A chart to a line of lock header

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  HTML code foris not where you need to insert. As the audio player is already hidden, try to place somewhere in the page by using the object-> the option Insert HTML code. And using layers, you can place it in the back.

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  It would be the original behavior of Oracle Forms in the scenario of pessimistic locking.

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• WAITED TOO LONG FOR A CACHE LINE ENQUEUE LOCK!

  Hi all
  
  Ora10g
  
  All of a sudden this afternoon users have complained that they are unable to connect to the database, I tried to log in and was able to confirm that suspended connection.
  
  I checked the alerts log and I found these:
  

  Thread 1 advanced to log sequence 11682
    Current log# 3 seq# 11682 mem# 0: D:\ORACLE\ORADATA\TURBDV2\REDO03.LOG
  Mon Jun 13 09:00:15 2011
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  Mon Jun 13 10:00:27 2011
  Thread 1 advanced to log sequence 11683
    Current log# 1 seq# 11683 mem# 0: D:\ORACLE\ORADATA\TURBDV2\REDO01.LOG
  Mon Jun 13 13:15:50 2011
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  Mon Jun 13 13:51:28 2011
  WAITED TOO LONG FOR A ROW CACHE ENQUEUE LOCK! pid=27
  System State dumped to trace file c:\oracle\admin\turbdv2\udump\turbdv2_ora_7668.trc
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  WARNING: inbound connection timed out (ORA-3136)
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  How to solve this error please...

  KinsaKaUy? wrote:
  I checked the alerts log and I found these:

  
  Thread 1 advanced to log sequence 11682
  Current log# 3 seq# 11682 mem# 0: D:\ORACLE\ORADATA\TURBDV2\REDO03.LOG
  Mon Jun 13 09:00:15 2011
  WARNING: inbound connection timed out (ORA-3136)
  Mon Jun 13 10:00:27 2011
  Thread 1 advanced to log sequence 11683
  Current log# 1 seq# 11683 mem# 0: D:\ORACLE\ORADATA\TURBDV2\REDO01.LOG
  Mon Jun 13 13:15:50 2011
  WARNING: inbound connection timed out (ORA-3136)
  Mon Jun 13 13:51:28 2011
  
  

  WAITED TOO LONG FOR A ROW CACHE ENQUEUE LOCK! pid=27

  System State dumped to trace file c:\oracle\admin\turbdv2\udump\turbdv2_ora_7668.trc
  Mon Jun 13 14:50:44 2011
  WARNING: inbound connection timed out (ORA-3136)
  Mon Jun 13 15:23:10 2011
  

  How do i resolve this error please....

  Well looking at alert.log, you encountered two issue a)ORA-3136 and b) WAITED TOO LONG FOR A ROW CACHE ENQUEUE LOCK

  For a) ORA-3136 , please follow the below metalink note which explains about the resolution for this. You might need to increase SQLNET.INBOUND_CONNECT_TIMEOUT from 60 to slight higher.
Following the note from MOS
Troubleshooting ORA-3136: WARNING Inbound Connection Timed Out [ID 465043.1]

  
  The default value of 60 seconds is good enough in most conditions for the database server to authenticate a client connection. If it is taking longer, then it's worth checking the following items before implementing the workaround: 
  
  1. Check whether local connection on the database server is successful & quick.
  2. If local connections are quick ,then check for underlying network delay with the help of your network administrator.
  3. Check whether your Database performance has degraded in anyway.
  4. Check alert log for any critical errors for eg, ORA-600 or ORA-7445 and get them  resolved first. 
  

  As you said that users could not connect to the database, so above may be the reasons for what you need at the Fund.

  Second, you got the warning message "WHEREAS TOO LONG for A LINE CACHE ENQUEUE LOCK", which is also linked to the shared pool.

  Make a small conclusion on two question above, it seems that your shared pool size is not enough. For this you must check AWR reports during this difficult period and confirmation that there is not any event of related waiting for shared pool.

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• Grouping of lines from common lines in detail header

  Hello

  I have two tables TAB_MST and TAB_DTL with the information as below:

  {code}

  CREATE TABLE TAB_MST
  (
  NUMBER OF MSTCOL
  )
  /

  ALTER TABLE TAB_MST ADD CONSTRAINT TAB_MST_PK PRIMARY KEY (MSTCOL)
  /

  INSERT INTO TAB_MST (MSTCOL) VALUES (1);
  INSERT INTO TAB_MST (MSTCOL) VALUES (2);
  INSERT INTO TAB_MST (MSTCOL) VALUES (3);
  INSERT INTO TAB_MST (MSTCOL) VALUES (4);

  CREATE TABLE TAB_DTL
  (
  NUMBER OF MSTCOL
  NUMBER OF DTLCOL
  )
  /

  ALTER TABLE TAB_DTL ADD CONSTRAINT TAB_DTL_PK PRIMARY KEY (MSTCOL, DTLCOL)
  /

  INSERT INTO TAB_DTL (MSTCOL, DTLCOL) VALUES (1, 1);
  INSERT INTO TAB_DTL (MSTCOL, DTLCOL) VALUES (1, 2);
  INSERT INTO TAB_DTL (MSTCOL, DTLCOL) VALUES (1, 3);
  INSERT INTO TAB_DTL (MSTCOL, DTLCOL) VALUES (1, 4);
  INSERT INTO TAB_DTL (MSTCOL, DTLCOL) VALUES (1, 5);
  INSERT INTO TAB_DTL (MSTCOL, DTLCOL) VALUES (2, 4);
  INSERT INTO TAB_DTL (MSTCOL, DTLCOL) VALUES (2, 7);
  INSERT INTO TAB_DTL (MSTCOL, DTLCOL) VALUES (2, 8);
  INSERT INTO TAB_DTL (MSTCOL, DTLCOL) VALUES (2, 9);
  INSERT INTO TAB_DTL (MSTCOL, DTLCOL) VALUES (3, 8);
  INSERT INTO TAB_DTL (MSTCOL, DTLCOL) VALUES (3, 9);
  INSERT INTO TAB_DTL (MSTCOL, DTLCOL) VALUES (3, 10);
  INSERT INTO TAB_DTL (MSTCOL, DTLCOL) VALUES (3, 11);
  INSERT INTO TAB_DTL (MSTCOL, DTLCOL) VALUES (4, 12);
  INSERT INTO TAB_DTL (MSTCOL, DTLCOL) VALUES (4, 13);
  INSERT INTO TAB_DTL (MSTCOL, DTLCOL) VALUES (4, 14);

  COMMIT;

  {code}

  I want to group the rows in the Master table (TAB_MST) to different groups based on the data in the secondary table (TAB_DTL) with output like below

  MSTCOL GROUPID
  1               1
  2               1
  3               1
  4               2

  Rule for grouping are as follows:

  (1) if there is a common value of DTLCOL for two different values of MSTCOL, then two MSTCOL values should be grouped under the same group, for example for the above case of sample
  DTLCOL (value = 4) is common for MSTCOL = 1 and MSTCOL = 2, so MSTCOL 1 and MSTCOL 2 belong to the same group (GROUPID = 1).
  DTLCOL (value = 8, 9) is common for MSTCOL = 2, MSTCOL = 3, so 3 MSTCOL must belong to the same group as MSTCOL 2 (GROUPID = 1)
  There is no common value of DTLCOL for MSTCOL = 4, so it is in a separate group.

  Here is the PL/SQL block to highlight this grouping behavior. Two temporary tables are created to achieve this:

  {code}

  CREATE TABLE TAB_MST_GROUP
  (
  NUMBER OF MSTCOL
  GROUPID NUMBER
  )
  /

  CREATE TABLE TAB_TMP_GROUP
  (
  GROUPID NUMBER
  )
  /

  
  DECLARE
  CURSOR c1
  IS
  SELECT * FROM tab_mst;

  prevmstcol NUMBER;
  prevgroupid NUMBER: = 1;
  vtmpgroupid NUMBER;
  BEGIN
  DELETE tab_mst_group;

  FOR r1 IN c1
  LOOP
  IF prevmstcol IS NULL
  THEN
  INSERT INTO tab_mst_group
  VALUES (r1.mstcol, prevgroupid);

  prevmstcol: = r1.mstcol;
  ON THE OTHER
  INSERT INTO tab_tmp_group
  SEPARATE SELECT GroupID
  OF tab_mst_group a, tab_dtl b, tab_dtl c
  WHERE a.mstcol = b.mstcol
  AND c.dtlcol = b.dtlcol
  AND c.mstcol = r1.mstcol;

  IF SQL % ROWCOUNT = 0
  THEN
  prevgroupid: = prevgroupid + 1;

  INSERT INTO tab_mst_group
  VALUES (r1.mstcol, prevgroupid);
  ON THE OTHER
  SELECT MIN (groupid) IN the vtmpgroupid OF tab_tmp_group;

  UPDATE tab_mst_group
  SET groupid = vtmpgroupid
  WHERE groupid IN (SELECT tab_tmp_group FROM groupid);

  INSERT INTO tab_mst_group
  VALUES (r1.mstcol, vtmpgroupid);

  SELECT MAX (groupid) IN tab_mst_group prevgroupid;

  DELETE tab_tmp_group;
  END IF;
  END IF;
  END LOOP;
  END;

  {code}

  
  Question:

  a. can achieve us in SQL instead of PL/SQL?
  b. fresh general reading of TAB_DTL grows exponentially if the number of cases in TAB_MST develops. How can we reduce the number of TAB_DTL reading as the real lines of TAB_DTL is very high.

  
  Thank you
  sukhijank

  Hi, Sukhijank,

  Thanks for the additional information.  Has not only learned these details since posting your first message, did you?  If you post information like that in your first post, and then people can use it to give you a better response to the first answer.

  The idea I had for a recursive solution of WITH clause will not work after all.

  I think that the best solution will be in PL/SQL, using a table like tab_mst_group that you posted, but with an extra column:

  CREATE TABLE TAB_MST_GROUP
  (
    mstcol NUMBER PRIMARY KEY,
    groupid   NUMBER,
    levelnum NUMBER
  );
  CREATE INDEX tab_mst_group_groupid_levelnum
  ON     tab_mst_group (levelnum, groupid);
  

  If llevelnum = 0, which means that the allocation of groupid is not certain; If levelnum > 0, then groupid is correct.

  Here is a procedure you can use to fill in the table:

  CREATE OR REPLACE PROCEDURE tab_mst_group_populate
  AS
      new_groupid  tab_mst_group.groupid%TYPE
       := 0;
      new_levelnum tab_mst_group.levelnum%TYPE;
      num_added  PLS_INTEGER;
      truncate_stmt VARCHAR2 (50) := 'TRUNCATE TABLE tab_mst_group';
  BEGIN
      --  *****  Remove old entries from the table  *****
      -- dbms_output.put_line (truncate_stmt || ' = truncate_stmt in tab_mst_group_populate'); -- Debugging
      EXECUTE IMMEDIATE  truncate_stmt;
  
      --  *****  Populate table with all mstcols, and 1-member groups  *****
      INSERT INTO  tab_mst_group (mstcol, groupid, levelnum)
      SELECT    m.mstcol
      ,       m.mstcol  AS groupid
      ,       MIN ( CASE
                       WHEN  o.mstcol IS NULL
       THEN  1
       ELSE  0
                   END
      )  AS lvlnum
      FROM     tab_mst    m
      LEFT JOIN tab_dtl    d ON  d.mstcol = m.mstcol
      LEFT JOIN tab_dtl    o ON  o.dtlcol = d.dtlcol
              AND o.mstcol   != d.mstcol
      GROUP BY    m.mstcol;
  
      --  ***** Get groupid for lowest mstcol that still needs one  *****
      WHILE  new_groupid IS NOT NULL
      LOOP
          SELECT  MIN (groupid)
  INTO new_groupid
  FROM tab_mst_group
  WHERE levelnum = 0;
  IF  new_groupid   IS NOT NULL
  THEN
       --  ***  Confirm groupid for this one mstcol  ***
       UPDATE  tab_mst_group
       SET     levelnum = 1
       WHERE   levelnum = 0
       AND     groupid = new_groupid;
       new_levelnum := 2;
       num_added := 1;
       --  ***  Add neighboring mstcols to this group  ***
  
       WHILE  num_added > 0
       LOOP
           UPDATE  tab_mst_group
    SET groupid   = new_groupid
    , levelnum  = new_levelnum
    WHERE levelnum  = 0
    AND groupid   IN (
                     SELECT  d2.mstcol
              FROM  tab_mst_group g1
        JOIN  tab_dtl       d1  ON  d1.mstcol  = g1.mstcol
        JOIN  tab_dtl       d2  ON  d2.dtlcol  = d1.dtlcol
                      AND d2.mstcol != d1.mstcol
        JOIN  tab_mst_group g2  ON  g2.mstcol  = d2.mstcol
        WHERE  g1.levelnum  = new_levelnum - 1
        AND  g1.groupid   = new_groupid
        AND  g2.levelnum  = 0
           );
    num_added := SQL%ROWCOUNT;
    dbms_output.put_line (num_added || ' = num_added');
           new_levelnum := new_levelnum + 1;
       END LOOP;
  END IF;
      END LOOP;
  
  END tab_mst_group_populate;
  /
  SHOW ERRORS
  

  The basic strategy is that we start assuming that each mstcol will have its own groupid.  The CASE expression in the INSERT statement sets levelnum = 1 for the mstcols that do not exist in the tab_dtl table, or are not related to other mstcols in tab_dtl.  The loop after that looks like for tab_mst_group lines are always 0, which means that the grpupid must still be confirmed or changed.  He begins by finding the lowest mstcol which still has levelnum = 0 and makes a new group.  The inner loop looking for related mstcols and the brand as being in the same group.

  You could combine tab_mst and tab_mst_group; I see no need to have a separate table (but maybe do you).  If combine you them, then you would not truncate the table in the procedure.

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