3.1b1 mozilla lightning multiweek grey month week

Similar Questions

• Get the number of month, week and day between 2 dates

  Hi all
  
  Is it possible to display the number of months, weeks and days between 2 dates? by using only the SQL or PL/SQL...
  
  Entry:
  Date: October 1, 2010
  Date: October 19, 2010
  
  I want output like below (assuming starts the week from Monday to Sunday in oracle).
  
  October 1, 2010-(since it's in the middle of the week)
  October 2, 2010-(since it's in the middle of the week)
  October 3, 2010-(since it's in the middle of the week)
  40. (4 Oct-10 Oct falls into the 40th week of the year)
  41. (11 Oct-17 Oct falls into the 41st week of the year)
  October 18, 2010-(since it's in the middle of the week)
  October 19, 2010-(since it's in the middle of the week)
  
  
  Note: If there is a month between the date, the number of the month should be displayed.
  End of the month, the remaining date included with a full week, then the week of the year number should
  displayed. After posting the week, remaining dates should be displayed as it is...
  
  
  Appreciate your help...
  
  
  
  Thank you.
  Fox.

  You mean something like this...

  SQL> ed
  Wrote file afiedt.buf
  
    1  WITH t AS (select date '2010-09-27' as fdate, date '2010-11-21' as tdate from dual)
    2  --
    3  -- END OF TEST DATA
    4  --
    5  select dt2
    6  from (
    7        select dt,
    8               case when days_of_mn = days_in_month then 'Whole: '||to_char(dt,'Month')
    9                    when days_of_wk = 7 then 'Week: '||to_char(dt,'fmWW')
   10               else to_char(dt, 'DD-fmMonth-YYYY')
   11               end as dt2
   12              ,row_number() over (partition by
   13                 case when days_of_mn = days_in_month then to_char(dt,'Month')
   14                                  when days_of_wk = 7 then 'Week: '||to_char(dt,'fmWW')
   15                 else to_char(dt, 'DD-fmMonth-YYYY')
   16                 end order by dt) as rn
   17        from (
   18              select dt, wk, mn, days_in_month
   19                    ,count(*) over (partition by wk) as days_of_wk
   20                    ,count(*) over (partition by mn) as days_of_mn
   21              from (
   22                    select fdate+rownum-1 as dt
   23                          ,to_number(to_char(fdate+rownum-1,'fmWW')) as wk
   24                          ,to_number(to_char(fdate+rownum-1,'fmMM')) as mn
   25                          ,to_number(to_char(last_day(fdate+rownum-1),'fmDD')) as days_in_month
   26                    from t
   27                          connect by rownum <= tdate-fdate+1
   28                   )
   29             )
   30        ) x
   31  where rn = 1
   32* order by dt
  SQL> /
  
  DT2
  -----------------
  27-September-2010
  28-September-2010
  29-September-2010
  30-September-2010
  Whole: October
  Week: 44
  Week: 45
  Week: 46
  19-November-2010
  20-November-2010
  21-November-2010
  
  11 rows selected.
  
  SQL>
  

• Annual, monthly, weekly data

  I now of tables with data, I use Oracle 11 g R2.
  
  CREATE TABLE GroupName
  (group_id NUMBER (8) NOT NULL,
  GroupName varchar2 (30)
  );
  
  insert into GroupName values (10, 'Group 1');
  insert into GroupName values (20, 'Group2');
  
  CREATE TABLE group_device
  (group_id NUMBER (8) NON NULL
  level_id number 4 not null
  member_id NUMBER (4) NOT NULL
  device_id NUMBER (10) NOT NULL
  , varchar2 (30) nom_peripherique
  , batch number (2)
  , install_date DATE NOT NULL
  remove_date DATE
  );
  
  INSERT INTO group_device (group_id, level_id, member_id, device_id, nom_peripherique, batch, install_date, remove_date) VALUES (10, 1, 1, 123, "device123", 2, TO_DATE (May 23, 2012 "," mm/dd/yyyy"), TO_DATE (May 28, 2012","mm/dd/yyyy"));
  INSERT INTO group_device (group_id, level_id, member_id, device_id, nom_peripherique, batch, install_date, remove_date) VALUES (10.2, 1, 456, "device456", 2, TO_DATE (May 28, 2012 "," mm/dd/yyyy"), TO_DATE (June 1, 2012","mm/dd/yyyy"));
  INSERT INTO group_device (group_id, level_id, member_id, device_id, nom_peripherique, batch, install_date, remove_date) VALUES (10.2, 1, 789, 'device789', 1, TO_DATE (June 1, 2012 "," mm/dd/yyyy"), null);
  INSERT INTO group_device (group_id, level_id, member_id, device_id, nom_peripherique, batch, install_date, remove_date) VALUES (10, 1, 2, 999, 'device999', 1, TO_DATE (May 4, 2012 "," mm/dd/yyyy"), TO_DATE (May 17, 2012","mm/dd/yyyy"));
  INSERT INTO group_device (group_id, level_id, member_id, device_id, nom_peripherique, batch, install_date, remove_date) VALUES (10.2, 4, 1123, "device1123", 2, TO_DATE (January 22, 2012 "," mm/dd/yyyy"), TO_DATE (January 27, 2012","mm/dd/yyyy"));
  INSERT INTO group_device (group_id, level_id, member_id, device_id, nom_peripherique, batch, install_date, remove_date) VALUES (10, 1, 4, 1456, 'device1456', 1, TO_DATE (January 27, 2012 "," mm/dd/yyyy"), TO_DATE (January 28, 2012","mm/dd/yyyy"));
  commit;
  
  
  create table (reads
  number of DEVICE_ID,
  number of ReadValue,
  date of readtimestamp);
  
  
  Insert in the values of readings (123,.51, to_date (' 05/21/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (123,.61, to_date (' 05/22/2012 ',' mm/dd/yyyy'));
  
  Insert in the values of readings (123,.21, to_date (' 05/23/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (123, 2.51, to_date (' 05/24/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (123, 3.51, to_date (' 05/25/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (123, 4.51, to_date (' 05/26/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (123,.61, to_date (' 05/27/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (123,.91, to_date (' 05/28/2012 ',' mm/dd/yyyy'));
  
  Insert in the values of readings (123, 4.51, to_date (' 05/29/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (123, 4.51, to_date (' 05/30/2012 ',' mm/dd/yyyy'));
  
  Insert in the values of readings (123, 7.61, to_date (' 06/17/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (123, 9.91, to_date (' 06/18/2012 ',' mm/dd/yyyy'));
  
  Insert in the values of readings (123, 15.51, to_date (' 06/21/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (123, 101, to_date (' 05/28/2012 ',' mm/dd/yyyy'));
  
  
  Insert in the values of readings (456, 33,51, to_date (' 05/26/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (456, 23.61, to_date (' 05/27/2012 ',' mm/dd/yyyy'));
  
  Insert in the values of readings (456, 67.91, to_date (' 05/28/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (456, 46,51, to_date (' 05/29/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (456, 98.51, to_date (' 05/30/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (456, 34.51, to_date (' 05/31/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (456, 34.51, to_date (' 06/01/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (456, 34.51, to_date (' 06/02/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (456, 34.51, to_date (' 06/03/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (456, 34.51, to_date (' 06/04/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (456, 34.51, to_date (' 06/05/2012 ',' mm/dd/yyyy'));
  
  Insert in the values of readings (789, 198,51, to_date (' 05/30/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (789, 234.51, to_date (' 05/31/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (789, 334.51, to_date (' 06/01/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (789, 434.51, to_date (' 06/02/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (789, 534.51, to_date (' 06/03/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (789, 634.51, to_date (' 06/04/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (789, 734.51, to_date (' 06/05/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (789, 222.51, to_date (' 06/06/2012 ',' mm/dd/yyyy'));
  
  
  Insert in the values of readings (123,.51, to_date (' 05/01/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (123,.61, to_date (' 05/02/2012 ',' mm/dd/yyyy'));
  
  Insert in the values of readings (999, 4.21, to_date (' 05/03/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (999, 25.51, to_date (' 05/04/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (999, 33,51, to_date (' 05/05/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (999, 44.51, to_date (' 05/06/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (999, 78,61, to_date (' 05/17/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (999, 98,91, to_date (' 05/18/2012 ',' mm/dd/yyyy'));
  
  
  
  Insert in the values of readings (1123, 91.51, to_date (' 01/21/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (1123, 94.61, to_date (' 01/22/2012 ',' mm/dd/yyyy'));
  
  Insert in the values of readings (1123, 99,21, to_date (' 01/23/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (1123, 72.51, to_date (' 01/24/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (1123, 53.51, to_date (' 01/25/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (1123, 44.51, to_date (' 01/26/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (1123, 99.61, to_date (' 01/27/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (1123, 105.91, to_date (' 01/28/2012 ',' mm/dd/yyyy'));
  
  Insert in the values of readings (1123, 204.51, to_date (' 01/29/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (1123, 464.51, to_date ('01 2012 30', ' mm/dd/yyyy'));
  
  Insert in the values of readings (1456, 733.51, to_date (' 01/26/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (1456, 823.61, to_date (' 01/27/2012 ',' mm/dd/yyyy'));
  
  Insert in the values of readings (1456, 967.91, to_date (' 01/28/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (1456, 346.51, to_date (' 01/29/2012 ',' mm/dd/yyyy'));
  Insert in the values of readings (1456, 398.51, to_date ('01 2012 30', ' mm/dd/yyyy'));
  
  
  
  commit;
  
  
  I wrote the following question.
  
  Select elgl.groupname,
  TO_CHAR (to_date ('01' |)) Mo. Month_Number | ((' ' 2012 ', 'DDMMYYYY'), 'MM') as Month_name,.
  NVL ((select sum (nvl(cr.readvalue,0))
  reads cr, group_device, el GroupName
  where cr.device_id = eh.device_id
  and cr.device_id in (eh.device_id)
  and eh.level_id = 1
  and el.group_id = eh.group_id
  and el.groupname = elgl.groupname
  and Trunc (cr.readtimestamp, 'MM') = To_Date ('01' |) Mo. Month_Number | (((' ' 2012 ', 'DDMMYYYY')), 0) Readvalue.
  NVL ((select sum (nvl(cr.readvalue,0)) of reads cr, group_device, el groupname))
  where cr.device_id = eh.device_id
  and cr.device_id in (eh.device_id)
  and eh.level_id = 2
  and el.group_id = eh.group_id
  and el.groupname = elgl.groupname and Trunc (cr.readtimestamp, 'MM') = To_Date ('01' |) Mo. Month_Number | (((' ' 2012 ', 'DDMMYYYY')), 0) Grouptotal,.
  NVL (((select sum (nvl(cr.readvalue,0))
  reads cr, group_device, el GroupName
  where cr.device_id = eh.device_id
  and cr.device_id in (eh.device_id)
  and eh.level_id = 1
  and el.group_id = eh.group_id
  and el.groupname = elgl.groupname
  and Trunc (cr.readtimestamp, 'MM') = To_Date ('01' |) Mo. Month_Number | ((' ' 2012 ', 'DDMMYYYY')).
  (by selecting sum (nvl(cr.readvalue,0)) reads cr, group_device, el groupname)
  where cr.device_id = eh.device_id
  and cr.device_id in (eh.device_id)
  and eh.level_id = 2
  and el.group_id = eh.group_id
  and el.groupname = elgl.groupname and Trunc (cr.readtimestamp, 'MM') = To_Date ('01' |) Mo. Month_Number | ((((' ' 2012 ', 'DDMMYYYY'))), '0') Diff,.
  round (((select sum (nvl(cr.readvalue,0))
  reads cr, group_device, el GroupName
  where cr.device_id = eh.device_id
  and cr.device_id in (eh.device_id)
  and eh.level_id = 1
  and el.group_id = eh.group_id
  and el.groupname = elgl.groupname
  and Trunc (cr.readtimestamp, 'MM') = To_Date ('01' |) Mo. Month_Number | (((' ' 2012 ', 'DDMMYYYY'))).
  (by selecting sum (nvl(cr.readvalue,0)) reads cr, group_device, el groupname)
  where cr.device_id = eh.device_id
  and cr.device_id in (eh.device_id)
  and eh.level_id = 2
  and el.group_id = eh.group_id
  and el.groupname = elgl.groupname and Trunc (cr.readtimestamp, 'MM') = To_Date ('01' |) Mo. Month_Number | (((((' ' 2012 ', 'DDMMYYYY'))) * 100), 3) by
  of the LLNA GroupName, (select lpad(level,2,'0') from dual connect by level month_number < = 12) MB
  order of elgl.groupname, month_name;
  
  
  gives me suite out -.
  
  Group 1 01 3270,05 1330.4 1939,65 245.794
  Group 1 02 0 0 0
  Group 1 03 0 0 0
  Group 1 04 0 0 0
  Group 1 05 409.78 737, 58 - 327.8 55.557
  Group 1 06 33.03 3067, 61 - 3034.58 1.077
  Group 1-07 0 0 0
  Group 1-08 0 0 0
  Group 1-09 0 0 0
  Group 1 10 0 0 0
  Group 1 11 0 0 0
  Group 1 12 0 0 0
  
  
  Which is good, but I think that this query is very complicated instead I'm looking for better query that can give me a similar output. This request is also for the year, but I need for the week and month.
  GroupName | Name of the month | ReadValue | Total Group | Difference | Percentage - exit 1 of the request
  GroupName | Name of the week | ReadValue | Total Group | Difference | Percentage - result of application 2
  GroupName | Name of the day | ReadValue | Total Group | Difference | Percentage - exit 3 of the application
  
  Thank you

  For percentage his right just not. It should come as - *(readvalue-grouptotal) /readvalue) * 100

  The part of my calculation of the PCT in the query is:

  ROUND(readvalue / grouptotal, 2)
  

  Do you really need my help to change this calculation to return (readvalue grouptotal) / readvalue) * 100?

  I will note that when I corrected the error "divisor is equal to zero", I was obviously pressed / not paying attention. I tacked on an extra DECODING when all I had to do was to change the existing. Should have been just:

  DECODE(grouptotal, 0, 0, ROUND(readvalue / grouptotal, 2)) AS PCT
  

  Remember, DECODE will have to be changed when you change the calculation to meet your needs.

• Programming logic needed to retrieve the records for the last month/week

  Hi all
  
  I need assistance in programming SQL logic.
  
  Oracle database version: 10.2.0.3.0
  
  Requirement
  
  In an environment of DW, I need to program to weekly and monthly automated batch insert the data from Data_tbl to Reporting_tbl to generate reports. Descriptions of paintings are given below.
  
  Table 1 - Data_tbl (Source of table - this table is updated daily).
  
  Record_dt first name last name
  
  
  Table 2 - Reporting_tbl_ (the target table)
  
  Cycle_dt first name last name
  
  1. monthly report
  
  In the SQL query, I where clause conditions.
  
  Where Record_dt > = 1 November 08 ' and record_dt < = 30 November 08 '
  
  Using the above condition in development, I'm pulling over the last months data source table data. This will be repeated every month, and it should be automated.
  that is, if I run this report at any time in December 2008, he should choose documents dates from Nov 01 to November 30, 2008. If I run this report at any time in January 2009, he should choose documents dates to Dec. 01 to December 31, 2008.
  Date values must be assigned for the last month. Value of Cycle_dt in the target table must be the date of the end of last month as on November 30, 2008, 31-dec-2008.
  
  
  2 weekly Report
  
  In the SQL query, I where clause conditions.
  
  Where Record_dt > ='01-dec-08' and record_dt < ='' 07-dec-08
  
  Monday week start date and end date is Sunday.
  If I run the report between the 08 Dec-14 Dec, it should make records of the dates of Dec. 01 to December 7, 2008.
  On 15 December, he should seek from 08 Dec-14 Dec.
  Value of Cycle_dt in the target table must be the date of last weekend, as on December 7, 2008, December 14, 2008.
  Please help me with the logic for both monthly and weekly reports.
  
  Thank you

  Hello

  TRUNC (dt, 'W') is the beginning of the week, which may be different days, according to the NLS parameters in your session. Unless you want something that varies from one session to the next, you should stick with the weeks of ISO.

  TRUNC (SYSDATE + 1, 'IW') - 1
  

  is the Sunday of the week underway Sunday to Saturday, which starts and ends in 1 day before the ISO week.
  To find the precedent of the week from Sunday to Saturday:

  WHERE   record_dt >= TRUNC (SYSDATE - 6, 'IW') - 1
  AND     record_dt <  TRUNC (SYSDATE + 1, 'IW') - 1
  

  If you were interested in a week from Saturday to Friday (either 2 days earlier than the ISO week):

  TRUNC (SYSDATE + 2, 'IW') - 2
  

• How can you determine what the user watch calendar view (month, week, day, list) the calendar of CSS (5.0)

  We run Apex 5.0.1.00.06 and I would like to add a region to a page, if the user displays the LIST of the CSS calendar view. I can't understand how to determine which view the user displays currently. Is it possible to determine to create a condition to show another region in they are on a particular view?

  BillH104 wrote:

  We run Apex 5.0.1.00.06 and I would like to add a region to a page, if the user displays the LIST of the CSS calendar view. I can't understand how to determine which view the user displays currently. Is it possible to determine to create a condition to show another region in they are on a particular view?

  This can be achieved using some dynamic measurements, to hide the region if the calendar is the display month view when loading the page and to show/hide the region when you click the list/month selector.

  Add a static region ID to region calendar for use in jQuery selectors.

  Name: See the region list - load

  Event: Loading the page

  Condition: Expression of JavaScript

  Value:$('#static-region-id .fc-month-view').length > 0

  Real Action

  Action: Hide

  Selection type: Region

  Region:

  Nom : See the region list - click

  Event: Click

  Selection type: jQuery Selector

  jQuery Selector:.fc-button-group button

  Condition: Expression of JavaScript

  Value:$(this.triggeringElement).hasClass('fc-list-button')

  Real Action

  Action: Show

  Selection type: Region

  Region:

  
  

  Action of false

  Action: Hide

  Selection type: Region

  Region:

• calculation of the week and the month of the column date

  I have 3 data as column

  with tab as 
  (
    select 'Topshop' brand, '10-JUL-11' deliverydate, '100' qty from dual union all
    select 'Topshop' brand, '10-JUL-11' deliverydate, '400' qty from dual union all
    select 'NewSita' brand, '11-JUL-11' deliverydate, '200' qty from dual union all
    select 'LaGress' brand, '12-JUL-11' deliverydate, '300' qty from dual union all
    select 'LaGress' brand, '10-AUG-11' deliverydate, '100' qty from dual union all
    select 'LaGress' brand, '11-AUG-11' deliverydate, '200' qty from dual union all
    select 'Topshop' brand, '12-AUG-11' deliverydate, '300' qty from dual union all
    select 'NewSita' brand, '10-SEP-11' deliverydate, '100' qty from dual union all
    select 'Topshop' brand, '11-SEP-11' deliverydate, '200' qty from dual union all
    select 'NewSita' brand, '12-SEP-11' deliverydate, '300' qty from dual
  ) select * from tab

  I need to convert it to 4 columns
  
  Brand | Month | Week (start date). Amount (sum)
  
  Please let me know what are the options I have, in particular the calculation of date and time functions available to solve these problems.
  
  Thank you
  w\

  Check this box

  with tab as
  (
  Select the option 'Topshop' brand, July 10, 11 'deliverydate, ' 100' qty of any union double
  Select the option 'Topshop' brand, July 10, 11 'deliverydate, ' 400' qty of any union double
  Select the option "NewSita" brand, 11 July 11 'deliverydate, ' 200' qty of any union double
  Select "brand the LaGress, 12 July 11' deliverydate, '300' qty of union double all the»
  Select "brand the LaGress, 10 Aug 11' deliverydate, '100' qty of union double all the»
  Select "brand the LaGress, 11 Aug 11' deliverydate, '200' qty of union double all the»
  Select the option 'Topshop' brand, 12 Aug 11 'deliverydate, ' 300' qty of any union double
  Select the brand 'NewSita',' 10-SEP-11 deliverydate, '100' qty of all double union
  Select the option 'Topshop' brand,' 11-SEP-11 deliverydate, '200' qty of any union double
  Select the option "NewSita" brand, deliverydate, '300' qty of the double' 12-SEPT-11
  ) select the brand, deliverydate, NEXT_DAY (to_date (deliverydate, 'DD-MON-yy'), "LUN")-7, Qty tab.

• start date for each week of the month

  Dear members
  
  How can I find double, the start date of each week of the month in a year.
  beginning of the week is the word "Monday".
  
  
  year month week day date
  ----------------------------------------------------------------------------------------
  Monday, January 3, 2011 JAN 1, 2011
  2011 2 JAN Monday, January 10, 2011
  Monday, January 17, 2011 January 3, 2011
  JAN 4 2011 on Monday, January 24, 2011
  2011 to January 5 Monday, January 31, 2011
  
  
  Thank you
  
  teefu

  Hello

  You can use this:

  with t as  (select to_date ('01/01/2011', 'DD/MM/YYYY') start_date from dual)
  select  date_calc
  from (
          select  start_date,
                  (level-1)*7+trunc (start_date , 'D')+1   as date_calc
          from t
          connect by level <=53)
  where trunc(date_calc,'YYYY')=trunc(start_date,'YYYY') ;
  

  Kind regards
  Sylvie

• The folder in Inbox disappered after "compact folders" applied (and installed Lightning). MSF file seems to stay at the disk again. How to restore the folder?

  I have several folders in the Inbox.
  The last time (for months) Thunderbird asked to compact files. Last week, I deleted unnecessary messages in folders and applied "compact" on the Inbox (root) folder.
  Today, that I discovered that one of the folders inside the Inbox disappeared. However when I look at the e-mail on local disk storage I still see msf file with the name of the record lost in the Inbox.sbd folder.
  I also have installed lightning and Thunderbird update week last next to compression of files.
  Can I restore folder in the Inbox?

  is there another file of the same name, other than the MSF?

• Would be useful to have a way to tell if the addons are compatible before installing an update. Lightning is the main concern for us.

  Thunderbird updated to 24.5.0 but I need to know with certainty that the Lightning has a compatible version before doing the update. Cannot afford to lose this calendar. When I look at the mozilla lightning site, it shows the current version, the one I use, is compatible with my current Thunderbird 24.4.0,. But the site of lightning indicates the 24-compatible version of lightning has not yet been published. Yes, is this to say that if I update Thunderbird 24.5.0 then the current version of the lightning will not properly work or not at all?

  I would like to see an option in the dialog to update Thunderbird that shows me each of my addons, which will be compatible with the new version of Thunderbird, and will not, then I would select update or wait.

  Thank you.

  Lightning will continue to work with TB 24.5.0.

  https://addons.Mozilla.org/en-us/Thunderbird/addon/lightning/

  Search for 'Version information' at the bottom of the page.

  A corresponding version of Lightning will be available with each major release of Thunderbird. This will be 31 TB sometime later this year.

• Cannot download Mozilla FireFox. Microsoft says its an unknown Editor, who is in!

  In early April, I downloaded Mozilla Firefox. For two weeks, that it worked perfectly. Then when he offered some Applications, I have investigated them, but decided to not choose any. When I tried to leave the page to go back to my MSN home page, however, I couldn't do it. So I restarted my laptop, thinking I could start again. But no, I had returned to the Aps page yet. This happened twice more, closed for five minutes and I tried again. Success! But I was still furious with Firefox, so I downloaded Google Chrome and then uninstalled Firefox.

  After struggling with Chrome for another two weeks, because it does not work well with a relatively weak signal of blue UBS, I decided to go back to Firefox. Went on the Mozilla site and downloaded the same version I had before. But when I tried to install it, Microsoft intervened, claiming that she was of "Unknown Publisher" and could be dangerous. If I wanted to deal with the risk, however, I was able to proceed with the installation. But when I tried to install it, Microsoft says that it is corrupted! and refused.
  Then, I went through my files and found the icon of Firefox I had installed in April, he dragged on the desktop and tried to install it. However, Microsoft says again, it was from an unknown Publisher and could be dangerous, etc. And when I tried the same Firefox I had before, Microsoft has again refused, saying, corrupt! "
  It's exasperating recent history concerning my attempts frustrated trying to install Firefox. Mozill Firefox has been around for many years and is well known, then how dare Microsoft argue that Firefox from an "Unknown Publisher" and then claim that downloading the same who worked before was "corrupt"!?

  Hello

  ·         What web browser do you use to download Mozilla Firefox?

  ·         If you use Internet Explorer, then what is the version of Internet Explorer you are using?

  ·         What version of the operating system is installed on the system?

  ·         From which site you are trying to download Mozilla Firefox?

  To check the installed version of Internet Explorer see the link below

  http://Windows.Microsoft.com/en-us/Windows-Vista/find-out-which-version-of-Internet-Explorer-youre-using

  If you use Google chrome to download Mozilla Firefox so that you can see the link below.

  http://www.Google.com/support/chrome/bin/topic.py?hl=en&topic=14681

  You can also post the question on the link if you use Google Chrome to download the file below.

  http://www.Google.com/support/forum/p/chrome/label?lid=43d46e8d92fef559&hl=en

  Please provide more information on the issue so that we can help you better

• How to subtract the different monthly amounts of the same column

  Hi all

  I'm creating a quarterly report to display purchase against 13 weeks orders (same quarter courses there will be US 13 weeks).

  First month 4 weeks, 2 months 4 weeks and 3 months was 5 weeks all the time. I have a data dimension table that will tell me the number of the week (Col1 Eg; 1, 2, 3) and the number of months (col2 Eg):

  01/11/2013

  01/12/2013

  01/01/2014

  ) this week belongs to...

  My data;

  Month week in.

  01/11/2013 1 100

  01/12/2013 5 50

  01/01/2014 9 110

  Desired output:

  Month	Week	PO
  01/11/2013	1	100
  01/11/2013	2	100
  01/11/2013	3	100
  01/11/2013	4	100
  01/12/2013	5	100 50
  01/12/2013	6	100 50
  01/12/2013	7	100 50
  01/12/2013	8	100 50
  01/01/2014	9	-110 (100-50)
  02/01/2014	10	-110 (100-50)
  03/01/2014	11	-110 (100-50)
  04/01/2014	12	-110 (100-50)
  05/01/2014	13	-110 (100-50)

  My version of oracle's Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64 bit.

  Thank you

  Hello

  Using the response code that I have posted on your previous post, here's a way to do:

  WITH bucket AS (
    SELECT date '2013-11-1' mon, 100 po  FROM dual UNION ALL
    SELECT date '2013-12-1' , 50 FROM dual UNION ALL
    SELECT date '2014-1-1' , 110 FROM dual
  ),
  mm AS (
  SELECT
    mon, po,
    rownum month_no,
    CASE
      WHEN rownum=1 THEN po
      ELSE LAG(po, 1, 0) OVER (ORDER BY mon) - po
    END po_diff
  FROM bucket
  ),
  week AS (
    SELECT rownum n FROM dual CONNECT BY level <= 5
  )
  SELECT mon "Month",
    ROW_NUMBER() OVER (ORDER BY mon,n) "Week",
    n wk,
    po_diff "PO"
  FROM week, mm
  WHERE month_no = 3
  OR (month_no IN (1,2) AND n <= 4)
  ORDER BY month_no, wk ;
  

• Week of the year (from Monday to Sunday)

  Hi guys,.

  I searched 'Week of the year' and that you have not found a solution to my problem.

  I think that the standard Oracle 'IW' function returns the week of the year beginning January 1.  This year, for example, Monday, January 6 is back as week 1 because on 1 January was Wednesday, therefore, it is in the 1st 7 days of the year.

  Select to_char (to_date(:p_date,'DD/MM/YYYY'), 'IW') wrong_week_no

  , to_char (to_date (: p_date + 2, ' DD/MM/YYYY'), 'IW') correct_week_no

  of the double

  I would like the query to return the week number from Monday to Sunday, so in this case, the 6th should return as number 2 of the week.

  In the query above, by adding 2 to the date gives me the correct week number but won't work for 2015 and 2016.

  Any help would be appreciated.

  I use the Oracle 10 g platform.

  Thank you

  Chris

  Do you mean like this?

  SQL > break the month jump 1
  SQL > set linesize 200
  SQL > set pagesize 2000
  SQL > column month format a20
  SQL > column week format a4
  SQL > with req as (select '& Required_Year_YYYY' year of double)
  2, offset as (select case when to_char (trunc (to_date (yr, 'YYYY'), 'YYYY'), 'IW') in ('52 ', ' 53') then 1 else 0 end as the offset of req)
  3 select lpad (Month, - 20 (20-length (month)) / 2) months.
  4 '('|| semaine ||') ' as the week, "Mo", "You", "We", "Th", "Fr", "Sa", "knew".
  5 of)
  6. Select to_char (dt, 'fmMonth YYYY') month,
  7 case when to_char (dt, 'mm') = '12 ' and to_char (dt, 'iw') = ' 01' and offset = 0 then ' 53 "
  8 when to_char (dt, 'mm') = '12 ' and to_char (dt, 'iw') = '01' and offset = 1 then ' 54'
  9 when to_char (dt, 'mm') = '01' and to_char (dt, 'iw') and ('52', ' 53 ") then"1"
  10 to_char (to_number (to_char (dt, 'iw')) + offset) other end than the week,.
  11 max (decode (to_char(dt,'d'), '1', lpad (to_char (dt, 'GFMD') 2)),) "Mo."
  12 max (decode (to_char(dt,'d'),'2 ', lpad (to_char (dt, 'GFMD'), 2))) "you."
  Max (decode (to_char(dt,'d'),'3 ', lpad (to_char (dt, 'GFMD'), 2))) 13 '' We. ''
  14 max (decode (to_char(dt,'d'),'4 ', lpad (to_char (dt, 'GFMD'), 2))) "Th."
  15 max (decode (to_char(dt,'d'),'5 ', lpad (to_char (dt, 'GFMD'), 2))) "Fr."
  16 max (decode (to_char(dt,'d'),'6 ', lpad (to_char (dt, 'GFMD'), 2))) "his."
  17 max (decode (to_char(dt,'d'),'7 ', lpad (to_char (dt, 'GFMD'), 2))) "Su".
  18 in (select trunc (to_date (req.yr, 'YYYY'), 'y')-1 + rownum dt)
  19 object, req
  20 where rownum<= add_months(trunc(to_date(req.yr,'yyyy'),'y'),12)="" -="" trunc(to_date(req.yr,'yyyy'),'y')="">
  21, offset
  22 group by to_char (dt, 'fmMonth AAAA'), case when to_char (dt, 'mm') = '12 ' and to_char (dt, 'iw') = ' 01' and offset = 0 then ' 53 "
  23 when to_char (dt, 'mm') = '12 ' and to_char (dt, 'iw') = '01' and offset = 1 then ' 54'
  24 when to_char (dt, 'mm') = '01' and to_char (dt, 'iw') and ('52', ' 53 ") then"1"
  25 to_char (to_number (to_char (dt, 'iw')) + offset) to another end
  (26) x
  27 order by to_date (month, "Month YYYY"), to_number (x.week)
  28.
  Enter the value for required_year_yyyy: 2012
  old 1: with req as (select '& Required_Year_YYYY' year of double)
  new 1: with req (select '2012' year of double)

  MONTH WEEK Mo Tu we Th his di ve
  -------------------- ---- -- -- -- -- -- -- --
  January 2012 (1) 1
  (2) 2 3 4 5 6 7 8.
  (3) 9 10 11 12 13 14 15.

  
  (4) 16 17 18 19 20 21 22.
  (5) 23 24 25 26 27 28 29.
  (6) 30 31.

  February 2012 (6) 1 2 3 4 5
  (7) 6 7 8 9 10 11 12.
  (8) 13 14 15 16 17 18 19.
  (9) 20 21 22 23 24 25 26.
  (10) 27 28 29.

  March 2012 (10) 1 2 3 4
  (11) 5 6 7 8 9 10 11.
  (12) 12 13 14 15 16 17 18.
  (13) 19 20 21 22 23 24 25.
  (14) 26 27 28 29 30 31.

  April 2012 (14) 1
  (15) 2 3 4 5 6 7 8.
  (16) 9 10 11 12 13 14 15.
  (17) 16 17 18 19 20 21 22.
  (18) 23 24 25 26 27 28 29.
  (19) 30

  May 2012 (19) 1 2 3 4 5 6
  (20) 7 8 9 10 11 12 13.
  (21) 14 15 16 17 18 19 20.
  (22) 21 22 23 24 25 26 27.
  (23) 28 29 30 31.

  June 2012 (23) 1 2 3
  (24) 4 5 6 7 8 9 10.
  (25) 11 12 13 14 15 16 17.
  (26) 18 19 20 21 22 23 24.
  (27) 25 26 27 28 29 30.

  July 2012 (27) 1
  (28) 2 3 4 5 6 7 8.
  (29) 9 10 11 12 13 14 15.
  (30) 16 17 18 19 20 21 22.
  (31) 23 24 25 26 27 28 29.
  (32) 30 31.

  August 2012 (32) 1 2 3 4 5
  (33) 6 7 8 9 10 11 12.
  (34) 13 14 15 16 17 18 19.
  (35) 20 21 22 23 24 25 26.
  (36) 27 28 29 30 31.

  September 2012 (36) 1 2
  (37) 3 4 5 6 7 8 9.
  (38) 10 11 12 13 14 15 16.
  (39) 17 18 19 20 21 22 23.
  (40) 24 25 26 27 28 29 30.

  October 2012 (41) 1 2 3 4 5 6 7
  (42) 8 9 10 11 12 13 14.
  (43) 15 16 17 18 19 20 21.
  (44) 22 23 24 25 26 27 28.
  (45) 29 30 31.

  November 2012 (45) 1 2 3 4
  (46) 5 6 7 8 9 10 11.
  (47) 12 13 14 15 16 17 18.
  (48) 19 20 21 22 23 24 25.
  (49) 26 27 28 29 30.

  December 2012 (49) 1 2
  (50) 3 4 5 6 7 8 9.
  (51) 10 11 12 13 14 15 16.
  (52) 17 18 19 20 21 22 23.
  (53) 24 25 26 27 28 29 30.
  (54) 31

  64 selected lines

  I used 2012 for example, because in this case, it has 54 weeks.

  So, here we have 1 January during the week 1, but 2 January's second week, as is Monday, etc.

• A query with workingdays by month and per period

  Can someone help me on how to build a SQL query that is difficult?
  
  I work with SQL Oracle. It is intended to be calculated over a certain period, to find the working days of each month for each person.
  
  I have a request to work to calculate the number of days 1 month less holidays
  
  SELECT count (*) NUM_WORK_DAYS
  De)
  Select to_date (January 1, 2010 ", 'dd-mm-yyyy') + ROWNUM-1 day
  Of object
  Where ROWNUM < to_number (to_char (last_day (January 1, 2010 '), JJ ')) + 1).
  Where to_number (to_char (day, 'd.')) between 1 and 5
  And not exists (select NULL
  Holiday
  Where Holiday.hol = day)
  
  There is a datetable with the following structure where I can get the periods:
  DATES
  YEAR | MONTH | WEEK | SD
  2010 | 201002 | 201006 | 02/09/2010
  All the required month are present
  It is expected that the user gives a start and specify an end time.
  
  I have a table of workingdays per person named
  CALENDAR
  CAL | MY | MAR | SEA | GAME | FRI | SAM | SUN
  Nobody | THERE | THERE | N | THERE | THERE | N | N
  
  And an array of holidays
  HOLIDAY
  CAL | HOL
  Nobody | 01/01/2010
  
  How can I combine the query for the business days and create a query that returns the number of workingdays by month for many people for several months? I will ask the user to give a start point and an end of period
  
  I am aware that I ask a lot of your time, but I can't imagine the solution myself. Thanks in advance
  
  GR,
  Els

  You can change the query in this way:

  with period as (
  select DATE '&start_day' start_date, DATE '&end_day' end_date
    from dual),
  days as (
  select start_date+level-1 day
    from dual,period
  connect by level <= end_date-start_date+1),
  mycal as (
  select person, 'monday' day, mon works from calendar union all
  select person, 'tuesday' day, tue from calendar union all
  select person, 'wednesday' day, wed from calendar union all
  select person, 'thursday' day, thu from calendar union all
  select person, 'friday' day, fri from calendar union all
  select person, 'saturday' day, sat from calendar union all
  select person, 'sunday' day, sun from calendar
  )
  select person, to_char(d.day,'yyyymm') month, count(0)
    from mycal c, days d
   where c.day = trim(to_char(d.day,'day'))
     and c.works='Y'
     and not exists (select 1 from holiday h where h.person=c.person and h.hol=d.day)
  group by person, to_char(d.day,'yyyymm');
  

  Max
  http://oracleitalia.WordPress.com

• Events are not displayed in my calendar

  I just installed the module for Thunderbird Lightning and I soon saw that events have disappeared from view in the calendar.
  I took notes to add network United Kingdom and the United States holiday schedules (for example: iCal to: http://mozorg.cdn.mozilla.net/media/caldata/UKHolidays.ics) and the United Kingdom, those who appeared, until I chose the calendar section to add those to the United States.
  All calendars are checked.
  I clicked on synchronize calendars without result.
  I see the father's in the list at the top, but not the tab day, week, multiweek or month.
  I've hunted the docs but couldn't find something that would be show/hide events from these points of view for calendars which are turned on.

  All thoughts welcome.
  Thank you

  Thunderbird 24.5.0
  2.6.5 lightning
  Windows 7 x 64 (home)

  I had to restart Thunderbird there are moments (Virtual identify the module was not picking up an SMTP account).
  I found that a process of Thunderbird 'hiding' and use the Task Manager to kill him.

  Virtual identity picked up the changes.
  The events appeared on the calendar and in the sidebar events etc...

  I hope that this has solved it.

• How can I see less songs?

  Hey

  In the playlist added recently, how do to show less songs as now his watch 100 +, but I just want to see the songs that I've added in the last month/week or more

  Thank you Elder

  If you select the playlist and click on the "Edit Playlist" button to the right of it, you should be able to specify the duration (for example 2 weeks stated on my image below), and you can limit how many songs to incorporate (if you check the checkbox to the left of his line):