A query to get the values of the batch % off tab Formulation of incoming materials.

Does anyone have a request that they would like to share to get the % batch out of the tab of the formulation of specifications of Formulation of incoming materials? Thank you!

David

I believe you can find this on the table of gsmFormulationInputs, using the percentBatchFactor column (* 100), while the percentage of step is PercentStepFactor.

Is that what you are looking for?

Tags: Oracle Applications

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SQL query to get the NULL records after the last matching flag

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SQL >

Hello

user11164339 wrote:

Hi Frank - when I run the query, I don't see the results data.

I get

FLAG OF THE ID

----- ----------

7

8

9

What you do differently?

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Can you help me with the sql query?

Maybe it's

SQL> with t as (
 select '50' usr_login from dual union all
 select '52' from dual union all
 select '53' from dual union all
 select '55' from dual union all
 select '57' from dual union all
 select '123' from dual union all
 select '111' from dual union all
 select '145' from dual union all
 select 'XELSYSADM' from dual union all
 select 'TESTUSER' from dual union all
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)
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--
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/
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---------------
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I need help, is there other ways to get the list of tables used in a query?
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In general you would add a condition 1 = 2 just to restrict the display of the entire table. Then should not be causing any noticeable performance degradation. You can even use ROWNUM< 2.="" that="" will="" do="" a="" count="" stopkey.="" which="" could="" be="">

SQL > select * from emp where rownum<>

no selected line

SQL > select * from table (dbms_xplan.display_cursor);

PLAN_TABLE_OUTPUT
--------------------------------------------------------------------------------
SQL_ID, 97f4bd002xfy0, number of children 0
-------------------------------------
Select * from emp where rownum<>

Hash value of plan: 4269703525

---------------------------------------------------------------------------
| ID | Operation | Name | Lines | Bytes | Cost (% CPU). Time |
---------------------------------------------------------------------------
|   0 | SELECT STATEMENT |      |       |       |     2 (100) |          |
|* 1 | COUNT STOPKEY |      |       |       |            |          |
|   2.   TABLE ACCESS FULL | EMP |     1.    38.     2 (0) | 00:00:01 |
---------------------------------------------------------------------------

Information of predicates (identified by the operation identity card):
---------------------------------------------------

1 Filter (ROWNUM<>

19 selected lines.

But its always good to bench mark it yourself.

How to rewrite this query to get the correct results?

Friends,

DB: 9iR2

I need to get the name of the employee and the employee number that are not in the table of presence.
but this query is not the right answer.

select e.eno,e.ename from empl e
where e.eno not in (select a.eno from attendance a)

Thank you

Depending on your data

SQL> create table attendance(
  2  ENO   VARCHAR2(5),
  3   TDATE VARCHAR2(10),
  4   IN_TIME  VARCHAR2(6),
  5   OUT_TIME VARCHAR2(6),
  6   SHIFT_NO  NUMBER(1));

Table created.

SQL>  create table empl(
  2   ENO VARCHAR2(5),
  3   ENAME  VARCHAR2(75));

Table created.

SQL> insert into empl values('11','AA');

1 row created.

SQL>   insert into empl values('12','AB');

1 row created.

SQL>    insert into empl values('13','AC');

1 row created.

SQL>     insert into empl values('14','AD');

1 row created.

SQL>   insert into empl values('15','AF');

1 row created.

SQL>  insert into attendance values('11','23-3-2009','9.00','6.00',1);

1 row created.

SQL>  insert into attendance values('14','24-3-2009','9.00','6.00',1);

1 row created.

SQL>  insert into attendance values('11','25-3-2009','9.00','6.00',1);

1 row created.

SQL>  insert into attendance values('13','23-3-2009','9.00','6.00',1);

1 row created.

SQL>  insert into attendance values('15','23-3-2009','9.00','6.00',1);

1 row created.

SQL> commit;

Commit complete.

select e.eno,e.ename
from empl e
where not exists(select 1 from attendance a where a.eno=e.eno);

ENO     ENAME

12     AB

Twinkle

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Hello
Oracle 10 g 2 10.2.0.3 - 64 bit
I want back the number of accounts with two different types of funds (say A and B). Some accounts hold only one of the two funds, and some support both. I want to get the counts like this:
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- accounts holding the Fund-A and B funds
Here is what I started with but need assistance to meet the requirement above:
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select 
count(distinct acct.bkoff_acct_no ) accounts_holding_fund_A
from xe_account acct,
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        xec_tal_asset_allocation alloc,
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Hello

Here is another way, it is easier to adapt to different jobs and different numbers of jobs:

WITH got_distinct_jobs AS

(

SELECT DISTINCT deptno, job

FROM scott.emp

WHERE job IN ("ANALYST", "CLERKS") - or what

)

got_job_list AS

(

SELECT LISTAGG (job, ",") THE Group (ORDER BY work) AS job_list

OF got_distinct_jobs

GROUP BY deptno

)

SELECT job_list

COUNT (*) AS num_departments

OF got_job_list

GROUP BY job_list

;

This shows all the combinations of the jobs listed in the WHERE clause of got_distinct_jobs. You don't need to change anything else in the query. There may be any number of jobs.

Output:

JOB_LIST NUM_DEPARTMENTS

------------------------------ ---------------

CLERK 2

ANALYST, CLERK 1

Query to get the difference between 2 totals of 2 different queries

I wanted to know if it is possible to get the difference between 2 totals of 2 different queries. Let me explain with an example:
1 application of^st - sum (homepass) Select table 1
2^th query: select sum (homepass) from table2
Is it possible to display the difference as -
Select sum (homepass) in table 1 - sum (homepass) from table2
I know that the above query would give syntax error, but is there a better way or something to get the above done task from a single query.

Hopefully, my question is clear.

Please get back with the answer to my query.

Concerning

You can always do something like
```
SELECT a.cnt - b.cnt
FROM (SELECT sum(homepass) cnt from table1) a,
      (SELECT sum(homepass) cnt from table2) b
```
I'd be somewhat dubious, although on a data model that had two tables with the same name of the column where it really made sense to subtract one amount from each other. This would strongly imply that there should be a single table with an additional column TYPE eventually.

Justin

I have run this query to get the result as below, but, even if my query is running fine, that I do not get the expected result.

I'm looking for only column compare to my same target table as a table source.

My query:

Select case when column_name_s is null and column_name_t is not null

then "alter table GRADE_CONVERSION drop | column_name_t | ';'

When column_name_s is not null and column_name_t is null

then "alter table GRADE_CONVERSION add | column_name_s | ' ' || data_type_s | « ; »

else 'alter table modify GRADE_CONVERSION | column_name_t | ' ' || data_type_t | « ; »

alterations of the end

from (select s.column_name column_name_s, t.column_name column_name_t,

s.data_type data_type_s, t.data_type data_type_t

(select column_name, column_id, data_type

of all_tab_cols@database

where owner = 'erhan.

and table_name = "GRADE_CONVERSION."

+ 1

full outer join

(select column_name, column_id, data_type

of all_tab_cols@database

where owner = 'sarigul.

and table_name = "GRADE_CONVERSION."

+ 6

on s.column_name = t.column_name

)

Tables:

Target table: table GRADE_CONVERSION in sarigul@database

LETTER_GRADE		VARCHAR2 (2)
GRADE_POINT		NUMBER (3.2)
MAX_GRADE		NUMBER (3)
MIN_GRADE		NUMBER (3)

Table source: Table GRADE_CONVERSION in erhan@database

LETTER_GRADE		VARCHAR2 (2)
GRADE_POINT		NUMBER (3.2)
MAX_GRADE		NUMBER (3)
MIN_GRADE		NUMBER (3)
CREATED_BY		VARCHAR2 (30)
CREATED_DATE		DATE
MODIFIED_BY		VARCHAR2 (30)
MODIFIED_DATE		DATE

want to see output that is similar to this * (please ignore the names of column here it's just a clear example :))

ALTER table Target_table change BOOK_ID Varchar2 (4);

ALTER table Target_table I addSBN_10 Varchar2(13), null;

ALTER table drop TITLE Target_table;

Erhan_toronto wrote:

1.I used src.nullable src_nullable and tgt.nullable tgt_nullable but only show Yes as below: but want to see the result as not null or null

ALTER table TEST_TARGET change the NUMBER of MAX_GRADE (3, 2) Yes

Ok. So it's all about the Yes and the no decoding to Default Null or Not Null, isn't it?

So, to test, change one of the table of sample for NOT NULL columns in the source table, and then run the following query:

with src as
(
  select src.table_name src_table_name, src.column_name src_col_name, src.data_type src_data_type, src.data_length src_data_len, src.data_precision src_data_precision, src.data_scale src_data_scale,
         src.nullable src_nullable
    from user_tab_columns src
   where table_name = 'TEST_SOURCE'
),
tgt as
(
  select tgt.table_name tgt_table_name, tgt.column_name tgt_col_name, tgt.data_type tgt_data_type, tgt.data_length tgt_data_len, tgt.data_precision tgt_data_precision, tgt.data_scale tgt_data_scale,
         tgt.nullable tgt_nullable
    from user_tab_columns tgt
   where table_name = 'TEST_TARGET'
),
col_details as
(
  select src.src_table_name, nvl(tgt.tgt_table_name, first_value(tgt_table_name) over(order by tgt_table_name nulls last)) tgt_table_name,
         src.src_col_name, src.src_data_type, src.src_data_len, src.src_data_precision, src.src_data_scale, src.src_nullable,
         tgt.tgt_col_name, tgt.tgt_data_type, tgt.tgt_data_len, tgt.tgt_data_precision, tgt.tgt_data_scale, tgt.tgt_nullable
    from src
    left outer join tgt
      on (
          src.src_col_name = tgt.tgt_col_name
         )
)
select *
  from (
        select case
                when tgt_data_type != src_data_type or tgt_data_len != src_data_len or tgt_data_precision != src_data_precision or tgt_data_scale != src_data_scale or src_nullable != tgt_nullable
                  then 'alter table ' || tgt_table_name || ' modify ' || tgt_col_name || ' ' || src_data_type || ' (' ||
                  case when src_data_type in ('DATE') then null
                       else
                            case
                              when src_data_type in ('VARCHAR', 'VARCHAR2')
                                then nvl(to_char(src_data_len), ' ') || ') '
                              else  decode(nvl(src_data_precision, -1), -1, null, nvl(to_char(src_data_precision), ' ') || ', ' || nvl(to_char(src_data_scale), ' ') || ')')
                            end
                  end
                  || decode(src_nullable, 'NO', ' NOT NULL', ' DEFAULT NULL')
                when tgt_col_name is null
                  then 'alter table ' || tgt_table_name || ' add ' || src_col_name || ' ' || src_data_type ||
                  case when src_data_type in ('DATE') then null
                       else
                            case
                              when src_data_type in ('VARCHAR', 'VARCHAR2')
                                then nvl(to_char(src_data_len), ' ') || ') '
                              else  decode(nvl(src_data_precision, -1), -1, null, nvl(to_char(src_data_precision), ' ') || ', ' || nvl(to_char(src_data_scale), ' ') || ')')
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                  end
                  || decode(src_nullable, 'NO', ' NOT NULL', ' DEFAULT NULL')
               end alter_statement
          from col_details
        )
where alter_statement is not null;

Erhan_toronto wrote:

2. when I run below under user sarigul and erhan I get the result as OWNER, TABLE_NAME, COLUMN_NAME DATA_TYPE... I have a link between two users. They have access to two tables.

Select * from all_tab_columns

where owner = 'erhan' and table_name = "TEST_SOURCE."

Select * from all_tab_columns

where owner = 'sarigul' and table_name = "TEST_TARGET."

Alright. This means that you both users are on the same database. Only change, you will have to do in the above query is so change user_tab_columns to all_tab_columns and add the OWNER predicate respectively with the clause.

Query to get the total counts in the given scenario
Hello

I use Oracle 10 g

I have a table with the following data

AgId Trm CD S
-------------------------------------------------
A 1000 100010, 12 - JAN
A 1000 100019, 20 - MAR
1000 100019 D 20-JUL
-------------------------------------------------
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1001 100011 D 20 - FEB
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-------------------------------------------------
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-------------------------------------------------
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-------------------------------------------------
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1004 100017 21 - JUN HAS
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-------------------------------------------------
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1005 100020 D 11 - AUG

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But, the AgId '1003' is D its CRT is disconnected after activation (according to the date column 'CD')
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SQL query to get the number of days monthwise
Hello
I'm new to sql, can someone please tell me query to find the number of days between the two dates months wise.
say
FIRSTDATE last date
21/03/2011-25/06/2011

March April May June
9 22 23 18
Hello

Welcome to the forum!

Here's one way:
```
WITH     all_dates     AS
(
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               ,     TO_DATE ('25/06/2011', 'DD/MM/YYYY')     AS end_date
               FROM     dual
          )
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)
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            )               AS month
,       COUNT (*)               AS num_days
FROM       all_dates
WHERE       a_date - TRUNC (a_date, 'IW')     < 5
GROUP BY  TRUNC (a_date, 'MONTH')
ORDER BY  TRUNC (a_date, 'MONTH')
;
```
What is a 'working day '? I guess you mean every day except Saturday or Sunday, but the query aboveare sometimes figures less than you have asked:
```
MONTH             NUM_DAYS
--------------- ----------
March 2011               9
April 2011              21
May 2011                22
June 2011               18
```
Are a few days working on Saturday or Sunday? How do you get the 22 working days in April 2011 and 23 in may?

SQL is good at obtaining results with a variable number of rows, but you have to say exactly the desired number of columns when you write the query.
If you really need the output of the way you said, with any number of columns, then watch in swing or a grouping of the chain . See the FAQ forum
https://forums.Oracle.com/forums/Ann.jspa?annID=1535
"4. How can I convert rows to columns.

A query to get the values of the batch % off tab Formulation of incoming materials.

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