To select adjacent records of same amount

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  Hi all
  
  I write the code below, to select multiple records in table advanced for the update after clicking on the button update in the Search Page.
  I write this code in Processform request, but I got the exception when I run the code below.
  
  
  If (PageContext.GetParameter ("UpdateOnSeaBtn")! = null)
  {
  Am = (XxSupppacklistAMImpl) pageContext.getApplicationModule (webBean) XxSupppacklistAMImpl;
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  PackingListSeaVORowImpl line;
  
  HashMap vParm = new HashMap();
  
  Row [] rows = upDtVO.getFilteredRows ("SingleSelection", "Y");
  int fetCount = upDtVO.getRowCount ();
  System.out.println ("Teh recovered rowcount is:," + fetCount);
  
  RowSetIterator multiIter;
  multiIter = upDtVO.createRowSetIterator ("multiIter");
  multiIter.setRangeStart (0);
  multiIter.setRangeSize (fetCount);
  
  
  for (int i = 0; i < fetCount; i ++)
  {
  Row = (PackingListSeaVORowImpl) multiIter.getRowAtRangeIndex (i);
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  {
  If (Row.GetAttribute ("ItemNumber")! = null)
  {
  Object vitemNum = row.getAttribute ("ItemNumber");
  System.out.println ("The selected element Num is:," + vitemNum);
  vParm.put ("ItemNumber", vitemNum);
  
  pageContext.setForwardURL ("OA.jsp?page=/xxfls/oracle/apps/po/packlist/webui/XxSuppalistcrealistPG", / / here, I got the exception below)
  NULL,
  OAWebBeanConstants.KEEP_MENU_CONTEXT,
  NULL,
  vParm,
  false, / / RetainAM
  OAWebBeanConstants.ADD_BREAD_CRUMB_NO,
  OAWebBeanConstants.IGNORE_MESSAGES);
  }
  }
  }
  
  multiIter.closeRowSetIterator ();
  
  }
  }
  }
  
  could you, please, can someone help on this.
  
  
  I got below exception to the side server when it is run the code above.
  Error (125,48): method setForwardURL (java.lang.String, null, null, byte, java.util.HashMap, boolean, java.lang.String, byte) is not not in the interface oracle.apps.fnd.framework.webui.OAPageContext
  
  Kind regards

  Hello

  832859 wrote:

  for (int i = 0; i)<>
  {
  Row = (PackingListSeaVORowImpl) multiIter.getRowAtRangeIndex (i);
  If (Row.GetAttribute ("SingleSelection")! = null)
  {
  If (Row.GetAttribute ("ItemNumber")! = null)
  {
  Object vitemNum = row.getAttribute ("ItemNumber");
  System.out.println ("The selected element Num is:," + vitemNum);
  vParm.put ("ItemNumber", vitemNum);

  > pageContext.setForwardURL"OA.jsp.page=/xxfls/oracle/apps/po/packlist/webui/XxSuppalistcrealistPG",//here I got below exception

  NULL,
  OAWebBeanConstants.KEEP_MENU_CONTEXT,
  NULL,
  vParm,
  false, / / RetainAM
  OAWebBeanConstants.ADD_BREAD_CRUMB_NO,
  OAWebBeanConstants.IGNORE_MESSAGES);
  }
  }
  }

  -Here is you call pageContext.setForwardURL loop.
  >

  I got below exception to the side server when it is run the code above.
  Error (125,48): method setForwardURL (java.lang.String, null, null, byte, java.util.HashMap, boolean, java.lang.String, byte) is not not in the interface oracle.apps.fnd.framework.webui.OAPageContext

  -check 5th param should nt be vParm if it is null

  Finally... After the for loop ends call... y bcz assume this page grouped 10 rows can he navigate both on the next page...:

  pageContext.setForwardURL ("OA.jsp?page=/xxfls/oracle/apps/po/packlist/webui/XxSuppalistcrealistPG",
  NULL,
  OAWebBeanConstants.KEEP_MENU_CONTEXT,
  NULL,
  NULL,
  false, / / RetainAM
  OAWebBeanConstants.ADD_BREAD_CRUMB_NO,
  OAWebBeanConstants.IGNORE_MESSAGES);
  }

  Concerning
  Meher Irk

  Published by: Meher Irk on March 31, 2011 19:54

• By selecting certain records by using the check box

  Hello
  
  I have a similar problem mentioned in this thread Re: select specific records using the checkbox I got if I have only one primary key value in the work table. I don't know how to handle it when I have several primary keys of the table I want to use for filtering?
  
  Thank you.

  Hello

  You can use rowid
  First report

  SELECT APEX_ITEM.CHECKBOX(1,e.rowid) chk,
  e.*
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  Use even submit after processes.
  And target page report

  SELECT e.*
  FROM emp e
  WHERE EXISTS(
  SELECT 1
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  WHERE c.collection_name = 'P46COL'
  AND c.c001 = e.rowid)
  

  Kind regards
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  Thank you!
  

  Copy the following code:
  
  Select * from employee where startdate<>
  

  This means:

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• Selection of records in the same table problem

  Hi all
  
  I have the following table
  

  with emp as (
             select '11' A,'aaa' B, '40' C from dual union all
             select '11','bbb', '40' from dual union all
             select '33','ccc', '30' from dual union all
             select '44','ddd', '20' from dual union all
             select '11','eee', '10' from dual
            )

  My results should be
  

  A           B        C
   
  11        aaa      40
  11        bbb     40      
  11        eee     10

  Basically the requirement is select different combination of values in the column 'B' need to know what is the value of 'A' (it must be the same for all records of three)
  
  
  Hope in this sense.
  
  
  See you soon
  
  Sexy

  an attempt to rephrase:

  you want all the files "aaa", "bbb" and "EEA" where, for each set of column A, where they exist.

  that is, if games to have only "aaa" and "bbb" but not "eee" in column B, then you don't want to retrieve this record?

  Try this:

  SQL> with emp as (
    2  select '11' A,'aaa' B, '40' C from dual union all
    3  select '11','bbb', '40' from dual union all
    4  select '33','ccc', '30' from dual union all
    5  select '44','ddd', '20' from dual union all
    6  select '11','kkk', '20' from dual union all
    7  select '10','eee', '20' from dual union all
    8  select '11','eee', '10' from dual
    9  )
   10  select a, b, c
   11   from (select emp.*, count(*) over (partition by a) cnt
   12    from emp
   13   where b in ('aaa','bbb','eee'))
   14   where cnt = 3
   15  /
  
  A                                B                                C
  -------------------------------- -------------------------------- --------------------------------
  11                               eee                              10
  11                               aaa                              40
  11                               bbb                              40
  
  3 rows selected.
  

  Published by: WhiteHat June 30, 2011 11:04

• Query to select other records and then the same in 2 tables

  Dear all,
  
  My database is 10 gr 2 and OS is Linux.
  I have 2 tables with the same fields and almost the same data. There are just a few different lines in table 1 and table 2 that do not match each other.
  
  I need to select these non-matching rows in both tables in a single request.
  
  Kindly help on that.
  
  Best regards, Imran

  You have at LEAST two ways!

  (SELECT * FROM table_A
  minus
  SELECT * FROM table_B)
  union all
  (SELECT * FROM table_B
  minus
  SELECT * FROM table_A)
  /
  

  For example:

  SQL> create table table_a (col_1 number,  col_2 varchar2(5));
  
  Table created.
  
  SQL> create table table_b (col_1 number,  col_2 varchar2(5));
  
  Table created.
  
  SQL> insert into table_a values (1,'A');
  
  1 row created.
  
  SQL> insert into table_a values (2,'B');
  
  1 row created.
  
  SQL> insert into table_b values (1,'X');
  
  1 row created.
  
  SQL> insert into table_b values (2,'Z');
  
  1 row created.
  
  SQL> insert into table_a values (3,'C');
  
  1 row created.
  
  SQL> insert into table_b values (3,'C');
  
  1 row created.
  
  SQL> commit;
  
  Commit complete.
  
  SQL>
  SQL> select * from table_a minus select * from table_b
    2  union all
    3  select * from table_b minus select * from table_a
    4  /
  
       COL_1 COL_2
  ---------- -----
           1 X
           2 Z
  
  SQL> (select * from table_a minus select * from table_b)
    2  union all
    3  (select * from table_b minus select * from table_a)
    4  /
  
       COL_1 COL_2
  ---------- -----
           1 A
           2 B
           1 X
           2 Z
  
  SQL>
  

  Hemant K Collette

• Bill standard and a note of credit with the same amount

  Hello
  I have a standard AP invoice with an amount of €100 and the note of credit-€100.
  
  The standard invoice and credit rating have the same supplier and distribution and status are validated and recorded is Yes.
  
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  If I try to create a payment with this invoice and credit note, I get an error because I can't make a payment to zero.
  
  I do so with a suspense account? How can I do?
  
  Thanks in advance!

  Hello.

  Enter a zero payment amount and select the two documents.

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  It is a simplified version of my reality... But let's concentrate on this simple scenario.

  -- The technical id is used for foreign keys. 
  -- [document_id is a business key and the combination of document_id version is unique]
  CREATE TABLE documents 
  (
    technical_id NUMBER(10), 
    document_id number(10),
    version number(10),
    title varchar2(100)
  );
  
  
  CREATE TABLE attachments
  (
    technical_id number(10), -- primay key 
    attachment_id number(10),  -- concat of attachment_id and version is unique!
    version number(10),
    language varchar2(100),
    title varchar2(100)
  );
  
  
  CREATE TABLE doc_attachments
  (
    document_id number(10),
    attachment_id number(10)
  );
  

  Now, imagine the following inserts.

  INSERT INTO documents(technical_id, document_id, version, title) VALUES(1, 1, 1, 'document 1 (version 1)');
  INSERT INTO documents(technical_id, document_id, version, title) VALUES(2, 1, 2, 'document 1 (version 2)');
  INSERT INTO documents(technical_id, document_id, version, title) VALUES(3, 1, 3, 'document 1 (version 3)');
  
  
  INSERT INTO attachments(technical_id, attachment_id, version, language, title) VALUES(99, 10, 1, 'fr', 'attachment 10 (version 1)');
  INSERT INTO attachments(technical_id, attachment_id, version, language, title) VALUES(98, 10, 1, 'en', 'attachment 10 (version 2)');
  INSERT INTO attachments(technical_id, attachment_id, version, language, title) VALUES(97, 10, 2, 'fr', 'attachment 10 (version 3)');
  
  
  INSERT INTO doc_attachments(document_id, attachment_id) VALUES(1, 99);
  INSERT INTO doc_attachments(document_id, attachment_id) VALUES(1, 98);
  
  
  INSERT INTO doc_attachments(document_id, attachment_id) VALUES(3, 97);
  

  In this scenario,.

  -J' have version 3 of the same document.

  -Two different attachments; one of them has two version.

  -3 links between documents and attachments.

  If you pay attention, you will notice that I have no connection between the attachment and the second version of the document. And also, I have different languages for the same attachment. In this scenario, I want to the next exit. The list of all versions of a document with their attachments (all languages) and "gaps" with attachments previous.

  The logic is a bit tricky to understand the output. Basically, for each document, I want to see all the 'last home"received for this folder. Later we hear the fixation with the largest number of version for the same id of attachment.

  doc_tech_id doc_version attac_tech_id attachment_version language
  ----------- ----------- ------------- ------------------ -------- 
           1            1            99                  1       fr -- the first and second insert are generating these two first output records.
           1            1            98                  1       en 
  
  
           2            2            99                  1       fr -- since I did not have any link between the second version of the doc and the attachment, 
           2            2            98                  1       en -- I should have exactly the same as the previous version. So I duplicate records.
           
           3            3            97                  2       fr -- I have a link in the join table between document in version 3 and the second version of the attachment.
           3            3            98                  1       en                     
  

  It is a scenario... I wonder if this is doable in a single query? Can someone help me?

  Thank you

  with

  documents such as

  (select 1 technical_id, 1 document_id, version 1, title "document 1 (version 1)" of all the double union)

  Select 2,1,2, "document 1 (version 2)" dual Union all

  Select 3,1,3, "document 1 (version 3)" of the double

  ),

  As spare part

  (select 99 technical_id, 10 attachment_id, 1 version, language 'fr', "attachment 10 (version 1)" title of all the double union)

  Select 98,10,1, 'FR', "attachment 10 (version 2)" dual Union all

  Select 97,10,2, 'fr', "attachment 10 (version 3)" of the double

  ),

  doc_attachments as

  (select 1 document_id, 99 attachment_id union double all the)

  Select 1.98 Union double all the

  Select double 3.97

  )

  Select the language, attac_tech_id, doc_tech_id, attac_version, doc_version

  from (select doc.technical_id, doc_tech_id,

  doc.version doc_version,

  ATTS.technical_id attac_tech_id,

  ATTS.version attac_version,

  ATTS. Language,

  ROW_NUMBER() over (partition doc.technical_id, atts.language, doc.version

  order by case when doc.version = 3 then atts.version to another atts.technical_id end desc

  ) rn

  document No.

  left outer join

  doc_attachments x partition by (x.attachment_id)

  On x.document_id = doc.technical_id

  inner join

  Spare atts

  On x.attachment_id = atts.technical_id

  )

  where rn = 1

  DOC_TECH_ID	DOC_VERSION	ATTAC_TECH_ID	ATTAC_VERSION	LANGUAGE
  1	1	98	1	en
  1	1	99	1	en
  2	2	98	1	en
  2	2	99	1	en
  3	3	98	1	en
  3	3	97	2	en

  the order by clause appears to produce the result you expect, but I can't explain why it should be applied

  Concerning

  Etbin

• Re: Error on select multiple records

  I need the script below to select a single record by person_id. But when I run it, I have several recordings by same person_id you I used separate in the Charly.
  
  As you can see below from the result of the query, the person_ids (21934 and 20102) appear twice.
  
  What I want is only one record a.person_id.
  
  Any guidance?
  
  
  
  

  select a.person_id, c.org_name, a.person_type, c.org_code, a.first_name, a.last_name, d.position_title, b.email_address
  from person a, person_emails b, organization c, position_titles d, positions e
  where a.person_id = b.person_id and a.employee_status = 'A' and a.organization_code = c.org_code and a.person_type = 'AMER HIRE' and a.organization_code = e.org_code  and d.position_title_number = e.position_title_number
  order by c.org_name
  ;

  20102 AFRICA Benin AMER HIRE 351801 Robert Tallman EXPERT r
  21934 AFRICA Benin AMER RENTAL 351801 Keith Howard COUNTRY DIRECTOR
  16440 AFRICA Benin AMER HIRE 351801 Jen Norinee EXPERT [email protected]
  20102 AFRICA Benin AMER HIRE 351801 Robert Tallman APCD/RURAL DEVELOPMENT rfrie
  21934 AFRICA Benin AMER RENTAL 351801 John Doe APCD and RURAL DEVELOPMENT
  21934 AFRICA Benin AMER RENTAL 351801 John Doe APCD/PROGRAMMING & TRAINING
  21934 AFRICA Benin AMER RENTAL 351801 John Doe k EXPERT

  You can try this and simply choose the title column that works for you, but for the first or the last title, you will need to fill in the correct sort order for this question:

   SELECT a.person_id
        , c.org_name
        , a.person_type
        , c.org_code
        , a.first_name
        , a.last_name
        , max(d.position_title) max_title
        , min(d.position_title) min_title
        , max(d.position_title)
            keep (dense_rank first order by some_column) first_title
        , max(d.position_title)
            keep (dense_rank last order by some_column) last_title
        , b.email_address
     FROM person a
        , person_emails b
        , organization c
        , position_titles d
        , positions e
    WHERE a.person_id             = b.person_id
      AND a.employee_status       = 'A'
      AND a.organization_code     = c.org_code
      AND a.person_type           = 'AMER HIRE'
      AND a.organization_code     = e.org_code
      AND d.position_title_number = e.position_title_number
    GROUP BY a.person_id
        , c.org_name
        , a.person_type
        , c.org_code
        , a.first_name
        , a.last_name
        , b.email_address
    ORDER BY c.org_name ;
  

  Moreover, in the future try formatting your code is readable with out having to scroll from left to right so.

  Published by: Sentinel on June 4, 2013 13:36