Why not this shadowfilter?

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• Right now, Firefox works on Sony Ericsson Xperia X 10, but not on the Xperia X 10 mini. Why is this and it will be fixed?

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  HotMail has its own Forums, so you can ask your questions there.

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  http://windowslivehelp.com/

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  http://windowslivehelp.com/forums.aspx?ProductID=1

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  Since your any question related to an external site and does not clearly represent the destination of the link, I have the irreversible.

  For completeness, here is the link to zero Google announcement that you referenced.

  Google online security blog: project announcing zero

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• Why not set a number in this datagrid?

  Hello

  Flash CS5

  (Keep this separate from my other thread in order not to divert too much and help others with this problem.)

  I have a datagrid whose content is not pulled from an outside source, but written in the code just to test. The grid if you click above appears in a box of dynamic text on the stage, (after a section of youtube that used dynamic text) but I get:

  BusRoute: undefined

  Sttmnt1: Oxford

  Sttmnt2: Burford

  Sttmnt3: Swindon

  Why not the number?  It contains the number of this title for each line is said by the way.

  code is: -.

  Import fl.controls.DataGrid;
  import flash.events.Event;
  Import fl.controls.ScrollPolicy;

  var item1:Object = {BusRoute: '43', Sttmnt1: 'Oxford', Sttmnt2: 'Burford', Sttmnt3: 'Swindon'};
  var item2:Object = {BusRoute: "361", Sttmnt1: "Evesham", Sttmnt2: "ChippingNorton", Sttmnt3: "Am Buckingh"};

  var myTextFormat:TextFormat = new TextFormat();
  myTextFormat.font = "Arial";
  myTextFormat.color = 000000
  myTextFormat.size = 14;

  var datagrid:DataGrid = new DataGrid;
  DataGrid.Move (20.50);
  DataGrid.Width = 200;
  DataGrid.Height = 70;
  datagrid.rowHeight = 35;
  DataGrid.Columns is ["BusRoute", "Sttmnt1", "Sttmnt2", "Sttmnt3"];.
  DataGrid.Columns [0]. Width = 30;
  DataGrid.Columns [1]. Width = 70;
  DataGrid.Columns [2]. Width = 70;
  datagrid.resizableColumns = true;
  datagrid.horizontalScrollPolicy = ScrollPolicy.ON;
  datagrid.setRendererStyle ("textFormat", myTextFormat);
  datagrid.addItem (item1);
  datagrid.addItem (item2);

  addChild (datagrid);

  datagrid.addEventListener (Event.CHANGE, gridItemClick);

  function gridItemClick(event:Event):void {}
  
  DataGridSelectedRowText.text = "BusRoute:" + event.target.selectedItem.Task + "\n";
  DataGridSelectedRowText.appendText ("Sttmnt1:" + event.target.selectedItem.Sttmnt1 + "\n");
  DataGridSelectedRowText.appendText ("Sttmnt2:" + event.target.selectedItem.Sttmnt2 + "\n");
  DataGridSelectedRowText.appendText ("Sttmnt3:" + event.target.selectedItem.Sttmnt3 + "\n");
  
  }

  Envirographics

  
  

  In your objects item1 and item2 property you set first to be 'BusRoute.

  var item1:Object = {BusRoute: '43', Sttmnt1: 'Oxford', Sttmnt2: 'Burford', Sttmnt 3: "Swindon"};

  but in your attempt to acquire the data you seem to be referring to him as "stain".

  DataGridSelectedRowText.text = "BusRoute:" + event.target.selectedItem.Task + "\n";

  One of them must be changed to agree with each other.

• Why is this work not running?

  Why is this work not running?
  

  SQL> BEGIN
    2  DBMS_SCHEDULER.RUN_JOB('EXCHANGE_PART_JOB');
    3  END;
    4  /
  BEGIN
  *
  Error in line 1:
  ORA-00911: invalid character.
  ORA-06512: in "SYS.DBMS_ISCHED", line 150
  ORA-06512: in "SYS.DBMS_SCHEDULER", line 441
  ORA-06512: in line 2

  This work follow these steps:

  CREATE OR REPLACE PROCEDURE Exchange_Partition IS
  Sql_Exchange VARCHAR2(2000);
  BEGIN
  Sql_Exchange := 'ALTER TABLE HR.GPS_LOG_HIS EXCHANGE PARTITION '||
  'udp_part'||TO_CHAR(SYSDATE-1/24,'YYYYMMDDHH24')
  ||' WITH TABLE HR.GPS_LOG';  
  EXECUTE IMMEDIATE Sql_Exchange;
  END;
  /

  Use the following program:

  BEGIN
    DBMS_SCHEDULER.create_program (
      program_name        => 'exchange_part_prog',
      program_type        => 'STORED_PROCEDURE',
      program_action      => 'EXCHANGE_PARTITION',
      --Use a database directory to replace the OS directory.
      number_of_arguments => 0,
      enabled             => TRUE,
       comments            => 'Program to exchange partitions for hr.gps_log_his table or other tables
                               use a shell script.');
  END;
  /

  Use the following code to create the work:

  BEGIN
    DBMS_SCHEDULER.create_job (
      job_name      => 'exchange_part_job',
      program_name  => 'exchange_part_prog',
      schedule_name => 'exchange_part_hourly_schedule',
      enabled       => TRUE,
      auto_drop     => false,
      comments      => 'Job defined to exchange partitions for gps_log_his table or orhter tables.');
  END;
  /

  Ok

  ORA-14099: all rows in the table are not eligible for the specified partition
  Cause: There is at least one line in the non-partitioned table which does not qualify for the partition specified in the PARTITION of EXCHANGE ALTER TABLE
  Action: Ensure that all the lines in the segment qualify for the partition. Perform the operation table alter with the NO CHECK option. Run ANALYZE table VALIDATE on that partition, namely the invalid rows and delete them.

  I think you should check the data in gps_log, some lines must belog to another partition?

  Concerning
  Peter

• After iPhoto deleting Library.migratedphotolibrary why not get all this disk space?

  I've migrated photos on my Mac (OS 10.11.2) months ago.

  I talked to AppleCare just before and I was told that I could remove the old Library.migratedphotolibrary iPhoto after confirmation of everything was in pictures and Photos Library.photoslibrary.

  I did, and they are, so I removed the old library thought I would free 113 GB of disk space on my MBP. The old library was the size and the new library is 128 GB because it has ceased to grow since the migration into Photos, and everything seems to be there.

  So I moved iPhoto Library.migratedphotolibrary into the trash and empty the trash. It took some time for the trash to empty! But once completed, instead of 113 GB of space to reclaim it seems that I only got back around 10 GB of space.

  Why is this? Were two libraries really sharing pointers to the same pictures?

  Thank you

  Doug

  The following explanation should help: Photos saves disk space to share images with your iPhoto or Aperture - Apple Support libraries