IOM sql Query to get the status of the failed task

Similar Questions

• SQL query to get the NULL records after the last matching flag

  I have a xx1 table with id and flag columns. So I want the data in this table, after the last flag matched. I want that data to id 7 in the rooms. Even if the id 2,3,5 are null flag 'Y' was at 6. ID so I need a query to get the data of the xx1 table after the last correspondence flag (from 7 to 9 id).

  SQL > create table xx1

  2 (identification number,

  3 flag varchar2 (10));

  Table created.

  SQL > insert into xx1 values (1, 'Y');

  1 line of creation.

  SQL > insert into values xx1 (2, null);

  1 line of creation.

  SQL > insert into values xx1 (3, null);

  1 line of creation.

  SQL > insert into xx1 values (4, 'Y');

  1 line of creation.

  SQL > insert into values xx1 (5, null);

  1 line of creation.

  SQL > insert into xx1 values (6, 'Y');

  1 line of creation.

  SQL > insert into values xx1 (7, null);

  1 line of creation.

  SQL > insert into values xx1 (8, null);

  1 line of creation.

  SQL > insert into values xx1 (9, null);

  1 line of creation.

  SQL > select * from xx1.

  FLAG OF THE ID

  ---------- ----------

  1. IS

  2

  3

  4. IS

  5

  6. IS

  7

  8

  9

  9 selected lines.

  SQL >

  Hello

  user11164339 wrote:

  Hi Frank - when I run the query, I don't see the results data.

  I get

  FLAG OF THE ID

  ----- ----------

  7

  8

  9

  What you do differently?

• SQL query to get the numbers from 0 to 99

  How can we write a sql query to get values from 0 to 99... This should not come from any table

  SELECT LEVEL - 1
    FROM  DUAL
    CONNECT BY LEVEL <= 100
  /
  

  SY.

• SQL query to get the items for which transactions have not been saved

  Hi people,

  Have a small doubt I want to compile a SQL query in the inventory where I get these items for what transactions do not have been recorded during a period of at least one specified number of days.

  The days might be 30 days or 2 months depends on. If I want to get those items for which no transactions were reported for lets say 30 days. Could someone give me an idea of how to go about this thing? I use r12. I came up with the following query, but it gives a lot of records. The commented parts of this query is only commented on
  

  
  

  SELECT DISTINCT msi.segment1,

  MSI. Description,

  MSI.primary_uom_code,

  MSI.inventory_item_id

  MSI mtl_system_items_b / *,.

  mtl_material_transactions mmt * /.

  WHERE / * msi.inventory_item_id = mmt.inventory_item_id

  AND msi.organization_id = mmt.organization_id

  AND NVL ((SELECT SUM (transaction_quantity)

  OF mtl_onhand_quantities

  WHERE inventory_item_id = msi.inventory_item_id),

  0) = 0

  AND TRUNC (mmt.transaction_date) < = SYSDATE - & D

  AND * / NOT EXISTS (SELECT *)

  OF mtl_material_transactions mmt

  WHERE msi.inventory_item_id = mmt.inventory_item_id

  AND msi.organization_id = mmt.organization_id

  AND TRUNC (mmt.transaction_date) < SYSDATE - & D);

  Hi fatimakhellil

  Try the following code and mark it as correct if your problem be resolved.

  SELECT DISTINCT msi.segment1,

  MSI. Description,

  MSI.primary_uom_code,

  MSI.inventory_item_id,

  MSI.organization_id,

  Ms.secondary_inventory_name,

  (select max (transaction_date) in the mtl_material_transactions where msi.inventory_item_id = inventory_item_id

  AND msi.organization_id = organization_id) last_transaction_date

  OF mtl_system_items_b msi.

  Ms. mtl_secondary_inventories

  WHERE ms.organization_id (+) = msi.organization_id

  AND msi.source_subinventory = ms.secondary_inventory_name (+)

  AND NOT EXISTS (SELECT *)

  OF mtl_material_transactions mmt

  WHERE msi.inventory_item_id = mmt.inventory_item_id

  AND msi.organization_id = mmt.organization_id

  AND mmt.subinventory_code = ms.secondary_inventory_name

  AND mmt.organization_id = ms.organization_id

  AND TRUNC (mmt.transaction_date) BETWEEN TRUNC (SYSDATE - & d) AND TRUNC (SYSDATE))

• SQL query to get the number of days monthwise

  Hello
  I'm new to sql, can someone please tell me query to find the number of days between the two dates months wise.
  say
  FIRSTDATE last date
  21/03/2011-25/06/2011
  
  March April May June
  9 22 23 18

  Hello

  Welcome to the forum!

  Here's one way:

  WITH     all_dates     AS
  (
       SELECT     start_date + LEVEL - 1     AS a_date
       FROM     (
                 SELECT     TO_DATE ('21/03/2011', 'DD/MM/YYYY')     AS start_date
                 ,     TO_DATE ('25/06/2011', 'DD/MM/YYYY')     AS end_date
                 FROM     dual
            )
       CONNECT BY     LEVEL     <= end_date + 1 - start_date
  )
  SELECT       TO_CHAR ( TRUNC (a_date, 'MONTH')
              , 'fmMonth YYYY'
              )               AS month
  ,       COUNT (*)               AS num_days
  FROM       all_dates
  WHERE       a_date - TRUNC (a_date, 'IW')     < 5
  GROUP BY  TRUNC (a_date, 'MONTH')
  ORDER BY  TRUNC (a_date, 'MONTH')
  ;
  

  What is a 'working day '? I guess you mean every day except Saturday or Sunday, but the query aboveare sometimes figures less than you have asked:

  MONTH             NUM_DAYS
  --------------- ----------
  March 2011               9
  April 2011              21
  May 2011                22
  June 2011               18
  

  Are a few days working on Saturday or Sunday? How do you get the 22 working days in April 2011 and 23 in may?

  SQL is good at obtaining results with a variable number of rows, but you have to say exactly the desired number of columns when you write the query.
  If you really need the output of the way you said, with any number of columns, then watch in swing or a grouping of the chain . See the FAQ forum
  https://forums.Oracle.com/forums/Ann.jspa?annID=1535
  "4. How can I convert rows to columns.

• Need for SQL query to get the result.

  Region	Month	Trx type	Summary of the resolution
  AMERICAS	-13 may	Adjustments	Fix
  EMEA	-13 may	Adjustments	Incorrect
  AMERICAS	-13 may	Credit memo	Incorrect
  EMEA	-13 may	Invoice	Fix
  AMERICAS	-13 may	Credit memo	Fix
  OFD	-13 may	Adjustments	Fix
  AMERICAS	-13 may	Invoice	Incorrect
  DVL	-13 may	Adjustments	Fix
  DVL	-13 may	Adjustments	Fix
  OFD	-13 may	Adjustments	Fix

  Above my Table and here is the result required. Similarly for other regions as well. Can someone help me with the SQL query?

  Region	Summary of the resolution	Setting	Credit memo	Invoice	Total general
  AMERICAS	Fix	1	1		2
  	Incorrect	0	1	1	2

  Like this?

  SQL > select * from transaction_audit;

  MTH TRX_TYPE REGION BOARD
  -------- ------ ----------- ---------
  AMERICAS-13 may SETTINGS CORRECT
  EMEA-13 may INCORRECT ADJUSTMENT
  AMERICAS-13 may CREDIT MEMO INCORRECT
  EMEA-13 may INVOICE CORRECT
  AMERICAS-13 may CREDIT MEMO CORRECT
  OFD-13 may SETTINGS CORRECT
  AMERICAS-13 may INVOICE INCORRECTE
  LAD-13 may SETTINGS CORRECT
  LAD-13 may SETTINGS CORRECT
  OFD-13 may SETTINGS CORRECT

  10 selected lines.

  SQL > select region
  2, resolution_summary
  3, count (decode (trx_type, "ADJUSTMENTS", trx_type)) adjustments
  4, County (decode (trx_type, 'HAVING', trx_type)) credit_memo
  5, County (decode (trx_type, "BILL", trx_type)) Bill
  transaction_audit 6
  Group 7
  8 by region
  9, resolution_summary
  10 Decree
  11 by region
  12, resolution_summary
  13.

  REGION TAKE ADJUSTMENTS CREDIT_MEMO INVOICE
  -------- --------- ----------- ----------- ----------
  CORRECT THE AMERICAS 1 1 0
  0 1 1 INCORRECT AMERICAS
  EMEA CORRECT 0 0 1
  INCORRECT EMEA 1 0 0
  DAL ADDRESS 2 0 0
  OFD CORRECT 2 0 0

  6 selected lines.

  SQL >

• SQL query to get the range of Date values

  Hello
  
  The database is Oracle11i.
  
  I'm looking for a way to generate a list of the dates of a fixed date in the past (could be hardcoded) at the time of the day (sysdate).
  
  In other words, if the fixed date is June 19, 2011, and assuming today ' today is June 24, 2011 the SQL must be able to generate the
  
  Next: -.
  
  June 19, 2011
  June 20, 2011
  June 21, 2011
  June 22, 2011
  June 23, 2011
  June 24, 2011
  
  And the constraint is that I can not make any change to the database in question. I can only shoot a (SELECT) SQL query. NO.
  
  use time dimension type of approach (time dimension is not available here) and no procedure, etc. from PL/SQL. Is it possible?
  
  Thank you

  Jaimeen Shah wrote:
  Hello

  The database is Oracle11i.

  I'm looking for a way to generate a list of the dates of a fixed date in the past (could be hardcoded) at the time of the day (sysdate).

  In other words, if the fixed date is June 19, 2011, and assuming today ' today is June 24, 2011 the SQL must be able to generate the

  Next: -.

  June 19, 2011
  June 20, 2011
  June 21, 2011
  June 22, 2011
  June 23, 2011
  June 24, 2011

  And the constraint is that I can not make any change to the database in question. I can only shoot a (SELECT) SQL query. NO.

  use time dimension type of approach (time dimension is not available here) and no procedure, etc. from PL/SQL. Is it possible?

  Thank you

  SQL> def date_start = '13/11/2010'
  SQL> def date_end   = '22/11/2010'
  SQL> with
    2    data as (
    3      select to_date('&date_start', 'DD/MM/YYYY') date1,
    4             to_date('&date_end',   'DD/MM/YYYY') date2
    5      from dual
    6    )
    7  select to_char(date1+level-1, 'DD/MM/YYYY') the_date
    8  from data
    9  connect by level <= date2-date1+1
   10  /
  THE_DATE
  ----------
  13/11/2010
  14/11/2010
  15/11/2010
  16/11/2010
  17/11/2010
  18/11/2010
  19/11/2010
  20/11/2010
  21/11/2010
  22/11/2010
  

• SQL query to get the desired result

  I have the array with the following values

  Account	Functional currency	Billing currency	Amount	Header 5
  101	USD	USD	10 h 00
  101	USD	CAD	12 h 00
  102	JPY	USD	9 h 00
  102	JPY	CAD	3.00
  102	JPY	SGD	2.00

  If the account has one different inv_currencypar that the functional currency and then

  I have to summarize the amount in this account by viewing the billing currency

  If the account has more than one other inv_currencypar that the functional currency and then

  I have to summarize the amount in this account showing the functional currency as the currency of invoicing

  I need output like this:

  Account

  Functional currency Billing currency Total amount Header 5101USDCAD10:00 pm102JPYJPY2:00 pm

  Can we get over output in sql without writing pl/sql program?

  Hello

  According to your specific needs, here's a way:

  SELECT account

  functional_currency

  CASE

  WHEN 1 = COUNT (DISTINCT NULLIF (invoice_currency

  functional_currency

  )

  )

  THEN MAX (NULLIF (invoice_currency

  functional_currency

  )

  )

  Of OTHER functional_currency

  END AS invoice_currency

  The SUM of (amount) AS total_amount

  header5

  FROM table_x

  GROUP BY account

  functional_currency

  header5

  ;

  If you would care to post CREATE TABLE and INSERT statements for your sample data, and then I could test this.

  Is it possible to have 2 (or more) of different functional_currencies in the same account?

• SQL query to get the dates between two dates

  Hello

  We have a chart with start date and end date... Now I need to get all the dates between the start date and end date...

  Table looks to below...

  Create the table date_table (start_date, end_date date);

  The table data will be as below:

  start_date end_date

  January 1, 2013 January 4, 2013

  February 1, 2013 February 3, 2013

  ...............          .................

  ...............          ..................

  ...............           .................

  May 1, 2013 may 3, 2013

  
  

  I want a result like below...

  
  

  holiday_dates

  January 1, 2013

  January 2, 2013

  January 3, 2013

  January 4, 2013

  February 1, 2013

  February 2, 2013

  February 3, 2013

  .................

  .................

  .................

  .................

  May 1, 2013

  May 2, 2013

  May 3, 2013

  
  

  Can anyone help... ?
  

  Ramesh9158 wrote:

  Hello

  Your query will not work for our case...

  First... We do not know the number of rows in the table... If we cannot use the union...

  Second... hard coding of dates... but we do not know what could be that goes back in the table... it could be no matter what it takes not only as appearing to the interpreter...

  Hey riri.

  My code will work everywhere I use with with union all statement to create the example data.

  Try the query:

  -The main query

  Select d1 + row_number() over (partition by iden) - stopped by iden holiday 1

  Of

  connect by level<= d2="" -="" d1="" +="">

  and prior iden iden =

  and prior sys_guid() is not null

  ----

  Ramin Hashimzade

• Dynamic SQL query to get the unique value of list in a column

  I have two tables: tblWorkers and tblSkills. tblWorkers has a column, skills, which is populated by a field of multiple-checkbox with one or more skill_IDs of tblSkills, so each tblWorkers.Skills consists of a list of one or more comma-delimited values. For any Skill_ID, I need to generate a list of all workers with the appropriate skills, so I tried to do something in the direction of SELECT WorkerName FROM tblWorkers WHERE IN of skills (skills, #FORM. Skill_ID #)... or WHERE skills (ListFind (skills, #FORM. Skill_ID #))... etc.? My results (once I have had data type mismatches of the road) return all workers, not just those with the desired skills. There must be an easy way to do... How people with a little more experience CF/SQL I do this?

  > each tblWorkers.Skills consists of a list of one or more comma-delimited values

  This is your problem. You store a list of values that you want to access power/query separately in a single column. You will have to burst in a separate table.
  TblWorkers

  TblSkills

  TblWorkerSkills
  mapping table of many workers with skills.

  If you do not change your data model now, you will constantly be butting your head against that.

• SQL Query to get the logged in username user name in the Fusion Applications?

  Hi team, can someone please provide, how to retrieve the currently logged in username / UserID in Fusion Applications R9? Reg Sridhar

  Please use this query:-select FND_GLOBAL. USER_GUID, FND_GLOBAL. Double user_name

• SQL query to get the first four characters of an address

  Hi gurus,

  
  

  Can you please help me with the below quries on how to achieve this. Could be really helpful if you could provide a sample sql on your side.

  
  

  Req:

  I have a requriement where I should display the first four characters other than a space to address, for example: becomes R, DISH etc. F. in passing in a ROOM address a DISH 1 FLORIAN AVENUE would therefore "RAF1", while a CORNER, 23 STREET address would be "23CO".
  

  
  

  Words such as c/o, co, rear should be ignored, if any.

  Thanks in advance.

  
  

  Kind regards

  Peoples
  

  Hi John,.

  Here is an implementation of a pl/sql function that suggested a franc. It uses two lists, one with the words which are replaced with the first character and a second with words to ignore.

  create or replace function first_four (p_input in varchar2) return varchar2 is

  type t_words is table of the varchar2 (100);

  p_replace t_words: = t_words ('ROOM', 'FIELD', 'FLAT', 'FLT', 'BLOCK', 'UNIT', 'STUDIOS', 'CARAVAN', 'APARTMENT');

  p_ignore t_words: = t_words ("C/o ', 'CO', 'BACK TO'");

  v_input varchar2 (100);

  Start

  -Put the entry in a local-variable he

  v_input: = upper (p_input);

  -delete the words contained in the ignore list

  because me in 1.p_ignore.count

  loop

  v_input: = replace (v_input, p_ignore (i));

  end loop;

  -Replace the words by first character in the replacement list

  for r in 1.p_replace.count

  loop

  v_input: = replace (v_input, p_replace (r), substr (p_replace (r), 1, 1));

  end loop;

  -remove the spaces and return only the first 4 characters

  Return substr (replace (v_input, ' '), 1, 4);

  end;

  /

  It returns the expected results for the four examples you gave:

  SQL > with t as)

  2 select address 'FLAT 3 a 12 LILLYHAM ROAD' of all the double union

  3 select ' GREE LANE GLOSONTH 45' across Union double

  4 Select "FLAT 3 221 b Baker Street," of all the double union

  5. Select "C/o CARAVAN 32 STREET BLOK 6 RICHMOOND' of the double)

  6. Select ff first_four (address) of t;

  FF

  --------------------------------------------------------------------------------

  F3A1

  45GR

  F322

  C32B

• SQL query to get the employee details for those who have the same salary

  Hi Experts,
  

  Connected to:
  Oracle Database 11g Enterprise Edition Release 11.1.0.7.0 - Production
  With the Partitioning, OLAP, Data Mining and Real Application Testing options
  
  SQL> WITH EMP AS
    2  (
    3  SELECT 1000 EMPNO,100 SAL FROM DUAL UNION ALL
    4  SELECT 1001,90 FROM DUAL UNION ALL
    5  SELECT 1002,80 FROM DUAL UNION ALL
    6  SELECT 1003,90 FROM DUAL UNION ALL
    7  SELECT 1004,100 FROM DUAL UNION ALL
    8  SELECT 1005,20 FROM DUAL UNION ALL
    9  SELECT 1006,10 FROM DUAL
   10  )SELECT * FROM EMP;
  
       EMPNO        SAL
  ---------- ----------
        1000        100
        1001         90
        1002         80
        1003         90
        1004        100
        1005         20
        1006         10
  
  7 rows selected.
  SQL>

  Desired output:
  

       EMPNO        SAL
  ---------- ----------
        1000        100
        1004        100
        1001         90
        1003         90

  Please suggest how to work on the request?
  
  Thank you

  Oh, try

  WITH EMP AS
      (
      SELECT 1000 EMPNO,100 SAL FROM DUAL UNION ALL
      SELECT 1001,90 FROM DUAL UNION ALL
      SELECT 1002,80 FROM DUAL UNION ALL
      SELECT 1003,90 FROM DUAL UNION ALL
      SELECT 1004,100 FROM DUAL UNION ALL
      SELECT 1005,20 FROM DUAL UNION ALL
      SELECT 1006,10 FROM DUAL
     )
  SELECT * FROM EMP WHERE SAL IN (
  SELECT SAL FROM (
  SELECT count(sal) OVER (PARTITION BY SAL ORDER BY EMPNO) SAL_CNT, SAL FROM EMP
  )
  WHERE  SAL_CNT >1)
  ORDER BY SAL DESC;
  
  EMPNO     SAL
  1004     100
  1000     100
  1003     90
  1001     90
  4 rows returned in 0.01 seconds
  

  * 009 *.

• Suggest the Sql query to get the years, months, days of the two dates.

  Hi all

  SELECT TO_DATE('06-02-2014','DD-MM-YYYY') - TO_DATE('01-04-1998','DD-MM-YYYY') SERVICE_DAYS OF THE DOUBLE

  5790 SERVICE_DAYS

  POWER REQUIRED:
  YEARS MONTHS DAYS
  15 10 5

  OUTPUT DISPLAY:

  Select
  Floor(5790/ 365.25),
  Floor (mod (5790,365.25) / (365.25 / 12)),.
  ceil (mod(5790,365.25 / 12))
  Double;

  YEARS MONTHS DAYS
  15 10 7 - TWO DAYS MORE

  
  How they calculate manually is as follows:

  2014 02-06
  1998-04-01
  ---------------
  05 - days
  
  2014 02-06
  1998-04-01
  + 12
  ---------------
  10 month 02 is lower than 04, so we borrow 12 months of TI (2014) years will be (2013)
  
  2014 02-06
  1998-04-01
  -(1).
  ---------------
  15. for the years since we-1

  Kind regards

  Afzal.

  OK... so try not not to multiply the reminder to add_months with 30 but to solve the 'day-thing' in a different way...

  first step (data) is only my implementation testdata.

  WITH DATA AS (SELECT TO_DATE('02-03-2014','DD-MM-YYYY') AS Degnide

  TO_DATE('07-04-2008','DD-MM-YYYY') AS dayfrom

  OF the double

  UNION ALL

  SELECT TO_DATE('12-04-2014','DD-MM-YYYY') AS Degnide

  TO_DATE('11-05-1994','DD-MM-YYYY') AS dayfrom

  OF the double

  UNION ALL

  SELECT TO_DATE('06-02-2014','DD-MM-YYYY') AS Degnide

  TO_DATE('01-04-1998','DD-MM-YYYY') AS dayfrom

  OF the double

  )

  calc AS (SELECT months_between (dayto, dayfrom) SERVICE_DAYS

  Degnide

  dayfrom

  DATA)

  SELECT Degnide

  dayfrom

  floor(service_days/12) IN years

  floor (mod(service_days,12)) AS month

  , BUSINESS sign (EXTRACT (Degnide DAY) - EXTRACT (DAY FROM dayfrom))

  WHEN THEN-1 EXTRACT (DAY FROM Degnide) + 30 - EXTRACT (DAY OF THE dayfrom)

  WHEN 0 then 0

  WHEN 1 THEN EXTRACT (Degnide DAY) - EXTRACT (DAY FROM dayfrom)

  0 OTHERWISE

  end as days

  CALC

  HTH

• SQL query to get the given result

  Hi friends
  
  My data in the table are given below
  
  user transaction_date transaction_type
  1 1st August 2011
  August 2, 2011 1 c
  1 3 August 2011
  1 b 3 August 2011
  1 August 4, 2011 a
  1 b 4 August 2011
  2 3 August 2011
  2 b 3 August 2011
  August 4, 2011 2 c
  2 b 4 August 2011
  2 August 5, 2011 a
  2 b August 5, 2011
  2 August 7, 2011 a
  2 b 7 August 2011
  
  I want the count for each user as, how many times he made a transaction type transaction immediately after 'b' type?
  
  As the output of above data should be
  
  number of users
  1 2
  2 3
  
  Thanks in advance :)

  Maybe (NOT TESTED).

  select "user",
         count(criteria) "count"
    from (select "user",
                 transaction_date,
                 transaction_type,
                 case when transaction_type = 'b'
                       and lag(transaction_type,1) over (partition by "user",transaction_date
                                                             order by transaction_date,transaction_type) = 'a'
                      then 1
                 end criteria
            from the_table
         )
   group by "user"
   order by "user"
  

  Concerning

  Etbin