SQL query to get the number of days monthwise

Similar Questions

• Suggest the Sql query to get the years, months, days of the two dates.

  Hi all

  SELECT TO_DATE('06-02-2014','DD-MM-YYYY') - TO_DATE('01-04-1998','DD-MM-YYYY') SERVICE_DAYS OF THE DOUBLE

  5790 SERVICE_DAYS

  POWER REQUIRED:
  YEARS MONTHS DAYS
  15 10 5

  OUTPUT DISPLAY:

  Select
  Floor(5790/ 365.25),
  Floor (mod (5790,365.25) / (365.25 / 12)),.
  ceil (mod(5790,365.25 / 12))
  Double;

  YEARS MONTHS DAYS
  15 10 7 - TWO DAYS MORE

  
  How they calculate manually is as follows:

  2014 02-06
  1998-04-01
  ---------------
  05 - days
  
  2014 02-06
  1998-04-01
  + 12
  ---------------
  10 month 02 is lower than 04, so we borrow 12 months of TI (2014) years will be (2013)
  
  2014 02-06
  1998-04-01
  -(1).
  ---------------
  15. for the years since we-1

  Kind regards

  Afzal.

  OK... so try not not to multiply the reminder to add_months with 30 but to solve the 'day-thing' in a different way...

  first step (data) is only my implementation testdata.

  WITH DATA AS (SELECT TO_DATE('02-03-2014','DD-MM-YYYY') AS Degnide

  TO_DATE('07-04-2008','DD-MM-YYYY') AS dayfrom

  OF the double

  UNION ALL

  SELECT TO_DATE('12-04-2014','DD-MM-YYYY') AS Degnide

  TO_DATE('11-05-1994','DD-MM-YYYY') AS dayfrom

  OF the double

  UNION ALL

  SELECT TO_DATE('06-02-2014','DD-MM-YYYY') AS Degnide

  TO_DATE('01-04-1998','DD-MM-YYYY') AS dayfrom

  OF the double

  )

  calc AS (SELECT months_between (dayto, dayfrom) SERVICE_DAYS

  Degnide

  dayfrom

  DATA)

  SELECT Degnide

  dayfrom

  floor(service_days/12) IN years

  floor (mod(service_days,12)) AS month

  , BUSINESS sign (EXTRACT (Degnide DAY) - EXTRACT (DAY FROM dayfrom))

  WHEN THEN-1 EXTRACT (DAY FROM Degnide) + 30 - EXTRACT (DAY OF THE dayfrom)

  WHEN 0 then 0

  WHEN 1 THEN EXTRACT (Degnide DAY) - EXTRACT (DAY FROM dayfrom)

  0 OTHERWISE

  end as days

  CALC

  HTH

• Get the number of days in a month based on the month and year of fields

  I have a column in my form which lists the days in a month. I want to configure a hidden field that calculates the total number of days in a month, based on the month and year of the field inputs. The number of days will determine what appears on the column. For example, if I put 4 months, and 2016 in the field of the year, I get 30 in the hidden field. Thus, on the column 'Day', I'll have numbers 1-30. Or if I put 2 months and 2016 in the field of the year, I get the 29 in the hidden field. If the numbers 1-29 appears in the column 'day '.

  Found this on some forum javascript code:

  //Month is 1 based
function daysInMonth(month,year) {
   return new Date(year, month, 0).getDate();
}

//July
daysInMonth(7,2009); //31
//February
daysInMonth(2,2009); //28
daysInMonth(2,2008); //29

  I do not know how to convert this code in JavaScript to adobe and don't really know how to use it. All I know how to do is to configure the field values for the field month and year as variables. I am a novice programmer and would appreciate it really all the help I can get. Thank you in advance!

  The code seems to be JavaScript and runs as needed by using the JavaScript console.

  I would like to consider making more general code, so if you have a date string that includes at least the month and year we could just call the function and get the number of days for that month.

  The following script will calculate the number of days in a month, by using at least the month and year values can display the result on the JavaScript console and all of the value field for the field that has this code as the custom calculation Script.

  function daysInMonth (oDate) {}
  return new Date (oDate.getFullYear (), oDate.getMonth () + 1, 0) .getDate ();
  }

  nMonth var = this.getField("Month").valueAsString; get the value of month;
  nYear var = this.getField("Year").valueAsString; get the value of the year;

  Event.Value = "";

  If (nMonth! = "" & nYear!) = "") {}
  var MyDate = util.scand ("' / mm/yyyy ', nMonth +" / "+ nYear); convert to date object;
  var nDaysInMonth = daysInMonth (MyDate); get the number of days;

  Console.Open (); Open the JavaScript console;

  Console.clear(); clear the console;

  Console.println ("Days in" + nMonth + ":" + nDaysInMonth); show days in month;

  Event.Value = nDaysInMonth; Set the value of the field;

  }

• Get the number of days, months and year

  Hi all
  
  I'm using OBIEE 11 g. I have a line of dash for year (2010, 2011, etc.) and months (Jan, Feb,..., Dec). How can I get the number of days in a given month and year in my report?
  
  For example, if I choose to Jan & 2011, I'd get 31 and 356. And if I choose Feb & 2011, I would get 28 and 356.
  
  Thank you!

  I have something more good option here... Try to use this

  DAYOFMONTH (TIMESTAMPADD (SQL_TSI_DAY, DAYOFMONTH (CURRENT_DATE) *-1, TIMESTAMPADD (SQL_TSI_MONTH, 1, CURRENT_DATE)))

  This will give you the days for the month in progress (Oct 2011) after calculating the last day of each month... Similary dynamically pass the value Date or month... You will need to modify this function but shud be simple. Hope this helps :)

• Compare and get the number of days since the same date field

  Hello
  
  I need to get the results in days when comparing the same field, date
  
  For example,.
  
  Primary_key_field Date_field
  100000002 1 January 10
  100000004 February 1st, 10
  100000005 30 April 10
  100000006 April 18, 10
  100000007 29 April 10
  100000008 May 1st, 10
  
  extract the first two date_field records based on the primary_key_field. (January 1, 2010 and February 1, 2010) and compare and find the difference and who appear in number of days, the same fetch two disks and do the same math... How can I achieve this... is it possible to make the SQL thro? Please help me solve this problem...
  
  Thank you and best regards,
  KBG.

  This is the query using functions oracle Analytics

  Primary_key_field Date_field
  100000002 1 January 10
  100000004 February 1st, 10
  100000005 30 April 10
  100000006 April 18, 10
  100000007 29 April 10
  100000008 May 1st, 10

  Select rn, date_field, next, next - date_field "Diff".
  de)
  ROW_NUMBER() SELECT over (ORDER BY primary_key_field) rn,
  date_field, LEAD (date_field) OVER (ORDER BY date_field) next
  FROM table_name)
  /

• SQL query to get the NULL records after the last matching flag

  I have a xx1 table with id and flag columns. So I want the data in this table, after the last flag matched. I want that data to id 7 in the rooms. Even if the id 2,3,5 are null flag 'Y' was at 6. ID so I need a query to get the data of the xx1 table after the last correspondence flag (from 7 to 9 id).

  SQL > create table xx1

  2 (identification number,

  3 flag varchar2 (10));

  Table created.

  SQL > insert into xx1 values (1, 'Y');

  1 line of creation.

  SQL > insert into values xx1 (2, null);

  1 line of creation.

  SQL > insert into values xx1 (3, null);

  1 line of creation.

  SQL > insert into xx1 values (4, 'Y');

  1 line of creation.

  SQL > insert into values xx1 (5, null);

  1 line of creation.

  SQL > insert into xx1 values (6, 'Y');

  1 line of creation.

  SQL > insert into values xx1 (7, null);

  1 line of creation.

  SQL > insert into values xx1 (8, null);

  1 line of creation.

  SQL > insert into values xx1 (9, null);

  1 line of creation.

  SQL > select * from xx1.

  FLAG OF THE ID

  ---------- ----------

  1. IS

  2

  3

  4. IS

  5

  6. IS

  7

  8

  9

  9 selected lines.

  SQL >

  Hello

  user11164339 wrote:

  Hi Frank - when I run the query, I don't see the results data.

  I get

  FLAG OF THE ID

  ----- ----------

  7

  8

  9

  What you do differently?

• Query to get the number of records

  Hi all
  
  I would get the number of records in all tables in a schema. I don't want to run select count (*) of < table name >, because there are nearly 400 paintings. So I need a generic quqeyr that will give the recordcount for all tables.
  
  Experts good help yourslef to tide me over.

  Do you need a specific account? Or an approximate count is sufficient? Do you use the RBO and CBO?

  If you use the CBO and want an approximate count, column NUM_ROWS USER_TABLES should give you what you want.

  If you need a specific account, you will have full scan all tables. You can automate this process via SQL dynamic, i.e.

  DECLARE
    l_cnt INTEGER;
  BEGIN
    FOR x IN (SELECT table_name FROM user_tables)
    LOOP
      EXECUTE IMMEDIATE 'SELECT COUNT(*) FROM ' || x.table_name INTO l_cnt;
      dbms_output.put_line( 'Table ' || x.table_name || ' has ' || l_cnt || ' rows.' );
    END LOOP;
  END;
  

  Lawrence was also a [solution based on XML Query | http://laurentschneider.com/wordpress/2007/04/how-do-i-store-the-counts-of-all-tables.html] to count all the rows in each table in a schema.

  Justin

• get the number of days of the week to sysdate

  Hi all

  my need is to get the number of the day of the week of sysdate.

  Here's how can I make it right now:

  Select to_char(sysdate,'Dy') t1 double

  But he returns the abbreviated name of the day of the week while I need number of days of the week.

  Please help me. Thanks in advance.

  Best regards

  --

  Marco

  Or if you want the ISO week (Monday = day 1):

  Select trunc (sysdate) - trunc(sysdate,'IW') + 1 double;

• IOM sql Query to get the status of the failed task

  Hello world
  
  We have an obligation as we need to get the status of a particular task (say Create User in OID - Completed\Rejected status resource) for the particular user. We are able to get the status of the provisioed of resources to the user but not the status of the special mission which is trigerred for the user.can someone put some light on it. We must have the SQL query to do this.
  
  Thanks in advance.
  
  Kind regards
  MKN

  Hello
  Use this query to get the status of the task, also check the cooments

  SELECT USR. USR_LOGIN, OSI. SCH_KEY, ANN. SCH_STATUS, STA. STA_BUCKET OF
  OSI, CHS, STA, MIL, TOS, PKG, OUEDRAOGO, USR, OBJ, OST
  WHERE OSI.MIL_KEY = MIL.MIL_KEY
  AND ANN. SCH_KEY = OSI. SCH_KEY
  AND STA. STA_STATUS = SCH. SCH_STATUS
  AND TOS. PKG_KEY = PKG. PKG_KEY
  AND MIL. TOS_KEY = TOS. TOS_KEY
  AND OUÉDRAOGO. USR_KEY = USR. USR_KEY
  AND OUÉDRAOGO. OST_KEY = OST. OST_KEY
  AND OST. OBJ_KEY = OBJ. OBJ_KEY
  AND OSI. ORC_KEY = OUEDRAOGO. ORC_KEY
  AND OBJ. OBJ_NAME = "User AD".
  AND OST. OST_STATUS = "Provisioning" - filter accordinglly
  AND STA. STA_BUCKET = 'pending' - filter accordinglly
  AND PKG. PKG_NAME = "AD User" - filter accordinglly
  AND MIL.MIL_NAME = 'System' - filter accordinglly Validation
  ;
  Thank you
  Kuldeep

• How to get the number of days in a month of belonging to a range of dates

  Hi, I'm going crazy around a problem, I have 2 dates and one month I wanto to retrieve the number of days belonging to the months that fall within the range.
  
  for example:
  
  month of January 2011. begin_date = January 11, 2011, May 30, 2011 end_date result is 21
  month of January 2011. begin_date = December 11, 2010, result of end_date, January 10, 2011 10
  month January 2011 .begin_date = 2 February 2011, end_date may 25, 2011 result 0
  month of January 2011. begin_date = January 3, 2011, January 5, 2011 result DATE END 3
  
  and so on...
  
  I appreciate any suggestion
  Thank you
  
  
  Andrea

  Something like that... ?

  SQL> with t as
    2  (select  to_date('11/01/11','dd/mm/yy') from_dt,
    3           to_date('30/05/11','dd/mm/yy') to_dt,
    4           'Jan-11' mnth from dual)
    5  select least(last_day(to_date(mnth,'Mon-yy')),to_dt) -
    6         greatest(to_date(mnth,'Mon-yy'),from_dt) cnt
    7  from t  ;
  
         CNT
  ----------
          20
  

  If 0 is also expected...

  SQL> with t as
    2  (select  to_date('11/01/11','dd/mm/yy') from_dt,
    3           to_date('30/05/11','dd/mm/yy') to_dt,
    4           'Jan-11' mnth from dual union all
    5           select  to_date('11/01/11','dd/mm/yy') from_dt,
    6           to_date('30/05/11','dd/mm/yy') to_dt,
    7           'Jan-12' mnth from dual
    8           )
    9  select from_dt,to_dt,mnth,
   10         greatest(
   11              least(last_day(to_date(mnth,'Mon-yy')),to_dt)
   12              -
   13              greatest(to_date(mnth,'Mon-yy'),from_dt)
   14                 ,0) cnt
   15  from t;
  
  FROM_DT   TO_DT     MNTH          CNT
  --------- --------- ------ ----------
  11-JAN-11 30-MAY-11 Jan-11         20
  11-JAN-11 30-MAY-11 Jan-12          0
  

  Published by: JAC on February 9, 2012 19:22

• SQL query to get the numbers from 0 to 99

  How can we write a sql query to get values from 0 to 99... This should not come from any table

  SELECT LEVEL - 1
    FROM  DUAL
    CONNECT BY LEVEL <= 100
  /
  

  SY.

• How to get the number of days

  Hai bloggers,
  See us have 365 days a year for all first half we'll have 180 + days (if we choose first half as the guest and we select week as guest number and the last date of this particular week must indicate in the report) and the number of days until this date or a week should also display... If we choose the second half and half week number it should show number of days until this week and more Date of this issue of the day week should be from 1 to 180 + only way (July 1 m is 1)
  
  Thank you

  You must use the timestampdiff function to calculate the number of days. One of the way to calculate is how

  cases where "Time". "" Calendar semester "= 1 then timestampdiff (SQL_TSI_DAY, CAST (EVALUATE ('TO_DATE (%1, %2)','' 01-01 |' @{YEAR} {2010}',"DD-MM-YYYY") AS DATE), cast OFF (EVALUATE ('TO_DATE' (1%, 2%), 30-06' |' @{YEAR} {2010}',"DD-MM-YYYY") AS DATE)) else timestampdiff (SQL_TSI_DAY, MOUNT (EVALUATE ('TO_DATE (%1, %2)','01-07' |' @{YEAR} {2010}',"DD-MM-YYYY") AS DATE), cast OFF (EVALUATE ('TO_DATE' (1%, 2%),' 31-12 |' @{YEAR} {2010}',"DD-MM-YYYY") AS DATE)) end

  If you want to calculate between the 1st day of the half and the last date a week then after

  cases where "Time". ' ' Calendar semester ' = 1 then timestampdiff (SQL_TSI_DAY, CAST (EVALUATE ('TO_DATE (%1, %2)','01-01' |' @{YEAR} {2010}', 'DD-MM-YYYY') AS DATE), MAX (MAX ("Time".) "Calendar Date"))) else timestampdiff (SQL_TSI_DAY, CAST (EVALUATE ('TO_DATE (%1, %2)','01-07' |' @{YEAR} {2010}', 'DD-MM-YYYY') AS the DATE), MAX (MAX ("Time".) " End Calendar Date")))

  Hope that it will answer your question

  Thank you
  Phani.

• SQL query to get the items for which transactions have not been saved

  Hi people,

  Have a small doubt I want to compile a SQL query in the inventory where I get these items for what transactions do not have been recorded during a period of at least one specified number of days.

  The days might be 30 days or 2 months depends on. If I want to get those items for which no transactions were reported for lets say 30 days. Could someone give me an idea of how to go about this thing? I use r12. I came up with the following query, but it gives a lot of records. The commented parts of this query is only commented on
  

  
  

  SELECT DISTINCT msi.segment1,

  MSI. Description,

  MSI.primary_uom_code,

  MSI.inventory_item_id

  MSI mtl_system_items_b / *,.

  mtl_material_transactions mmt * /.

  WHERE / * msi.inventory_item_id = mmt.inventory_item_id

  AND msi.organization_id = mmt.organization_id

  AND NVL ((SELECT SUM (transaction_quantity)

  OF mtl_onhand_quantities

  WHERE inventory_item_id = msi.inventory_item_id),

  0) = 0

  AND TRUNC (mmt.transaction_date) < = SYSDATE - & D

  AND * / NOT EXISTS (SELECT *)

  OF mtl_material_transactions mmt

  WHERE msi.inventory_item_id = mmt.inventory_item_id

  AND msi.organization_id = mmt.organization_id

  AND TRUNC (mmt.transaction_date) < SYSDATE - & D);

  Hi fatimakhellil

  Try the following code and mark it as correct if your problem be resolved.

  SELECT DISTINCT msi.segment1,

  MSI. Description,

  MSI.primary_uom_code,

  MSI.inventory_item_id,

  MSI.organization_id,

  Ms.secondary_inventory_name,

  (select max (transaction_date) in the mtl_material_transactions where msi.inventory_item_id = inventory_item_id

  AND msi.organization_id = organization_id) last_transaction_date

  OF mtl_system_items_b msi.

  Ms. mtl_secondary_inventories

  WHERE ms.organization_id (+) = msi.organization_id

  AND msi.source_subinventory = ms.secondary_inventory_name (+)

  AND NOT EXISTS (SELECT *)

  OF mtl_material_transactions mmt

  WHERE msi.inventory_item_id = mmt.inventory_item_id

  AND msi.organization_id = mmt.organization_id

  AND mmt.subinventory_code = ms.secondary_inventory_name

  AND mmt.organization_id = ms.organization_id

  AND TRUNC (mmt.transaction_date) BETWEEN TRUNC (SYSDATE - & d) AND TRUNC (SYSDATE))

• SQL query to get the dates between two dates

  Hello

  We have a chart with start date and end date... Now I need to get all the dates between the start date and end date...

  Table looks to below...

  Create the table date_table (start_date, end_date date);

  The table data will be as below:

  start_date end_date

  January 1, 2013 January 4, 2013

  February 1, 2013 February 3, 2013

  ...............          .................

  ...............          ..................

  ...............           .................

  May 1, 2013 may 3, 2013

  
  

  I want a result like below...

  
  

  holiday_dates

  January 1, 2013

  January 2, 2013

  January 3, 2013

  January 4, 2013

  February 1, 2013

  February 2, 2013

  February 3, 2013

  .................

  .................

  .................

  .................

  May 1, 2013

  May 2, 2013

  May 3, 2013

  
  

  Can anyone help... ?
  

  Ramesh9158 wrote:

  Hello

  Your query will not work for our case...

  First... We do not know the number of rows in the table... If we cannot use the union...

  Second... hard coding of dates... but we do not know what could be that goes back in the table... it could be no matter what it takes not only as appearing to the interpreter...

  Hey riri.

  My code will work everywhere I use with with union all statement to create the example data.

  Try the query:

  -The main query

  Select d1 + row_number() over (partition by iden) - stopped by iden holiday 1

  Of

  connect by level<= d2="" -="" d1="" +="">

  and prior iden iden =

  and prior sys_guid() is not null

  ----

  Ramin Hashimzade

• SQL query to get the range of Date values

  Hello
  
  The database is Oracle11i.
  
  I'm looking for a way to generate a list of the dates of a fixed date in the past (could be hardcoded) at the time of the day (sysdate).
  
  In other words, if the fixed date is June 19, 2011, and assuming today ' today is June 24, 2011 the SQL must be able to generate the
  
  Next: -.
  
  June 19, 2011
  June 20, 2011
  June 21, 2011
  June 22, 2011
  June 23, 2011
  June 24, 2011
  
  And the constraint is that I can not make any change to the database in question. I can only shoot a (SELECT) SQL query. NO.
  
  use time dimension type of approach (time dimension is not available here) and no procedure, etc. from PL/SQL. Is it possible?
  
  Thank you

  Jaimeen Shah wrote:
  Hello

  The database is Oracle11i.

  I'm looking for a way to generate a list of the dates of a fixed date in the past (could be hardcoded) at the time of the day (sysdate).

  In other words, if the fixed date is June 19, 2011, and assuming today ' today is June 24, 2011 the SQL must be able to generate the

  Next: -.

  June 19, 2011
  June 20, 2011
  June 21, 2011
  June 22, 2011
  June 23, 2011
  June 24, 2011

  And the constraint is that I can not make any change to the database in question. I can only shoot a (SELECT) SQL query. NO.

  use time dimension type of approach (time dimension is not available here) and no procedure, etc. from PL/SQL. Is it possible?

  Thank you

  SQL> def date_start = '13/11/2010'
  SQL> def date_end   = '22/11/2010'
  SQL> with
    2    data as (
    3      select to_date('&date_start', 'DD/MM/YYYY') date1,
    4             to_date('&date_end',   'DD/MM/YYYY') date2
    5      from dual
    6    )
    7  select to_char(date1+level-1, 'DD/MM/YYYY') the_date
    8  from data
    9  connect by level <= date2-date1+1
   10  /
  THE_DATE
  ----------
  13/11/2010
  14/11/2010
  15/11/2010
  16/11/2010
  17/11/2010
  18/11/2010
  19/11/2010
  20/11/2010
  21/11/2010
  22/11/2010