Trying to wrap my brain around self-joins.

Similar Questions

• Self-joins in Discoverer?

  Hello
  
  I'm new to the discoverer. According to the "All discoverer" page, I use the following:
  OracleBI Discoverer 10g (9.0.4.00.00)
  Oracle Business Intelligence Discoverer Plus 10g (10.1.2.55.26)
  Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64bi
  
  I'm looking to create reports of discoverer of data requiring the self-joins, and I wonder if this is even possible.
  
  A simplified form of the query I use looks like the following:

  SELECT
          qll.operand
        , pa.list_header_id
        , pa.list_line_id
  
  FROM
          apps.qp_pricing_attributes        pa
        , apps.qp_pricing_attributes        pa1
        , apps.qp_pricing_attributes        pa2
        , apps.qp_list_lines                qll
  
  WHERE   qll.LIST_LINE_ID                  = pa.LIST_LINE_ID
  AND     pa.PRICING_ATTRIBUTE              = 'PRICING_ATTRIBUTE23'   -- ship dates
  
  AND     qll.list_line_id                  = pa1.list_line_id (+)
  AND     pa1.PRICING_ATTRIBUTE             = 'PRICING_ATTRIBUTE27'   -- origin
  
  AND     qll.list_line_id                  = pa2.list_line_id (+)
  AND     pa2.PRICING_ATTRIBUTE             = 'PRICING_ATTRIBUTE99'   -- item
  
  AND     pa.list_header_id                 =  12050      -- header id
  
  /******************************   TEST DATE   *********************************/
  AND     sysdate
              BETWEEN to_date(pa.PRICING_ATTR_VALUE_FROM,'YYYY/MM/DD HH24:MI:SS')
              AND     to_date(pa.PRICING_ATTR_VALUE_TO,  'YYYY/MM/DD HH24:MI:SS')

  Essentially, the above query returns price several attributes for a given rate and collapses them all to a single line of output.
  
  So are even possible in discoverer of self-joins? I note that in the documentation
  Oracle® Business Intelligence Discoverer Plus User Guide 10 g Release 2 (10.1.2.1) B13915-04
  the only reference to self-joins seems to be regarding the LAG function, although even that seems to offer very small overview of the use of this function.
  
  I guess I could ask a DBA to create a view and a report out of sight. But are there other options?
  
  THX.
  
  -Wayne

  In SQL * Plus, you can write the following SQL code
  Select a.empno, a.ename, b.empno, b.ename
  of the emp a, b of the emp
  where a.mgr = b.empno;

  In Discoverer, you cannot join EMP to itself.

  work around
  ========

  Import the EMP table in your sector of activity for
  a second time, giving you a table EMP1. Then, create a join between EMP and EMP1:

  EMP. MGR = EMP1. ENAME

• Wrap the object around a path?

  Hello!

  I was wondering if there is a quick way to do it. Watch here: 2015-02-19_0920 - library of losse2010 I am trying to wrap the links in the chain along the "curly" of the text. At first, I thought that I cut and paste the link and then turn them to follow the line but realized it's a lot of your time! I was wondering if there is a way to align the links throughout the text 'lines' of faster way using a path or a brush any?

  THX

  What you want is a brush model.

  https://helpx.Adobe.com/Illustrator/using/brushes.html

  https://helpx.Adobe.com/Illustrator/how-to/Illustrator-create-pattern-brush.html

• Need help with a self-join query

  Hello
  I have A table with the following data
  
  OID parent_oid
  4 of 10
  4 2
  2 2
  12 6
  6 6
  
  parent_oid is the parent of the oid. I would like a query that displays the final parent of the oid. The result must indicate the following
  
  Final parent OID
  2 of 10
  4 2
  2 2
  12 6
  6 6
  
  I use Oracle 10 g. I am familiar with free joins, but that alone will not do the job. Thank you!

  Hello

  arizona9952 wrote:
  ... I am familiar with free joins, but that alone will not do the job.

  You are absolutely right!

  A self-join 2-way would work for lines have no parent, or lines which are directly related to their final ancestor (such as the oid = 4), but not for what anyone further.
  A 3-way self-join would work to a level more away from the last row, but no more. That would be enough with the small set of sample data that you posted, but it won't work if you have added a new rank parent_id = 10.
  An N - way self-join would work for up to N + 1 levels, but no more.

  You need something that can go to any number of levels, such as CONNECT BY:

  SELECT     CONNECT_BY_ROOT oid     AS oid
  ,     parent_oid          AS final_parent
  FROM     a
  WHERE     CONNECT_BY_ISLEAF     = 1
  CONNECT BY     oid     = PRIOR parent_oid
       AND     oid     != parent_oid
  ;
  

  Published by: Frank Kulash, February 22, 2010 19:09

  On sober reflection, I think that a request from top down, as one below, would be more effective than a motion up and down, like the one above:

  SELECT     oid
  ,     CONNECT_BY_ROOT     parent_oid     AS final_parent
  FROM     a
  START WITH     parent_oid     = oid
  CONNECT BY     parent_oid     = PRIOR oid
       AND     oid          != PRIOR oid
  ;
  

• Request Cross-listing (Partition by Clause? Self-join?)

  Hello
  
  I need a query that cross-list will be a teacher teaches this semester of courses. Essentially, both fields must be the same (i.e.: CourseTitle & Section), while the third field is different (for example: subject).
  
  For example, Max Power is a Professor teaching the 3 course, one co-inscrit (123 ENG and JRL 123):
  

  LastName     FirstName     Subject     Section     CourseTitle
  Power          Max          ENG     123     English Composition
  Power          Max          ENG     452     Robert Frost Poetry     
  Power          Max          JRL     123     English Composition
  Power           Max          ENG      300     Faulkner & Twain

  The result of the desired query is:

  LastName     FirstName     Subject     Section     CourseTitle
  Power          Max          ENG     123     English Composition
  Power          Max          JRL     123     English Composition

  Basically, I don't need that the courses co-inscrit in the output. Is this an instance where I use a "Partition by Clause' or should I create a self-join?
  
  Well thanks for all help and comments.

  Hello

  user11137889 wrote:
  Unfortunately, I can't create tables. I don't have permission. I can't modify, add or remove all the data.

  It is no possible to work! You should have your own schema in a database of development, perhaps on your own machine, where you can create tables freely. You can develop or test software effectively without this ability.
  You must post CREATE TABLE and INSERT to your sample data, even if you can't test. Without this, all anyone can do is guess.

  If you want to only count each topic once, then replace COUNT (*) by COUNT (DISTINCT subject). Here, 'subject' can be almost any kind of expression, for example:

  count( DISTINCT substr ( ssbsect_ptrm_code
                          , 1
                   , 1
                   )
       ) over ( partition by  ssbsect_crse_numb
                    ,          scbcrse_title
           ) cnt
  

• Best self-join necessary.

  Is there a more effective way to get data at the bottom of the example I created? It is a completely false attempt to imitate what I really need.
  
  I need to get the registration information based on a query that uses a global fuction based on the value of a field. The data in the record I need have the MAX (due_date) and in the case below, it would be recording #7
  

  CREATE TABLE TEST_TABLE (  
  ORDER_ID               VARCHAR2(15 Byte),
  CUST_ID                VARCHAR2(15 Byte),
  DUE_DATE               DATE,
  PAID_DATE              DATE,
  NAME                   VARCHAR2(25 Byte),
  ADDRESS                VARCHAR2(20 Byte),
  CITY                   VARCHAR2(20 Byte),
  STATE                  VARCHAR2(20 Byte),
  ZIP                    VARCHAR2(10 Byte)
  ); 
  COMMIT;
  
  INSERT INTO TEST_TABLE VALUES (1,11,'09-JAN-09','11-JAN-09','John Smith','1234 Main St.','Orlando','FL','35555');
  INSERT INTO TEST_TABLE VALUES (2,12,'21-JUL-09','21-JUL-09','Sally Sue','12 Way.','Orlando','FL','35568');
  INSERT INTO TEST_TABLE VALUES (3,16,'15-APR-09','15-APR-09','Bill Walsh','4 Rogers Ave.','Orlando','FL','85563');
  INSERT INTO TEST_TABLE VALUES (4,11,'20-AUG-09','20-AUG-09','John Smith','1234 Main St.','Orlando','FL','35555');
  INSERT INTO TEST_TABLE VALUES (5,98,'04-OCT-09','04-OCT-09','Philip Rogers','990 S New St.','Orlando','FL','96584');
  INSERT INTO TEST_TABLE VALUES (6,45,'05-NOV-09','06-NOV-09','Jack Johnson','234 New Main South.','Orlando','FL','36544');
  INSERT INTO TEST_TABLE VALUES (7,11,'01-OCT-09','06-OCT-09','John Smith','1234 Main St.','Orlando','FL','35555');
  INSERT INTO TEST_TABLE VALUES (8,12,'01-OCT-09','04-OCT-09','Sally Sue','887 New Way Apt1234.','Orlando','FL','87965');
  INSERT INTO TEST_TABLE VALUES (9,76,'10-MAY-09','10-MAY-09','Mike Jackson','41 N Alt Way','Orlando','FL','21458');
  COMMIT;
  
  
  select 
       tt2.order_id,
       tt2.paid_date,
       tt2.due_date,
       tt2.name,
       tt2.zip
  from
      (
      select 
          cust_id,
          max(due_date) as d_date
      from TEST_TABLE tt 
          where cust_id = '11'
      group by cust_id
      )tt1
      join TEST_TABLE tt2 on tt1.cust_id = tt2.cust_id and d_date = tt2.due_date

  ORDER_ID PAID_DATE END_DATE NAME ZIP
  7-10/06/2009-10/01/2009 John Smith 35555
  
  These data are required as well as other MULTIPLE tables, so this is not the only join or the one self-join. Yet once, would not join only there are some with more than 9 tables with more than 4 DB so group by at the end could get quite complex.
  
  Thanks in advance.

  Just scan the table once. Analytical use

  select order_id, paid_date, due_date, name, zip
    from (
          select order_id, paid_date, due_date, name, zip, cust_id, max(due_date) over() due_date_max
            from test_table
           where cust_id = '11'
         )
   where due_date = due_date_max
  

• Reg: self-join n subqry.

  Hi friends
  can you tell me, in void query and Self join query will be faster and gives better performance.
  Example:
  
  Select * from emp where a.empid in (select empid from deparment where deptid = 10);
  OR
  Select * from emp a, Department b where a.empid = b.empid and deptid = 10'
  
  Who will be the best. Please suggest.
  
  -Best regards,.
  Aude - Darling

  you will understand by yourself if you check the plan to explain to the two statements...
  If not, please post them to the above statements

  Ravi Kumar

• Trying to wrap text around an image in Dreamweaver CC2015.

  If I click on an image of the property bar rises, but in older versions by clicking on an image shows the bar properties with additional choices: spacing vertically and horizontally and "Align" with text wrap as a choice. Is now gone?  I read the other posts, but they seem to require coding rather than this quick method in design mode.  Or am I missing something?  Thank you.

  Is now gone?

  Yes.  Panels that has promoted old coding methods have disappeared.

  Dreamweaver is now much more web standards aware helps you produce better code.

  Use CSS floats, margins, and padding on your image.

  .floatLt {

  float: left;

  Padding: 1%;

  margin: 2%;

  border: 1px solid #EEE;

  }

  

  This text will wrap around the floating element. This text will wrap around the floating element. This text will wrap around the floating element. This text will wrap around the floating element. This text will wrap around the floating element. This text will wrap around the floating element.

  Nancy O.

• Text wrapping is square around a png image

  Hi I have a png as a file below.

  

  I know how to make a wrap text around an image, but the text surrounds the image as a rectangle

  

  and I want to wrap around the image, not the rectangle.  I tried to add a white background for the png and cutting the edges, see screenshot below.  I used red to display purposes.

  

  But she always wraps as a rectangle.

  Appreciate your help.

  

  This works! When the PNG is incorporated.

• How do wrap you text around images?

  I am trying to learn CSS, and I can't understand how to wrap text around pictures...

  http://aldenmarin.com/BTP/btpindex.htm

  My images are in columns. Also, what is the best way to adjust margins inside a column?

  Apply a rule to float left or float right to your image and include all desired margins

  {.imgfloatleft}

  float: left;

  margin-bottom: 0;

  right margin: 20px;

  }

• Wrapping a design around a 3D object

  Hello, I am trying to understand how take the fish scale model that I did (on ovals) and processing it so that it is not only the form of the three sections of the sketch, but also that the scales remain aligned between them once the Blue design is wrapped around an object (3D) real.

  

  I'm doing a sticker for all the world a model airplane.  That's what looked like the real plane:

  

  

  I intend hand painting the rest of the pieces of fish, but the 1/144 scale (about 25mm long), fish scales are a little small to paint evenly!

  If someone wants to play with the real .ai file, I downloaded on my server:

  www.wingsofwar.org/UserImages/FuselageWrap.ai

  Thank you for your time and help,

  Keith

  

  Here is a copy of your original file.

  JET

• Could not find the wrapping of text around an image in Keynote

  I see post of 2007 where you can't wrap text around an image in Keynote. Is this always the case? Hope not... very disappointing if so.

  There is no tool to wrap text in Keynote. Text wrapping is a tool of print media to maximize space in the column in print, if that's what you try to do, use the Apple's Pages.

  Keynote is a presentation of screen based application, (slide show) so there is very little use for the text wrapping.

  You can do a work around, but it is not perfect:

  • Place the image on the slide

  

  • Place the two shapes on the slide, one for the area of text, image size
  • order click on the two forms;     to select both
  • Format > forms > subtract shapes;     will cut a hole in the greatest shape
  • Paste the text into the larger shape

  

  • format text

  

• I want to wrap the text around a transparent sphere

  I want to be able to wrap text around a transparent in illustrator sphere, such as the text of Forefront is darker than the background text.  I followed this tutorial logo 3D (new) - YouTube video, but I can't understand what is happening after expansion to 06:13.  Can someone help me, please and thank you.

  Assuming that you got to the part where the object is expanded (06:10), depending on whether you choose the "direct selection tool" and select only the outline of the circle (invisible, but if you wanted to see go to view > outline) carefully not choose anything else and delete (twice). And then you just object > Dissocier 3 times. as a result your forehead back text will be selectable.

• Unable to retrieve the data using self join

  I'm trying to find the time required to close a ticket. The ticket goes through different stages: NEW, INPROCESS, CLOSED, REOPENED. If the ticket is reopened so the next step would be INPROCESS and then CLOSED.

  The CC_TICKET_INFO table contains information on the last step of the ticket. Table CC_TICKET_HISTORY contains information on every step of the ticket.

  The challenge here is that if the ticket is reopened so it should be considered as 2 instances instead of 1.

  Trial of stages: NEW-INPROCESS-> CLOSE >

  Second instance of stages: REOPEND -> INPROCESS-> CLOSE.

  Following SQL is to generate the data:

  CREATE TABLE CC_TICKET_INFO

  (

  TICKET_ID VARCHAR2 (20 BYTE) NOT NULL

  TICKET_STATUS VARCHAR2 (60 BYTE)

  , created_date timestamp (6)

  , LAST_CHANGED timestamp (6)

  , ASSIGNED_TO VARCHAR2 (20)

  CONSTRAINT PK_CC_TICKET_INFO PRIMARY KEY

  (

  ticket_id

  )

  )

  CREATE TABLE CC_TICKET_HISTORY

  (

  TICKET_ID VARCHAR2 (20 BYTE) NOT NULL

  TICKET_STATUS VARCHAR2 (60 BYTE)

  , CREATED_DATE TIMESTAMP (6) NOT NULL

  ASSIGNED_TO VARCHAR2 (255 BYTE)

  CREATED_BY VARCHAR2 (60 BYTE)

  CONSTRAINT PK_CC_TICKET_HISTORY PRIMARY KEY

  (

  TICKET_ID

  CREATED_DATE

  )

  )

  insert into cc_ticket_history values ('D21207155', 'NEW', 6/28/2013-17:28:59 ', null, 'jsg - st');

  insert into cc_ticket_history values ('D21207155', 'INPROCESS', 6/28/2013-17:48:19 ', 'ah-eg","ah-eg");

  insert into cc_ticket_history values ('D21207155', 'CLOSED', 6/28/2013 18:54:23 ', 'ah-eg","ah-eg");

  insert into cc_ticket_history values ('D21207155', 'REOPENED', 7/2/2013 19:55:04 ', 'ah-eg","jsg - st");

  insert into cc_ticket_history values ('D21207155', 'INPROCESS', 7/2/2013 20:11:17 ', "sr - eg", "sr - eg");

  insert into cc_ticket_history values ('D21207155', 'CLOSED', 7/2/2013 23:06:16 ', "sr - eg", "sr - eg");

  insert into CC_TICKET_INFO values ('D21207155', 'CLOSED', 6/28/2013-17:28:59 ', ' 02/07/2013-23:06:16 ', "sr - eg");

  ______________________________________________________________________

  I want to find the time difference between 6/28/2013 18:54:23 'and 6/28/2013-17:28:59 ' (first instance)

  and between 23:06:16 7/2/2013 ' and 7/2/2013 19:55:04 "(second instance)

  Is the closest, I make the through this query:

  Select L.ticket_id, L.CREATED_DATE, R.CREATED_DATE as close_date, L.TICKET_STATUS, R.TICKET_STATUS cc_ticket_history cc_ticket_history join RIGHT L R on (L.rowid < R.rowid) where (L.TICKET_STATUS = 'NEW' R.TICKET_STATUS AND 'CLOSED' =) OR (L.TICKET_STATUS = 'REOPENED' AND R.TICKET_STATUS = 'CLOSED');

  Can it be done through SQL?

  Hello

  ORA - aff wrote:

  Etbin thanks for the reply. I think you're closer!

  The first 3 orders insert above form the first instance. The second 3 inserts statements form the second instance.

  Ideally, I'd like the output to something like this (values taken by top of insert statements):

  Ticket_ID STATUS CREATED_DATE CLOSED_DATE TIME_DIFFERENCE

  D21207155 CLOSED ON 28/06/2013 17:28:59 6/28/2013 18:54:23

  D21207155 CLOSED ON 07/02/2013 19:55:04 07/02/2013 23:06:16

  You can do this by using the analytical LAST_VALUE function:

  WITH got_opened_date AS

  (

  SELECT ticket_id, ticket_status, created_date

  LAST_VALUE (CASE

  WHEN ticket_status IN ('NEW', 'REOPENED')

  THEN created_date

  END

  IGNORES NULL VALUES

  ) OVER (PARTITION BY ticket_id

  ORDER BY created_date

  ) AS opened_date

  OF cc_ticket_history

  )

  SELECT ticket_id

  ticket_status AS status

  opened_date AS created_date

  created_date AS closed_date

  NULL AS time_difference

  OF got_opened_date

  WHERE ticket_status = 'CLOSED '.

  ORDER BY ticket_id

  closed_date

  ;

• Seen the lock of brain on Left Join

  Always on Oracle 11.2.0.1.0
  
  Examples of data
  

  CREATE TABLE theEmails (
  RID NUMBER(10) PRIMARY KEY,
  employee NUMBER(6),
  emailType VARCHAR2(4),
  emailAddress VARCHAR2(50),
  emailActive number(1)
  )
  ;
  INSERT INTO theEmails VALUES(778437,231509,'OTHR','[email protected]',0);
  INSERT INTO theEmails VALUES(847168,231509,'WRK1','[email protected]',0);
  INSERT INTO theEmails VALUES(784690,231509,'OTHR','[email protected]',1);
  INSERT INTO theEmails VALUES(1459884,239868,'OTHR','[email protected]',0);
  INSERT INTO theEmails VALUES(1485781,239868,'OTHR','[email protected]',1);
  INSERT INTO theEmails VALUES(1485782,239868,'WRK1','[email protected]',0);
  INSERT INTO theEmails VALUES(1501028,231509,'WRK1','[email protected]',1);
  INSERT INTO theEmails VALUES(1492288,239868,'WRK1','[email protected]',1);
  INSERT INTO theEmails VALUES(1456785,239865,'OTHR','[email protected]',0);
  INSERT INTO theEmails VALUES(1489166,239865,'WRK1','[email protected]',0);
  INSERT INTO theEmails VALUES(1482668,239865,'WRK1','[email protected]',0);
  INSERT INTO theEmails VALUES(1482667,239865,'OTHR','[email protected]',1);
  
  
  
  CREATE TABLE thePeople (
  employee NUMBER(6),
  recordNum NUMBER(2),
  lastName VARCHAR2(20),
  firstName VARCHAR2(20)
  )
  ;
  
  INSERT INTO thePeople VALUES(231509,0,'P','Michelle');
  INSERT INTO thePeople VALUES(239868,0,'K','Dan');
  INSERT INTO thePeople VALUES(239865,0,'T','Mary');

  So, here is my SQL that does not work well:
  

  SELECT p.employee, p.recordNum, p.lastName, p.firstName, e.emailaddress, e.emailactive, e.emailtype
  FROM thePeople p LEFT JOIN theemails e ON p.employee = e.employee
  WHERE (e.emailactive = 1)
        AND
        (e.emailtype = 'WRK1')
        AND
        (e.emailaddress LIKE '%school.edu')
  ;

  AND this:
  

  SELECT p.employee, p.recordNum, p.lastName, p.firstName, e.emailaddress, e.emailactive, e.emailtype
  FROM thePeople p LEFT JOIN theemails e ON p.employee = e.employee
  WHERE (e.emailactive = 1 OR e.emailactive IS NULL)
        AND
        (e.emailtype = 'WRK1' OR e.emailtype IS NULL)
        AND
        (e.emailaddress LIKE '%school.edu' OR e.emailaddress IS NULL)

  Both give me this:
  
  employee | record | lastName. firstName. emailAddress. emailActive | emailType
  231509 | 0 | P     | Michelle | [email protected] | 1. WRK1
  
  
  But what I need is the following:
  employee | record | lastName. firstName. emailAddress. emailActive | emailType
  239868 | 0 | K     | Dan |      |     |
  231509 | 0 | P     | Michelle | [email protected] | 1. WRK1
  239865 | 0 | T     | Mary |          |
  
  
  Email from Dan is not included, because his "wrk1" email does not stop it school.edu
  E-mail Mary is not included, because his 'wrk1' email is not active.
  However, I need to come back with their numbers of name registration and employee.
  
  
  Once it works, I'll add employee = number in the WHERE clause, because I only need to find a person both for the actual production.
  
  What I am doing wrong?
  
  Thank you!
  
  Michelle

  Hello

  WHERE is the filtering actually record the selection.

  In your case, you might want to include in your LEFT OUTER JOIN ON conditions:

  SELECT p.employee, p.recordnum, p.lastname, p.firstname
       , e.emailaddress, e.emailactive, e.emailtype
    FROM    thepeople p
         LEFT JOIN
            theemails e
         ON     p.employee = e.employee
            AND e.emailactive = 1
            AND e.emailtype = 'WRK1'
            AND e.emailaddress LIKE '%school.edu';
  

  If you put them in your JOIN conditions actually join Chronogram of table theemails that adapt to the conditions of membership.
  As you use LEFT [OUTER] JOIN unmatched chronogram thepeople table will be displayed even when the theemail table column appears with a NULL value in the output files

  I hope that I was able to unlock your brain. :-)

  Kind regards.
  Al

  Published by: Alberto Faenza on 25 October 2012 16:58
  Additional note added