Similar Questions

• That means 1e9 and why this query does not work?

  What does 1e9? Someone has links to documentation on this oracle? And why I get this error?
  

  SQL> select segment_name,(bytes/1e9) AS size from dba_segments where segment_name='MSG_MASTER';
  select segment_name,(bytes/1e9) AS size from dba_segments where segment_name='MSG_MASTER'
                                     *
  ERROR at line 1:
  ORA-00923: FROM keyword not found where expected

  SIZE is a keyword - so if you want the name of the column size then use 'SIZE' else give it a different name

  Try dividing by other exponentials, then you'll see how: 1e0 1e1 (div 1), (div by 10), 1e2 :-) etc

  Mette

  Published by: mettemusens on 2009-05-12 16:02

• Why this scriipt does not work with Firefox? < embed src = "News2008Fall.pdf" width = '615' height = '3200' > < / embed > "

  Please tell me why this script does not work with Firefox. It works with Safari. Here is the page that includes the script: www.lionsgatehoa.org/newslettertest.html. Thank you. Tom Engleman

  Here's the script in my html document:

  < embed src = "News2008Fall.pdf" width = '615' height = '3200' > < / embed > "

  Edit: removed # phone

  Works for me on Linux.
  
  Your system details list does not display the Adobe Reader plugin, so you'll have to (re) install this program.

  See:

  • https://support.Mozilla.org/KB/using+the+Adobe+Reader+plugin+with+Firefox
  • http://KB.mozillazine.org/Adobe_Reader
  • http://get.Adobe.com/reader/otherversions/

• Why this SQL does not work?

  The following code does not work when I try to delete rows from a table of test. The test table has no unique or primary key on it and is defined as test (identification number). Can you explain to me why it doesn't work?
  

  
  

  delete from test a where a.rowid in (select b.rowid from test b where b.id = a.id and b.rowid != a.rowid);

  
  

  
  

  
  

  When I run the subquery (selection) with replacement of the actual values of a.rowid and the table queried a.id (IE.select b.rid from test2 b where b.id = 1 and b.rid != 'XXX'

  ), the subquery returns exactly as expected (that is to say, it gives the rowid is different from that which went from subquery). And as although I know the internal subquery must return the result for each row of the table in the outside circle delete statement, and only after that should execute the delete statement. For example, for the first row of the table in the external suppression, the delete statement must send the ID of the first row in the internal subquery and then wait the result which should return. And then runs the delete statement, in which case the subquery must return the rowid is different from that which went from subquery (ie.

  b.rowid != a.rowid

  ). Am I wrong? What is the error in this statement.
  
  

  
  

  P.S. The sql is also not working if we replace remove it with the update or select
  

  in this case, the subquery must return the rowid is different from that which went from subquery (IE.

  b.rowid != a.rowid

  ). Am I wrong? What is the error in this statement.

  You are right that this subquery should return other than past rowid thr. But you used the IN clause as well as below:

  where a.rowid in

  What States remove the line if rowid returned by the subquery contains the identifier for the row whose ID was passed. As the inner query is to return another rowid, therefore, no row is deleted.

  To remove duplicate lines, try the query (Replace tablename/columns with your) below:

  DELETE FROM emp A

  WHERE A.ROWID > ALL (SELECT B.ROWID

  PEM'S B

  WHERE A.empno = B.empno);

• Why this mixture does not work?

  I work in CS4 on Mac. I want to do a 10 pastel colors color wheel. I had planned to use ten spokes - each scratched a color - and then mix together them. I did it before with success with other colors, I got the idea for this Web site: http://colorburned.com/create-a-color-picker-icon-in-illustrator/

  However, it does not for the moment. Here are my photos before and after.

  

  Any ideas on the reasons that a segment is so shredded? I tried to increase the width of each RADIUS of 1 pt to 4pt, but it did not help.

  You need to duplicate the higher-level object and place it under the entire stack.

  

  In this example, the strokes begin with yellow (the bottom) and eventually green (at the top of the stack).

  Select the green path, Edit > copy, edit > paste in front, object > Arrange > put in the background... and then create the mix.

  You need to start and stop of the same color in the same place for the entire circle mix properly.

• Why this code does not work, its simple!

  Hello

  I know the myVISITORinfoFormdomain name, say, the name is myTextField25, but I do not know its full path! but, I want to make gray and read-only, so I put the code below (I put the cursor on the node 'myVISITORinfoForm' and selected the DocReady event)

  var c = xfa.resolveNode("myTextField5").fillColor = '192,192,192. "
  var d = xfa.resolveNode("myTextField26").fillColor = '192,192,192. "
  var e = xfa.resolveNode("myTextField25").access = "readOnly";
  var f = xfa.resolveNode("myTextField26").access = "readOnly";

  I also tried another field of myTextField26, I also kept the same code in the FormReady events initialization... but has not worked!

  myTextField25 and myTextField26 are positioned on the 3rd page of the mySubForm12 subform.

  Pls let me know wht miss me?

  Thank you

  Hello

  If you want to make each field read only and gray, so why not script directly in each of the two textfields?

  It's the two fields docReady event:

  this.fillColor = "192,192,192";
  this.access = "readOnly";
  

  You can only do this if the fields are not null (for example when the form is returned to you). In this case you would wrap the script in an if statement:

  if (this.rawValue === null)
  {
       this.fillColor = "192,192,192";
       this.access = "readOnly";
  }
  

  I don't think the way you declare variables and setting properties on one line will work. Also, the use of the xfa.resolveNode is not effective.

  Hope that helps,

  Niall

• Why this text does not work well?

  Hi guys,.

  I am having trouble with this text.

  http://www.pixentral.com/show.php?picture=1y1N3lL5KPRBejo9GlPhEdkpl4KDQe

  It's in a column and the text block ends with the word 'amorosa '. I don't know why in the text the word "looking" will move to the next line and can only be inserted after that «nostalgia DEL...» "line of text even if ups with the end of the image apparently large enough to hold.

  http://www.pixentral.com/show.php?picture=1nu94bPp66d7lumber8SBjn6eI7Z1

  Maybe there is a better way to work with tabs, avoiding the list and so forth, but so far I have not understand it... so I work with the tools I know.

  Thanks for any info!

  See you soon,.

  SEBS

  Most importantly, you should do in this file is to remove all the keystrokes unnecessary (circled in red on my picture).

  

  You only need a paragraph return after caida, a tab after Coccoz, a tab after Catalanand without tab in the 'second paragraph' text (such as after del), and you do not need a line break after amorosa.

  After you have removed all the junk, set a tab on the left for the "second column and take note of its position." Suppose that you assign the p180 tab. To do the hanging indent, set the left indent p180 and first line indent to-p180 (i.e. negative 180 points). In this way, all text will be in the "second column", except the first line of the paragraph, which in this case are the names that make up your "first column". When you are ready to start with a new name, it's when you need a normal declaration.

• Puzzled why this code does not work... (Update record) ASP/VB - please help.

  What I'm trying to do is to check two values of database and if they are what I said I want the code to run (record code update). Here's what I have:
  
  < % if (rsSoftwareRequests.Fields.Item("Approved"). Value) = "Yes" AND rsSoftwareRequests.Fields.Item ("EmailSent"). Value) = "False" then % >
  < %
  If (CStr (Request ("MM_update")) = "form1") then
  If (not MM_abortEdit) then
  'perform the update
  Dim MM_editCmd
  
  Set MM_editCmd = Server.CreateObject ("ADODB.Command")
  MM_editCmd.ActiveConnection = MM_Intranet_New_STRING
  MM_editCmd.CommandText = "UPDATE SoftwareRequest SET EmailSent."
  =?, ApprovedByUserName =? WHERE ID =? »
  MM_editCmd.prepared = true
  MM_editCmd.parameters.Append MM_editCmd.CreateParameter ("param1",
  1, 50, 202 Request.Form ("EmailSent")) ' adVarWChar
  MM_editCmd.parameters.Append MM_editCmd.CreateParameter ("param2",
  202, 1, 255, Request.Form ("ApprovedByUserName")) ' adVarWChar
  MM_editCmd.parameters.Append MM_editCmd.CreateParameter ("param3",
  5, 1, -1, MM_IIF (Request.Form ("MM_recordId"),
  Request.Form ("MM_recordId"), null)) ' adDouble
  MM_editCmd.execute
  MM_editCmd.ActiveConnection.close
  
  
  ' add the query string to the redirect URL
  Dim MM_editRedirectUrl
  MM_editRedirectUrl = "software_hardware1.asp".
  If (Request.QueryString <>"") then
  If (InStr (1, MM_editRedirectUrl, "?", vbTextCompare in) = 0) then
  MM_editRedirectUrl = MM_editRedirectUrl & "?" &
  Request.QueryString
  On the other
  MM_editRedirectUrl = MM_editRedirectUrl & "" &
  Request.QueryString
  End If
  End If
  Response.Redirect (MM_editRedirectUrl)
  End If
  End If
  % >
  < % end If % >
  
  
  The recordset is set above the statement 'IF '... I put these values in the HTML body to see if it is pulling them correctly and yet it is the code under the IF statement is not pull out... I don't understand?
  
  
  Any help would be appreciated. Thank you!
  

  I think that is the oder of your orders, I did a quick page to test and it works fine, I left the sql insert at the top of the page where DW put and I think all his money form if SO, was the order in my page like this:

  Insert code - report
  RS for the values-

  <%If (rsSoftwareRequests.Fields.Item("Approved").Value) = "Yes" AND rsSoftwareRequests.Fields.Item("EmailSent").Value) = "False" Then%>
  

  
  FORM code right after IF THEN exposed
  
  
  
  <% end if %>

  Notice the document.form1.submit () is inside the IF THEN statement so it will trigger if the FI THEN returns true and that is not the value of the onLoad of the body, it should work, I left the record insertion code where DW puts but try it inside the fi can. NOTE: If the user has JS disabled the page will not work, but there are risks to everything!

• Why this code does not work in dreamweaver?

  <! DOCTYPE HTML >

  < html >

  < head >

  < style type = "text/css" >

  {body

  Width: 100%;

  height: 100%;

  margin: 0px;

  padding: 0px;

  }

  < / style >

  < / head >

  < body >

  < img src = "images/last.png" alt = "left" style ="width: 100%; "/ >

  < / body >

  < / html >

  When I put it in the tab code Dreamweaver html blank document page, it does not seem to load. Any suggestions?

  Are you sure that the image is in the folder named "images" last.png? Are you sure the image is to use the right color RGB and CMYK not the space.

  There's nothing wrong with the code that I can see. What happens if you try just text:

  Hello

• I have no idea why this 1130 does not work.

  Hello, everyone!

  I work in an elementary school in Detroit. We bought an access point Cisco 1130 for use on our local network. The problem is that our wireless laptops do not receive its signal.

  Here are the details.

  1. I connected the access point to our network and it turned.

  2. I used IPSU to find the IP address.

  3. I used Internet Explorer to connect to the access point.

  4. I gave you a fixed IP address on our field.

  5. I also entered the SSID and the WEP key.

  Everything seems good. The circular led on top of the access point is green. Unfortunately, Windows XP cannot 'see' the network signal.

  Is there someone who could help me get this thing working?

  Thank you very much

  -Ed

  All new 1130 AP come from the factory with the disabled radios. As you have seen, you need to enable them manually. I'm glad you have all this work!

• Why this introduction does not work?

  < html >
  < head >
  < style type = "text/css" >
  H1 {make-size: 300%; do-family: "Comic Sans MS"; color: 66FFFF; text-align: center ;}}
  H2 {font-size: 150%; do-family: "Comic Sans MS"; color: fd0202; text-align: left ;}}
  p {color: #EEEEEE; make-weight: lighter; text-align: left ;}}

  < / style >
  < body style = "" background-color: #151a1d; ">"
  < / head >
  < body >

  < h2 > 13,700,000,000 BC. (From OUR UNIVERSE FROM HUBBLE TELESCOPE DATA 1990 CALCULATED) < h2 / >

  < h2 > 4,567,000,000 BC (BEGINNING OF HADEAN EON) < h2 / >

  < p > name derived from Hades, the Greek God of the underworld name and referring
  to the devilishly hot, partially melted Earth surface and frequent collisions with other bodies of the solar system during this period. Geologist Preston Cloud defined
  In 1972 as the run-up to the oldest rocks known on Earth. Massive star exploded and produced the large cloud of gas and dust that came together like melted
  of the masses and became our solar system consisting of a Sun and planets. Our Sun was only 70% as bright as today ' hui. < p / >

  IT WORKED YESTERDAY WITH SOME RED TEXT BUT NOW SHOWS UP AS BLACK ON BLACK BACKGROUND H2 TEXT.  WHAT I AM DOING WRONG?

  You still have a duplicatetag...

  ... also, your end tags are formatted incorrectly. You currently have

  and

  instead of and

  . You can also change one of your

  affects a

  defined as indicated in your css.

  Check out the rest of the tags at the end of your page as well, I still don't see an end

  or both.

• Why this example does not work

  I couldn't run this example vi, he told me that sub vi is missing.

  How can I run this vi.  I have LABVIEW 8.5

  Atef

  Hello

  Cannot open under VI LV8.5 cause cause of too old version of VI. It is possible to open in LV7.1.  Here should work now. I mass compile of 7.1 to 8.5 by 8.0.

  But I think that there is an app for old VI can open in LV up to 8.5. Maybe someone will give link.

  Concerning

• Why this Spry does not work?

  as a simple test case, I created a new VBScript/ASP file and in it, I created a form with a text field, a Spry confirm the text field and another field of text for a field of blur. When I smack F12 for a race "fields do not match' get an immediate error before getting even a single character. Below the source code. What's wrong?

  ==================================

  "< %@LANGUAGE="VBSCRIPT "CODEPAGE ="65001"% >

  < ! DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional / / IN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd" > ""

  " < html xmlns =" http://www.w3.org/1999/xhtml ">

  < head >

  < meta http-equiv = "Content-Type" content = text/html"; charset = utf-8 "/ >"

  < title > Untitled Document < /title >

  "< script src="/SpryAssets/SpryValidationConfirm.js "type =" text/javascript"> < / script >

  "< link href="/SpryAssets/SpryValidationConfirm.css "rel ="stylesheet"type =" text/css"/ >

  < / head >

  < body >

  < p > < / p >

  < form id = "form1" name = "form1" method = "post" action = "" >

  PWD1 < label for "pwd1" = > < / label >

  < input type = "text" name = "pwd1" id = "pwd1" / >

  < span id = "spryconfirm1" >

  < label for = "pwd2" > pwd2 < / label >

  < input type = "text" name = "pwd2" id = "pwd2" / >

  < span class = "confirmInvalidMsg" > the values don't match. </span > < / span >

  blur of < label for = "blur" > < / label >

  < input type = "text" name = "blur" id = "fuzzy" / >

  < / make >

  < p > < / p >

  < script type = "text/javascript" >

  var spryconfirm1 = new Spry.Widget.ValidationConfirm ("spryconfirm1", "pwd1", {isRequired:false, validateOn:["blur"]});})

  < /script >

  < / body >

  < / html >

  ==============================

  If the path to the support files are false. You may have noticed that I have linked files in the repository of Adobe.

  GRAMPS

• Why this section does not appear in the list overview of the hearing.

  I only stumbled in this part of the new Forum hearing by a link in one of the messages from Steve G. probably, it should appear as one of the options as well as the hearing CS 5.5, Audition 3.01 and earlier versions and hearing FAQ?

  fact

• I want to record with &lt; alt &gt; &lt; s &gt; in the Exact program online. This function does not work. This is the first time I use this program with firefox.

  Question
  I want to record with < alt > < s > in the Exact program online. This function does not work. This is the first time I use this program with firefox.

  edit, escaped mod < s > in order to avoid the line through question

  A web page can be defined a "accesskey" for an item. Unlike IE/Chrome/Safari, who use the Alt key only, Firefox requires pressing Alt and Shift to activate the element. In other words, try

  ALT + SHIFT + S

  and see if it works.

  I don't know of any way to change this so that the change is not necessary. There may be an add-on?