Why this query produces no output?
Why this query produces no output?select * from
(
SELECT 40 as startvalue, (24 * 60)*(To_Date('00:40', 'HH24:MI') - To_Date('00:00', 'HH24:MI')) as c
FROM dual di
) q
where q.c = q.startvalueAnd just to show that it works if round you...
SQL> ed
Wrote file afiedt.buf
1 select * from
2 (
3 SELECT 40 as startvalue, round((24 * 60)*(To_Date('00:40', 'HH24:MI') - To_Date('00:00', 'HH24:MI')),0) as c
4 FROM dual di
5 ) q
6* where q.c = q.startvalue
SQL> /
STARTVALUE C
---------- ----------
40 40
I certainly wouldn't say using TRIM as PS has suggested. TRIM is a string function, not a digital function.
Tags: Database
Similar Questions
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Why this query can remove duplicates?
Why this query can remove duplicates? Can someone give me detailed explanation?
Thank you
select salary from employees union select salary from employees;Hello
See the docs.
' Example of the UNION
The following statement combines the results of two queries with the UNION operator which eliminates duplicates of selected lines.
"This statement shows that you must match the data type (using the function TO_CHAR) when the columns do not exist in one or the other table"http://download.Oracle.com/docs/CD/B19306_01/server.102/b14200/queries004.htm#i2054381
Edit
Here's another interpretation of your question:
http://asktom.Oracle.com/pls/asktom/f?p=100:11:0:P11_QUESTION_ID:1224636375004
Published by: hoek on October 22, 2009 17:40
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Stupid old backpacker (me) cannot understand why this query returns 1 row
Hi all
In reference to {: identifier of the thread = 2456973}, why do
only 1 rank and not 1 for each task? In fact, I had to test it myself to believe.select sum(count(decode(job, 'CLERK', 1, null))) CLERKS , sum(count(decode(job, 'SALESMAN', 1, null))) SALESMANS from emp group by job;
It returns the data as if the query were
Using only a single aggregate (count or sum) returns 1 row per job, as expectedselect sum(CLERKS), sum(SALESMANS) from (select count(decode(job, 'CLERK', 1, null)) CLERKS, count(decode(job, 'SALESMAN', 1, null)) SALESMANS from emp group by job)John Stegeman wrote:
It returns the data as if the query wereselect sum(CLERKS), sum(SALESMANS) from (select count(decode(job, 'CLERK', 1, null)) CLERKS, count(decode(job, 'SALESMAN', 1, null)) SALESMANS from emp group by job)Exactly the point ;-)
It seems that Oracle actually do, a group of 'double' in the same operation.
Attend plans to explain in this example:SQL> select count(decode(job, 'CLERK', 1, null)) CLERKS 2 , count(decode(job, 'SALESMAN', 1, null)) SALESMANS 3 from scott.emp group by job; CLERKS SALESMANS ---------- ---------- 0 0 0 0 0 0 0 4 4 0 Execution Plan ---------------------------------------------------------- Plan hash value: 1697595674 --------------------------------------------------------------------------- | Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | --------------------------------------------------------------------------- | 0 | SELECT STATEMENT | | 5 | 40 | 4 (25)| 00:00:01 | | 1 | HASH GROUP BY | | 5 | 40 | 4 (25)| 00:00:01 | | 2 | TABLE ACCESS FULL| EMP | 14 | 112 | 3 (0)| 00:00:01 | ---------------------------------------------------------------------------And compare it to the one with the double aggregates:
SQL> select sum(count(decode(job, 'CLERK', 1, null))) CLERKS 2 , sum(count(decode(job, 'SALESMAN', 1, null))) SALESMANS 3 from scott.emp group by job; CLERKS SALESMANS ---------- ---------- 4 4 Execution Plan ---------------------------------------------------------- Plan hash value: 417468012 ---------------------------------------------------------------------------- | Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | ---------------------------------------------------------------------------- | 0 | SELECT STATEMENT | | 1 | 8 | 4 (25)| 00:00:01 | | 1 | SORT AGGREGATE | | 1 | 8 | 4 (25)| 00:00:01 | | 2 | HASH GROUP BY | | 1 | 8 | 4 (25)| 00:00:01 | | 3 | TABLE ACCESS FULL| EMP | 14 | 112 | 3 (0)| 00:00:01 | ----------------------------------------------------------------------------There are GROUP BY hash and SORT GLOBAL times.
It is really unnecessary to an aggregate on an aggregate - if two aggregates are used "in the same group level.
Sum() aggregates are used on an already aggregated value, so it doesn't look like Oracle which actually cures like 'first do the internal aggregate using the group specified by and then do the external aggregation on the result with any group.'Look at this example where I combine aggregates "double" with "single" aggregates:
SQL> select sum(count(decode(job, 'CLERK', 1, null))) CLERKS 2 , sum(count(decode(job, 'SALESMAN', 1, null))) SALESMANS 3 , count(decode(job, 'SALESMAN', 1, null)) SALESMANS2 4 , count(*) COUNTS 5 from scott.emp group by job; CLERKS SALESMANS SALESMANS2 COUNTS ---------- ---------- ---------- ---------- 4 4 1 5 Execution Plan ---------------------------------------------------------- Plan hash value: 417468012 ---------------------------------------------------------------------------- | Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | ---------------------------------------------------------------------------- | 0 | SELECT STATEMENT | | 1 | 8 | 4 (25)| 00:00:01 | | 1 | SORT AGGREGATE | | 1 | 8 | 4 (25)| 00:00:01 | | 2 | HASH GROUP BY | | 1 | 8 | 4 (25)| 00:00:01 | | 3 | TABLE ACCESS FULL| EMP | 14 | 112 | 3 (0)| 00:00:01 | ----------------------------------------------------------------------------When you mix "doubles" and "single" aggregates, Oracle decides that unique aggregates belong to the 'outer' aggregation
SALESMAN2 did a count on the aggregated work column which is the result of the 'internal' group by - so only 1.
The count (*) is also the result of the aggregation of the 'internal '.I don't know if it's documented or if it is an 'effect' of internal code used for GROUPING SETS or the internal code used to enable the analytical functions like this:
SQL> select count(decode(job, 'CLERK', 1, null)) CLERKS 2 , count(decode(job, 'SALESMAN', 1, null)) SALESMANS 3 , sum(count(decode(job, 'CLERK', 1, null))) over () CLERKS2 4 , sum(count(decode(job, 'SALESMAN', 1, null))) over () SALESMANS2 5 from scott.emp group by job; CLERKS SALESMANS CLERKS2 SALESMANS2 ---------- ---------- ---------- ---------- 0 0 4 4 4 0 4 4 0 0 4 4 0 0 4 4 0 4 4 4 Execution Plan ---------------------------------------------------------- Plan hash value: 4115955660 ---------------------------------------------------------------------------- | Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | ---------------------------------------------------------------------------- | 0 | SELECT STATEMENT | | 5 | 40 | 4 (25)| 00:00:01 | | 1 | WINDOW BUFFER | | 5 | 40 | 4 (25)| 00:00:01 | | 2 | SORT GROUP BY | | 5 | 40 | 4 (25)| 00:00:01 | | 3 | TABLE ACCESS FULL| EMP | 14 | 112 | 3 (0)| 00:00:01 | ----------------------------------------------------------------------------Personally, I think that I would have preferred if Oracle has raised an error on this "double aggregation" and therefore require me to write this way (if it's the result I wanted):
select sum(CLERKS), sum(SALESMANS) from (select count(decode(job, 'CLERK', 1, null)) CLERKS, count(decode(job, 'SALESMAN', 1, null)) SALESMANS from emp group by job)I don't really see a good use case for aggregations of 'double'-, but rather that he could give you undetected bugs in your code, if you happen to do double aggregation without noticing.
Interesting thing to know ;-)
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Can't understand why this query returns multiple lines with the same data
Hi all
I am a relative novice and self-taught when it comes to SQL. I wrote a query to our reporting tool that returns multiple rows, and I can't understand why. I know that I can use the SELECT DISTINCT option, but it really slows the execution when I do. I'd really rather understand if I can change the code to avoid the multiples. This is the query. I've included a few statements in italics to help explain the break. Any ideas?
SELECT MATSITE, MATPONUM, FIRSTRECPTDATE
Of
Subquery that concludes the first date on which purchase orders have been implemented with ACK State
(SELECT ACKSTAT. PONUM AS 'ACKPONUM', (MIN (ACKSTAT. CHANGEDATE)) AS 'FIRSTACKDATE '.
OF PZMAX. POSTATUS ACKSTAT
WHERE (ACKSTAT. STATE = 'ACK') AND (ACKSTAT.ORGID ='CGSALTUS)
GROUP OF ACKSTAT. PONUM),
Subquery that concludes the first reception against a purchase order transaction for purposes of comparison
(SELECT TRANS. PONUM AS "MATPONUM", TRANS. SITEID AS 'MATSITE', (MIN (TRANS. TRANSDATE)) AS 'FIRSTRECPTDATE '.
OF PZMAX. MATRECTRANS TRANS
WHERE (TRANS.ORGID ='CGSALTUS) AND (TRANS. HOUR > =: startDate and TRANS. TRANSDATE < =: endDate)
TRANS GROUP. SITEID, TRANS. PONUM)
WHERE
(ACKPONUM = MATPONUM AND FIRSTRECPTDATE < FIRSTACKDATE) OR (NOT EXISTS (SELECT 1 FROM PZMAX. POSTATUS ACKSTAT2 WHERE (ACKSTAT2. PONUM = MATPONUM) AND (ACKSTAT2. STATE = 'ACK') AND (ACKSTAT2.ORGID ='CGSALTUS)))
The where the instruction is intended to find when one of two conditions exists. ((1) received happened before the command either in ACK or 2) a reception that's happened, but the purchase order is never in ACK State. It seems that this second condition that creates multiple lines.
Any thoughts will be appreciated geratly.
Dave Teece
-
Why this query SQLLite returns the same all the time?
Hello
I use a search box to accept a query on three columns and am page before based on the last record, which in this case is Run Baby Run by Loopy
I know for a fact that the database has a song inside by Loopy called Straight Down the Line, so this should at least be showing that. But it does is display the same songs again.
Can someone explain the error in my logic here?
SELECT * WHERE DiscID AS "loopy %" songs or artist LIKE 'loopy %' or AS "loopy %" title AND artist > = 'LOOPY' COLLATE NOCASE Title > = 'Run Baby Run' COLLATE NOCASE ORDER BY artist COLLATE NOCASE ASC, title COLLATE NOCASE ASC LIMIT 20
Thanks for taking a peek.
This is a forum for AS3, not SQL - etc., which may explain the slow Pickup on your ad. While someone might offer something at some point, you should try to find a forum where they discuss SQL programming, which could mean going out of the domain of Adobe. The closest thing I can think that would be a forum in the Adobe forums game...
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Hello
My java file, I get the data in this format 18-11-2010 0:00:00
So I used the query in this way
select distinct to_char (USAGEDATE, ' yyyy-mm-dd hh: mm :) from testsummary where USAGEDATE BETWEEN 2010-10-18 0:00:00 and 18-11-2010 0:00:00)
Help, pleasequery is incorrect and needs to read
Select distinct to_char (USAGEDATE, 'yyyy-mm-dd hh24:mi:ss')
of testsummary
where USAGEDATE BETWEEN to_date ("2010-10-18 0:00:00 ',' yyyy-mm-dd hh24:mi:ss'") and to_date ('18-11-2010 0:00:00 ',' yyyy-mm-dd hh24:mi:ss')----------------------
Sybrand Bakker
Senior Oracle DBA -
That means 1e9 and why this query does not work?
What does 1e9? Someone has links to documentation on this oracle? And why I get this error?
SQL> select segment_name,(bytes/1e9) AS size from dba_segments where segment_name='MSG_MASTER'; select segment_name,(bytes/1e9) AS size from dba_segments where segment_name='MSG_MASTER' * ERROR at line 1: ORA-00923: FROM keyword not found where expectedSIZE is a keyword - so if you want the name of the column size then use 'SIZE' else give it a different name
Try dividing by other exponentials, then you'll see how: 1e0 1e1 (div 1), (div by 10), 1e2 :-) etc
Mette
Published by: mettemusens on 2009-05-12 16:02
-
Why this query does not work on the CF when it works fine on MYSQL?
Subject says it all. I can run it through console mysql and get the result that I need, but when I place it inside a cfquery that he will not treat.
SET @saldo = 20000;
SELECT
IF (Co.transtipo=0,@saldo:[email protected],@saldo:=@saldo+t.transmonto),
@saldo: = @saldo - t.transmonto.
t.TransID,
t.cuentaid,
t.operacionid,
t.fechatrans,
t.voucher,
t.cheque,
t.transtitular,
t.transmonto,
t.transdetalle,
t.modificado,
Co.transtipo,
Co.Operacion
OF cuentastrans t
LEFT JOIN cuentasoperacion co ON t.operacionid = co.operacionid
WHERE the t.cuentaid = 7
ORDER BY t.fechatrans ASCFixed, coldfusion must be labeled with 'AS' of the expressions in the opposite case he used to index the column.
-
Why between date is not return data for this query?
Hello
I have a table with this structure and I write this query to retrieve a few lines based on certain conditions, but this query returns no data. Can you please tell why?
ID DT 003 11/8/2011 002 10/8/2011 001 9/8/2011And the execution of the query:
Published by: starting August 13, 2011 07:10SELECT * FROM TABLE_NAME WHERE DT BETWEEN TO_DATE('08/08/2011','dd/mm/yyyy') AND TO_DATE('12/08/2011','dd/mm/yyyy');
>
>
But what is the problem with that, why this date does not match when I'm providing the date format?
What part don't you understand? You have not used TO_DATE when inserting data and default date format is dd/mm/yyyy, right? Same default date format is used if you are running:
SELECT * FROM TABLE_NAME
Original of your post States select returns above:
ID DT 003 11/8/2011 002 10/8/2011 001 9/8/2011So the dates that you inserted are November 8, 2011, October 8, 2011-September 8, 2011. TO_DATE('08/08/2011','dd/mm/yyyy') is now August 8, 2011 and TO_DATE('12/08/2011','dd/mm/yyyy') is August 12, 2011. Then of course:
SELECT * FROM TABLE_NAME WHERE DT BETWEEN TO_DATE('08/08/2011','dd/mm/yyyy') AND TO_DATE('12/08/2011','dd/mm/yyyy').
will return all the lines. Bottome line - never write code that uses the implicit conversions date since your code becomes dependent on the NLS client settings and maybe working for a client and fail or produce erroneous results for other customers.
SY.
-
Why is-isn't this query with XMLTABLE and XMLTYPE post? (xmlns)
OK, Miss me something here - because this query returns two rows:
Select seq_num, prdt_num
of the double.
XMLTable ('/ food/product ' passage)
XmlType ("< name of food =" Test Feed"> ' |)
' < product id = "3000001" > < > 101 ExternalId < / ExternalId > < / product > ' |
' < product id = "3000002" > < > 102 ExternalId < / ExternalId > < / product > ' |
("< / power >")
columns
seq_num for the ordinalite,
prdt_num number of path "ExternalId")
;
and it does NOT work:
Select seq_num, prdt_num
of the double.
XMLTable ('/ food/product ' passage)
XmlType ("< name of food ="Test Feed"xmlns ="http://www.bazaarvoice.com/xs/PRR/SyndicationFeed/4.1"> ' |)
' < product id = "3000001" > < > 101 ExternalId < / ExternalId > < / product > ' |
' < product id = "3000002" > < > 102 ExternalId < / ExternalId > < / product > ' |
("< / power >")
columns
seq_num for the ordinalite,
prdt_num number of path "ExternalId")
;
The namespace document seems to be valid... I'm missing something obvious, I believe. But it's late, and it's Friday.
Published by: rjbryla on June 4, 2010 15:35Namespaces
When everything looks good, check your namespaces and prefixes. That you will get every day of the week.
Derived from the post "How I declare mapping prefix to namespace with XMLTable()?" in the FAQ on this forum, your second XML would look like
select seq_num, prdt_num from dual, xmltable(xmlnamespaces(default 'http://www.bazaarvoice.com/xs/PRR/SyndicationFeed/4.1'), '/Feed/Product' passing xmltype('' || ' ') columns seq_num for ordinality, prdt_num number path 'ExternalId');101 102 -
Why this erroneous query works well? -Answer
DB version: 10 gr 2
I wanted to reproduce the non-use of rownum when used with an ORDER BY clause.
Because ORDER BY is evaluated finally (after ROWNUMs are generated), the query below give bad result put most of the time.
But the following query
give me a correct result. Then, when this query will start to give erroneous results?select ename,join_date from test where rownum<4 order by join_date
Published by: Nichols on December 15, 2008 03:37alter session set nls_date_format='DD-MM-YYYY HH:MI:SS'; SELECT SYSDATE FROM DUAL; SYSDATE ------------------- 15-12-2008 11:40:30 create table test (ename varchar2(15), join_date date); insert into test values('JAMES',SYSDATE); insert into test values('CHESTER',SYSDATE); insert into test values('SUNITA',SYSDATE); insert into test values('GARRY',SYSDATE); insert into test values('KAREN',SYSDATE); insert into test values('ABDUL',SYSDATE); insert into test values('YING',SYSDATE); set lines 400 select * from test; ENAME JOIN_DATE --------------- ------------------- JAMES 15-12-2008 11:41:21 CHESTER 15-12-2008 11:41:40 SUNITA 15-12-2008 11:41:56 GARRY 15-12-2008 11:42:17 TIM 15-12-2008 11:42:44 KAREN 15-12-2008 11:52:46 ABDUL 15-12-2008 11:53:01 YING 15-12-2008 11:53:18 CHAICE 15-12-2008 12:14:27 THELMA 15-12-2008 12:14:54 select ename,join_date from test where rownum<4 order by join_date; ENAME JOIN_DATE --------------- ------------------- JAMES 15-12-2008 11:41:21 --correct CHESTER 15-12-2008 11:41:40 --correct SUNITA 15-12-2008 11:41:56 --correct
Published by: Nichols on December 15, 2008 03:56
Published by: Nichols on December 15, 2008 04:09Run the same query, but the order of join_date DESC. You will see that the result is completely incorrect.
The query takes just three records (not the 'top three' - there is no order) and then ordered these records based on the ORDER BY in the final predicate. -
Sorting and grouping - two months in this query
Hi all
Thanks a lot for JAC
I am doing a project for the construction company, I faced this problem by grouping points according to the relationship between these points the
Relationship is from 1 to 100. If the point between what means there is relationship between these points has come.
resolve this question already, but the results does not correct when the table contains more data.
Jac and thanks a lot to him.
This example for more details
for example, I have these points
In addition, we can see the relationship between these points as followsid location percentage comments 1 loc 1,2 20% that mean point 1 and 2 close to each other by 20% 2 loc 1,3 40% that mean point 1 and 3 close to each other byy 40% 3 Loc 8,6 25% that mean point 8 and 6 close to each other by 25% 4 Loc 6,10 20% 5 LOC 11,10 10 % 6 LOC 15,14 0%
-points 1,2,3 in a group why because close 1.2 and 1.3 a relationship which means 1.3 also hid the relationship.
-Points 6,8,10,11 in the second group there are the relationships between them.
- but no relationship between 1, 2 or 3 with any point of 6,8,9,10,11
-as well as no relationship between 15, 14, which means 14 in the third group and 15 in the fourth group.
Whati need?
to group the points that growing a relationship according to the percentage value
The most important part is to group the points. For EXAMPLE, the query below, the gropuing is not correct.
I have the following table with data
When I used this query, the results is not correctdrop table temp_value; create table temp_value(id number(10),location varchar2(20), percentage number(9)); insert into temp_value values (1,'LOC 1,2',10); insert into temp_value values (2,'LOC 1,3',0); insert into temp_value values (3,'LOC 1,4',0); insert into temp_value values (4,'LOC 1,5',0); insert into temp_value values (5,'LOC 1,6',0); insert into temp_value values (6,'LOC 2,3',0); insert into temp_value values(7,'LOC 2,4',0); insert into temp_value values (8,'LOC 2,5',30); insert into temp_value values (9,'LOC 2,6',0); insert into temp_value values (10,'LOC 3,4',0); insert into temp_value values (11,'LOC 3,5',0); insert into temp_value values (12,'LOC 4,5',40); insert into temp_value values (13,'LOC 4,6',0); insert into temp_value values (14,'LOC 6,7',40); insert into temp_value values (15,'LOC 7,2',0); insert into temp_value values (16,'LOC 8,2',60); insert into temp_value values (17,'LOC 8,3',0); insert into temp_value values (18,'LOC 3,1',0); insert into temp_value values (19,'LOC 9,6',30); insert into temp_value values (20,'LOC 11,2',0); insert into temp_value values (22,'LOC 12,3',10); insert into temp_value values (23,'LOC 19,3',0); insert into temp_value values (24,'LOC 17,3',0); insert into temp_value values (24,'LOC 20,3',0);
resultswith t as (select percentage,loc1,loc2,sum(case when percentage = 0 then 1 when loc1 in (l1,l2) then 0 when loc2 in (l1,l2) then 0 when l1 is null and l2 is null then 0 else 1 end) over(order by rn) sm from ( select id,location,percentage, regexp_substr(location,'\d+',1,1) LOC1, regexp_substr(location,'\d+',1,2) LOC2, lag(regexp_substr(location,'\d+',1,1)) over(order by percentage desc) l1, lag(regexp_substr(location,'\d+',1,2)) over(order by percentage desc) l2, row_number() over(order by percentage desc) rn from temp_value order by percentage desc ) ) select loc,min(sm)+1 grp from( select loc,rownum rn,sm from( select percentage,decode(rn,1,loc1,loc2) loc,sm from t a, (select 1 rn from dual union all select 2 from dual ) b order by percentage desc,decode(rn,1,loc1,loc2) asc ) ) group by loc order by min(sm),min(rn);
SQL > /.
SQL >LOC GRP -------------------- ---------- 2 1 8 1 6 2 7 2 4 3 5 3 9 4 1 5 12 6 3 6 11 13 LOC GRP -------------------- ---------- 19 14 17 15 20 22 14 rows selected.
but the just is
Thanks in advance.Location group No 2 1 8 1 4 1 5 1 1 1 6 2 7 2 9 2 12 3 3 3 19 4 17 5 20 6
Published by: Isabelle on November 30, 2012 03:07OK, I thought an it once again and found out how to include with any such percentage points.
In your example expected output you missed the 11 that's why we got 7 groups now.
The order of the Group 2 and 3 is ambiguous, because the highest percentage of these groups is the same.with connects as ( select distinct loc1 ,loc2 ,connect_by_root(loc1) grp ,percentage per from temp_value --start with --percentage != 0 connect by nocycle (prior loc2 = loc1 or prior loc1 = loc2 or prior loc1 = loc1 or prior loc2 = loc2) and percentage != 0 and prior percentage != 0 ) select loc ,dense_rank() over (order by decode(per,0,1,0), grp) grp from ( select loc ,max(grp) keep (dense_rank first order by per desc, grp) grp ,max(per) keep (dense_rank last order by per nulls first) per from ( select loc1 loc ,grp ,per from connects union select loc2 ,grp ,per from connects ) group by loc ) order by 2,per desc,1 LOC GRP 2 1 8 1 4 1 5 1 1 1 12 2 3 2 6 3 7 3 9 3 11 4 17 5 19 6 20 7Think we are done now ;-)
Edited by: chris227 at 30.11.2012 16:46Edited by: chris227 at 30.11.2012 17:12
order correctedEdited by: chris227 at 30.11.2012 17:15
simplification, no need to rank in linking subqueryEdited by: chris227 at 30.11.2012 17:26
-
How can I change this query to generate a sequence
This query
Returns the following resultsselect SZSTCLA_PIDM, SZSTCLA_TERM_CODE, SZSTCLA_LAST_NAME from SZSTCLA,SHRTGPA where SZSTCLA_PIDM IN ( 120125,186114) AND SHRTGPA_TERM_CODE = SZSTCLA_TERM_CODE AND shrtgpa_pidm = SZSTCLA_PIDM AND SZSTCLA_RECORDED_EARNED_CRED > 0 ORDER BY SZSTCLA_TERM_CODE
Notice that ruptures in every szstcla_pidm, I need to change the query, so it can display a sequence number for each SZSTCLA_TERM_CODESZSTCLA_PIDM SZSTCLA_TERM_CODE SZSTCLA_LAST_NAME 186114 198810 Johnson 186114 198820 Johnson 186114 198910 Johnson 186114 198920 Johnson 186114 199010 Johnson 186114 199020 Johnson 186114 199110 Johnson 186114 199120 Johnson 120125 200720 Smith 120125 200810 Smith 120125 200820 Smith 120125 200910 Smith 120125 200920 Smith 120125 201010 Smith 120125 201020 Smith 120125 201110 Smith 120125 201120 Smith
so, it will be like
thenSZSTCLA_PIDM SZSTCLA_TERM_CODE SZSTCLA_LAST_NAME seq 186114 198810 Johnson 1 186114 198820 Johnson 2 186114 198910 Johnson 3 186114 198920 Johnson 4 186114 199010 Johnson 5 186114 199020 Johnson 6 186114 199110 Johnson 7 186114 199120 Johnson 8SZSTCLA_PIDM SZSTCLA_TERM_CODE SZSTCLA_LAST_NAME seq 120125 200720 Smith 1 120125 200810 Smith 2 120125 200820 Smith 3 120125 200910 Smith 4 120125 200920 Smith 5 120125 201010 Smith 6 120125 201020 Smith 7 120125 201110 Smith 8 120125 201120 Smith 9Looks like below, this is what you are looking for, but I can't understand why some documents are missing from the sample output
COL1 COL2 SZSTCLT_LAST_NAME RN -------- -------- ------------------------------ -- 120125 200920 Smith 1 120125 201010 Smith 2Maybe, if you could explain it, the query can be modified to exclude these folders as well. But, for now, downwards should suffice.
select szstclt_pidm col1, szstclt_term_code col2, szstclt_last_name, row_number() over (partition by szstclt_pidm order by szstclt_term_code) rn from szstclt a join shrtgpt b on a.SZSTCLT_PIDM = b.SHRTGPT_PIDM and a.SZSTCLT_TERM_CODE = b.SHRTGPT_TERM_CODE where SZSTCLT_PIDM IN ( 120125,186114); COL1 COL2 SZSTCLT_LAST_NAME RN -------- -------- ------------------------------ -- 120125 200920 Smith 1 120125 201010 Smith 2 120125 201020 Smith 3 120125 201110 Smith 4 120125 201120 Smith 5 186114 198810 Johnson 1 186114 198820 Johnson 2 186114 198910 Johnson 3 186114 198920 Johnson 4 186114 199010 Johnson 5 186114 199020 Johnson 6 186114 199110 Johnson 7 186114 199120 Johnson 8 13 rows selected -
Why this CASE statement would not work?
If I use a CASE in my SELECT statement and met a strange thing and just need help to understand why he did it.
When I type this, it does not work:
CASE TRIM (Column1)
WHEN NULL THEN Column2
WHEN 'foo' THEN Column2
Of ANOTHER Column1
END AS NewColName
I use this query in an Oracle procedure to insert data into another table. The data inserted in the column of NewColName end up being 4 empty spaces, located in Column1. In the logic of this, TRIM must remove all the empty spaces, and he should get mapped to the first statement WHEN, who must insert the value of Column2, but that does not occur. I tried the following versions of the first line as well:
LTRIM (RTRIM (Column1)) CASE
CASE of REPLACE (Column1, ' ', ")
and they all produce the same result. I also tried to change WHEN NULL for WHEN " and it changed nothing. However, when I rewrite the statement in this way it works the way it should:
CASE
WHEN TRIM (Column1) IS NULL, Column2
WHEN TRIM (Column1) = 'foo' THEN Column2
Of ANOTHER Column1
END AS NewColName
In my mind, it seems that these two methods are trying the same thing, why we could work and the other not? Only, it has no sense to me.
Thank youHello
Welcome to the forum.
In your first statement, you have
WHEN NULL THEN.
This is the same as x = NULL.
Nothing is never equal to NULL, if you find yourself in your ELSE clause.
Concerning
Peter -
How to write this query in the hierarchy
Hi gurus,
Really need your help on this query. Thank you very much in advance.
SELECT t1.key as root_key , (SELECT t2.unit_id AS unit_id level-1 AS level , t2.name, t2.creator FROM tab t2 START WITH t2.unit_id = t1.unit_id -----check each node as root CONNECT BY prior t2.unit_id = t2.parent_unit_id ) t1.name as parent_unit_name FROM tab t1
I'll write a query of the hierarchy as above, and that EACH line (node, totally more than 10200) is checked as root node to see how many sheets are accessible for her... It must be implemented in a single query.
I know inline query should NOT return multiple rows or multiple columns, but the inline elements are necessary and can certainly be made in a correct solution.
(env):
Database Oracle 12 c Enterprise Edition Release 12.1.0.2.0 - 64 bit Production
PL/SQL Release 12.1.0.2.0
)
Test data:
select 1 as unit_id, null as parent_organization_unit_id, 'U1' as name from dual union all select 2, 1, 'U2' FROM DUAL UNION ALL SELECT 3, NULL, 'U3' FROM DUAL UNION ALL SELECT 4, 3, 'U4' FROM DUAL UNION ALL SELECT 5, 2, 'U5' FROM DUAL UNION ALL SELECT 6, 5, 'U6' FROM DUAL UNION ALL SELECT 7, 6, 'U7' FROM DUAL UNION ALL SELECT 8, 5, 'U8' FROM DUAL UNION ALL SELECT 9, 5, 'U9' FROM DUAL;
Final result should be like this
key unit_id, level, name, parent_name 1 1 0 u1 u1 1 2 1 u2 u1 1 5 2 u5 u1 1 6 3 u6 u1 1 7 4 u7 u1 1 8 3 u8 u1 1 9 3 u9 u1 2 2 0 u2 u2 2 5 1 u5 u2 2 6 2 u6 u2 2 7 3 u7 u2 2 8 2 u8 u2 2 9 2 u9 u2
Don't know how get you your output, it does not match your data...
with tab as)
Select 1 as unit_id, null as parent_organization_unit_id 'U1' as the name of double
Union of all the
Select 2, 1, 'U2' FROM DUAL
UNION ALL
SELECT 3, NULL, 'U3' FROM DUAL
UNION ALL
SELECT 4, 3, 'U4' FROM DUAL
UNION ALL
SELECT 5, 2, 'U5' OF THE DOUBLE
UNION ALL
SELECT 6, 5, 'U6' OF THE DOUBLE
UNION ALL
SELECT 7, 6, "U7" OF THE DOUBLE
UNION ALL
SELECT 8, 5, 'U8' FROM DUAL
UNION ALL
9. SELECT, 5, 'U9' FROM DUAL
)
Select dense_rank() key (order by connect_by_root unit_id), unit_id, level - 1 as 'LEVEL', connect_by_root name root_parent_name
t tab
Start with parent_organization_unit_id is null
Connect prior unit_id = parent_organization_unit_id
KEY UNIT_ID LEVEL ROOT_PARENT_NAME 1 1 0 "U1". 1 2 1 "U1". 1 5 2 "U1". 1 6 3 "U1". 1 7 4 "U1". 1 8 3 "U1". 1 9 3 "U1". 2 3 0 "U3". 2 4 1 "U3".
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