A hierarchical report query SQL formatting to display the output as a tree

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  SQL: how to display the second string of the function in the Jobs table only if the function has more than one string.

  Hello

  You can use REGEXP_SUBSTR Oracle/PLSQL: REGEXP_SUBSTR function

  Select the function double REGEXP_SUBSTR('PUBLIC RELATION REPRESENTATIVE ','[^]+',1,2);

  Do you have any value of the column as no 2nd string?

• How to use a parameter query to select and display the data in the table of the façade

  Hiiiiii

  I am using Access 2007 database
  I want to select the specific data in the database using control of the chain as 'select product, size, weight of ProductInfo where barcode (chain control) =?'  and also display the same table of façade.

  I use the connected database toolkit.
  I saw the example of the parameterized insert, but it did not help to use parameterized select query, as well as to display data of parameterized select query.

  I looked for example on parameterized select query, but I don't have any.
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  HII szewczak
  Thanks for the reply
  but I did not getsolution in one of your shared links
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• Query results pane should display the entire XML following the execution of the query

  Hi, I'm trying to get the xml output results returned in sqldeveloper returned in full.

  they are truncated to.

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  JM

  Hi jm,

  In the line of query results, did scroll all the way to the right, then click twice on the «...» "at the end of the line to open the cell editor?

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  Kind regards

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  SQL development team

• How to display the output of query clause?

  Hello. I use Forms Developer 10g. I have a datablock that uses a from_clause_query. In my from_clause_query, I used a WITH AS SELECT.
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• the two equii join and natural join are equall.will both display the output of the same

  the two equii join and natural join are equall.will both display even
  
  output?

  Hello
  It keeps you a little test and check yourself?

  See the link below.

  http://psoug.org/reference/joins.html

  Connected to:
  Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - Production
  With the Partitioning, OLAP, Data Mining and Real Application Testing options
  
  SQL> CREATE TABLE parents (
    2  person_id  NUMBER(5),
    3  adult_name VARCHAR2(20),
    4  comments   VARCHAR2(40))
    5  PCTFREE 0;
  
  Table created.
  
  SQL>
  SQL> CREATE TABLE children (
    2  parent_id    NUMBER(5),
    3  person_id    NUMBER(5),
    4  child_name   VARCHAR2(20),
    5  comments     VARCHAR2(40))
    6  PCTFREE 0;
  
  Table created.
  
  SQL>
  SQL> INSERT INTO parents VALUES (1, 'Dan', 'So What');
  
  1 row created.
  
  SQL> INSERT INTO parents VALUES (2, 'Jack', 'Who Cares');
  
  1 row created.
  
  SQL> INSERT INTO children VALUES (1, 2, 'Anne', 'Who Cares');
  
  1 row created.
  
  SQL> INSERT INTO children VALUES (1, 1, 'Julia', 'Yeah Right');
  
  1 row created.
  
  SQL> INSERT INTO children VALUES (2, 1, 'Marcella', 'So What');
  
  1 row created.
  
  SQL> COMMIT;
  
  Commit complete.
  
  SQL>
  SQL> SELECT adult_name, child_name
    2  FROM parents NATURAL JOIN children;
  
  ADULT_NAME           CHILD_NAME
  -------------------- --------------------
  Jack                 Anne
  Dan                  Marcella
  
  SQL> select adult_name,child_name from parents a, children b
    2  where a.person_id=b.person_id;
  
  ADULT_NAME           CHILD_NAME
  -------------------- --------------------
  Jack                 Anne
  Dan                  Julia
  Dan                  Marcella
  
  SQL> ed
  Wrote file afiedt.buf
  
    1  select adult_name,child_name from parents a, children b
    2* where a.person_id=b.parent_id
  SQL> /
  
  ADULT_NAME           CHILD_NAME
  -------------------- --------------------
  Dan                  Anne
  Dan                  Julia
  Jack                 Marcella
  
  SQL>
  

  Kind regards
  Avinash

• is trace SQL - possible to appoint the output trace file?

  Hello
  
  I put DBMS_SYSTEM. SET_SQL_TRACE_IN_SESSION in my database. This is the version 10.2 running on Linux.
  Now, I want to display the trace file using tkprof. It is in my directory in $ORACLE_BASE/admin/SID/udump. But there are more tracks and they are all the same: instancename_ora_traceid, is very difficult to find the right one.
  Is it possible to make the sql trace file to be named by any other means?
  
  Thanks in advance.
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  Hello

  Yes, you can change then what is the purpose of this
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  Add with the tracefile_identifier

  Select c.value | '\' || d.instance_name | "_ora_" | a.SPID | '.trc' trace_file_is_here
  v $ process a, v$ session b, v$ parameter c, v$ instance d
  where a.addr = b.paddr
  and b.audsid = userenv ('sessionid')
  and c.nom = 'user_dump_dest;

  -Pavan Kumar N

  Published by: pounet on December 9, 2008 22:23

• Unable to display the output of a concurrent program

  Dear members,
  
  I use Oracle R12.1.3 Vision Instance.
  
  I ran the program create accounting. When I click on the button to display output, the browser gets displayed and gets immediately closed. I'm unable to view the output.
  
  Can someone help me please to solve this issue?
  
  Thanks in advance.
  
  Kind regards.

  I faced this problem once. That's the problem with the settings of Internet Explorer.
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• Unable to display the output in the next block

  Hello
  I tried the next block... But unable to see the output
  Could you suggest me in this...
  

  0-----)
  
  PL/SQL procedure successfully completed.

  Although made setserverout
  
  but of no use
  
  Please help me
  
  Published by: josh1612 on April 5, 2010 12:14 AM

  Hello

  Check if the script given below will print something...

  DECLARE
    ..
  BEGIN
     DBMS_OUTPUT.PUT_LINE('START OF ANONYMOUS BLOCK');
    ..
     DBMS_OUTPUT.PUT_LINE('END OF ANONYMOUS BLOCK');
  END;
  

  If so, check your logic for the results expected, if not... Check the settings of sqlplus

  * 009 *.

  Edited to take off your real script :) forums

  Published by: 009 April 5, 2010 12:18 AM

• When I filled a form field using a query SQL result is displayed but not registered in the table.

  I write in the topic, I have created a form and in some of their fields, I used a SQL query to get information from a table based on the user who has been logging.

  The information displayed well, but when I press "Send button" loses information and the field in the table is shown empty.

  
  

  Anyone know what is happening?

  I enclose below a picture of the problem

  Concerning

  

  Hi ANTHONY,.

  ANTHONY wrote:

  I give you the credentials of my database, I hope you could do it works and most importantly, showing me what the error care...

  Feel free to change what you want in the application

  https://Apex.Oracle.com/pls/Apex/f?p=4550:1:2838412118981:

  BANCO_PRUEBAS

  ADMIN

  password

  It is interesting that, when I use APEX 5.0.1.00.06, I have some errors form appearing not using APEX 4.1.0.00.32

  Check your 77569 application-> Page 1. I have modified the page element attributes. Now it's working.

  Here are the changes (I will explain for P1_NOMBRE, did the same for the P1_APELLIDOS and P1_CATEGORIA):

  • 'Source' has become article attributed to him include:

  Source: Replacement always, value that exists in session state

  Source type: column database

  Source of value or an expression: NUMBER

  • The "Default" article now the following attributes:

  By default of Type: PL/SQL function body

  Default value:

  DECLARE
  
    L_NOMBRE B_LISTA_EMPLEADOS.NOMBRE%TYPE;
  
  BEGIN
  
    select NOMBRE
    into   L_NOMBRE
    from   B_LISTA_EMPLEADOS
    where  USERNAME = :APP_USER;
  
    RETURN L_NOMBRE;
  
  EXCEPTION
    WHEN NO_DATA_FOUND THEN
    RETURN NULL;
  
  END;
  

  Kind regards

  Kiran

• query or pl sql block to display the mentioned result

  create table shirt (color varchar2 (10), number Qty., number s, number m, l, xl, xxl number);

  insert into shirt values ('black', 10, 5,2,1,2,0);

  insert into shirt values ('black', 8, 2,1,2,0,3);

  insert into shirt values ('White', 5, 2,1,1,0,1);

  insert into shirt values ('White', 7, 2,1,2,1,1);

  How to get the bottom of output?

  Expected result:

  G1 G2 QUANTITY

  Black s 7

  Black 3 m

  Black           l                 3

  XL Black 2

  XXL black 3

  White s 4

  White m 2

  white            l                2

  XL white 1

  White xxl 2

  Vinodh

  Correction
  

  
  

  with

  shirt as

  (select "black" color, quantity 10, 5 s, 2 m, 1 l, 2-xl, xxl 0 of all the double union)

  Select 'Black', 8, 2, 1, 2, 0, 3 double Union all

  Select 'White', 5, 2, 1, 1, 0, Union 1 double all the

  Select 'White', 7, 2, 1, 2, 1, 1 double

  )

  Select the color of g1, g2, quantity

  (select color, concerned, sum (m) m, sum (l) l, sum (xl) xl, sum (xxl) xxl

  shirt

  Group by color

  )

  UNPIVOT (quantity for g2 in (as ', m mod', 'l' l, xl as "xl", xxl as a 'xxl'))

  order of g1, decode(g2,'s',1,'m',2,'l',3,'xl',4,'xxl',5,6)

  G1	G2	QUANTITY
  Black	s	7
  Black	m	3
  Black	l	3
  Black	XL	2
  Black	XXL	3
  White	s	4
  White	m	2
  White	l	3
  White	XL	1
  White	XXL	2

  Concerning

  Etbin

• Help of query SQL - inner joins and the separate results

  Hello
  
  ASP VB, SQL Server
  
  I have a structure of data base with 3 tables - users, albums and photos. each user has a identifier unique, each record has a unique albumid and also contains a column with the user name. each record in the photo has a unique id so that store the user name and the album in which the image belongs.
  
  I'm writing a query that returns a list of the albums for a particular user (based on a user name query string) and who will also bring back the id of the first record in the table for each of these albums photo.
  
  the closest I get is to run a query to select albumid albums where userid = varuserid with a join internal on the pictures table to remove the photo ID - problem I then it comes out all the photos from the photos table where userid = varuserid, so when I do a repeat region to display a list of albums for a certain user It produces a list of all the photos where userid = varuserid
  
  I really want to return just a list of ID album based on the username variable, but also to return the first record in the table of photos for each of these albumids
  
  I tried different combinations of inner joins, select distinct etc but no joy.
  
  any suggestion would be appreciated as am floundering here...
  
  
  
  
  

  First, you must define 'first' with regard to the photos. Is there a
  timestamp? They are numbered inside the album? Do you really care who is
  "first", or do you want simply a shot? You also neglected to indicate if they are
  empty photo albums have been allowed. I assumed that the empty albums are not
  allowed.

  Whatever you decide, the answer will be similar.
  SQL Server tends to get better results with joins with subqueries. You will have
  See such a written request more often with subqueries, and there isn't
  nothing wrong with that, but I'll use a join on a derived table. I have
  have not all column names (hint, hint), so I made them, but the
  Comments should help out you.

  SELECT A.Title, P.PhotoID, P.Caption, A.AlbumID, P.ImagePath
  FROM dbo. A albums
  -build a table derived, consisting of photo ID lowest for each
  album.
  INNER JOIN (SELECT AlbumID, MIN (PhotoID) AS FirstPhoto FROM dbo. Photos
  AlbumID GROUP) AS PM WE A.AlbumID = PM. AlbumID
  -details of the photo for the photo shown in the table above
  INNER JOIN dbo. Photos P on A.AlbumID = P.AlbumID AND
  H. FirstPhoto = P.PhotoID
  User A.UserID ='some WHERE '

  "tedstar" wrote in message
  News:ee4pfn$de$1@forums. Macromedia.com...
  > I am writing a query that returns a list of the albums for a
  > particular user (based on a user name query string) and also bring
  > return
  > the id of the first record in the table for each of these albums photo.

• With the help of SQL, need to display the previous year, current year and the year next to single variable

  Hi all

  We have an obligation to state the previous year, current year and values of the year next as a LOV in the ADF page.

  This is the query that retrieves the previous year, current year and next year. But the result of this query displays values in 3 columns:

  Select (Extract(year from sysdate)-1), extract (year sysdate), (extract (year sysdate) + 1) twice;

  Output:

  2012 2013 2014

  
  

  But I want to display them in a single with 3 rows as column:

  2012

  2013

  2014
  

  
  

  Please your ideas.

  or in the same way

  SELECT EXTRACT (YEAR FROM ADD_MONTHS (SYSDATE, 12 *(LEVEL-2)))

  OF the double

  connect by level<>

• Hierarchical Oracle query help needed - path between the crux of two brothers and sisters

  I want to find the path between two nodes of oracle hierarchical Table.
  
  Consider the following case-
  NodeId - ParentId
  =============
  1 > > > > > > 0
  2 > > > > > > 1
  3 > > > > > > 2
  4 > > > > > > 3
  5 > > > > > > 0
  6 > > > > > > 5
  Here I want to query the database table that if there is a path between nodes 3 and 5?
  The previous query you provided work upwards to the root node.
  
  Here is my expected result, 3-> 2-> 1-> 0-> 5
  
  Yet once if I have a query in the table to get the path between 1 and 3, I want to get out of the way - next
  1-> 2-> 3
  
  Therefore, the query works in both cases. Where ADI root can act as an intermediate or no node.
  
  Can you please guide me how I can get it?
  
  Thank you.

  Hello

  user13276471 wrote:
  I want to find the path between two nodes of oracle hierarchical Table.

  Consider the following case-
  NodeId - ParentId
  =============
  1 >>>>>> 0
  2 >>>>>> 1
  3 >>>>>> 2
  4 >>>>>> 3
  5 >>>>>> 0
  6 >>>>>> 5
  Here I want to query the database table that if there is a path between nodes 3 and 5?
  The previous query

  What application is this? If you're referering to another thread, then post a link, such as {message identifier: = 10769125}

  you provided work upwards to the root node.

  Here is my expected result, 3--> 2--> 1--> 0--> 5

  Yet once if I have a query in the table to get the path between 1 and 3, I want to get out of the way - next
  1--> 2--> 3

  Therefore, the query works in both cases. Where ADI root can act as an intermediate or no node.

  Can you please guide me how I can get it?

  I think you want something like this:

  WITH     bottom_up_from_src    AS
  (
       SELECT     nodeid
       ,     parentid
       FROM     table_x
       START WITH     nodeid      = :src_nodeid
       CONNECT BY     nodeid   = PRIOR parentid
  )
  ,     bottom_up_from_dst     AS
  (
       SELECT     *
       FROM     bottom_up_from_src
      UNION ALL
       SELECT     parentid     AS nodeid
       ,     nodeid          AS parentid
       FROM     table_x
       WHERE     nodeid     NOT IN (
                                        SELECT  nodeid
                                 FROM    bottom_up_from_src
                                    )
       START WITH     nodeid        = :dst_nodeid
       CONNECT BY     nodeid        = PRIOR parentid
  )
  SELECT      :src_nodeid || SYS_CONNECT_BY_PATH (parentid, '-->')     AS display_path
  FROM       bottom_up_from_dst
  WHERE       parentid     = :dst_nodeid
  START WITH  nodeid     = :src_nodeid
  CONNECT BY  nodeid     = PRIOR parentid
  ;
  

  This will show how you can get it from: src_nodeid at dst_nodeid, moving to the top or to the bottom of a hierarchy at a time step. This will work regardless of the fact that
  

  
  
  • : src_nodeid is the ancestor of the: dst_nodeid, or
    
  • : src_nodeid is a descendant of: dst_nodeid, or
    
  • both: src_nodeid and: dst_nodeid are the descendants of another node (e.g. 0).
    

  I hope that answers your question.
  If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements) and also publish outcomes from these data.
  Explain, using specific examples, how you get these results from these data.
  Always say what version of Oracle you are using (for example, 11.2.0.2.0). It is always important, but particularly so with CONNECT BY queries, because each version since Oracle 7 had significant improvements in this area.
  See the FAQ forum {message identifier: = 9360002}

• How to display the output of PL/SQL and difficulty package below error (please help)

  -PACKAGE SPECIFICATION AND met with success, but I see no way out, an error is also here... Please help. How do I solve this problem
  -with the code
  
  CREATE OR REPLACE PACKAGE package_variables
  -Declare the components of a package.
  Established PROCEDURE (VARCHAR2 value);
  Public FUNCTION get RETURN VARCHAR2;
  END package_variables;
  /
  
  
  
  CREATE OR REPLACE PACKAGE BODY package_variables
  -Declare the package-scoped variable.
  variable VARCHAR2 (20): = "initial value";
  -Define the function
  Get function RETURN VARCHAR2 IS
  BEGIN
  RETURN variable;
  END get;
  -Define the procedure.
  PROCEDURE set(value VARCHAR2) IS
  BEGIN
  variable: = value;
  The END value;
  END package_variables;
  /
  
  
  
  Result VARIABLE VARCHAR2 (20)
  CALL package_variables.get () IN: result;
  SELECT: result AS result FROM dual;
  
  
  RUN package_variables.set ("new value '");
  CALL package_variables.get () IN: result;
  SELECT: result AS result FROM dual;
  
  /*
  
  OUTPUT
  
  
  PACKAGE compiled package_variables.
  PACKAGE compiled package_variables BODY.
  
  Error at startup on line 2 of the command:
  CALL package_variables.get () IN: results
  Error report:
  SQL error: ORA-01008: not all variables
  01008 00000 - "not all variables.
  * Cause:
  * Action:
  RESULTS
  --------------------------------
  
  
  1 selected lines
  
  anonymous block filled
  
  Error at startup on line 2 of the command:
  CALL package_variables.get () IN: results
  Error report:
  SQL error: ORA-01008: not all variables
  01008 00000 - "not all variables.
  * Cause:
  * Action:
  RESULTS
  --------------------------------
  
  
  1 selected lines
  
  */

  The package name is package_variables (note the 's'. Plural.) But using package_variable (in the singular) in your call.
  Also select in as a SQL statement seems to be not valid. You encapsulate a begin - end around her block.

  SQL> begin
    2  select package_variables.get into :outcome from dual;
    3  end;
    4  /
  
  PL/SQL procedure successfully completed
  outcome
  ---------
  Initial Value