Zero denominator ratio multiply (17:17)

Similar Questions

• After effects error: Zero denominator ratio multiply. (17:17). How to fix?

  I changed the fps rate in the Preview Panel.

  29.97 FPS at 59,94 frames per second.

  And I did a preview.

  When I went back to 29.97 and did listen to excerpts, pops up this error when I try to render the RAM preview.

  It seems that fps with whole number works normal, because I put in 30 frames per second, 25, 24, 15, and all the normal work, the problem appears only when put in 29.97 FPS or 59,94 images per second.

  Restart your machine.

• The proxy in CS5.5 error

  Hey

  Not sure if anyone else has experienced this. When I put a proxy for a model, I get an error that says: "after effects error: zero denominator ratio multiply." (17:17) ". I looked at the error code in the data base of the Mylenium, but nothing helped.

  The error only occurs when the proxy-enabled model is viewed in the comp window. If I go to a parent model (the one that uses the proxy-enabled model as a layer), everything works fine. This behavior started when I went to CS5.5.

  Also, I use tif sequences for the proxies, and the error occurs if I use always an or a sequence.

  Any ideas?

  (I'm on Windows 7 64-bit, if it's relevant.)

  You set yourself "Cache indicator layer Show" ON?

  If so, please try to disable.

  To make it

  (1) composition > new Composition

  (2) in the timeline panel, click the drop-down (upper right corner of the timeline panel)

  (3) uncheck the box "see the indicator Cache layer.

  I hope this helps.

  Thank you.

  -keiko

• Error code (17:18)

  I get an error code, (17:18) After Effects error reading: zero denominator conversion ratio denominators when I try to load an asset of QuickTime in the composition Panel. Any ideas on how to work around it, or better yet, to solve this problem?

  .. .the problem was a version date of the Quicktime; I've updated and the problem disappeared.  Thank you!

  Alan

• JavaScript for the sum of a column cells

  Hi all -

  I have a table in expansion (lines can be added) and I am using the line of the column footer to calculate the average of the cells which do not have the value 0.

  Form Calc is usually great, but in this case, I need to divide the sum by the number of cells that are not zero and I don't know how to do this via form Calc.

  Successfully used javascript to identify the total number of occurrences and identify the number of instances that are zero, then the part of the denominator of the equation is fine. (Number of cases - number of zeros = denominator.)

  Now, it's just the numerator. There must be a loop, right?

  Is called table: table1

  Line is called: data

  cell is called: rated

  Any thoughts? Or more effective methods? Thank you very much.

  B

  Hello

  a solution in FormCalc could look this way:

  form1.#subform[0].table1.footer.sum::calculate - (FormCalc, client)
  var c = 0
  var s = 0
  for i = 0 upto (_data.count - 1) do
    if (data[i].eValue gt 0) then
    c = Sum(c, 1)
    s = Sum(s, data[i].eValue)
    endif
  endfor
  
  if (s gt 0 and c gt 0) then
    $ = Round(s / c)
  else
    $ = 0
  endif
  

  Put this scriot in the calculate of the cell of the footer line event.

• Arithmetic operation

  Hello, these days, I find a problem with this operation and I can't find the way to resolved, I think the problem is that I can't use integers in Java Card.
  
  I do with 2 divisions, and there's a moment that Wicks Chang because wear I guess.
  
  short temp = (short) (ofini/2);
  
  I tried to solve this
  
  short temp = (short) ((ofini/2) & 0xF7);
  
  but it solves not all the numbers I can use with "ofini" happening at 0 - JJ.
  
  Is there a solution? If I solve it, I'd be able to finish my applet... XD

  Why divide by 2? Use travel instead. It's faster.

  signed pit: short divided = value > 1; (carpet on the left with the sign bit)
  divide unsigned: short udivided = value > 1; (left-pads with zero bits)

  multiply by 2: using left shifts, (than right buffers of operation with zeros): short multiplied = value<>
  multiply by 5 just an addition is needed for: short fivetimes = (value<2) +="">

  This is a basic optimization which also works with many other languages including C and assembler.

• Photoshop multiply by zero, gets zero

  Hi all.

  I try to add a color cast in the form of gray button, profiled (defined by a vector mask), by superimposing it with a with a Uni Green fill adjustment layer and setting the blend mode 'multiply '.

  

  Shape layer has transparent pixels around the edge, so I'm not expecting an operation to 'multiply' will cause visible green here.  But he does.  It's no good.  I need to export this image to a PNG with transparency intact.

  I see the green adjustment layer has a channel "Color fill 1 mask", but copy the shape layer and paste it into this channel of mask do not seem to help.  The display shows a very thin edge of the vector shape, but I can't seem to do anything with it.

  What is the right way to reach my goal here?

  Thank you!

  Clip the fill color for shape layer Layer - Opt/Alt-click between two thumbnails when a small box down arrow appears, or right-click on the name of the CFL in the layers panel and choose Create a clipping mask.

  An alternative is to not use a CFL and instead to give the shape layer a layer Style color overlay where you can choose the color and fashion, mixing too.

• passage on zero power

  Hello

  I'm usign zero crossing.vi to measure frequency, and 1/2 (RMS)

  In addition, I need a release supplement that provides a logical output for each passage of zero.

  Maybe it's pretty easy, but I'm not good in labview.

  waiting for your help.

  Thank you.

  The output of zero crossing points by zero Crossing.vi are passing zero as the samples index position in the block of input signals. You can convert the index zero crossing zero-hour crossing by multiplying the dt of the wave. Then you can generate the digital 1/0 output based on the time of zero and calculate the number of crossings per second.

  The frequency is calculated according to the points of passage of zero because the period (1/frequency) signal sinusoidal can be determined from both zero time of crossings.

• How to find the ratio between the two frequencies in the fft

  Hi, I'm Jean,

  I need to find the ratio of the frequencies of 1st and 2nd graph fft.

  Already, I received information of this site only. Mr. Alten helped me.

  Now, I have to continue the same problem and need to find the ratio of the frequencies.

  Please someone help me guys...

  I will attach my vi file and the text file.

  John,

  Should you report the frequencies or the report of the amplitudes of the components at these frequencies?

  The Information.vi of your multiple for the Signal Processing, extract > range of measures of waveform should do what you want.

  The frequency resolution is not very good because you have cycles relatively little waveforms (2 ~ for the lower frequency). I added a few zeros to improve resolution, even if a larger sample of data would be better.

  Lynn

• Function of zero crossing

  Hello

  I found this passage function to zero in one of the old forums and I'm trying to understand how it works. In my case, I have two sine waves, instead of a square pulse but I can really understand how this feature works. I know that the first, the waves are generated, and then you get their attributes, data values are in the detector of passage over who controls the case statement but I do not know how the trigger time and interaval are used to build the table, I think that the timestamp outside of the loop 'for' is for the storage of the previous itteration zero crossings , but I'm not really sure. I have no idea what is happening at the final stage before the time of transition to zero are subtarcted, as in the table of threshold and so on. I read how each function separately, but I can't add the blocks together.

  So I was wondering if someone could explain how it works?

  Thank you

  Add to what crossrulz said, it helps to understand what is the code you are looking at.

  Apparently you don't understand quite what the t0 and dt.  T0 is the time at the starting point in the waveform.  There can be a wide variety of time instead of just 0.  DT is the time interval between samples.  If we multiply by dt iteration, we know how much time has passed since the first sample.  After 0, 0dt is identical to 0 s.  From there on, 1dt, 2dt, 3dt, etc. can all be calculated for a measure of time value.  But, it measures only 'time in the first sample."  If it measures only that the timestamp can be empty.  If you want to convert the time from the first sample a real time, you must add the initial time.  For example, if dt is 1s and t0 is 16:00, after 3 samples we to 2dt up to 2 seconds.  Does worry about 2 seconds or 04:00:02

  The 'picture of big timestamp' is fed into what we call a shift register.  You can use this registry to pass values between the iterations of a loop.  Before the loop, we feed a table not initialized in the shift register.  The first time that the construction is used, he fed an empty array and the timestamp to record first.  It is then output to the shift to the right of the loop register.  This value is passed to the next iteration.  It will continue until we reach the table of construction for the second time.  Now, table 1 element is introduced into the upper entrance of the table build and a new timestamp is added at the end of the table.  This will continue with the array of size n arriving at top of entry and the most recent timestamp is added at the end to make an array of size n + 1.  If we want to keep all the timestamps, we like this logic.  You could plug it into the bottom and the timestamp again upward.  That would put the most recent timestamp in the first element of the array.  You just want to include the old array so keep you all the timestamps instead of just the most recent.

• Problems with Newton Raphson zero Finder

  Hey all,.

  I am trying to solve an equation with Newton Raphson zero Finder, but I can't get a result out of it, with this data set. It works with other sets of data, that I tried, and I solved this instance of the equation with another program and got the result I wanted (about 20), but for some reason, I have solve difficulties in Labview. I have attached my VI and the data that I use. This is what the formula, entering the Finder VI zero is supposed to look like:
  ((t * ((0.05594 * t + 5.2842) * t + 137.37)) / (1000 *(t+246))) - 1.987512E - 2
  As I said, I get the result I want, when I solve for this specific instance of the formula with another program, so I know that the formula is correct.

  Please let me know if you have an overview

  When you say it looks like the right place for zero, he returned to 19.94484, which seems to be about 20.

  1. connecting an indicator to the Newton Raphson zero error output Finder.vi gives-23021: two function values have the same sign. Automatic error handling does not pick up screws errors that have no deviation of the clusters. This error indicates that the zero is that not between the search terms or there are several zeros in this range.

  2. the default start and end values are 0 and 1. End changing to 100 product the result above. It seems that another zero 246 so that you can't do the limits too far.

  It is often useful to view data. Plot the data and the results of the formulas on the graphs to see what is happening. Using Eval Single-Variable Array.vi I get this:

  Note that it shows two passages to zero.

  Although it doesn't seem to be a problem here, with very large or very small values can lead to digital errors of overflow, underflow or retransmit.  Multiplying your table of spectrum and the initial settings by 1E23 and then later by dividing by the same factor (if necessary) could help avoid such problems.

  Lynn

• How to multiply really small numbers that are commensurate with 10 ^-4

  My program requires me to read some values of Excel cells, which she does, and multiply with each other.  Unfortunately, when I read of the cell and convert it to digital, it rounds to zero because it's a very small number as 3.86 * 10 ^-4.  I don't want to do this. How would it stop happenning.

  • How do you get data from excel?
  • How do you convert to numeric values? What do you use to convert?  (for example you must use "fractional chain to the number" instead of 'decimal string to the number')?
  • What is the data type of the result? (Make sure that it is orange and not blue).
  • What is the display format of the indicator?

• I want to convert my logic large table - multiply in a library called the faster, need some advice on the code of C.

  Hello everyone,

  In my VI, I have a code that looks like this-

  

  Each table is 2D size 512 by 640.  The time it takes to run this whole chain is approximately 28miliseconds. Seems fast, but I need to cut it to about 10ms.  I tried to make the tables 1 d, but saves only about 2 ms.  I even tried to cut the table 1 d in half and duplicate the code and then combine them at the end (a half-hearted attempt at optimizing multi-core) and who showed zero improvement...

  I guess my last option (please let me know if there are other options) is to compile a DLL that will do this for me.

  I'm a bit confused on how I'm supposed to implement table multiplies in C, however.

  What I do run for(;;) a loop and multiply each item one by one?  It seems that that would be much slower than anything done LabView in-house to do this multiplication of cross-checking.

  Thank you!!

  MK

  If you don't know how you would in C, I don't know why you think that move it to a DLL will make it faster. In C, you will need to either make operations sequentially in a loop for, as you mentioned, or find a library for parallelization of this operation. There is no built-in c function to multiply the tables.

  One thing you might try in your LabVIEW code is to multiply it in a loop for, where you make an addition to each iteration and store the result in a shift register. Also remember the current power of the original array into a shift register. Which should reduce the number of copies of the table you need, which can speed up to turn the code. So, you initialize it the 'sum' with the first table shift register and the shift register current electric table with the result of the subtraction (or, Alternatively, with a table of the same size, filled with 1, according to the order in which you want to do things). Multiply this table by the first multiplier, add it to the sum, and multiply the power of the original (subtraction) table, storing to the power shift register. Repeat until you are finished.

• Calculator simple division by zero help

  Hello, I'm doing a simple calculator with four basic operations. I want an LED light up when I'm dividing by zero. However, if I divide by zero, the LED lights up, and then when I switch to another operation, the LED stays on until I turn to 'divide' and the denominator is not zero. Can someone help me with this problem? Thank you. My VI file is attached.

  RavensFan wrote:

  # No, if wire you a False constant out to other cases.

  ... or just thread out from the case of the divide and set the tunnel exit to "use default if thread continues. It turns on only if the divide operation runs AND the divisor is zero. If can be skewed (off) in all other conditions.

• Aligning a zero position on a graph with several scales &amp; Auto scale

  Hello!

  I hope it's a quick - but google searches and browse the forums nothing have mounted.

  I have a graph with two scales - a position and a speed (which can obviously differ from each other). I want to be able to do is to have the scale auto chart/scales - but for the 0 position to stay in the center of the chart. With 0 balance point to different places, this is the graph that is very difficult to understand at a quick glance.

  If you see the attached screenshot - the positions of two 0 are in different places.

  Is it possible to have the scale automatically, but for zero to stay in the center of the graph for the two scales?

  Many thanks in advance,

  Sam

  (As I know) you can't do this with auto scale.

  Disable the autoscale, and then manually set the interval to be symmetric compared to zero for each scale.

  Find the maximum of the absolute value of each table of marks.  Then put it away on + and - of this value.  (in the example below, I did a loose fit by multiplying by 1.1).  Since you have more than one scale of the axis, you need to browse to treat each of them at a time.  First of all, he must be told what balance Y you want to adjust, then, set the values.

  

  Another option would be to have align the zeros, but not that the scale is symmetrical around them.  You can do that too, it takes just a little more math.  I would like to know if that's what you want.