Programming logic needed to retrieve the records for the last month/week

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  Published by: shiva March 27, 2011 22:14

  Hello
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• How to complete the data for months current quarter of the last month of the previous quarter

  • Here is the create table and insert the statement how my data is as

    CREATE TABLE SAMPLEDATA (Snapshot_M DATE, Date_Ky DATE, F_Quantities INTEGER)

    INSERT INTO VALUES SAMPLEDATA (SEPTEMBER 1, 2014 ", 1 SEPTEMBER 2014", 14)

    INSERT INTO VALUES SAMPLEDATA (OCTOBER 1, 2014 ", 1 OCTOBER 2014", 13)

    INSERT INTO VALUES SAMPLEDATA (1 NOVEMBER 2014", 1 NOVEMBER 2013', 12)

    INSERT INTO VALUES SAMPLEDATA (DECEMBER 1, 2014", 1 DECEMBER 2013', 11)

    INSERT INTO VALUES SAMPLEDATA (JANUARY 1, 2014 ", 1 JANUARY 2014", 10)

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    Desired results set:

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    10 1/1/2014-3/1/2014

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    4/1/2014 5/1/2014 23

    4/1/2014 6/1/2014 23

    4/1/2014 7/1/2014 23

    
    

    My requirement is to load the data in the cube.

    
    

    So to summarize, data that are loaded onto the month last only a quarter Q1 tax (Jan) should server as a data for the quarter Q2 next month (February, March, April), the data loaded on the last month of Q2 (Apr) will be server as forecast data for Q3 months and so on.

    
    

    Thank you in advance.
    

    
    

    
    

    
    

  with

  SAMPLEDATA as

  (select to_date('09/1/2014','mm/dd/yyyy') snapshot_m, to_date('09/01/2014','mm/dd/yyyy') date_ky, 14 f_quantities of all the double union)

  Select to_date (October 1, 2014 "," mm/dd/yyyy ""), to_date (1 October 2014 "," mm/dd/yyyy"), 13 union double all the

  Select to_date (November 1, 2013 "," mm/dd/yyyy ""), to_date (1 November 2013 "," mm/dd/yyyy"), 12 union double all the

  Select to_date (December 1, 2013 "," mm/dd/yyyy ""), to_date (1 December 2013 "," mm/dd/yyyy"), 11 union double all the

  Select to_date (January 1, 2014 "," mm/dd/yyyy ""), to_date (1 January 2014 "," mm/dd/yyyy"), 10 of all the double union

  Select to_date (February 1, 2014 "," mm/dd/yyyy ""), to_date (1st February 2014 "," mm/dd/yyyy"), 90 union double all the

  Select to_date (March 1, 2014 "," mm/dd/yyyy ""), to_date (1 March 2014 "," mm/dd/yyyy"), 20 union double all the

  Select to_date (April 1, 2014 "," mm/dd/yyyy ""), to_date (1 April 2014 "," mm/dd/yyyy"), 23 union double all the

  Select to_date (May 1, 2014 "," mm/dd/yyyy ""), to_date (1 may 2014 "," mm/dd/yyyy"), 30 union double all the

  Select to_date (June 1, 2014 "," mm/dd/yyyy ""), to_date (1 June 2014 "," mm/dd/yyyy"), 70 union double all the

  Select to_date (July 1, 2014 "," mm/dd/yyyy ""), to_date (1 July 2014 "," mm/dd/yyyy"), 20 union double all the

  Select to_date (August 1, 2014 "," mm/dd/yyyy ""), to_date (1 August 2014 "," mm/dd/yyyy"), 22 of the double

  )

  Select snapshot_m, date_ky, last_value (f_quantities) ignore nulls on f_quantities (order by date_ky)

  of (trunc (add_months (snapshot_m-1), 'q') select snapshot_m, date_ky,)

  -case when trunc (add_months (snapshot_m-1), 'q')! = lag (trunc (add_months(snapshot_m,-1), 'q')) (date_ky order)

  then lag (f_quantities) (date_ky order)

  end f_quantities

  of sampledata

  where date_ky > = date ' 2014-01-01'

  )

  where snapshot_m > = date ' 2014-01-01'

  order of date_ky

  SNAPSHOT_M	DATE_KY	F_QUANTITIES
  01/01/2014	01/02/2014	10
  01/01/2014	01/03/2014	10
  01/01/2014	01/04/2014	10
  01/04/2014	01/05/2014	23
  01/04/2014	01/06/2014	23
  01/04/2014	01/07/2014	23
  01/07/2014	01/08/2014	20
  01/07/2014	01/09/2014	20
  01/07/2014	01/10/2014	20

  Concerning

  Etbin

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  Hello
  in the Sub statement I need to print the last value
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  Please help me
  

  SELECT REGEXP_SUBSTR('5454 4587454 547451 188745 5555','[^'||' '||']+'||' ',1,5)  p1 from dual;

  Thanks in advance
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  Karthick_Arp wrote:
  Like this

  with t
  as
  (
  select '5454 4587454 547451 188745 5555' str
  from dual
  )
  select regexp_substr(str, ' [[:digit:]]*$')
  from t
  

  Why leave space in front of her?

  SQL> ed
  Wrote file afiedt.buf
  
    1  with t as (select '5454 4587454 547451 188745 5555' str from dual)
    2  --
    3  select regexp_substr(str, '[0-9]+$')
    4* from t
  SQL> /
  
  REGE
  ----
  5555
  
  SQL>