket has a dual core (not type hyperthreading) and the other CPU Socket has one heart (hyperthreaded). If this is the case, you will have 3 physical 4 CPU cores, (because it takes into account the hyper-threaded architecture) and 2 taken. It's just an option, you will need to check it out.

  Q2. No-Idle wait events are events that are not classified by Oracle as a "Idle" of events to wait wait:

  • Example of Idle wait-event: SQL * Net client message (server process is waiting for the client process to do something)
  • Idle wait-event example: db file scattered read (event waiting user IO representing a multilock read as full scan of the table or full scan small index.
  • You can get a complete list of active waiting events by running:

  Select name from v$ event_name where wait_class <> "inactive".

  • You can get a full list of the events of inactive waiting by running:

  Select name from v$ event_name where wait_class = 'Idle '.

  
  

  DB time is therefore the sum of all events of active waiting and also the CPU time that is a statistic:

  • You can see the value of the amount of time CPU in 10s of miiliseconds (centisecondes) for an exeuting session:

  SELECT THE VALUE

  FROM v$ sesstat JOIN v$ statname USING (statistics #)

  WHERE name = 'CPU used by this session' AND SID =

  • You can see the value of the time total CPU in 10s of milliseconds (centisecondes) for the instance of exeuting:

  SELECT the value from v$ sysstat

  WHERE name = 'CPU used by this session.

• begin and end in awr report

  Hi all

  Hope all are well. I need your help, I doubt reading the awr report.

  Summary of the report

  Cache sizes

  	Start	End
  Cache buffers:	572 M	572 M	Std block size:	8K
  Size of the shared pool:	408 M	408 M	Log buffer:	13 604 K

  My question is what is 'START' and 'END' in the figure above and why to cache buffer and shared pool sizes are the same for BEGIN and END.your help appreciated, thanks in advance.

  Best regards.

  size of the buffer at the start of the snapshot cache

  size of the buffer at the end of the snapshot cache

  Shared at the beginning of the snapshot pool

  Shared pool, at the end of the snapshot

  So that means: either you did not Oracle or Oracle to change these settings dynamically does not need to change.

  Always send four-digit version of your database and platform info. This forum is not keeping track of it.

  ---------------

  Sybrand Bakker

  Senior Oracle DBA

• questions about the awr report &amp; sqlt

  Hi guys,.

  DB version: 10.2.0.5

  Need your advice.

  For my AWR report, I put the 30-day retention period. From my understanding, the information in awr report are taken from several views of dba_hist *.

  Points of view takes only those albums n intenstive SQL Statistics on resources?

  I ask this because I have a doubt. Let's say that on 18/03/2014, I detected a long SQL with sql id xxx.

  Using SQLT (such method), I can only see the historical performance of Plan (delta) for this particular SQLs 16/03, 17/03, 18/03.

  In this case, we can say that the SQLs shot only 3 days for the last 30 days? Or it can also mean that the particular SQL was not classfified at the top of the page resource n intensive 18/02 to 15/03 SQLs (probably use a better plan - for example: plan a different value)?

  Thank you

  That is right.

  Concerning

  Jonathan Lews

• What is the measure of the value "Waiting" in AWR report?

  Event	Expected	% Time - out	Wait total (s) times	AVG wait (ms)	Waiting for /txn
  SQL * Net more data from dblink	406 747		466	1	184.13
  reading of scattered files DB	28 659		330	12	12.97
  SQL * Net message from dblink the	30 115		254	8	13.63
  log file parallel write	21 021		177	8	9.52

  Hi all

  As the example below, I question what is the measure of the value "Waiting" in the section "event wait" AWR report?

  Because "Expected" the value is high, but "Queue time Total (s)" is low. example "SQL * Net message from dblink the" a 30 115 "expected' but 'Queue time Total (s)' lower 'DB file scattered read' w 28 659 'wait '.

  Could you please explain more about the value "waiting"?

  Thank you

  Hiko

  taohiko wrote:

  Event	Waits	%Time -outs	Wait total (s) times	Avg wait (ms)	Waits /txn
  SQL * Net more data from dblink	406 747		466	1	184.13
  reading of scattered files DB	28 659		330	12	12.97
  SQL * Net message from dblink the	30 115		254	8	13.63
  log file parallel write	21 021		177	8	9.52

  Hi all

  As the example below, I question what is the measure of the value "Waiting" in the section "event wait" AWR report?

  It is simply a... count the number of times where the system had to "WAIT" on the specified event.

  Because "Expected" the value is high, but "Queue time Total (s)" is low. example "SQL * Net message from dblink the" a 30 115 "expected' but 'Queue time Total (s)' lower 'DB file scattered read' w 28 659 'wait '.

  Watch "AVG time-out.    In one case, there are fewer occurrences of the event, but the average wait by event time was higher.

  If I buy 3 burgers and pay $1000 each

  or I buy 500 burgers and pay $1.00 each.

  Why 3 hamburgers cost more than 500 burgers?

  Could you please explain more about the value "waiting"?

  "Waiting" is the number of times that the system had to wait for the named event, during the sampling period.

  "Total wait time" is the total time (measured in seconds) spent waiting on all occurrences of the specified event, during the sampling period.

  "Avg" wait"is the time (expressed in milliseconds) means spent on each occurrence of the specified event, during the sampling period.

  It seems pretty obvious.  You count how many times it happens something (wait), you measure it, time spent doing this something fracture (total wait time) and tells you the total time spent (total wait time) by the number of times it happened (waits) to find out the average time spent on each occurrence of that something.

  Thank you

  Hiko

• time in AWR report:

  Hello!
  
  Please advise on my AWR report:
  
  Library Cache activity
  First DB/Inst: ONL/onl snaps: 18386-18388 (elapsed time: 7 205 715 s time DB: 15065,22 dry).
  Second DB/Inst: ONL/onl Snaps: 18554-18556 (elapsed time: 7 145 385 sec time DB: 7911,7 sec)
  
  Here the comma separates the fractions of a second of the entire part?
  Why DB time > elapsed time?
  
  Thank you and best regards,
  Pavel

  Pavel wrote:
  my last post is correct?

  You mean this statement?

  time difference for reasons of parallel operation?

  I can't tell, too less to comment about.

  Aman...

• AWR report analysis

  DB version: 10 gr 2
  
  After watching Top 5 wait events and SQL Statistics, what is the next most important thing I should look for an AWR report?
  

  It would depend on the top events of the page you saw. For example, if you saw the events of 5 waiting albums, he had very high DB file scattered read, this means that there are statements that go mainly to access the complete table. You must search on these queries. Or if there is a high Contetion lock, for example, Shared Pool latch Conteions, this means that there are many sttement that is intended for hard analysis and dispute this lock of. So, you should look for these sql who are cnstants more and do not bind variable.
  So this isn't a standard way, but it's according to what you see. On the blog of Jonathan Lewis, there is an excellent series of how to read the Statspack report. I suggest to read. This would make a good base to cross with AWR report also.
  HTH
  Aman...

• (Admin) is not in the sudoers file.  This incident will be reported.

  So I got a Mac on OS X El Capitan and I can't use sudo from the admin; Yes the main admin, I repeat, ADMIN account. Whenever I use a sudo command, the error message appears.

  «(Name of the Admin) is not in the sudoers file.»  This incident will be reported. »

  How can I fix? This is not ordinary.

  First of all, it is not a "main ADMIN' - it is not Windows. Any user can be configured to administer the Mac. Nothing is special about one.

  As for the sudoers file, if you do not have an account that can access (including your admin, again, the ADMIN can not), you cannot change it.

  There are several ways to create a new admin account. And here's one: http://apple.stackexchange.com/questions/164331/i-don ' t-have-administrator-account t-on-my-mac

  When you say, «so I got a Mac...» "Do you mean that you're someone else, used a Mac?

  If Yes, then you should just start Internet recovery, wipe the drive completely and reinstall OS X. That will fix the problem for you and all the others left by the previous owner.

• awrrpti script - awr report fails

  Friends...

  OS: Linux

  DB: 11 GR 2

  I'm trying to solve this riddle, supposed to be a simple fix but not able to finish it...

  We run awrrpti script to generate AWR report for the whole day. What I do is ask DBA_HIST_SNAPSHOT and get the snapshot min (first) and max (last) of the day. Then I fed that range from snap_id to awrrpti script to generate AWR report all day to single instance.

  It works perfectly well, but if instance gets restarted during the day then my approach above does not work and AWR report generation fails.

  Current approach:

  1. the DBA_HIST_SNAPSHOT query

  2. download MIN (snap_id), MAX (snap_id) for the day

  3. power #2 to awrrpti via bind variable

  4 generate the unique HTML report for the instance

  Query used to collect the id of component software snap-in min/max:

  Select min (snap_id), max (snap_id)

  Of

  (select snap_id, begin_interval_time, end_interval_time

  of dba_hist_snapshot

  where begin_interval_time > = trunc(sysdate-1)

  and being_intreval_time < = trunc(sysdate-1+23/24)

  );

  Tips to avoid failures of AWR report generation if instance gets restarted?

  How to go to the entry below in simple sql? It is possible to start «WITH max_startup...» "in the sql script?

  Yes, there is no problem. Is it just another way to write the query

  But you can use this one instead:

  SELECT MIN(dhs.snap_id) min_snap_id, MAX(dhs.snap_id) max_snap_id
  FROM DBA_HIST_SNAPSHOT dhs,
  (SELECT MAX(startup_time) max_startup_time FROM DBA_HIST_SNAPSHOT) mst
  where dhs.startup_time = mst.max_startup_time
  and begin_interval_time >= trunc(SYSDATE-1)
  and begin_interval_time <= trunc(sysdate-1+23/24)
  ;
  

  again will try, test and update this blog

  Forum! Please, I beg you.

  Concerning

  Juan M

• Why has no expected output to the report job history?

  Hello

  I use web services BEEP to schedule reports and retrieve them (by e-mail and the history of work report in the web interface) and have had success with it. Today, when I added a new report and changed a few things, I can no longer see or retrieve the output of the report as a result of the scheduled task.

  So, to be clear, under 'output & Delivery' for a history of particular job, in the table, the output shows, the only line of the table just text in it who told you: "no available exit. My previous experience, this kind of thing always had a link to the report that was generated.

  Here are some of the remarkable things, I changed:

  -a different user to the web service BEEP ScheduleService authentication

  -another folder stores reports

  -layouts are BI Publisher templates instead of RTF models

  Scheduled reports are sent by e-mail (e-mail is the only destination I specify) with success always, so I receive the report by email very well... but I need to be able to get the release of the web interface, after it was sent by email too. And he has not shown when I view the error report work history.

  Any ideas on what Miss me which prevents the release of the report to appear in the report job history? Maybe an administration that disables the Central exit by user/folder?

  Thank you...

  
  Kevin

  It turned out that the name of the job was too long. The name of the job may include a maximum of 100 characters.

• Bug? : cannot execute predefined "last awr" report with the latest version of the SQL Developer

  Using sql developer before 4.x... report works fine

  Using SQL developer 4.0.0.13... report fails with ORA-01422

  using the actual query to generate awr against the same range of component snap works perfectly

  I opened a SR on the question

  Thank you

  It's always a good idea to open a SR when you are able.  I assume that you have already received a response from support.  For others I wondered about this, the question is likely related to running the report against a CCR environment, as indicated in the following bug:

  Bug 18132564 - LAST AWR REPORT FAILS WITH ORA-01422 IN CCR ENVIRONMENTS
  

  The call of the AWR report requires parameters for a DB and an ID of Instance, so that the report should run, as in earlier versions, for only the current instance, or be modified to run all instances in the cluster.

  Kind regards

  Gary

  SQL development team

  P.S.: And, in fact, a discussion prior forum - ai2 4.0-AWR and ASH giving ora-01427

  lead following bugs are connected and supposed to be fixed for SQL Developer 4.0...

  
  

  Bug 17481944 - PERFORMANCE PANELS NEED AWR/ASH/ADDM FOR RAC ENVIRONMENTS SUPPORT

  
  

  ... with the developer commenting

  I've added a number instance selection control to the various reports: ASH,.
  AWR, difference and SQL. The control is supposed to be visible when the
  connection is a RAC system, tests should a RAC.

  So if you are not on a RAC system, or are on CARS but do not see the selection number instance control, please let us know.

  Post edited by: Gary Graham

• How to take awr report

  A little confused in the generation of awr report using awrrpt.sql

  Here are the pictures that we have in the repository.

  	8257 November 13, 2013 02:00	1
  	8258 November 13, 2013 02:30	1
  	8259 November 13, 2013 03:00	1
  	8260 November 13, 2013 03:30	1
  	8261 November 13, 2013 04:00	1
  	8262 November 13, 2013 04:30	1

  And the test run we had was between 02:15 at 03:45.  What shots should I choose as the ID of the snap-snap-in begin end snap ID.

  I got this question when I saw how the shots were taken as snap ID 8258

  SNAP_ID BEGIN_INTERVAL_TIME

  END_INTERVAL_TIME

  --------- ------------------------------ ----------------------------

  8258 13 NOVEMBER 13 02.00.19.314 AM

  13 NOVEMBER 13 02.30.23.284 AM

  where I was going to select 8257 as the ID of the snap-snap-in begin.

  Which snap IDs makes more sense for the time window of 02:15 at 03:45.

  Thank you

  Siva.

  Yes, after 02:15 activity is recorded in wink 8258, because at the time the 8257 snap was taken (02:00) the workload has not watched yet. In order something to be registered, it must extend the instant collection interval. Instant is the current state of the instance, and if you set the snapshot collection at intervals of more than an hour, you might be missing information. Also there is no need to set the very short interval (provable 15 min.). An hour is an average value, and that's by default. On the first response I wrote snap 8527 because under 'time window' 8527 is correct snap_id, but in the context of statistical collection snap_id 8528 is correct.

  Post edited by: IvicaArsov

• question of AWR report

  Hi all

  Oracle 11 g RAC 2

  Solaris

  get below the question when awr report generating.

  type: report

  number of days: 10

  declare

  *

  ERROR on line 1:

  ORA-20200: Instant Begin Id 10020 does not exist for this database instance.

  ORA-06512: at line 22

  Please someone help me why over error. (Note am capable of generating the report of 5 days but not 10 days)

  Thank you

  Mike.

  Eventually, the retention period is less than 10 days?

  DBA_HIST_SNAPSHOT query to find the oldest snapshot available.

  Hemant K Collette