Zone in the XSLT conversion

Similar Questions

• The Date conversion chain.

  Hello

  I used following code to convert string to date but apply the time zone of the device during the conversion. I don't need this but I
  Here same time of this string.
  as
  String = '07:59:17.427 2009-07-31'
  Date = 2009-07-31 07:59:17.427

  Date formatter = new Date (HttpDateParser.parse ("07:59:17.427" 2009-07-31));
  SimpleDateFormat dateFormat = new SimpleDateFormat ("yyyy-MM-DD hh: mm:." "") "'SSS');
  String strCustomDateTime = dateFormat.format (formatter);

  SimpleDateFormat format according to the local time zone. DateFormat does not work. see the documentation for the API

• Dead zone near the top of the screen in Safari? Cannot use Safari to log even here, because the arear connection is at the top. Virtually all nearthe fields are dead. I have no problem going into the fields to halfway to the bottom of the screen. Chrome w

  Dead zone near the top of the screen in Safari? Cannot use Safari to log even here, because the login box is at the top. Virtually all of the fields near the top are dead. I have no problem going into the fields to halfway to the bottom of the screen. It comes to Chrome and it works very well.

  I suggest you only begin by taking the measures recommended in this support article.

• Dead zones of the screen when I write

  I get the dead zones of the screen when I write. They are not always in the same area of the screen, but go across the width.
  Everyone knows this and they found how to solve the problem?

  Hello

  It's not easy to say what can be the problem.
  Well, first of all, I would recommend to recover the OS with the recovery CD. If after this procedure, the problem persists then you should try to update the display driver. If this doesn't help, so I guess that it s something wrong with the hardware. In this case, you should ask for help ASP.

  Good bye

• to change the clock to the time zone of the East, but it is not in my time zone tab, how do I fix

  to change the clock to the time zone of the East, but it is in my time zone tab is downloadable

  http://www.pchelpforum.com/Windows-Vista-7/103836-how-change-Windows-Vista-time-zone-clock-Eastern.html

  http://WindowsXP.MVPs.org/timezones.htm

  http://Windows.Microsoft.com/en-us/Windows-Vista/change-the-display-of-dates-times-currency-and-measurements

  Hope this works

• Missing time zone - cannot see the India time zone in the list of time zones

  Hello

  I have a Windows 7 Home Premium 64-bit edition installed on my Dell Studio laptop. As I lived
  in the United Kingdom, I had setup my timezone UTC (Dublin, Edinburgh, Lisbon, London).

  Now, I have reinstalled in India. I want to change the time zone UTC + 5:30 (Delhi, Mumbai, Calcutta).
  However, this time zone is not listed in the drop-down list. So I can't set the time zone.

  I read on the site of Microsoft Support that Microsoft has released an update to resolve the problem of the time zones (Windows6 1 - KB2779562 - x 64).
  I have applied this update, but I don't see the India time zone in the list.

  Please can someone help me? All tracks will be appreciated.

  Thanks in advance.

  See you soon

  How to reset the zone list in Windows 7...

  http://www.SevenForums.com/tutorials/100925-time-zones-restore-missing-default-time-zones.html

• Version of zone during the upgrade of fromi 11.2.0 for 12.1.0

  Hello

  I recently upgraded from 11.2.0 to 12.1.0. Oracle proposes to launch a number of scripts after upgrade (as postupgrade_fixups.sql). So, when I ran, it registered a few recommendations:

  
  

  Corrections of post-upgrade beginning...

  **********************************************************************

  Check the label: OLD_TIME_ZONES_EXIST

  Check summary: Check use of the old zone data file

  Summary of fix: update the time zone by using the DBMS_DST package once the upgrade is complete.

  **********************************************************************

  Fixup gave information:

  INFORMATION: - > old time zone in use

  Database uses a file of zone prior to version 18.

  After the upgrade, it is recommended that the package DBMS_DST

  be used to upgrade the 12.1.0.2.0 version of database time zone

  the latest version that comes with the new version.

  Although it is said that this zone data file is older version 18, it said that it is not:

  SQL> SELECT version FROM v$timezone_file;
  VERSION
  ----------
  18
  

  Who to believe?

  postupgrade_fixups. SQL called dbms_preup.run_fixup_and_report('OLD_TIME_ZONES_EXIST'). As we see the value of "OLD_TIME_ZONE_EXIST" is preset here. Enter dbms_preup.run_fixup_and_report reveals another case with 'NEW_TIME_ZONE_EXISTS' that could return the expected result.

  So it seems that postupgrade_fixups.sql was formed when I ran dbupgdiag.sql; and this time I got the file version of zone 14 as it was my former 11 g environment. But now I am on env 12 c and have the new version of the zone file. IT would be great if postupgrade_fixups.sql perfroms checks again when running after upgrade, but not simply show what dbupgdiag.sql gathered before the upgrade.

• Attributes of hard code in the xslt file

  Hello

  I try to hardcode the attributes in the XSLT using setText, but during the execution, the attributes have the value null.

  Is not the right way to hardcode the attributes in the XSLT?

  Thank you!

  solved the problem by using the assign activity.

• How to use the zone with the calendar events settings?

  After looking through the questions in the time zones, scheduling and synchronization, I still can't my Palm Centro to exploit the way I think it should.

  I have a Verizon Centro, use Windows XP with Outlook and Hotsync synchronization manager 7.02 via a USB cable.  I do not use Palm Desktop.

  I expect events to pass the time in the calendar when I change the time zone, but they did not.

  I am preparing for a trip.  I enter several events in MS Outlook placing events occur in a different time zone in my calendar at the same time the event happen in my timezone (NY).   For example, a meeting of 9-10 am in Los Angeles is put in my calendar to outlook MS as 12-1 PM on the day of the meeting.  Then I have synced with my Centro and Outlook for New York time zone.  The Centro is set automatically update Date, time, area of the network in New York. The event of the meeting appears as 12-1 PM the correct day.

  Then I turn off the Centro phone (IE unplug the Verizon network), change the update time to 'Nothing' - is to say fully manual, change the time zone in Los Angeles and set the time to the exact time in Los Angeles.   I expect the meeting to 9-10 AM in my Centro calendar, but it's not!  I have try other combinations - let the time on the Date and the automatic time update and change the time zone in Los Angeles, etc..  I think I've tried all combinations.  Overall, I leave the Centro phone out of the Verizon network.  I can not get the meeting to change his time in the new time zone.

  What's the trick? What did I miss?

  You might ask why I'm trying this with the phone turned off - it's because I'm really much further that THE and in a GSM network where I will simply use the Center as a PDA.

  All advice appreciated.

  thepoeta-

  Thanks for the reply.

  In fact my preference was not established "new events use time zones."

  Meanwhile, I had loaded all the applointments of Outlook, about 20 of them,

  thinking that I would just manually move along the way.

  I'll play with time zone preference, but,.

  is it possible to identify the existing appointments in the

  Palm as belonging to a time zone that is different, just by using the Palm Centro?

  Thank you

  Neal

• How to add in the XSLT?

  All,

  version of the SOA: 11.1.1.4

  We have need for me to add to the current date in the XSLT file.  I looked in the "data functions", I could not find some predefined functions.  How he achieved in XSLT?  Any help is appreciated.

  Thank you

  Sen

  Deepak,

  I'll try and update you.

  Thank you

  Sen

• How to call a value of preference in the XSLT file

  Hi all

  How to call a value preference (which is defined in bpel already) in the XSLT?

  Can someone help me please

  Kind regards

  Villeneuve ch

  Get the value of preference and and check out the post below to pass as a parameter

  http://www.albinsblog.com/2012/07/passing-parameter-to-XSLT-in-SOA-11g.html#.UjfqfMZmiSo

  Concerning

  Albin I

• How generations for db in the XSLT file sequence number

  Hello gurus SOA,.

  I have a requirement, please see below

  I am using SOA 11.1.1.6

  Insert a webservice to db, XSLT call, I have 10 items next to the source and 11 items next to the target.

  • Source to target first 10 mappings are performed.
  • Now the requirement is, for the 11th element target we must pass a sequence number to the database targeted, means-(sequence number must be generated for each execution of the XSLT execution)

  How do the last point?

  Can someone help me please

  Hello

  You can pass the sequence number in the 11th element to help. "oraext:sequence-next-val("Sequence name as a string", "Datasource as a string") function.

  Kind regards

  Anshul

  


• xsl: include not solve any HOW to load the xslt

  I can't get * < xsl: include > * to work with XMLTRANSFORM in an environment of Oracle's PL/SQL 11.2.0.3. I work exclusively within the database.
  
  I have a basic XSLT which includes another XSLT using xsl: include. I want to load the base as an XMLTYPE XSLT and do transform another XML document, as if the entire XSLT was a large document.
  
  I loaded the base (base.xslt), the extension (include_with_base.xslt) and the combination of the two (entire_thing.xslt) in the XDB catalogue. base.xslt has this statement inside the node, xsl: stylesheet, attempting to include the other xslt:
  ' * < xsl: include href="/public/include_with_base.xslt" / >. *
  
  I have the files stored in XDB XSLT. It verifies that they are intact:
  1. the base xslt which has the xsl: include the statement loads very well.
  Select xdburitype('/public/base.xslt').getXML (double);
  
  2. the extension which is the target of the reference to include it in the basic xslt support very well.
  Select xdburitype('/public/include_with_base.xslt').getXML (double);
  
  3. the combination of the two, where I copy - paste all the children of include_with_base.xslt xslt:stylesheet in the xslt:stylesheet of base.xslt load node also very well.
  Select xdburitype('/public/entire_thing.xslt').getXML (double);
  
  However, when I try to run a transformation of some xml test using base.xslt, it fails:
  Select XMLTRANSFORM(xdburitype('/public/xml_input.xml').getXML (), xdburitype('/public/base.xslt').getXML ()) FROM dual;
  
  When I try to run the same transformation of the same test xml using entire_thing.xslt, it works:
  Select XMLTRANSFORM(xdburitype('/public/xml_input.xml').getXML (), xdburitype('/public/entire_thing.xslt').getXML ()) FROM dual;
  
  When I run both XSLT transformations and transformation using altovaxml is in the same directory of drive (and I use a relative reference with no path information and not an absolute reference, as I show in the above examples), the transformation works very well.
  
  What can I do to run a XSLT which is essential the XMLTRANSFORM < xsl: include... / > reference in there?
  
  Published by: user11359697 on April 15, 2013 13:49

  Ok thank you. Now I can reproduce the problem:

  SQL> select xmltransform(
    2           xdburitype('/public/PEOPLE.xml').getXML()
    3         , xdburitype('/public/BASE.xslt').getXML()
    4         )
    5  from dual;
  ERROR:
  ORA-31011: XML parsing failed
  ORA-19202: Error occurred in XML processing
  LPX-00602: Invalid child element '#text' of element 'binary'.
  
  no rows selected
  

  The error is related to the way in which the resources are stored in the XML DB repository and are accessible from XSLT.
  Apparently, when the resource is interpreted as a binary stream, the language of xsl: include directive fails. I would be considered a bug.

  By default, there is no mapping predefined MIME for the 'xslt' extension so the resource ' / public/TITLES "is stored using the default" application/octet-stream"MIME type
  You can check that by questioning RESOURCE_VIEW:

  SQL> set long 50000
  SQL> set longc 50000
  SQL> set lines 200
  SQL> set pages 100
  SQL> select xmlserialize(document res)
    2  from resource_view
    3  where equals_path(res, '/public/TITLES.xslt') = 1;
  
  XMLSERIALIZE(DOCUMENTRES)
  --------------------------------------------------------------------------------------------------------------------------------------------
  
  

  To work around the problem, you need to reference resources stored with a text-based MIME type, such as the "xsl" extension (predefined in xdbconfig):

  select *
  from xmltable(
         xmlnamespaces(default 'http://xmlns.oracle.com/xdb/xdbconfig.xsd')
       , '//extension-mappings/mime-mappings/mime-mapping'
         passing dbms_xdb.cfg_get()
         columns "extension", "mime-type"
       ) ;
  

  or if you want to keep the "xslt" extension, it maps to the mimetype "text/xml".
  You can do it like this:

  SQL> exec dbms_xdb.ADDMIMEMAPPING('xslt','text/xml');
  
  PL/SQL procedure successfully completed.
  
  SQL> commit;
  
  Commit complete.
  

  Drop and reload the resource ' / public/TITLES.xslt ' in the repository and it should be OK:

  SQL> select xmltransform(
    2           xdburitype('/public/PEOPLE.xml').getXML()
    3         , xdburitype('/public/BASE.xslt').getXML()
    4         )
    5  from dual;
  
  XMLTRANSFORM(XDBURITYPE('/PUBLIC/PEOPLE.XML').GETXML(),XDBUR
  ------------------------------------------------------------
  
  
    Hello, Mrs.AliceAble
    Hello, Mr.BobBungler
  
  

• For each does not properly in the XSLT file to two loops on a single node

  Hi all
  
  I'm transforming 2 inputs to a single target using XSLT. Both of the target entry of the same pattern and have the child element.
  In the XSLT, I gave this condition.
  "< xsl: for each select="$Variable1.payload/ns1:BookStore/ns1:Books ">
  < xsl: for-each select = "/ ns1:BookStore / ns1:Books" >
  "< xsl: if test="$Variable1.payload/ns1:BookStore/ns1:Books/ns3:BookId = ns3:Books / ns3:BookId ">
  
  My second for each does not work and in the target, I'm getting double elements. Help, please. Here are two xml source and xml desired target.
  1 XML source:
  
  < bookStore >
  < book >
  Name1 < name > < / name >
  author1 < author > < / author >
  < ID > 1 < / BookId >
  < quantity > 2 < / quantity >
  < price > < price / >
  < status > < / status >
  < book >
  < book >
  name2 < name > < / name >
  Author2 < author > < / author >
  < ID > 2 < / BookId >
  < quantity > 2 < / quantity >
  < price > < price / >
  < status > < / status >
  < book >
  < book >
  < name > NAME3 < / name >
  author of 3 < author > < / author >
  < ID > 3 < / BookId >
  < quantity > 2 < / quantity >
  < price > < price / >
  < status > < / status >
  < book >
  < / book >
  
  XML source 2:
  
  < bookStore >
  < book >
  < name > < / name >
  < author > < / author >
  < quantity > < / quantity >
  < ID > 1 < / BookId >
  < price > 100 < / price >
  < status > < / status >
  < book >
  < book >
  < name > < / name >
  < author > < / author >
  < quantity > < / quantity >
  < ID > 2 < / BookId >
  < price > 200 < / price >
  < status > NA < / status >
  < book >
  < book >
  < name > < / name >
  < author > < / author >
  < quantity > < / quantity >
  < ID > 3 < / BookId >
  < price > 300 < / price >
  < status > < / status >
  < book >
  < / book >
  
  Desired target XML:
  
  < bookStore >
  < book >
  Name1 < name > < / name >
  author1 < author > < / author >
  < ID > 1 < / BookId >
  < quantity > 2 < / quantity >
  < price > 100 < / price >
  < status > < / status >
  < book >
  < book >
  name2 < name > < / name >
  Author2 < author > < / author >
  < ID > 2 < / BookId >
  < quantity > 2 < / quantity >
  < price > 200 < / price >
  < status > NA < / status >
  < book >
  < book >
  < name > NAME3 < / name >
  author of 3 < author > < / author >
  < ID > 3 < / BookId >
  < quantity > 2 < / quantity >
  < price > 300 < / price >
  < status > < / status >
  < book >
  < / book >
  
  Thank you

  Hello

  It will not work like that... To do something like the following... Only one for each...

  
    
    
      ns1:Name
      ns1:Author
      ns1:BookId
      $Variable1.payload/ns1:BookStore/ns1:Books[ns1:BookId = $bookId]/Quantity
      $Variable1.payload/ns1:BookStore/ns1:Books[ns1:BookId = $bookId]/Price
      $Variable1.payload/ns1:BookStore/ns1:Books[ns1:BookId = $bookId]/Status
    
  
  

  I don't have to check the syntax, but you get the idea...

  I hope this helps...

  See you soon,.
  Vlad

• How to find the number of days between 2 date elements in the XSLT file

  Hello
  
  I need to calculate the number of days between 2 date elements (type xs: date). Can you please direct me as to how I can do the same thing.
  
  I work in 11g and using XSLT 1.0. I tried several options but yet to get a solution for this. I think that this can be done also using XSLT 2.0, but who has not worked for me.
  
  Can someone please help with this problem, thanks in advance!
  
  Thank you
  Anju

  Hello

  Have you seen this message?
  Re: Get the Date difference between 2 values of date in days

  You can do in the XSLT file since the dates are in ISO 8601 format.
  http://www.w3.org/TR/NOTE-datetime

  Here is a sample XSLT...

  The XSLT above will result in * 4 * for the next entry...

  
  2012-01-11T00:00:00.000-05:00
  2012-01-15T00:00:00.000-05:00
  
  

  You can test this example here...
  http://xslttest.appspot.com/

  I hope this helps...

  See you soon,.
  Vlad

  It is considered good etiquette to the answerers rewards with points (as "useful" - 5 pts - or 'correct' - 10pts)
  https://forums.Oracle.com/forums/Ann.jspa?annID=893