Update a row based on a line from another table

Hello

I have two tables that have the same field, but with a different name.


CREATE TABLE FAVE_CODE2_NEW_JOIN
(
VARCHAR2 (5 BYTE) BANKID NOT NULL,.
CUSTOMERID VARCHAR2 (12-BYTE) NOT NULL,
SIXID VARCHAR2 (12-BYTE) NOT NULL,
FAVCODE VARCHAR2 (13 BYTE),
IDX NUMBER (5),
DEFAULTT NUMBER (1)
)
TABLESPACE PORTFOLIO_FAVORITE
PCTUSED 0
PCTFREE 10
INITRANS 1
MAXTRANS 255
STORAGE)
64K INITIALS
ACCORDING TO 1 M
MINEXTENTS 1
MAXEXTENTS UNLIMITED
PCTINCREASE 0
DEFAULT USER_TABLES
)
LOGGING
NOCOMPRESS
NOCACHE
NOPARALLEL
MONITORING;




CREATE TABLE SUBSCRIPTION
(
SUBSCRIPTIONID RAW (16) NOT NULL,
APPID VARCHAR2 (64 BYTE) NOT NULL,
VARCHAR2 (64 BYTE) DEVICE ID,
SUBSCRIBERID NUMBER NOT NULL,
TIME_REGISTERED TIMESTAMP (6) DEFAULT SYSTIMESTAMP NOT NULL,
TIME_LAST_USED TIMESTAMP (6) DEFAULT SYSTIMESTAMP NOT NULL,
SUBSCRIPTION_TYPE VARCHAR2 (30 BYTE) NOT NULL,
SUBSCRIPTION_INFO VARCHAR2 (512 BYTE)
)
TABLESPACE PORTFOLIO_FAVORITE
PCTUSED 0
PCTFREE 10
INITRANS 1
MAXTRANS 255
STORAGE)
64K INITIALS
ACCORDING TO 1 M
MINEXTENTS 1
MAXEXTENTS UNLIMITED
PCTINCREASE 0
DEFAULT USER_TABLES
)
LOGGING
NOCOMPRESS
NOCACHE
NOPARALLEL
MONITORING;



SUBSCRIPTION_INFO in SUBSCRIPTION is equal to SIXID in FAVE_CODE2_NEW_JOIN. They have the same value

In the FAVE_CODE2_NEW_JOIN table, there is also a class FAVCODE.
Now, I want to know the record of VE_CODE2_NEW_JOIN that have the same sixid as SUBSCRIPTION_INFO in SUBSCRIPTION and then replace this with the value SUBSCRIPTION_INFO in FAVCODE


Some examples of the two tables:


SUBSCRIPTION:

B31E5F5D3CB6 RIe9pnbe7BtA8IuQ BB2-58CA815F9958 21 2012-01-10 19:18:39 2012-01-11 12:24:04 FT FSB0650444
010FB3AE74AE RIe9pnbe7BtA8IuQ 845-AD375E95ED90 21 2012-01-12 08:31:47 2012-01-24 08:53:09 FT FSB0650444
6119E731A26F RIe9pnbe7BtA8IuQ 76 113 a-DAD2E359BF3F 2012-01-04 00:25:05 2012-01-19 16:17:21 FT FSB0632948


FAVE_CODE2_NEW_JOIN:

08999 191111111111 FSB0650444 SWB0553263 11 0

As you can see they both the same "FSB0650368", but I want to replace this code with the FAVCODE corresponding to FAVE_CODE2_NEW_JOIN which is "SWB0553263".

I hope you got what I mean, please tell me to explain more if you have problems to understand what I mean.

Thanks in advance!

/ Louis

Like this

update subscription a
   set a.subscription_info =
       (
          select b.favcode
         from fave_code2_new_join b
        where b.sixid = a.subscription_info
       )
 where exists
       (
          select b.favcode
         from fave_code2_new_join b
        where b.sixid = a.subscription_info
       )

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