Similar Questions

• How can I stop Photoshop CS4 create a new layer each time I use the online tool?

  How can I stop Photoshop CS4 create a new layer each time I use the online tool?

  Whenever I use the online tool, a new layer is created. How can I stop this? No settings have been changed.
  
  Thanks in advance.

  Look at the three options in the top bar.

  

• I have Photoshop CS6 extended. When I create a new layer, I get the following message. Could not complete the command because the selected area is empty. What I am doing wrong?

  I have Photoshop CS6 Extended. When I create a new layer, I get the following message. Could not complete the command because the selected area is empty.

  What I am doing wrong?

  Thanks for any help

  Bob.

  How do you create the new layer? Looks like you have a selection and use ctrl/cmd-J. If you have a choice and it is empty, you will get this error.

• Questions: Create a new layer / switch between the screen Modes

  I spent the day to reset my workflow and keyboard shortcuts that I have the transition from CS5.5 on CC. A question about the ID:

  1. create a new layer draws up the InDesign menus? In CS5.5, I managed to create a shortcut customized in three programs (PS, I, ID). In cloud creative, no matter how hard I look in InDesign, that I can't find a place in the dialog box shortcuts keyboard to make a shortcut for this command.

  2 in Photoshop and Illustrator, by pressing the F button toggles between screen modes. In InDesign CS5.5, it does the same thing. However, CC does not seem to have this feature. He wants to assign three different shortcuts for Normal, overview and presentation of the screens. Correct, and is it possible to return to a toggle key 'F'?

  Thank you!

  Perhaps scriptable. Ask in the InDesign scripting

• In trying to edit my text layer, it creates a new layer. Help please: >

  Yes, as the subject of bed. I can't change my text layer. If I try to use the tool t it doesn't create a new layer. IM displaying a screen so that you can see that I don't have a T-layer.

  These are the characters. IM pretty noob on photoshop. So, you might go through the base of guidance on how to do it.

  However, I tried the t layer doubleclicking. There is no highlight on the text, nothing happens.

  

  All you can do is remove this layer and re-do with the text tool. There is no way to reverse this trend.

  Always keep a copy of your psd file unrasterized before you rasterize the text.

• 'create a new layer without dialogue' redefine shortciut

  Hello.

  A desire to redefine the default shortcut for the command 'create a new layer without dialogue' but I can't find this command in the shortcuts preferences.

  What section of the preferences in photoshop cs6 shortcut, nested this command?

  Thank you.

  I don't think it's a shortcut that can be redefined as such in the command Editor, but you could use a script and assign a keyboard shortcut for the script.

  The following script will make a new layer without the dialog box.

  // =======================================================
  var idMk = charIDToTypeID ("Mk");
  var desc10 = new ActionDescriptor();
  var idnull = charIDToTypeID ("null");
  var ref9 = new ActionReference();
  var idLyr = charIDToTypeID ("Lyr");
  Ref9.putClass (idLyr);
  desc10.putReference (idnull, ref9);
  executeAction (idMk, desc10, DialogModes.NO);

  You can copy the above script, paste into Adobe ExtendScript Toolkit CS6 , and then save the script in the cs6 Presets > Scripts folder in the program folder or the photoshop cs6 application.

  (you can call it as you like, therefore the .jsxextension)

  Then when you restart photoshop cs6, it should appear under file > Scripts and you can use the keyboard shortcuts Editor to assign a shortcut to the script.

  What operating system do you use?

• Cannot create a new layer when you open a gif file

  With the help of Photoshop Elements 8, I opened a gif that I want to change the text. I opened the file and the first thing I want to do is create a new layer, but I'm not able to. the button new layer in the layers box is disabled, as is the menu layers.  How to fix this?

  Image > Mode > RGB. But there are problems to open animated after the fact in recent versions of the EPS, GIF images sometimes. You end up with just one layer, then save your layered as a PSD or tiff for future editing.

• Cannot create a new layer (was: problem with programme)

  Flash CS6 doesn't let me choose text tool... computer laptop asus

  Create a new layer.

  Select the text tool.

  any problem?

• Hello Im having trouble with a create a new layer.

  For some reason when I create a new layer, the edges are rounded and when I 'fill' color happens as a gradation, how can I cancel it?

  

  You have the pen 100 px value in the Options bar

• quick method to create a new layer under the current layer?

  would be the best way to quickly create a new layer slot rather than above the active layer to assign a script to a keyboard shortcut - or is it possible to change the default new layer shortcut (command + option + SHIFT + N) to create a new layer above the current layer to create rather a under the active layer?

  Thank you

  Command-click the new layer in the layers Panel button.

• I created a backup feature of document for each document that I created, including new documents. I don't want no more of this function. How can I remove it?

  Original title: Backup Document

  I created a backup feature of document for each document that I created, including new documents. I don't want no more of this function. How can I remove it?

  Hey BradleyCloetingh,

  Can you reverse your actions when you first made the changes, just go through the process and change everything to the original?
  Or you could do a System Restore.
  Let us know if you are still looking for an answer.
  Thank you!

• When I click on light effects, it simply creates a new layer, and I can't really change/tweak the enlightenment... help

  Photoshop lighting effect filter does not work. A new layer called just the effects of light appears, why?

  Under help > system info, copy and paste the first two lines identifying the exact version of your OS and Photoshop.

  In Photoshop, the command is the menu Filter > render > lighting effects

  Don't use "Last filter" or it runs the command without bring to the top of the dialog box.

• How can I create a new layer that is a gradient?

  Hi, I'm very new to scripting photoshop and have some difficulty.

  I am looking for a way to take a picture I have and configure it to have a gradient opacity as he approaches middle, my thought on how to do was simply to create a layer that is a gradient from the upper left to lower right and secure then as a vector mask.

  Any ideas on how I could create this gradient layer of script or a better method to do this opacity gradient?

  Thanks in advance,

  Levianth

  You can try this:

  // 2012, use it at your own risk;
  #target photoshop
  if (app.documents.length > 0) {
  var myDocument = app.activeDocument;
  var theLayer = myDocument.activeLayer;
  if (theLayer.isBackgroundLayer == true) {theLayer.isBackgroundLayer = false};
  // create gradient layer;
  // =======================================================
  var idMk = charIDToTypeID( "Mk  " );
      var desc15 = new ActionDescriptor();
      var idnull = charIDToTypeID( "null" );
          var ref3 = new ActionReference();
          var idcontentLayer = stringIDToTypeID( "contentLayer" );
          ref3.putClass( idcontentLayer );
      desc15.putReference( idnull, ref3 );
      var idUsng = charIDToTypeID( "Usng" );
          var desc16 = new ActionDescriptor();
          var idType = charIDToTypeID( "Type" );
              var desc17 = new ActionDescriptor();
              var idType = charIDToTypeID( "Type" );
              var idGrdT = charIDToTypeID( "GrdT" );
              var idLnr = charIDToTypeID( "Lnr " );
              desc17.putEnumerated( idType, idGrdT, idLnr );
              var idGrad = charIDToTypeID( "Grad" );
                  var desc18 = new ActionDescriptor();
                  var idNm = charIDToTypeID( "Nm  " );
                  desc18.putString( idNm, "Custom" );
                  var idGrdF = charIDToTypeID( "GrdF" );
                  var idGrdF = charIDToTypeID( "GrdF" );
                  var idCstS = charIDToTypeID( "CstS" );
                  desc18.putEnumerated( idGrdF, idGrdF, idCstS );
                  var idIntr = charIDToTypeID( "Intr" );
                  desc18.putDouble( idIntr, 4096.000000 );
                  var idClrs = charIDToTypeID( "Clrs" );
                      var list3 = new ActionList();
                          var desc19 = new ActionDescriptor();
                          var idClr = charIDToTypeID( "Clr " );
                              var desc20 = new ActionDescriptor();
                              var idRd = charIDToTypeID( "Rd  " );
                              desc20.putDouble( idRd, 0.000000 );
                              var idGrn = charIDToTypeID( "Grn " );
                              desc20.putDouble( idGrn, 0.000000 );
                              var idBl = charIDToTypeID( "Bl  " );
                              desc20.putDouble( idBl, 0.000000 );
                          var idRGBC = charIDToTypeID( "RGBC" );
                          desc19.putObject( idClr, idRGBC, desc20 );
                          var idType = charIDToTypeID( "Type" );
                          var idClry = charIDToTypeID( "Clry" );
                          var idUsrS = charIDToTypeID( "UsrS" );
                          desc19.putEnumerated( idType, idClry, idUsrS );
                          var idLctn = charIDToTypeID( "Lctn" );
                          desc19.putInteger( idLctn, 0 );
                          var idMdpn = charIDToTypeID( "Mdpn" );
                          desc19.putInteger( idMdpn, 50 );
                      var idClrt = charIDToTypeID( "Clrt" );
                      list3.putObject( idClrt, desc19 );
                          var desc21 = new ActionDescriptor();
                          var idClr = charIDToTypeID( "Clr " );
                              var desc22 = new ActionDescriptor();
                              var idRd = charIDToTypeID( "Rd  " );
                              desc22.putDouble( idRd, 0.000000 );
                              var idGrn = charIDToTypeID( "Grn " );
                              desc22.putDouble( idGrn, 0.000000 );
                              var idBl = charIDToTypeID( "Bl  " );
                              desc22.putDouble( idBl, 0.000000 );
                          var idRGBC = charIDToTypeID( "RGBC" );
                          desc21.putObject( idClr, idRGBC, desc22 );
                          var idType = charIDToTypeID( "Type" );
                          var idClry = charIDToTypeID( "Clry" );
                          var idUsrS = charIDToTypeID( "UsrS" );
                          desc21.putEnumerated( idType, idClry, idUsrS );
                          var idLctn = charIDToTypeID( "Lctn" );
                          desc21.putInteger( idLctn, 4096 );
                          var idMdpn = charIDToTypeID( "Mdpn" );
                          desc21.putInteger( idMdpn, 50 );
                      var idClrt = charIDToTypeID( "Clrt" );
                      list3.putObject( idClrt, desc21 );
                  desc18.putList( idClrs, list3 );
                  var idTrns = charIDToTypeID( "Trns" );
                      var list4 = new ActionList();
                          var desc23 = new ActionDescriptor();
                          var idOpct = charIDToTypeID( "Opct" );
                          var idPrc = charIDToTypeID( "#Prc" );
                          desc23.putUnitDouble( idOpct, idPrc, 0.000000 );
                          var idLctn = charIDToTypeID( "Lctn" );
                          desc23.putInteger( idLctn, 0 );
                          var idMdpn = charIDToTypeID( "Mdpn" );
                          desc23.putInteger( idMdpn, 50 );
                      var idTrnS = charIDToTypeID( "TrnS" );
                      list4.putObject( idTrnS, desc23 );
                          var desc24 = new ActionDescriptor();
                          var idOpct = charIDToTypeID( "Opct" );
                          var idPrc = charIDToTypeID( "#Prc" );
                          desc24.putUnitDouble( idOpct, idPrc, 100.000000 );
                          var idLctn = charIDToTypeID( "Lctn" );
                          desc24.putInteger( idLctn, 2048 );
                          var idMdpn = charIDToTypeID( "Mdpn" );
                          desc24.putInteger( idMdpn, 50 );
                      var idTrnS = charIDToTypeID( "TrnS" );
                      list4.putObject( idTrnS, desc24 );
                          var desc25 = new ActionDescriptor();
                          var idOpct = charIDToTypeID( "Opct" );
                          var idPrc = charIDToTypeID( "#Prc" );
                          desc25.putUnitDouble( idOpct, idPrc, 0.000000 );
                          var idLctn = charIDToTypeID( "Lctn" );
                          desc25.putInteger( idLctn, 4096 );
                          var idMdpn = charIDToTypeID( "Mdpn" );
                          desc25.putInteger( idMdpn, 50 );
                      var idTrnS = charIDToTypeID( "TrnS" );
                      list4.putObject( idTrnS, desc25 );
                  desc18.putList( idTrns, list4 );
              var idGrdn = charIDToTypeID( "Grdn" );
              desc17.putObject( idGrad, idGrdn, desc18 );
          var idgradientLayer = stringIDToTypeID( "gradientLayer" );
          desc16.putObject( idType, idgradientLayer, desc17 );
      var idcontentLayer = stringIDToTypeID( "contentLayer" );
      desc15.putObject( idUsng, idcontentLayer, desc16 );
  executeAction( idMk, desc15, DialogModes.NO );
  // move layer below;
  var theGradient = myDocument.activeLayer;
  theGradient.move(theLayer, ElementPlacement.PLACEAFTER);
  // clipping mask;
  theLayer.grouped = true
  };
  

• Why should I create a new user profile when you remove a damaged user account?

  I have a corrupted user account and was referred to the following link http://windows.microsoft.com/en-CA/windows-vista/Fix-a-corrupted-user-profile

  However, I don't understand why we're required to go through this complicated process when we go to Control Panel - user accounts and family safety-user accounts - add and remove accounts delete user accounts until you can actually remove an account asks you if you want to keep the files of this account.  It is said that it can automatically save the contents of this user account office and favorite Documents, music, photos and videos in a new folder on the desktop.  I realize, this does not include e-mail messages, but I thought I could export those to a memory stick and then import them into my new user account.  It all seems a much simpler process than to create a new profile.  Why Microsoft suggests must create a new profile?

  Hello Kodika

  Thanks for the return of the response.  I guess that it was just a typo, but it's OK.  Please let us know if you have any other questions or you are experiencing other problems.

  Thanks again!

• Keeping selected when you create a new layer of origin

  Is it possible to "definitively" select a layer?

  
  At the moment I just a single layer that I am trying to select a portion of and then new layer by cutting. Once this new layer is selected, I have to reselect the original layer before you replicate this process again.

  On the one hand, this seems really minor, on the other hand, really Basic. I assume that there is an easy way to do what I'm overlooking. I need to replicate this process a few hundred times and work with / export sections is not conducive to my endgoal.

  possible?

  Not a new layer will become the current target layer in Photoshop. It that way forever and a lot of things relies on this.  If this was changed it would brake a lot.  The best thing you could do is an action that would do what you want to do and make a shortcut you can use instead of "new layer via cut."  The action would simply make a new layer by cutting then the Alt + [Select layers backward step.