a clear indicator for the while loop

Similar Questions

• How to create a control of time for the while loop?

  Hi all

  I want to control my time running of the loop. In other words, I want to stop everything in the execution of the loop after a time (in ms) that is defined by the user. For example user defines Control Panel for 5 seconds before a while loop runs and stops after 5 seconds.

  I don't know is it possible with the while loop. I managed with the timed loop, but this must be wrong with my application. Y at - it of the other loops for timed control if it is not possible with while loop? There is also a simple loop with .vi random number (0-1) as an attachment.

  Best regards

  Jick

  Hi again,

  I managed to solve my problem right after I posted my first message. I did it with the passage of time and the register shift (for the elapsed time of reset).

  Thanks for your replies anyway!

  Best R

  Jick

• loop for and while loop with empty table entry

  Hello

  I have a question with loop and loop.

  When a constant empty array (zero element) is connected to the loop For with "allowing the index", there are no interactions performed in loop For. But, if the loop is replaced by any loop, no problem.

  LabVIEW 2010

  Hello

  It is ok. I have no problem at all.

  For the 'loop' For when you connect the table thanks to indexing, the number of iterations is set to the size of the array. The iteration number assigned to N (in your case 10) is ignored.

  For the 'While' loop the number of iteration is defined by the Boolean Condition and the size of the array is ignored.

  Paul

• For results outside the while loop

  Dear friends,

  I have a while loop vi, which is attached to this mail. I want to update Boolean Boolean results, while the while loop runs. In fact this is not the case?

  Do I need to use it as a global variable or another simple method to do? Could you please guide me, or please alter the VI of the sample which is attached to this mail.

  Thank you

  Best regards

  Tom

  The Boolean value outside of the loop only will be updated, as wiring system, when the loop ends, it's how the LabVIEW data flow. The simplest method for updating the Boolean value outside of the loop is to unplug the wire, create a local variable (right click on the device, select 'create', 'Local Variable'), move the room inside the loop and hook it up to your function "equal." This is not necessarily the best method, just the easiest for this example.

• delete 2d array in the while loop

  I have a table 2D being initialized outside of the loop executing a state machine, how would a clear table 2d in the while loop? I guess I'm not sure what to wire a constant matrix empty 2D too =)

  When you want to erase (regardless of this Boolean condition), wire just a constant matrix 2D of your shift register.  See attachment.

• How the entry changes with each iteration of the while loop

  Hello

  can anyone explain (clarify) to know how or what contribution will be fed like the d block of adaptive filtering for the first, second entry (n) and remaining iterations of the while loop as shown in the picture as an attachment...

  As I need to feed the e (n) out of the while loop as input d (n) to the Adaptive block for the first iteration for the next iteration of the previous output e (n) of the block Adaptive must be fed back as input (n) d and other x (n) of entry form the DAQmx.

  Thank you.

  You have a shift register on the edge of the loop, so for the first iteration, the input (n) d will get everything that feeds the shift register on the left of the outside. After that the adaptive filtering performed, e (n) is injected in the shift to the right, register to be read from the shift register on the left on the next iteration. And so on. This seems pretty much what you want.

  PatanGova wrote:

  As I need to feed the e (n) out of the while loop as input d (n) to the Adaptive block for the first iteration for the next iteration of the previous output e (n) of the block Adaptive must be fed back as input (n) d and other x (n) of entry form the DAQmx.

  If you need retain the value in calls, use a node that is initialized in the world of feedback to feed out of the while loop at the entrance.

• Time for a while loop to run once

  Hello guys,.

  I want to measure the time for a while loop to run once. There is a piece of code raised. So I just created a simple VI to try, please let me know which is the right way to do it?

  And I wondered, when I run the VI without highlighting the execution, he wouldn't give me a number, maybe it's because the code is simple and really fast? I have to highlight all the time?

  Thank you

  Not quite right.  Both get primitive value time will run at the same time.  use an image sequence to force the order of execution, as shown.  I also brought in the relitve of accuracy seconds vi of VI. LIB\utilities because it depends on the clock of the system rather than the mSec timer accuracy.

  

• How to add the unique element (inside the while loop) to itself

  I have only digital output element that is in the while loop. Its value changes in each time the loop iteration. If lets say I want to adds the values of the ten first in iterations of the loop of this variable.  How can I do that.

  See attach image for more precision.

  Thank you

  JK

  

  Hi Joseph,.

  THINK THE STREAM!

  As the values are stored in the son and the shift registers (and NOT in any kind of variables), you must use these fundamentals of LabVIEW:

  

• Table 1 d in the while loop problem

  Hello world

  I searched this problem in the forum, but seems only some positions quite didn't answer.

  I'm stuck by saving the data in a while loop.

  I have a while loop, within which there are two exits in each iteration, I want to add to a table, and then after the while loop is completed, I want to combine these two tables in a 2D array (since the release of them must be a pair in my case).

  I tried 'Build array' and 'transpose array' and 'write in spreadsheet' element set, which maintains concerns me is how simply to add the result in a 1 d table during each iteration, these 2 outputs are in digital format, which prevent to directly create a table for it.

  Any idea is appreciated,

  Thank you

  Chen Kunsheng

  Here are some other ways to insert.

  It may be useful

• Force the While loop to exit when the delay is running

  Hello guys,.

  I have a While loop containing some jobs. One of them is delay for 10 seconds. When I push the stop button, the loop does not stop immediately. Instead, it stops after a few seconds (can be, pending other jobs is done).

  What can I do if I want to stop the loop immediately after I press the stop button?

  Thank you for sharing...

  Hello Yoppy,

  I don't know if I understand your problem completely, but here's the method I use to stop the while loop immediately (some ms delay will be there for you).

  I would like to know if the attachment helps.

  There are several ways to do it and you can get better solutions than this one on this community.

• To break out of the while loop (1)

  Hi all

  I have a simple question that if a callback to a command button function, I use a (bLoop) While
  loop, where bLoop is a boolean variable has the value TRUE, then how can I break up or out of this while loop by using a control on the façade, which released the while loop by setting bLoop = FALSE.

  I tried, but it didn't come out

  The problem here is that the CVI normally only runs a reminder at a time. While you are in snooze control, no treatment of GUI and subsequent calls to other reminders usually occurs.

  You can try the following approach-, but it's not really the best method:

  While (b_loop) {/ / within a reminder}

  ... / / Do your tight loop

  ProcessSystemEvents ();   Force the CVI to see if all the GUI needs maintenance controls

  }

  If you have a reminder of different control to erase the global b_loop, this packing approach might work for you.

  You must use this technique for very simple programs - it can quickly escape out of control and in the end upward in a mess if you're not careful. OR recommend that you use not ProcessSystemEvents() within a point of order.

  JR

• for and while loops

  Hello, im new to java, and now I have an assignment. I need to analyze a phone number like this-> (656) 345 6544 to 6563456544. I wrote the following code which works very well with a while loop. Now, I would like to know how can I make it work with a loop for.
  
  and the code is

  import java.io.*;
  public class Tema
  {
  
    public static String removeChar(String str, int i)
    {
      String first= str.substring(0,i);
      String last= str.substring(i+1,str.length());
      str=first+last;
      return str;
    }
    public static String cautaTrimite(String str)
    {
       /*for(int i=0; i<str.length(); i++)
      {
         if ((str.charAt(i)==' ')  ||(str.charAt(i)=='5')  ||(str.charAt(i)=='(')
            ||(str.charAt(i)==')') ||(str.charAt(i)=='-'))
            {
            str = removeChar(str,i);
            }*/
         int i=0;
          while(i<str.length())
           {
               if(( str.charAt(i)== ' ' )||( str.charAt(i)== '8' )
                       ||(str.charAt(i)==')')||(str.charAt(i)=='('))
        {
          str = removeChar(str,i);
        }   
              
        else
        {
          i++;
        }
  
           }
      
    return str;}
    public static void main (String [] args)
    {
    try{
       BufferedReader in=new BufferedReader(new InputStreamReader(System.in));
       System.out.println("Introduceti un numar de telefon oarecare: ");
       String str= in.readLine();
       
       str= cautaTrimite(str);
       System.out.println(str);
    
       }
    catch(IOException e){System.out.println("S-a produs o eroare de IO");}
    }
  }

  Published by: 1002443 on 30-Apr-2013 05:17

  In the while loop, you have full control on when you increment the i and when not, and what you're doing is correct.
  Do this with the because the loop always increments the i. To avoid this, you can discover that when you removeChar, you decrement the i, just to increment the loop right after.
  Everything in that this would mean by code more obscure all loop, so I wouldn't use it.

  Edit: Why you remove 8 in the while loop and 5 in the loop remains a great mystery.

  Published by: baftos on April 25, 2013 11:56

• store the value obtained in the while loop

  Hello

  I'm data acquisition (1,000 points every 0.1 s) in a while loop. I would like to calculate the average y of the first sample of 1000 points when I click on a Boolean 'calibrate', store that value somewhere (outside the while loop?) so that it can subtract from each new amplitude y. In the vi below, a new average value is calculated in each loop, although I would only use the first.

  You don't need to store the value outside the while loop. Keep the offset of the value when calibrate button is pressed and subtract the value with earned value. I modified your find VI the VI attached.

• URGENT::opening multiple files - i have 3 files in my directory... When I run the code I can open a file and read it... but the while loop get blocked after the first iteration... can someone me help or give some indications

  bbmChatDB of public database;

  public static FileConnection fconnRead = null;
  public static String fileReadData = "";
  public static InputStream is = null;
  data Byte [] = null;
  DataInputStream is = null;

  Here is my code...

  I have 3 files in my directory... When I run the code I can open a file and read it... but the while loop get blocked after the first iteration... can someone me help or give some indications

  try {}

  FileConnection fc = Connector.open("file:///store/home/user/documents/BSM/") (FileConnection); "

  If (fc.exists ()) {}

  Enumeration e = fc.list ();

  While (e.hasMoreElements ()) {}

  System.out.println ("files are:" + (String) e.nextElement ());

  play this file
  StringBuffer stringBuff = new StringBuffer();
  try {}
  System.out.println ("opening file")-;
  System.out.println ("file name is:" + (String) e.nextElement ());
  fconnRead = Connector.open("file:///store/home/user/documents/BSM/(String)e.nextElement(),Connector.READ_WRITE) (FileConnection);
  System.out.println ("data length")-;
  If (fconnRead.exists ()) {}
  is = fconnRead.openDataInputStream ();
  data = IOUtilities.streamToBytes (is);
  Ddd = new String string (data);
  fileReadData = ddd.toString ();
  System.out.println ("length of data:" + fileReadData.length ());
  System.out.println ("read data :" + fileReadData);

  }

  } catch (IOException ee) {}
  ee.printStackTrace ();
  System.out.println ("Exception in the read data :")
  + ee.getMessage ());
  }

  }
  }

  } catch (IOException e) {}

  e.printStackTrace ();
  }

  {Finally

  try {}
  If (is! = null) {}
  is. Close();
  }
  System.out.println ("is closed...");
  } catch (IOException e1) {}

  E1. PrintStackTrace();
  }

  If (fconnRead! = null) {}
  try {}
  fconnRead.close ();
  } catch (Exception e) {}
  System.out.println (try ());
  }

  }

  }

  You can recode this treatment so that it uses only:

  e.nextElement ())

  Once a loop iteration.

  Directly at the start saying something like:

  String fileName = e.nextElement ());

  and use fileName everywhere in your loop.

  Also be aware that printStackTrace() will do nothing in your situation, it only works if you catch Throwable.  So make sure you something output all your catches exception and also have a catch (Throwable t) to catch the things you miss, as follows:

  {} catch (Throwable t)

  t.printStackTrace ();

  System.out.println ("Eception exception:" + t.toString ());

  }

  I think your code is thrown an exception and you don't see it.

• To count the number of while loops, you just attach a DBL indicator for the little that I framed in the while loop of the program?

  I followed just one example in a book as while loops and I want to just make sure that I haven't missed something simple. My program is attached

  Hi type'ssteel,

  I can't open your vi at the moment, but as you say, you can use the terminal i. For iterations, you must add 1 to it. I start with 0.

  Mike