Two guests on the same column

Similar Questions

• apex5 pre-release - url filter applies to the two IRs with the same column name

  I've implemented 2 interactive reports on the same page, one on EMP (static id Throne) and the other on DEPT (deptir static id). Both the DEPTNO column. If I create the following filter via the URL: IR [throne] EQ_DEPTNO:20, the filter is applied to the two interactive reports.

  

  Hello

  Please let us know. It has the same root cause as your other reported problem. It's bug #20764255, which has already been identified and corrected on our development environment. A fix will be released in our production release.

  Concerning

  Patrick

  Member of the APEX development team

  My Blog: http://www.inside-oracle-apex.com

  APEX Plug-Ins: http://apex.oracle.com/plugins

  Twitter: http://www.twitter.com/patrickwolf

• Different guests on the same column

  Gurus:
  
  I have a requirement where we need to have Date guests separated for 4 different promotions.
  Now, I was thinking about the presentation configuration variable, but then it does not work with 'Between' condition.
  
  So how can I compare a fact for 4 different promotions (Sun) with 4 dates different (Sun) in the same report?
  
  I don't know if this is possible.
  Please help me.
  Thank you.
  
  Vinay

  I'm not sure that I understand your question completely, but it seems you need to get the same value (say sale) measure for 4 different dates in the same table.

  My suggestions would be to create dims again and use union all with each union report report led at different times of Sun.

• How to exchange the two values in the same column by using the UPDATE?

  Hi all
  
  I have a table named TEST, and it has a column called A.
  
  and has values as follows:
  
  A
  ------
  10
  20
  30
  40
  50
  
  My question is how to move '10' instead of '20' and '20' instead of '10' in the column? This permutation is only for the first two values (10, 20)
  
  Note: Must be only in SQL, not in PLSQL.
  
  Any advice?
  
  Thanks in advance?

  Update
  test
  the value a = decode(a,10,20,20,10,a);

  Alexander gelin
  http://nimishgarg.blogspot.com/

• DB two types in the same column

  Hello
  
  I have a column in an interactive report that displays a digit or a varchar2 (string) according to another column.
  
  What I want here is when it displays the string while it is, but when you display a number, then it sholud be justified right and 3 digits after that comma should be presented (7,000 or 7.123...). To display the number I am converting it to a char using to_char. If I didn't ' t make an error comes out.
  
  Is it possible to get what I want somehow?
  
  Please suggest.
  Thank you.

  Assuming that the maximum width of the column is known and is used a fixed-width font, I tend to choose an alignment and then add (or add) a number appropriate spaces for the string, or numeric values (in office, of course, on the alignment you chose).

  Justin

• subtracting the two rows in the same column

  Hello
  I have the following table with about 6000 lines of different year_month, but I compare and subtract v
  Contribution of the Organization Year_month
  Kano 200000 JAN-2011
  KADUNA 300000 JAN-2011
  ABUJA 400000 JAN-2011
  Kano 300000 FEB-2011
  KADUNA 200000 FEB-2011
  ABUJA 600000 FEB 2012
  I want to choose a year_month runtime to subtract the contribution of the first contribution of the second year_month year_month and give me the result, as shown in the following table
  Difference of JAN - FEB 2011 - 2011 organization
  Kano 200000 300000-100000
  300000 200000 100000 KADUNA
  ABUJA 400000 200000 600000
  Here is my code back will too
  
  create or replace function "GET_MONTHLY_VALUE".
  (q_name in VARCHAR2,
  hmoCode in VARCHAR2)
  return VARCHAR2
  is
  number of C1;
  Start
  Select NHIS_CONTRIBUTION in c1 of CONTRIBUTION_MGT where upper (YEAR_MONTH) = upper (q_name) and upper (ORGANIZATION) = upper (hmoCode);
  
  return to c1;
  exception when NO_DATA_FOUND THEN
  Returns a null value.
  end;
  
  -a call to the function above:
  
  create or replace function process_cont_monthly return varchar
  
  is
  Cursor cont_cursor is select ORGANIZATION of CONTRIBUTION_MGT;
  Start
  for
  cont_rec loop cont_cursor
  First, select GET_MONTHLY_VALUE(:p26_month,cont_rec.ORGANIZATION) GET_MONTHLY_VALUE(:p26_month2,cont_rec.ORGANIZATION) second,
  ABS (GET_MONTHLY_VALUE (:p26_month,cont_rec.ORGANIZATION)-GET_MONTHLY_VALUE(:p26_month2,cont_rec.ORGANIZATION)) difference
  of CONTRIBUTION_MGT;
  
  end loop;
  commit;
  end;
  I got totally confused and do not know what to do next
  Any help and the best guide is appreciated

  Analytics can also be used (assuming that you store dates as dates, ORDER BY working properly)

  create table t(org varchar2(10),mon date, cont number);
  insert into t(org,mon,cont) values ('Kano',to_date('201101','YYYYMM'),200000);
  insert into t(org,mon,cont) values ('KADUNA',to_date('201101','YYYYMM'),300000);
  insert into t(org,mon,cont) values ('Kano',to_date('201102','YYYYMM'),300000);
  insert into t(org,mon,cont) values ('KADUNA',to_date('201102','YYYYMM'),200000);
  commit;
  
  select * from t;
  ORG        MON                    CONT
  ---------- ---------------------- ----
  Kano       01-JAN-2011 00:00:00   200000
  KADUNA     01-JAN-2011 00:00:00   300000
  Kano       01-FEB-2011 00:00:00   300000
  KADUNA     01-FEB-2011 00:00:00   200000 
  
  select org,cont1 start_month,cont2 end_month,cont1-cont2 difference
    from (
          select org,mon,cont cont1,
                 lead(cont) over (partition by org order by mon) as cont2
          from t
          where  mon in (to_date('201101','YYYYMM'),to_date('201102','YYYYMM'))
          )
  where cont2 is not null;
  
  ORG        START_MONTH END_MONTH DIFFERENCE
  ---------- ----------- --------- ----------
  KADUNA          300000    200000     100000
  Kano            200000    300000    -100000 
  

• A target table is in charge of two different sources but the same columns, but a source is one database and another in a flat file.

  We all hope you are doing well.

  I have a business problem to implement in ODI 11 G. It's here. I'm trying to load a target table from two sources that have the same column names. But a source is to the file format and the other is in the Oracle database.

  That's what I think I'll create two mappings in the same interface by using the Union between the sources. But I don't know how the interface would connect to different logical architecture to connect to two different sources.

  Thank you

  SM

  You are on the right track, all in a single interface. Follow these steps

  (1) pull model of your data in the designer of the source file and your table model target to the target pane.

  (2) all relevant columns map

  (3) in the source designer to create a new dataset and choose as the UNION join type (this will create a separate tab in the source designer pane)

  (4) select the new dataset tab in the source designer pane and pull your source oracle table data model in the designer of the source. All columns that are relevant to the target card

  (5) make sure that your staging location is set to a relational technology i.e. in this case the target would be an ideal candidate because it is where the ODI will organize the data from source two files and oracle and perform the UNION before loading to the target

  If you want to watch some pretty screenshots showing the steps above, take a look at http://odiexperts.com/11g-oracle-data-integrator-part-611g-union-minus-intersect/

• Two or more SRID in the same column?

  Hello, I am working with Oracle Spatial, and I have a problem with the SRID.
  
  I have a column in a table with the SDO_GEOMETRY type and I need to create a Spatial Index to use. But to create a Spatial Index first, I need to insert metadata into the table incluied SRID: for example
  
  Insert in user_sdo_geom_metadata (table_name, column_name, srid, diminfo) values ('Spatial_Test', 'GEOMETRIA', 8307, SDO_DIM_ARRAY (SDO_DIM_ELEMENT('LONGITUDE',-180,180,0.5), SDO_DIM_ELEMENT ('LATITUDE',-90, 90, 0.5)));
  
  But I need to work with more than one SRID in this column. Is there anyway to have two or more SRID in the same column? How? and if I insert them, can they give any problem?
  
  Thank you very much.
  
  Good bye.

  ZeyKa,

  . . . . You can transform and store all your geometries in SRID 8307 and then turn to their original SRID when you SELECT them.

  -- "Example: Transform geometry from  to SRID 8307 for storage"
  -- "NOTE: Replace  and  with your values"
  INSERT INTO MyTable (ID, geometry,RenderSRID) VALUES (1, SDO_CS.TRANSFORM(,8307), );
  

  -- "Example: Transform stored geometry back to its "
  SELECT SDO_CS.TRANSFORM(geometry,RenderSRID) FROM MyTable WHERE ID = 1;
  

  Kind regards
  Noel

• By comparing the values in the same column

  Hello
  
  I have a requirement to do the following:
  
  The guest of the dashboard has two drop downs as 'Acct number 1' and others as 'Acct number 2 ". Both are the same column from the database. When two different values are chosen from the prompt, it should produce a report with the following 5 colomns, 'ACCT1', 'SALES AMOUNT ACCT1', "ACCT2", "SALES AMOUNT ACCT2", "DIFFERENCE".
  
  I tried to use a variable of presentation in the command prompt and it fills my column pther having the same value I have input for the first prompt.
  
  How can I do this? Thanks for your time and your help.

  Hello

  You can try it at the level of the report.

  * Ensure that you have set your guests with different effects. Suppose that the two PVs are acc1 and acc2.
  * Report, add below filter
  Account number is equal to @{acc1} {defualtvalue}
  OR
  Account number is equal to @{acc2} {defualtvalue}
  This will filter the report by the two account numbers.
  * Now apply below in your fx of all columns.

  "ACCT1: ' @{acc1} {defualtvalue}"
  ACCT1 SALES AMOUNT: FILTER (with the HELP of SalesCol (AccountNumber = ' @{acc1} {defualtvalue}'))
  "ACCT2: ' @{acc2} {defualtvalue}"
  ACCT2 SALES AMOUNT: FILTER (with the HELP of SalesCol (AccountNumber = ' @{acc2} {defualtvalue}'))
  DIFFERENCE: FILTER (with the HELP of SalesCol (AccountNumber = ' @{acc1} {defualtvalue}'))-FILTER (with the HELP of SalesCol (AccountNumber = ' @{acc2} {defualtvalue}'))

  Thank you

• Two objects with the same name

  Hi all

  In my production database, there is a materialized view and a table with the same name. The two objects have the same number and type of columns.

  Record from user_object table

  OBJECT_NAME

  SUBOBJECT_NAME

  OBJECT_ID

  DATA_OBJECT_ID

  OBJECT_TYPE

  CREATED

  LAST_DDL_TIME

  TIMESTAMP

  STATUS

  TEMPORARY

  GENERATED

  SECONDARY

  NAMESPACE

  EDITION_NAME

  TEST_OBJ

  151373

  151373

  TABLE

  22/06/2012

  22/06/2012

  2012-06 - 22:15:39:30

  VALID

  N

  N

  N

  1

  TEST_OBJ

  152287

  MATERIALIZED VIEW

  22/06/2012

  08/03/2012

  2012-06 - 22:16:08:46

  VALID

  N

  N

  N

  19

  I have another mode to normal display, TEST_NORMAL_VIEW, which selects the data of TEST_OBJ.

  Then, on which table data select. Please give some input on this subject.

  Kind regards

  Matondo

  A materialized view has 2 objects internally for her

  1. the materialized view (it is more of a model)

  2. the table that stores the actual data.

  So when you create a materialized view, you can see 2 objects created by querying the USER_OBJECTS.

  See this

  SQL> create materialized view my_test_mv as select * from emp;
  
  Materialized view created.
  
  SQL> select object_type, object_name, data_object_id from user_objects where object_name = 'MY_TEST_MV';
  
  OBJECT_TYPE        OBJECT_NAME          DATA_OBJECT_ID
  ------------------- -------------------- --------------
  TABLE              MY_TEST_MV                  1638964
  MATERIALIZED VIEW  MY_TEST_MV
  

  Now, you may notice that DATA_OBJECT_ID has null for the MV. DATA_OBJECT_ID is the Segment where the data is stored. As MV object is just a model and does not have data to null.

  The user has no direct access to the MY_TEST_MV table. See this

  SQL> drop table my_test_mv;
  drop table my_test_mv
             *
  ERROR at line 1:
  ORA-12083: must use DROP MATERIALIZED VIEW to drop "KARTHICK"."MY_TEST_MV"
  

  Also, you can associate an existing table to a materialized using the clause ON TABLE PREDEFINED view.

  Here is an example

  SQL> drop materialized view my_test_mv;
  
  Materialized view dropped.
  
  SQL> create table my_test_mv_new as select * from emp;
  
  Table created.
  
  SQL> select object_type, object_name, data_object_id from user_objects where object_name = 'MY_TEST_MV_NEW';
  
  OBJECT_TYPE         OBJECT_NAME          DATA_OBJECT_ID
  ------------------- -------------------- --------------
  TABLE               MY_TEST_MV_NEW              1638967
  
  SQL> create materialized view my_test_mv_new on prebuilt table as select * from emp;
  
  Materialized view created.
  
  SQL> select object_type, object_name, data_object_id from user_objects where object_name = 'MY_TEST_MV_NEW';
  
  OBJECT_TYPE         OBJECT_NAME          DATA_OBJECT_ID
  ------------------- -------------------- --------------
  TABLE               MY_TEST_MV_NEW              1638967
  MATERIALIZED VIEW   MY_TEST_MV_NEW
  
  SQL>
  

  Once you associate a Table with a MV direct Table access is limited. You can directly access only the MV.

• Compare two rows in the same table

  Hi all
  
  I need to compare two rows in the same table, I don't know hoe to do it in pl/sql. Please help me on this.
  
  example:
  
  price of ro TR
  xya0001 AMA.7 12
  xya0003 ama6 14
  xya0004 AMA.7 16
  
  in table b is a unique value for each line, I need to compare the price column and see if the first value is less than or greater than the following value and, if there is more to put the corresponding value of br to a variable, and if it is less, put the corresponding value of the br to another variable. I don't know a method to do this, as I'm new to pl/sql. Please help me in this

  for data in(select tr,br,price, lag(price) over ( order by tr) newcol
  from yourtable)
  loop
  if nvl(data.newcol,0) > data.price then
  variable1:=data.br;
  else
  varable2:=data.br;
  end if;
  end loop;
  

• Multiple values for the same column in the columns of diffétent in the same row?

  Hi all
  I wonder how you can display different values for the same column in different columns on the same line. For example, using a CASE statement, I can:
  
  CASE WHEN CODE IN ('1 ', ' 3') THEN COUNT (ID) AS 'Y '.
  CASE WHEN CODE NOT IN ('1 ', am') THEN COUNT (ID) AS "N".
  
  Yes, that will produce two columns but will produce null values to empty and also two separate registers.
  
  
  Any ideas?
  
  Thank you

  Are you sure that this code works for you?

  Select ID
           ,CASE WHEN MODE_CODE IN ('1', '3') THEN COUNT( No) END as "Fulltime"
           ,CASE WHEN MODE_CODE NOT IN ('1', '3') THEN COUNT( No ) END  as "Other"
  From table
  group by ID
  

  I guess the code above fails because MODE_CODE is not in your group by?

  My suggestion would be to put the CASE in the COUNT:

  Select ID
           ,COUNT(CASE WHEN MODE_CODE IN ('1', '3') THEN No END) as "Fulltime"
           ,COUNT(CASE WHEN MODE_CODE NOT IN ('1', '3') THEN No END)  as "Other"
  From table
  group by ID
  

  CASE expressions return no. when the respective conditions are true and NULL otherwise.
  COUNTY will have non-null values.

• Print data online in the same column

  Hello
  
  In a tabular report I want to print a column (for example: Description,) in two lines in the same cell.
  Because the description is too long. Is this possible in report 6i. Or any other solution for this?
  
  Please answer.

  Hello
  For the Description of the value vertical elasticity EXPAND field. Then it will automatically adjust based on the data.

  -Clément

• Update two tables at the same time?

  Hi, I'm having some trouble finding how to create a new field in both tables of the same shape. (php mysql)

  I have two paintings: a table listing the projects and

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  When the user submits the form the insert record server behavior creates a new project. The projectID in the project table field is an AutoNumber created in mysql.

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  I'm not a programmer so need help to understand this.

  See you soon,.

  How to retrieve the value of an autoincrement column:

  http://www.gotocode.com/art.asp?art_id=80&

• Creating records from two Tables at the same time...

  I would be very grateful if someone could help with the following query.
  
  I have two Tables, Tbl1 and Tbl2. Tbl1 has the following columns: -.
  
  Tbl1_Unique_ID, Description
  
  Tbl1_Unique_ID is of type ' * number *' and ' * PK * ', Description is of type' * Varchar2 *'.
  
  Tbl2 has the following columns: -.
  
  Tbl2_Unique_ID, Description, Tbl1_Unique_ID
  
  Tbl2_Unique_ID is of type ' * number *' and is the ' * PK * ', Description is of type' * Varchar2 *' and Tbl1_Unique_ID is of type ' * number *', is a ' * foreign key *' and is the ' * primary key *' from Tbl1.
  
  While I can create a page to display and create folders in Tbl1, I'm not course coding required to view and create records Tbl1 and Tbl2 simultaneously, as well as regarding the two together at the same time.
  
  I know that it involves one ' * INSERT *' statement, but I have problems the correct SQL query.
  
  Can anyone provide any assistance will be appreciated.

  Have you tried to create a form master / detail page? Because it seems that is what you need...