Update of table with 14 million records

Similar Questions

• Best way to update a table with separate values

  Hi, I would really appreciate some advise:
  
  I need to regularly perform a task where I update 1 table with all the new data that has been entered in another table. I cannot perform a complete insert because this will create data duplicated each time it works, so the only way I can think of is the use of cursors in the script below:
  
  
  CREATE OR REPLACE PROCEDURE update_new_mem IS
  tmpVar NUMBER;
  
  CURSOR c_mem IS
  SELECT nom_membre, member_id
  OF gym.members;
  CREC c_mem % ROWTYPE;
  
  
  BEGIN
  OPEN c_mem.
  LOOP
  SEEK c_mem INTO crec;
  EXIT WHEN c_mem % NOTFOUND;
  BEGIN
  UPDATE gym.lifts
  Name = crec.member_name
  WHERE member_id = crec.member_id;
  EXCEPTION
  WHEN NO_DATA_FOUND THEN NULL;
  END;
  IF SQL % NOTFOUND THEN
  BEGIN
  INSERT INTO gym.lifts
  (name, member_id)
  VALUES (crec.member_name, crec.member_id);
  END;
  END IF;
  END LOOP;
  CLOSE C_mem;
  
  END update_new_mem;
  
  
  
  This method works, but y at - it a (faster) easier way to update another table with new data only?
  
  Thank you very much

  >
  This method works, but y at - it a (faster) easier way to update another table with new data only?
  >
  Almost anything would be better than this treatment of slow-by-slow loop.

  You don't need a procedure, you should just use MERGE for this. See the examples in the section of the MERGER of the doc of the SQL language
  http://docs.Oracle.com/CD/B28359_01/server.111/b28286/statements_9016.htm

  MERGE INTO bonuses D
     USING (SELECT employee_id, salary, department_id FROM employees
     WHERE department_id = 80) S
     ON (D.employee_id = S.employee_id)
     WHEN MATCHED THEN UPDATE SET D.bonus = D.bonus + S.salary*.01
       DELETE WHERE (S.salary > 8000)
     WHEN NOT MATCHED THEN INSERT (D.employee_id, D.bonus)
       VALUES (S.employee_id, S.salary*.01)
       WHERE (S.salary <= 8000);
  

• Update of table with invalid identifiers

  Hello!
  
  I use a third-party plug-in and that comparisons of chemical structures. I want to update a table with the values of the other when the plugin matches two rows. However, I'm a problem invalid identifier.
  
  Two tables:
  PLATES: a VARCHAR2 columns of PLATE_SMILES, IN_DB
  INVEST: a VARCHAR2 columns of SMILES
  
  The operator is a binary: jc_compare (PLATE_SMILES, SMILES) = 1 (or 0 if they do not match)
  
  I want my query to say: "If comparison SMILES, PLATE_SMILES = 1, define IN_DB = 1 for row" - effectively asking if PLATE_SMILES exists in the table INVEST.
  
  I tried a number of "renditions", all identifiers not valid donations. Here is an example:
  
  Update (select plate. PLATE_SMILES, plate. IN_DB, invest. SMILES
  plate PLATES
  INVEST invest
  WHERE jc_compare (PLATE_SMILES, SMILES) = 1)
  set plate. IN_DB = 1;
  
  
  ORA-00904: "FLAT". "" IN_DB ": invalid identifier
  
  
  I hope that this should be an easy fix, and any help is greatly appreciated!

  Hello

  You have

  UPDATE (SELECT plate.plate_smiles,
                 plate.in_db,
                 invest.smiles
          FROM   plates plate, invest invest
          WHERE  jc_compare ( plate_smiles, smiles) = 1)
  SET    plate.in_db = 1;   -- Error here
  

  PLATE is not known outside the display online. Just remove it.

  Concerning
  Peter

• update of table with similar registration information using the same key

  Version: 11.1.0.7.0

  We have large table probably 30 M records

  -test code table follows

  create table people)

  person_id number,

  first name varchar2 (50).

  middle_name varchar2 (50).

  last_name varchar2 (50)

  );

  insert into persons (person_id, first_name, last_name, middle_name) values (1, 'JOHN', 'A', 'DOE');

  insert into people (person_id, first_name, last_name, middle_name) values (1, 'JOHN', ","DOE");

  insert into persons (person_id, first_name, last_name, middle_name) values (1, 'JOHN', 'ADAM', 'DOE');

  insert into persons (person_id, first_name, last_name, middle_name) values (2, 'JOHN', ' C ', 'DOE');

  insert into people (person_id, first_name, last_name, middle_name) values (2, 'JOHN', ","DOE");

  insert into people (person_id, first_name, last_name, middle_name) values (3, 'JOHN', ","MOE");

  insert into persons (person_id, first_name, last_name, middle_name) values (3, 'JOHN', 'FRANK', 'MOE');

  I am trying to write more efficient code to take the middle name of the most complete and updated all records with the same KEY (person_id) with her.

  Expected result:

  1, JOHN, ADAM, DOE

  1, JOHN, ADAM, DOE

  1, JOHN, ADAM, DOE

  2, JOHN, C., DOE

  2, JOHN, C., DOE

  3, JOHN, FRANK, MOE

  3, JOHN, FRANK, MOE

  Hello

  Here is an example of the use of the aggregate LAST instead of the function ROW_NUMBER analytic function:

  MERGE INTO dst people

  WITH THE HELP OF)

  WITH got_longest_middle_name AS

  (

  SELECT person_id

  , MIN (middle_name) DUNGEON (DENSE_RANK LAST ORDER OF LENGTH (REPLACE (middle_name, '.')))

  AS longest_middle_name

  AMONG the people

  WHERE middle_name IS NOT NULL

  GROUP BY person_id

  )

  SELECT person_id

  longest_middle_name

  Got_longest_middle_name c - c is for candidates

  WHERE DOES NOT EXIST)

  SELECT 1

  AMONG the people

  WHERE person_id = c.person_id

  AND c.longest_middle_name NOT AS REPLACE (middle_name, '.'). '%'

  )

  )             src

  WE (dst.person_id = src.person_id)

  WHEN MATCHED THEN UPDATE

  SET dst.middle_name = src.longest_middle_name

  WHERE dst.middle_name <> src.longest_middle_name

  OR dst.middle_name IS NULL

  ;

  I suspect that this may be a little faster, but try it on your system with your data to make sure.

• How to update the table with the number management

  Hello
  
  I need as there is a loc_tab of the created table as below,
  
  CREATE TABLE loc_tab
  (
  Country_ID NUMBER,
  country_code VARCHAR2 (3),
  country_name VARCHAR2 (50).
  State_ID NUMBER,
  state_code VARCHAR2 (3),
  state_name VARCHAR2 (50).
  city_id NUMBER,
  city_code VARCHAR2 (3),
  city_name VARCHAR2 (50)
  );
  
  I inserted records like below,
  

  COUNTRY_ID     COUNTRY_CODE     COUNTRY_NAME     STATE_ID     STATE_CODE     STATE_NAME     CITY_ID     CITY_CODE     CITY_NAME
  
            IND          INDIA                    TN          TAMIL NADU          CHN          CHENNAI
            IND          INDIA                    TN          TAMIL NADU          TRI          TRICHY
            IND          INDIA                    TN          TAMIL NADU          CMT          COIMBATORE
            IND          INDIA                    TN          TAMIL NADU          MDU          MADURAI
            IND          INDIA                    AP          ANDHRA PRADESH          HYD          HYDERABAD
            IND          INDIA                    AP          ANDHRA PRADESH          SEC          SECUNDRABAD
            AUS          AUSTRALIA               QLD          QUEENSLAND          BRI          BRISBANE
            AUS          AUSTRALIA               TAS          TASMANIA          HB          HOBART
            AUS          AUSTRALIA               TAS          TASMANIA          CCE          CITY OF CLEARANCE
            AUS          AUSTRALIA               TAS          TASMANIA          BUR          BURNIE

  Now, I wanted to update the table such that all ID columns are updated with running number.
  
  Each ID columns should get incremented so that, for Country_ID column corresponding to "India" If country_id is 1, that there must be one for all the lines with the name as "India". Likewise for "Australia".
  
  In the case of State, she also has the same logic with numbers repeated until the very name of the State comes.
  
  For the city, it of course will hold separate ID only because the name of the city will not get duplicated.
  
  This update must be done in the normal way using simple SQL such as no PLSQL don't like looping, etc... is involved.
  
  Here are the contents of the table, and that's how the table should be updated,
  

  COUNTRY_ID     COUNTRY_CODE     COUNTRY_NAME     STATE_ID     STATE_CODE     STATE_NAME     CITY_ID     CITY_CODE     CITY_NAME
                                          
  1          IND          INDIA          1          TN          TAMIL NADU     1     CHN          CHENNAI
  1          IND          INDIA          1          TN          TAMIL NADU     2     TRI          TRICHY
  1          IND          INDIA          1          TN          TAMIL NADU     3     CMT          COIMBATORE
  1          IND          INDIA          1          TN          TAMIL NADU     4     MDU          MADURAI
  1          IND          INDIA          2          AP          ANDHRA PRADESH     1     HYD          HYDERABAD
  1          IND          INDIA          2          AP          ANDHRA PRADESH     2     SEC          SECUNDRABAD
  2          AUS          AUSTRALIA     1          QLD          QUEENSLAND     1     BRI          BRISBANE
  2          AUS          AUSTRALIA     2          TAS          TASMANIA     1     HB          HOBART
  2          AUS          AUSTRALIA     2          TAS          TASMANIA     2     CCE          CITY OF CLEARANCE
  2          AUS          AUSTRALIA     2          TAS          TASMANIA     3     BUR          BURNIE

  Thank you and best regards,
  Shiva
  

• Update a table that has 1291444946 records

  Hi friends,
  
  We have table with 1291444946 records in this 13844852 files are updated. The current time is 12:22:55.19.This simple update statement
  

  update table_name set a=b where a=c;

  Superior wait event was scattered db read file.
  

  DB_Version=11.2.0.2
  OS=Solaris 10 x86
  SGA=16GB
  PGA=6GB
  Cursor_sharing=EXACT

  Is their anyway, we can reduce this time to 6 hours or less.
  
  Concerning
  NM

  What is the status here?

  Can you update us if you please, or close the message if the problem has been resolved

• Update a table with one column of another

  Oracle 11g
  Hello

  i'im trying to update the two columns of table SUPPORT (SUPPORT_X, SUPPORT_Y) with two columns of table POST_HTA_BT (POSTHTABT_GPS_X, POSTHTABT_GPS_Y)

  Understand that the two tables have the colum below:

  SUPPORT (SUPPORT_ID, SUPPORT_PLAQUE, POSTHTABT_ID, SUPPORT_X, SUPPORT_Y,...)

  POST_HTA_BT (POSTHTABT_ID, POSTHTABT_GPS_X, POSTHTABT_GPS_Y,...)

  The SUPPORT_PLAQUE has type varachar. Except the keys, the other columns are varchar type in both tables.

  The point here is to update the support_x, support_y with posthtabt_gps_x and posthtabt_gps_y.But before the update we have Sheik if the fifth number of the support plate is a number of characters from "0" to "9"and the rest of the caracter of the support_plaque is '00000'

  Please note that the support_plaque is stored in the table with the form: "0025800000!"

  So I did the below script, I try to execute in sql develop.

  SET SERVEROUTPUT ON

  DECLARE
  chiffre_liste varchar (200): = '0 ', '1', '2', '3', '4', ' 5 ', ' 6' ', 7', ' 8 ', ' 9';
  CURSOR CUR_GPS_SUPPORT IS
  Select MEDIA. SUPPORT_X, SUPPORT. SUPPORT_Y, POSTE_HTA_BT. POSTHTABT_ID, SUPPORT. EXPL_ID,
  SUPPORTED. SUPPORT_PLAQUE, POSTHTABT_GPS_X, POSTHTABT_GPS_Y
  support,.
  POSTE_HTA_BT
  where
  SUPPORTED. SUPPORT_X IS NULL and
  SUPPORTED. SUPPORT_Y IS NULL and
  SUPPORTED. POSTHTABT_ID = POSTE_HTA_BT. POSTHTABT_ID and
  SUPPORTED. EXPL_ID = POSTE_HTA_BT. EXPL_ID
  Order of SUPPORT. POSTHTABT_ID;

  w_POSTHTABT_ID POSTE_HTA_BT. Type of POSTHTABT_ID %;
  w_SUPPORT_X SUPPORT. TYPE % SUPPORT_X;
  w_SUPPORT_Y SUPPORT. TYPE % SUPPORT_Y;
  w_EXPL_ID SUPPORT. TYPE % EXPL_ID;
  w_SUPPORT_PLAQUE SUPPORT. TYPE % SUPPORT_PLAQUE;
  w_POSTHTABT_GPS_X POSTE_HTA_BT. TYPE % POSTHTABT_GPS_X;
  w_POSTHTABT_GPS_Y POSTE_HTA_BT. TYPE % POSTHTABT_GPS_Y;
  

  BEGIN
  DBMS_OUTPUT. Put_line ('loading the coordoonnees GPS - GPS Coord update takes care of starting ');

  FOR HEART LOOPING CUR_GPS_SUPPORT

  w_POSTHTABT_ID: = cur. POSTHTABT_ID;
  w_SUPPORT_PLAQUE: = cur. SUPPORT_PLAQUE;
  w_SUPPORT_X: = cur. SUPPORT_X;
  w_SUPPORT_Y: = cur. SUPPORT_Y;
  w_POSTHTABT_GPS_X: = cur. POSTHTABT_GPS_X;
  w_POSTHTABT_GPS_Y: = cur. POSTHTABT_GPS_X;
  

  If substr (cur.support_plaque, 5, 1 chiffre_liste) and substr (cur.support_plaque, 6, 5) = '00000'
  w_SUPPORT_X: = CUR. POSTHTABT_GPS_X
  w_SUPPORT_Y: = CUR. POSTHTABT_GPS_Y
  END if;
  EXCEPTION WHEN NO_DATA_FOUND THEN w_SUPPORT_X: = NULL and w_SUPPORT_Y: = NULL;
  END;
  

  -Updated the table of the supports
  Update SUPPORT
  Set SUPPORT_X = w_SUPPORT_X,
  SUPPORT_Y = w_SUPPORT_Y
  where SUPPORT_PLAQUE = w_SUPPORT_PLAQUE;
  -On valid imm? immediately
  commit;
  EXCEPTION when no_data_found then null;
  -No details found
  END;
  
  END;
  /

  and I got the following errors:

  Error report:
  ORA-06550: line 2, colum 34:
  PLS-00103: symbol ',' met instead of one of the following symbols:

  * & = - + ; <>/ is mod remains not rem
  <>< Hurst (*) > or! = or ~ = > = < = <>and like2 or
  like4 likec between | submultiset of type multiset Member
  ORA-06550: line 2, column 52:
  PLS-00103: symbol ';' met instead of one of the following symbols:

  ), * & = - + <>/ is mod remains not rem = >
  <>< Hurst (*) > or! = or ~ = > = < = <>and like2 or
  like4 likec between | Member of multiset must
  ORA-06550: line 38, colum 48:
  PLS-00103: symbol 'CHIFFRE_LISTE' met instead of one of the following symbols:

  (
  Symbol "(" a été substitué à "CHIFFRE_LISTE" verser continuer.) "
  ORA-06550: line 39, 12 colum:
  PLS-00103: symbol 'W_SUPPORT_X' met instead of one of the following symbols:

  ), * & -+ / at rem mod < Hurst (*) > rest and or.
  multiset
  ORA-06550: line 40, 12 colum:
  PLS-00103: symbol 'W_SUPPORT_Y' met instead of one of the following symbols:

  . (), * @ % & = - + <>/ is mod remains not rem
  <>< Hurst (*) > or! = or ~ = > = < = <>and like2 or
  like4 likec between | mult
  ORA-06550: line 41, colum 9:
  PLS-00103: symbol 'END' met instead of one of the following symbols:

  . (), * @ % & = - + <>/ is mod remains not rem
  <>< Hurst (*) > or! = or ~ = > = < = <>and like2 or
  like4 likec between | multiset members
  06550 00000 - "line %s, column % s:\n%s".
  * Cause: Usually a PL/SQL compilation error.
  * Action:

  I checked the line number, but do not see the error in my code.

  Please could you help me?

  peace

  Hello

  glad to know that it worked. In fact, I don't see the reason to make these complicated processes.

  Remember the mantra:

  • If you can do it with SQL then do it with SQL

  Good evening!

  Alberto

• update a table with sequence colmn

     how to update a colmn of table with sequence 
  
     e.x 
     
  COLMN1     COLMN2
  A     
  D     
  RTR     
  XX
  G     
  
  how to update colm2 like 
  
  COLMN1     COLMN2
  A               1
  D               2
  RTR               3
  XX              4
  G               5

  update tab set col2 = rownum;
  commit;
  

• Update the Table with the push button

  Hi I want to update my table using the push button that requires a transfer of account
  
  For example a single account transactions into 2nd account
  
  
  I used this query, but his does not work
  
  Update of cb
  Set cb_acc_id =: block3.acc_id_target
  where
  cb_acc_id =: block3.acc_id_source;
  
  
  
  Concerning
  
  Wasim Ismail

  You may forgot to validate your update...

  BTW:
  your form will not recognize, you start a transaction and make an update in the database.

• Update a table with primary key

  Hello

  I have a table called Temp

  CREATE TABLE TEMP
  (
     A   VARCHAR2 (50 CHAR),
     B   VARCHAR2 (50 CHAR),
     C   VARCHAR2 (50 CHAR),
     D   VARCHAR2 (18 CHAR),
     E   DATE,
     F   NUMBER,
     G   VARCHAR2 (18 CHAR),
     H   FLOAT
  );
  

  The primary key is the PRIMARY KEY: (A, B, C, D, E, F, G).

  I HAVE THE TEMPORARY TABLE 48052365 COUNTY,

  HOWEVER I HAVE A REQUIREMENT TO UPDATE WHERE E (COLUMN) IS WEDNESDAY, THE SAME DAY IN MONDAY (I.E., C - 2 TO EXISTING DATE)

  Approach;

  I CREATED the TABLE TEMP_WED_TO_MONDAY AND SELECTED ALL THE RECORDINGS ELIGIBLE IN CE AND TABLE AND INDEX UNIQUE CREATED on this SUBJECT. TO UPDATE, I WROTE UNDER ANONYMOUS BLOCK.

  Number of Tables: TEMP_WED_TO_MONDAY is 46,921,912 and count of total of the table is 48052365

  Anonymous block:

  DECLARE
     CURSOR UPDATE_TEMP_DATE
     IS
        SELECT A,
               B,
               C,
               D,
               E,
               F,
               G,
               E - 2 NEW_E
          FROM TEMP_WED_TO_MOONDAY;
  
  
     TYPE UPDATE_TEMP_DATE_REC IS RECORD
     (
        A       VARCHAR2 (50 CHAR),
        B       VARCHAR2 (50 CHAR),
        C       VARCHAR2 (50 CHAR),
        D       VARCHAR2 (18 CHAR),
        E       DATE,
        F       NUMBER,
        G       VARCHAR2 (50 CHAR),
        NEW_E   DATE
     );
  
  
     TYPE UPDATE_TEMP_DATE_TBL_TYPE IS TABLE OF UPDATE_TEMP_DATE_REC;
  
  
     UPDATE_TEMP_DATE_TBL   UPDATE_TEMP_DATE_TBL_TYPE;
  BEGIN
     OPEN UPDATE_TEMP_DATE;
  
  
     LOOP
        FETCH UPDATE_TEMP_DATE
           BULK COLLECT INTO UPDATE_TEMP_DATE_TBL
           LIMIT 1000000;
  
  
        EXIT WHEN UPDATE_TEMP_DATE_TBL.COUNT = 0;
  
  
        FORALL I IN UPDATE_TEMP_DATE_TBL.FIRST .. UPDATE_TEMP_DATE_TBL.LAST
           UPDATE TEMP
              SET E = UPDATE_TEMP_DATE_TBL (I).NEW_E
            WHERE     A = UPDATE_TEMP_DATE_TBL (I).A
                  AND B = UPDATE_TEMP_DATE_TBL (I).B
                  AND C = UPDATE_TEMP_DATE_TBL (I).C
                  AND D = UPDATE_TEMP_DATE_TBL (I).D
                  AND E = UPDATE_TEMP_DATE_TBL (I).E
                  AND F = UPDATE_TEMP_DATE_TBL (I).F
                  AND G = UPDATE_TEMP_DATE_TBL (I).G;
  
  
        COMMIT;
     END LOOP;
  
  
     CLOSE UPDATE_TEMP_DATE;
  END;
  
  

  But for the past 6 hours, it only updated records 20,00,000(Twenty lakh) only. because this update in the table and is also part of the teaching primary key I think it takes time, but pointers to improve/acceleration of the update

  Explain the plan:

  update statement all_rows (Cost 4)
    3 update hr.temp 
      2   table access by index rowid table hr.temp (Cost 4, Bytes : 64 ,Cardinality 1)
        1    index range scan index hr.temp_wed_to_monday (Cost 3: Cardinality 1)
  

  Thank you guys, I would be grateful if someone provides the solution for the scenario, rather than highlight the design. Please understand someone designed to best with whatever the limits it has during this period. (and this isn't me).

• Script table with Clob and record another database

  Hello
  
  How can I read the Clob column data and insert into another table in the database.
  
  The first Table is quality Test and second Production
  
  Is there a way without using Export / Import?
  
  What can I use the charger?
  
  
  
  With the help of 9i

  muttleychess wrote:

  mschnatt wrote:
  You can only try the db-link

  CREATE LINK of the DATABASE to CONNECT to IDENTIFIED BY with the HELP of "";

  and make the table

  create table...
  in select...

  Thank you, but too no work :-(:-(

  SQL> select id,clob_data from myclob@teste;
  select id,clob_data from myclob@teste
  *
  ERRO na linha 1:
  ORA-22992: cannot use LOB locators selected from remote tables
  

  Well you don't have the answer said to

  and make the table

  create table...
  in select...

  Also in the manual, you could save a lot of time if you open.

  http://docs.Oracle.com/CD/B14117_01/AppDev.101/b10796/adlob_wo.htm#1006314

  >
  The following syntax is supported on the remote LOB columns:

  CREATE TABLE t AS SELECT * FROM table1@remote_site;
  INSERT INTO t SELECT * FROM table1@remote_site;
  UPDATE t SET lobcol = (SELECT lobcol FROM table1@remote_site);
  INSERT INTO table1@remote_site select * from local_table;
  UPDATE table1@remote_siteset lobcol = (SELECT lobcol FROM local_table);
  DELETE FROM table1@remote_site 
  

  It is the only syntax support involving some LOBs in remote tables. No other use is supported.

• SQL Query to retrieve records in a table with the same records or only one record in a table

  Hello

  Got a curious requirment to extract the Non-distincts records in a table

  Example of

  Account number	Type of account
  12345	SB
  12345	SB
  12346	CR
  12346	SB
  12347	SB
  12348	CR
  12349	SB

  Requrirement is to retrieve the records as follows

  Result must be

  Account number	Type of account
  12345	SB
  12345	SB
  12347	SB
  12348	CR
  12349	SB

  You will notice that 12346 which has two separate lines have been eliminated in the result. I tried several qeries to achieve this result, one or the other had a few mismatch. Can someone give me a request for it.

  Thanks in advance.

  SELECT ACCOUNT_NUMBER,

  ACCOUNT_TYPE

  DE)

  SELECT ACCOUNT_NUMBER,

  ACCOUNT_TYPE,

  COUNT (*) ON CNT_ACC (ACCOUNT_NUMBER PARTITION).

  COUNT (*) ON CNT_NUM_TYP (PARTITION ACCOUNT_NUMBER, ACCOUNT_TYPE)

  FROM T1)

  WHERE CNT_ACC = CNT_NUM_TYP;

  exit;

  12345	SB
  12345	SB
  12347	SB
  12348	CR
  12349	SB

• Update a table with a query that uses the table updated

  Hi This is my request. It's a mistake, but I hope that the basic idea may carry out. Cost_before_Decision is a column by using an alter table statement, I added:
  

  UPDATE fraud_nov_14_final
  SET Cost_before_Decision = (select Cost_Prior 
                              from    fraud_nov_14_final ff
                                    ,(select cla_case_no, sum(case when decline = 1 or decline = 2  
                                                                THEN (nvl(total_cost_adj_old,0) + nvl(decline_estimate,0)) 
                                                                ELSE Total_Cost 
                                                                END) Cost_Prior
                                      from reporting.ci_final@test
                                          group by cla_case_no) z
                                                  where ff.cla_case_no = z.cla_case_no)

  Error I get is:
  Error report:
  SQL error: ORA-01427: einreihig subquery returns multiple rows
  01427 00000 - "einreihig subquery returns several lines.
  
  Thanks in advance for your help:
  
  Banner:
  Oracle Database 11 g Release 11.2.0.2.0 - 64 bit Production
  PL/SQL Release 11.2.0.2.0 - Production
  "CORE 11.2.0.2.0 Production."
  AMT for Linux: Version 11.2.0.2.0 - Production
  NLSRTL Version 11.2.0.2.0 - Production

  Try this

  update fraud_nov_14_final a
     set cost_before_decision = (
                      select cost_prior
                        from (
                           select cla_case_no, sum(case when decline = 1 or decline = 2  then (nvl(total_cost_adj_old,0) + nvl(decline_estimate,0)) else total_cost end) cost_prior
                             from reporting.ci_final@test
                           group by cla_case_no
                             ) b
                                 where a.cls_case_no = b.cls_case_no
                       )
  

• Update of table with no column

  Hello
  
  Why oracle is that although the statement is incorrect? is there any docid for this?
  
  SQL > select banner version of v$.
  
  BANNER
  ----------------------------------------------------------------
  Oracle9i Enterprise Edition Release 9.2.0.8.0 - 64 bit Production
  PL/SQL Release 9.2.0.8.0 - Production
  CORE Production 9.2.0.8.0
  AMT for Solaris: 9.2.0.8.0 - Production Version
  NLSRTL Version 9.2.0.8.0 - Production
  
  
  SQL > desc one
  Name Null? Type
  ----------------------------------------- -------- ----------------------------
  AA NUMBER (1)
  BB NUMBER (1)
  
  SQL > desc b
  Name Null? Type
  ----------------------------------------- -------- ----------------------------
  AA NUMBER (1)
  CC NUMBER (1)
  
  SQL > select * from a;
  
  AA BB
  ---------- ----------
  1 1
  2 2
  3 3
  4 4
  3 s
  
  SQL > select b bb;
  Select bb b
  *
  ERROR on line 1:
  ORA-00904: "BB": invalid identifier
  
  
  SQL > update a game aa = 3 where bb (select b BB); -> bb of the column does not exist in table b
  
  5 lines to date.
  
  SQL > select * from a;
  
  AA BB
  ---------- ----------
  1 of 3
  1 p
  3 3
  3 4
  6 P
  
  Thank you
  Shanker

  No specific document. He has correlated subqueries. There is, of course, usually join condition.

  http://download.Oracle.com/docs/CD/B19306_01/server.102/b14200/statements_10002.htm#i2066912

• How can I update this table with values from another table?

  Hello
  
  I have a table 'governed '. I want to replace the values in the column "regies.agent" by the value of the column "regies_personnes.id."
  As you can see the tables have a column of common values. IE regies.agent = regies_personnes.nom
  
  Table 'governed ':
  Insert into 'authorities' (AGENT) values ('Humberdot Alain");
  Insert into 'authorities' (AGENT) values ("Danard Patrick");
  
  Table 'regies_personnes ':
  Insert into REGIES_PERSONNES (NAME, ID) values ("Humberdot Alain", 1);
  Insert into REGIES_PERSONNES (NAME, ID) values ("Danard Patrick", 2);
  
  Before having it
  SQL > select agent of authorities;
  Humberdot Alain
  Patrick Danard
  
  After the update, the result should be
  SQL > select agent of authorities;
  1
  2
  
  Thank you for your kind reply.

  You can

  update regies r set agent = (select id from regies_persones p where r.agent = p.nom)
    where exists (select id from regies_persones p where r.agent = p.nom)