Using Regular Expressions in the Code of edge

Similar Questions

• One for the era: how to get this output using REGULAR EXPRESSIONS?

  How to get the bottom of output using REGULAR EXPRESSIONS?

  SQL> ed
  Wrote file afiedt.buf
  
    1* CREATE TABLE cus___addresses    (full_address                   VARCHAR2(200 BYTE))
  SQL> /
  
  Table created.
  
  SQL> PROMPT Address Format is: House #/Housename,  street,  City, Zip Code, COUNTRY
  House #/Housename,  street,  City, Zip Code, COUNTRY
  SQL> INSERT INTO cus___addresses VALUES('1, 3rd street, Lansing, MI 49001, USA');
  
  1 row created.
  
  SQL> INSERT INTO cus___addresses VALUES('3B, fifth street, Clinton, OK 74103, USA');
  
  1 row created.
  
  SQL> INSERT INTO cus___addresses VALUES('Rose Villa, Stanton Grove, Murray, TN 37183, USA');
  
  1 row created.
  
  SQL> SELECT * FROM cus___addresses;
  
  FULL_ADDRESS
  ----------------------------------------------------------------------------------------------------
  1, 3rd street, Lansing, MI 49001, USA
  3B, fifth street, Clinton, OK 74103, USA
  Rose Villa, Stanton Grove, Murray, TN 37183, USA
  
  SQL> The REG EXP query shouLd output the ZIP codes: i.e. 49001, 74103, 37183 in 3 rows.

  Published by: user12240205 on June 18, 2012 03:19

  /* Formatted on 2012/06/18 17:25 (Formatter Plus v4.8.8) */
  SELECT REGEXP_SUBSTR ((REGEXP_SUBSTR (full_address, '[^,]+', 1, 4)), '[[:digit:]]+') RESULT
    FROM cus___addresses
  

• How to extract the value of a tag XML using regular Expressions

  We get a response XML from a WEB SERVICE.

  I convert it to VARCHAR2.

  Now, I want to get the real answer that is inside the tag of the response.

  I tried this:

  DECLARE

  V_1 VARCHAR2 (30000): = ' < soap: Body > < ns:ProcessArgusFeedsResponse xmlns:ns = "urn: PegaRULES:SOAP:ArgusToPegaFeeds:Services" > ' |

  '< response > good < / answer >< / ns:ProcessArgusFeedsResponse > < / soap: Body > ';

  v_response VARCHAR2 (100);

  BEGIN

  DBMS_OUTPUT. PUT_LINE (V_1);

  v_response: = REGEXP_SUBSTR (v_1, ' / < >(.+?) < \/Response > answer /');

  dbms_output.put_line (v_response);

  END;

  It does not work.

  Any help would be greatly appreicated.

  Hello

  user12240205 wrote:

  We get a response XML from a WEB SERVICE.

  I convert it to VARCHAR2.

  Why?  XML has its own native ways of analysis; Why not use them?

  If you use regular expressions, then REGEXP_REPLACE, as shown above, is a good option in Oracle 10, but starting in Oracle 11.1, you can use REGEXP_SUBSTR like this:

  REGEXP_SUBSTR (v_1

  , '(.+?)'

  1

  1

  NULL

  1

  )

  The 6th argument is like a backreference; "He tells REGEXP_SUBSTR did not return to the entire organization, but only the part inside the 1st left '(' et correspondant à sa droite).

  The '?' to make it non-greedy is necessary only if v_1 can contain more than one response.

  Now, I want to get the real answer that is inside the tag of the response.

  I tried this:

  DECLARE

  V_1 VARCHAR2 (30000): = "" |

  'Good';

  v_response VARCHAR2 (100);

  BEGIN

  DBMS_OUTPUT. PUT_LINE (V_1);

  v_response: = REGEXP_SUBSTR (v_1, ' /(. +?)) <\ esponse="">/');

  dbms_output.put_line (v_response);

  END;

  It does not work.

  That's because it's looking for a slash ("/") before the '' tag and another after the ' tag.

  The backslash ("\") is not necessary here, but it is not nothing wrong.

• Find the words (wild cards) using regular expressions

  I'm testing to see if the words are present for revision 1 of a drawing of the cartridge.

  The script search the digit 1 followed by a date, a title, and 4 sets of initials.

  The number 1 is static, (date, title and original are the cards that they are different for each design).

  I use regular expressions to match the words.

  The regular expression highlighted in blue is the number 1 and the date.

  Him remains highlighted in orange does not match the title and initials.

  If anyone can help with the regular expression that is most appreciated.

  Once I got that work will add the form fields for the initials, noting only the console at this point for the tests.

  numWords = this.getPageNumWords (0);

  number of words on the page

  loop through the words on the page

  for (var j = 0; j < numWords-1; j ++)

  {/ / get the pair of words to test}

  ckWords = this.getPageNthWord (0, j) + ' ' + this.getPageNthWord (0, j + 1); test words

  Check if 1 26.05.16 THE STRENGTHENING REVISED MM SB AE GM word string is present

  If (ckWords.match(/ ^ 1\s [0-9] {1,2}.)) [0-9] {1,2}. [0-9] {2} \s\w+(\s+\w+){1,7}/))

  {

  Console.println (ckWords);

  }

  }

  You can use something like this:

  ckWords = this.getPageNthWord (0, j) + ' ' + this.getPageNthWord (j, 0, + 1) + ' ' + this.getPageNthWord (0, + 2 j) + ' ' + this.getPageNthWord (0, j + 3) + ' ' + this.getPageNthWord (0, j + 4) + ' ' + this.getPageNthWord (0, j + 5) + ' ' + this.getPageNthWord (0, j + 6);

  If (! ckWords.match (/ ^ 1\s\d {1,2} \.\d {1,2} \.\d {2} \s\w+ (?:-s + \w +) {1.8} \s([A-Z]{2})\s([A-Z]{2})-s ([A - Z] {2}) \s([A-Z]{2})$ /)) ckWords + ckWords + "" + this.getPageNthWord (0, j + 7);

  If (! ckWords.match (/ ^ 1\s\d {1,2} \.\d {1,2} \.\d {2} \s\w+ (?:-s + \w +) {1.8} \s([A-Z]{2})\s([A-Z]{2})-s ([A - Z] {2}) \s([A-Z]{2})$ /)) ckWords + ckWords + "" + this.getPageNthWord (0, j + 8);

  If (ckWords.match (/ ^ 1\s\d {1,2} \.\d {1,2} {2} \s\w+ \.\d (?:-s + \w +) 1.8 ([A - Z] {2}) \s([A-Z]{2})\s([A-Z]{2})\s {} \s([A-Z]{2})$ /))

  {

  ...

• Changeparticular the characters of a string using regular expressions...

  Hi all
  I'm writing a function using the function of expression regular oracles REGEXP_REPLACE but I could not succeed until now.
  
  My problem is as follows, I have a text in a column say "Scott Sdfdfs Sdfd" I want to replace all the s and S with X characters and make the text looks like "XdfXdf XdfdfX Xdfd".
  
  It is possible by using regular expressions in oracle?
  Can you give me some clue?
  
  Thank you

  select
    regexp_replace('sdfsdf Sdfdfs Sdfd',
                   's|S', 'X') Replaced
  from dual;
  

  REPLACED
  ------------------
  XdfXdf XdfdfX Xdfd 
  

• Help in regular Expression for the beaches of limitation

  Hi, I'm working on the provision of a text field is limited to dates, it's just a part of the code. I already have the validation of the dates, but I am now limiting what the user enters using a regular expression. This code works a little however, it does not limit me for example I can enter more than 2 digits, but then he limits based on the total amount allowable so for example 8 digits are allowed if I just type. I need to stop after 2 digits then have a - then 2 other numbers then one - and then followed by 4 digits. I tried to limit each section and grouping as well. Any help would be greatly appreciated. Thank you.

  It is in the format code and I am the appellant in the key sequence.

  function DateKS () {}

  var value = AFMergeChange (event);

  If (! event.willCommit) {}

  Allow only characters that match the regular expression

  Event.RC = /^([0]{0,1}[1-9]{0,1}|[_1]{0,1}[012]{0,1}) ([-] {0,1}) ([0] {0,1} [1-9] {0,1} |) [12] {0,1} [0-9] {0,1} | ([3] {0,1} [01] {0,1}) ([-] {0,1}) ([0-9] {0,4}) $/ .test (value);

  }

  }

  I decided that control for 100 and 400 was not necessary because this event does occur that all 400 years. But I'm working on it further and changed even more. Here is my code to work.

  function isLeapYear (year) {}
  year return % 4 = 0;
  }

  function checkDaysInMonth (day, month, year) {}
  daysInMonth var = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31];

  If (month = 2) {}
  If (isLeapYear (year)) {}
  daysInMonth [1] += 1;
  }
  }

  return daysInMonth [month - 1] > = day;
  }

  function checkDateFormat (dateStr) {}
  var errorMsg = ",
  maxYear = (new Date()) .getFullYear (),
  minYear = maxYear - 1,.
  match = dateStr.match(/^(\d{2})-(\d{2})-(\d{4})$/),
  months,
  day,
  year;

  If {(matches)
  month = parseInt (matches [1], 10);
  day = parseInt (matches [2], 10);
  year = parseInt (matches [3], 10);

  If (month < 1="" ||="" month=""> 12) {}
  errorMsg = "invalid value for the month: ' + matches [1];"
  } ElseIf (day = 0) {}
  errorMsg = "invalid value for the day:" + match [2];
  } else if (! checkDaysInMonth (day, month, year)) {}
  errorMsg = "number of days for invalid month: ' + match [2];"
  } ElseIf (year < minyear="" ||="" year=""> maxYear) {}
  errorMsg = "invalid value for the year:" + match [3] + "-must be between" + minYear + "and" + maxYear;
  }
  } else {}
  errorMsg = "invalid date format: ' + dateStr + ' \r\nPlease use format: dd-mm-yyyy ';"
  }

  return errorMsg;
  }

  function checkReceivedDate() {}
  var value = AFMergeChange (event),
  errorMsg = ";
     
  ignore control if the value is blank, because this field is not mandatory
  If (! value) {}
  return;
  }

  If {(event.willCommit)
  errorMsg = checkDateFormat (value);

  If (errorMsg) {}
  App.Alert (errorMsg, 0, 0, "error");
  Event.value = ";

  Returns false;
  }
  } else {}
  Allow only characters that match the regular expression
  Event.RC = /^(?:0) [1-9]? 1 [012]?) ? -? ( ? : 0 [1-9] ? | [12] [0-9]? 3 [01]?) ? - ? 2? 0? [0-9] {0,2} $/ .test (value);
  Event.RC = / ^ \d{0,2}-?\d{0,2}-?\d{0,4}$/.test(value);
  }

  Returns true;
  }

• String format using regular expressions

  Input string output format...
  
  SELECT q'<select ab_c "ABC", efg "EFG" from dual>' str FROM DUAL
  
  Output:
  
  STR                                  
  -------------------------------------
  select ab_c "ABC", efg "EFG" from dual
  
  
  Required output format using regular expression...
  
  
  STR                                  
  -------------------------------------
  select 'ab_c' "ABC", 'efg' "EFG" from dual

  Regular expressions have many limitations as tools of analysis, and you specify the rules you want. This expression puts quotation marks around a non-empty string before a quoted string:

  SELECT regexp_replace(q'',
                        '([^" ]+)( +"[^ ]*")' , '''\1''\2' ) str FROM DUAL;
  
  STR
  ------------------------------------------
  select 'ab_c' "ABC", 'efg' "EFG" from dual
  {code}
  
  It is not robust - a missing " will confuse it, and you should be using bind variables anyway.                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                
  		    
              
             
   
  		     
  regular expression - get the numbers from a string
   
  			 Hello world
  
  
  I'm trying to use regular expressions to get all the numbers in a string. The only problem is that the chain can vary.
  
  
  For example:
  
  
  It's my rope 3 and 8 I want 2 get out of those 7 numbers
  Random text 9 with 5 for everyone weekend 8
  
  
  How can I do?
  
  
  Thanks in advance :)
  			 
  Quote:
  
      Posted by: Scott Stroz
  
      
  
  #numbersOny #.
  Who will be only to crush all the numbers in a large number.
  The attached code will return a nice list of numbers.
  Though the numbers may contain commas or decimal points, the code can easily be adjusted
  		   
   
              
             
   
  		     
  Chips with 3 delimiter characters using regular expressions
   
  			 
  Hello world
  I have a function that is able to mark the input in a collection string using regular expressions.
  In case the input string is a character such as the comma or semicolon delimiter,
  We can just get the result we want like the example below.
  SQL> select * from v$version;
  
  
  BANNER
  --------------------------------------------------------------------------------
  Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - 64bit Production
  PL/SQL Release 11.2.0.1.0 - Production
  CORE    11.2.0.1.0      Production
  TNS for 64-bit Windows: Version 11.2.0.1.0 - Production
  NLSRTL Version 11.2.0.1.0 - Production
  SQL> with tab1 as (
    2      select 'abc,dfg,h,,1234' as col1 from dual
    3  )
    4  select regexp_substr(col1, '([^,]*)(,|$)', 1, level, 'i', 1) as result
    5  from tab1
    6  connect by level <= regexp_count(col1, ',')+1;
  
  
  RESULT
  ---------------
  abc
  dfg
  h
  
  1234
  But in the case where the channel of entry has 2 types of delimiter and each delimiter consists of 3 characters as below
  I wonder if it is possible to get the result as below.
  
  The input string: 01| ^ | ABCD| ^ | 111| * | 02| ^ | efgh| ^ | 222
  Separators: | * | is divided into lines, | ^ | is divided into columns
  
  Expected result:
  col1 col2 col3
  Row1 - > 01 abcd 111
  row2-> efgh 02 222
  Simply put, take a next
  
  The input string: 01| ^ | ABCD |^| 111 |*| 02 |^| efgh |^| 222
  Separator: | * |
  
  Result:
  01. ^ | ABCD | ^ | 111
  02. ^ | efgh | ^ | 222
  How can I achieve this using regular expressions?
  Kind regards
  Euntaek
  			 
  You need to know the number of the column from the outset:
  with tab1 as)
  Select ' 01 | ^ | ABCD | ^ | 111. * | 02. ^ | efgh | ^ | 222' as double col1
  )
  Select rownum,
  
  regexp_substr (regexp_substr (col1 '(.*?) ((\|\*\|)| $) ', 1, level, null, 1),'(.*?) ((\|\^\|)| $) ', 1, 1, null, 1) col1,.
  regexp_substr (regexp_substr (col1 '(.*?) ((\|\*\|)| $) ', 1, level, null, 1),'(.*?) ((\|\^\|)| $) ', 1, 2, null, 1) col2.
  
  regexp_substr (regexp_substr (col1 '(.*?) ((\|\*\|)| $) ', 1, level, null, 1),'(.*?) ((\|\^\|)| $) ', 1, 3, null, 1) col3
  of tab1
  connect by level<= regexp_count(col1,'\|\*\|')="" +="">
  /
  ROWNUM COL1 COL2 COL3
  ---------- ----- ----- -----
  1 01 abcd 111
  2 efgh 02 222
  SQL >
  SY.
  		   
   
              
             
   
  		     
  Validation of attribute text WITHOUT using regular expressions
   
  			 
  Hello world
  I'm working on a few validation rules for a text attribute and one of the conditions is that the text string can contain only alphanumeric characters.
  Because of the requirements that I can't use a regular expression here (the output should be a Boolean value confirming if the text is valid or not), so I need to find a way to write this in the rules...
  Yes, is there an easier way of writing this rule that the use of the ' Contains (< text >, < substring >)' function? Like this:
  [Etc. for all the non alpha numeric characters]
  If not, is it possible to write a rule that States that the text contains ONLY the following characters
  [Etc for all alphanumberic characters]
  Or is there some other function I could use it here?
  Appreciate any thoughts or input about how this could be solved, thank you in advance for your help.
  			 
  Unfortunately, regular expressions are the ideal solution for exactly the scenario you are exhibitor. The only alternative other than a broad 'or' statements is regular expressions, or write a custom function.
  		   
   
              
             
   
  		     
  A special character validation using regular expressions in ADF
   
  			 
  Hi guys,.
  I want to put the validation of a special as character (,.') ((en) &, -) using regular expressions.
  I asked the posting as [a-zA-Z0-9'(.),--/ &] but it does not work properly.
  Special characters should be like:
  Comma,
  Hyfan-
  Dot.
  Open and close braces (and).
  Ampercent &
  Apastrophy '
  Space ""
  Please help if anyone has idea.
  And I also tried to put under expression as...
  [a-zA-Z] + (\\s* [0-9] * [a-zA-Z] *-* & * \\(*\\) *, *'*. *) * [a-zA-Z0-9] + but we need the validation if we put special characters between the charater as "ab," chain "& (bc).
  his does not work if I put a special character at the beginning and the end of the string in the ADF
  			 
  Thanks Timo...
  its working fine...
  		   
   
              
             
   
  		     
  Regular expression for the format: 000-000 - 000000 000000
   
  			 
  Hi guys,.
  I need to validate the columns in a regular expression for the format of 000 000 - 000000 000000.
  For example - if the column contains a value such as "500 110 - 500044 000100" then it should return 'true' otherwise 'false. '
  Your timely help is well appreciated.
  Thanks in advance.
  			 
  Hello
  inDiscover wrote:
  Hi guys,.
  I need to validate the columns in a regular expression for the format of 000 000 - 000000 000000.
  For example - if the column contains a value such as "500 110 - 500044 000100" then it should return 'true' otherwise 'false. '
  Your timely help is well appreciated.
  Thanks in advance.
  If you want a regular expression
  REGEXP_LIKE (str
  {{' ^ {\d{3} \d{3}-\d{6} \d{6}$'
  )
  According to your needs.
  You don't need regular expressions for this.  It will be more efficient to use
  TRANSLATE (str
  '012345678'
  '999999999'
  ) = 999 999 - 999999 999999'
  		   
   
              
             
   
  		     
  Add an extension 'available' in the Code of edge
   
  			 
  Hello!
  How can I add the 'available' in the Code of edge tab extensions.
  Right now it shows as "installed".
  
  Thank you!
  
  Boco
  			 
  You can use the following steps to access the list of extension media: https://blogs.adobe.com/edgecode/enabling-the-brackets-extension-registry-in-edge-code/.
  Remember that media releases more frequently than Edge Code, so you can find some extensions in the list who say edge Code is not new enough to be compatible.  In many cases, the extension manager will allow you to install a version that is older and more compatible for a same extension, however.
  -Peter
  		   
   
              
             
   
  		     
  ADF Email of Validation using regular expressions
   
  			 Hello
  
  
  Wanted to add search Email Validation VO.
  
  
  It works if I put
  <af:validateRegExp pattern="[A-Z0-9._%+-]+@[A-Z0-9.-]+\.[A-Z]{2,4}" 
                                           messageDetailNoMatch="The value {1} is not a valid email address:"/>
  However, this requires identification of email to be entered in capital letters.
  
  
  I tried with below the option does not work.
  
  
                 <af:inputText value="#{bindings.xxEmail.inputValue}" label="Email"
                                        required="#{bindings.xxEmail.hints.mandatory}"
                                        columns="#{bindings.xxEmail.hints.displayWidth}"
                                        maximumLength="#{bindings.xxEmail.hints.precision}"
                                        shortDesc="#{bindings.xxEmail.hints.tooltip}" id="it5">
                              <f:validator binding="#{bindings.xxEmail.validator}"/>
                              <f:validateLength minimum="6"/>              
                              <af:validateRegExp pattern="[A-Za-z0-9._%+-]+@[A-Za-z0-9.-]+\.[A-Za-z]{2,4}" 
                                           messageDetailNoMatch="The value {1} is not a valid email address:"/>
                          </af:inputText>
  I got over information of
  
  ADF Email of Validation using regular expressions
  
  The user enter email id without @.
  
  
  
  
  
  
  Please suggest this model to reach.
  
  
  
  
  Thank you
  JIT
  
  
  Published by: appsjit on January 25, 2013 19:08			 
  Hello.
  My English is not very good.
  I use below format and it works
  
  "^ [_A-Za-z0 - 9-] + (\.). [_A-Za-z0-9-]+)*@[A-Za-z0-9][A-Za-z0-9-]+ (-.)] ([A Za-z0-9] +) * (-.) [A-Za - z] {2,}) $»
  messageDetailNoMatch = "the value {1} is not a valid email address" / >
  Habib
  Published by: Habib Eslami on January 26, 2013 01:22
  		   
   
              
             
   
  		     
  Using regular expressions to solve sys_refcursor of a record
   
  			 Regarding my Question about sys_refcursor with record type of thread, I thought it can be solved differently. It is:
  
  
  I have a string like ' 8:1706, 1194, 1817 ~ 1:1217, 1613, 1215, 1250'
  
  
  I need to do a few things using regular expressions and get something like
  
  
  select * from <table> where
  c1 in (8,1)
  and c2 in (1706,1194,1817,1217,1613,1215,1250);
  Is it possible by using regular expressions in a single select statement?			 
  Hello
  Game 6' - 8 "wrote:
  Your understanding is quite correct. But unfortunately it doesn't Frank.
  SQL> SELECT COUNT (*)
  2    FROM (SELECT sp.*
  3            FROM spml sp, spml_assignment spag
  4           WHERE sp.spml_id = spag.spml_id
  5             AND spag.class_of_svc_id = 8
  6             AND spag.service_type_id IN (1706, 1194, 1817)
  7             AND spag.carrier_id = 4445
  8             AND NVL (spag.haulage_type_id, -1) = NVL (NULL, -1)
  9             AND spag.effdate = TO_DATE ('01/01/2000', 'mm/dd/yyyy')
  10             AND spag.unit_id = 5
  11             AND sales_org_id = 1
  12          UNION ALL
  13          SELECT sp.*
  14            FROM spml sp, spml_assignment spag
  15           WHERE sp.spml_id = spag.spml_id
  16             AND spag.class_of_svc_id = 1
  17             AND spag.service_type_id IN (1217, 1613, 1215, 1250)
  18             AND spag.carrier_id = 4445
  19             AND NVL (spag.haulage_type_id, -1) = NVL (NULL, -1)
  20             AND spag.effdate = TO_DATE ('01/01/2000', 'mm/dd/yyyy')
  21             AND spag.unit_id = 5
  22             AND sales_org_id = 1);
  
  COUNT(*)
  ----------
  88
  
  SQL> SELECT COUNT (*)
  2    FROM spml sp, spml_assignment spag
  3   WHERE sp.spml_id = spag.spml_id
  4     AND spag.carrier_id = 4445
  5     AND NVL (spag.haulage_type_id, -1) = NVL (NULL, -1)
  6     AND spag.effdate = TO_DATE ('01/01/2000', 'mm/dd/yyyy')
  7     AND spag.unit_id = 5
  8     AND sales_org_id = 1
  9     AND REGEXP_LIKE ('8:1706,1194,1817~1:1217,1613,1215,1250',
  10                      '(^|~)' || spag.class_of_svc_id || ':'
  11                     )
  12     AND REGEXP_LIKE ('8:1706,1194,1817~1:1217,1613,1215,1250',
  13                      '(:|,)' || spag.service_type_id || '(,|$)'
  14                     );
  
  COUNT(*)
  ----------
  140
  
  SQL> 
  
  Published by: release 6' - 8 "August 11, 2009 20:04
  Serving what you ordered!
  Originally, you said that you are looking for something that produces the same result as
  where   c1 in (8, 1)
  and      c2 in (1706, 1194, 1817, 1217, 1613, 1215, 1250)
  
  in other words, the c1s could be coupled with any of the c2s.
  Now, it seems that what you want is
  where     (     c1 = 8
       and     c2 IN (1706, 1194, 1817)
       )
  or     (     c1 = 1
       and     c2 IN (1217, 1613, 1215, 1250)
       )
  
  in other words, c1 = 8 and c2 = 1250 is not good; is not c1 = 1 and c2 = 1706.
  In this case, try
  WHERE     REGEXP_LIKE ( s
                , '(^|~)' || c1
                       || ':([0-9]+,)*'
                       || c2
                       || '(,|~|$)'
                )
  		   
   
             
            
           
  		
   
            
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  Hi all Scenario of I have a chart with 2 sliders say Cur_1 and Cur_2. Cur_1 can have any value Y and Cur_2 has a value of Y which is "Num" less than the Cur_1 Y value where "Num" can be any number. For example, if Cur_1 = 50 and Num = 10, then Cur_2 
   
  		   
   
             
   
  		     
  Install Windows 7 on acer aspire E1 - 571G
   
  			 
  Okay so I saw this posted a few times, but is performed a few months ago. My problem: bought a new laptop, the material of the love, hate the abomination called 'Windows 8 '. My first solution: install from an old boot win7 disk I found lying around 
   
  		   
   
             
   
  		     
  Windows XP update problems... Help! KP951944, KB951550 and KB980371
   
  			 
  After the last update on WIndow Xp said what follows was not installed and why not... KP951944, KB951550 and KB980371. A site that requires a security until today ALSO said after their scanning that I'm missing ms09-043, MS09-073 and MS10-105, who al
   
  		   
   
             
   
  		     
  Matching of my Acer Tablet to Harman/Kardon speaker wireless
   
  			 
  I have an Acer Iconia tab A700.  Recently, I received as a gift a Harman/Kardon Onyx Studio wireless speaker.  I followed the instructions on how to connect through Bluetooth and my Tablet recognizes the speaker and I select but I don't get all the s
   
  		   
   
            
   
           
   
          
   
          
         
         
   
         
        
       
      
   
       
   
        
  
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