advice of dongle required please

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• TCS EX next generation USB dongle required

  ONE WITH TCS EX NEXT GENERATION USB DONGLE OR KNOWS ANY MERCHANT OR THE PERSON WHO SOLD OR WILLING TO SELL ITS USB DONGLE HASP PLEASE INFORM ME.

  You tried to paste TCS EX NEXT GENERATION USB DONGLE in Google search? I just do.

  It's the first thing you need to do if you have a question about a particular file.

  http://www.google.com/search?q=TCS+EX+NEXT+GENERATION+USB+DONGLE+&sourceid=ie7&rls=com.microsoft: en - us: ContextMenu IE & oe and ie ==.

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  UTC/GMT is 11:21 Tuesday, October 9, 2012

• just bought a lexmark s505 printer, does not connect to vista Home premium assistance required please

  can someone give advise please

  Have you followed the guide to use during the installation of the unit: http://support.lexmark.com/index?locale=en&page=product&productCode=LEXMARK_INTUITION_S505&segment=SUPPORT&userlocale=EN_US&frompage=null#2

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  JS
  http://www.PAGESTART.com

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• Download Flash Player 7 required please

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  There you go :)

  http://KB.Adobe.com/selfservice/viewContent.do?externalId=d9c2fe33

  Enjoy!

• G62-a13sa, no help from drivers not required please!

  Hello
  I have the laptop mentioned above it was running windows 7 Home premium 64-bit, but I recently did a clean install and instead installed Windows 7 Ultimate 64-bit.
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  You are the very welcome.

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• Wireless Connectivity icon Bug/Glitch - Solution required please!

  This is not the first time that I'm writing about this. This problem is stuck with my computer for a while now.

  I am connected to a wireless network by my taskbar icon does not show that. Not only that, but the host group is not working too. Internet works fine but I need to congregate to share.

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  Windows 7 Ultimate

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  Hey Shameer,

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  b. expand network adapters

  c. right-click the network adapter, and then click Update driver software

  d. click search automatically for updated driver

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  Homegroup from start to finish

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• Code help required please

  Hi, I bought a template I use for my portfolio page and I am currently building the site and tweak accordingly.   The problem at the moment is adding the code to the bottom of each box that 'see design' bed next to the icon magnifying glass, in IE and Safari, all is well, however in Firefox text appear next to the design of the view, this text that appears must be in the box slideshow that is displayed? help would be appreciated please.

  www.lorraines.co.nz

  What happens if you add the below css at the end of your css style sheet linked?

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• Graphics required - please help with Spec

  
  
  

• Upgrade from 5.1 to 5.5 tips precision required please

  Hello

  I hope someone can answer this in clear simple terms.

  We have Vcenter Server 5.1 build 799731

  The vcenter server is sitting on one of the 3 ESX host

  3 ESXi hosts are 5.1.0 799733

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  Construction of 1 and 2

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  We are fully licensed for HA and tolerance to failures and Vmotion etc.

  A QUESTION THAT WE HAVE WITH THE UPGRADE, OR AT LEAST I GUESS HER QUESTION I COULD DECEIVE ME, BUT THATS WHY IM ASKING HERE.

  We are a 24/7 operation, and it's a huge, huge deal for disable us some of the VM guests running on some of 3 guests.

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  or

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  We have not installed upgrading Manager I just physically getting by popping the CD in each of the 3 hosts one at a time as we have only 3

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• Synchronize the assistance required please

  Let's say you have 5 images in ACR. You click on the first, make all the necessary adjustments, select all, then click on synchronize, and all parameters are added to the other 4 images. Currently, I do not do this, I simply select all images and make adjustments to each of them at the same time. Is - this get the same result, or am I missed something by not using do not synchronize?

  Same result, assuming you set the parameters in only the groups that you select for synchronization.  In case you are thinking about coming, and in the other case, you remember that you forgot to think of come and first select the other images.

  A 'witch hunt' to do things the first way (first selection) may be that when you select images first, then change only one control, ALL the controls in this 'game' are then applied to selected images - the same that happen in a synchronization operation where you choose then the game (for example, "White Balance").  In other words, if you select all, then change only the color temperature slider, that the value of the slider hue is also applied to all selected images.  The "witch hunt" of sense when you think about how sync works, because of course, you see the Group explicitly in the case of synchronize.

  If you change some settings in a single image, and then synchronize with other images and check ALL groups, you will more than just the settings that you change twisted in the first image - you will realize ALL the same settings for all images.  This may end up being the same thing as what you do with the selection images first, because they probably all start with the same default values anyway - but it's not a given.

  -Christmas

• quick response required please...

  Hi friend

  I just want to create a horizontal box containing(textInput--3 fields and button) according to dynamically to the data in the database.

  I created a horizontal box with its child elements sucessfully but here I have to call a function to store the data entered by the end-user in textInput field in the database.

  I'm unable to retrieve data of a particular set of textinput field by clicking on the button

  to be clear, consider a small example

  textinputfield1 textinputfield2 textinputfield3 button

  textinputfield1 textinputfield2 textinputfield3 button

  no lines depend on data in the database. Now, by clicking on the button, I want the data set textfield to display.

  Thanks to advanceeee

  Hi Ravi,

  You can use the following code below...

  Note:

  Observe the code in blue and also code in green...

  The code in blue is rather a dynamic where in which you are dynamically looped through the children from your HBox container, regardless of the order of appearance of the TextInputs and it will work for any number of TextInputs horizontally...

  Where as the code in green is a kind of static and you code based on the index to hardcode the positions of occurrences in order to obtain the values.

  Observe the two know the difference... :))

  
  http://www.Adobe.com/2006/mxml"layout ="absolute">
   
   
    
     
     
     
     
     
     
   
     

  
    
  Import mx.containers.HBox;
  Import mx.collections.ArrayCollection;
  Import mx.controls.Alert;
  Import mx.controls.Button;
  Import mx.controls.TextInput;
     
  [Bindable] private var column1:Array = [1,2,3,4,5,6,7,8,9,10];

  Max [bindable] private var int;

  [Bindable] private var i: int;
        
  [Bindable] private var array_date:Array = new Array();
  private var u: URLRequest;
     
  public void addTrans(clickedBtn:Button):void {}
  var parentHBox:HBox = clickedBtn.parent as HBox;
             
              var enteredValues:String ="";
  for each (var control: * in parentHBox.getChildren ())
  {
  If (control is TextInput)
  enteredValues += (as TextInput control) .text + "";
  }
             
  Alert.Show ("values entered by the user in the input field are" + enteredValues);  
             
              / * var text1:String = (parentHBox.getChildAt (1) as TextInput) .text;
  var text2:String = (parentHBox.getChildAt (2) as TextInput) .text;
  var text3:String = (parentHBox.getChildAt (3) as TextInput) .text;
  var text4:String = (parentHBox.getChildAt (4) as TextInput) .text;
             
  Alert.Show ("values entered by the user in the input field are" + text1 + "" + Text2 + "" + Text3 + "" + Text4); */
  }

  ]]>
  

  Thank you

  Jean Claude

• Exciting requirement - please provide a solution

  I have a table as follows:
  

     
     CREATE TABLE test_detail
         (case                      CHAR(10) NOT NULL,
         item                         CHAR(9) NOT NULL,
         code                       CHAR(2) NOT NULL,
         type1               VARCHAR2(2),
         type2               VARCHAR2(2),
         type3               VARCHAR2(2),
         type4               VARCHAR2(2),
         type5               VARCHAR2(2),
         type6               VARCHAR2(2),
         amt1                NUMBER(9,2),
         amt2                NUMBER(9,2),
         amt3                NUMBER(9,2),
         amt4                NUMBER(9,2),
         amt5                NUMBER(9,2),
         amt6                NUMBER(9,2));
      
      
      
      INSERT INTO test_detail
      VALUES
      ('EML3371015','133761570','10','25','04','25','07','10','21',200,55,100,10,50,NULL)
      /
      INSERT INTO test_detail
      VALUES
      ('EML3371015','133761570','10','01','25','06','07','10','21',26,20,NULL,10,50,5)
      /
      INSERT INTO test_detail
      VALUES
      ('EML3371015','133761570','10','01','04','25','07','10','21',35.25,NULL,5,NULL,50,NULL)
      /
      INSERT INTO test_detail
      VALUES
      ('EMC6369600','140328551','10','01','04',NULL,NULL,NULL,NULL,75,54,NULL,NULL,NULL,NULL)
      /
      INSERT INTO test_detail
      VALUES
      ('EMH6353995','140328551','11','01','04','29','05','10','25',382,20.52,15,10,22,5.52)
      /
      commit;

  I want to check type2, type3, type4, type5, test_detail.type1, type6
  for types in {25,04} then take corresponding quantities test_detail.eob_column_amt [1.6] fields for the appropriate types SumOf
  
  The expected result is

  case       item       code            copay
  EML3371015      133761570      10            355 --amt1(25 of type1)+amt2(04 of type2)+amt3(25 of type3)
  EML3371015      133761570      10             20 --amt2(25 of type2 )
  EML3371015      133761570      10             5  -- amt2(04 of type2)+amt3(25 of type3)
  EMC6369600      140328551      10             54 -- amt2(04 of type2)
  EMH6353995      140328551      11             26.04 --amt2(04 of type2)+amt6(25 of type6)

  Can someone help me write a query?

  select  case,
          item,
          code,
          case
            when type1 in ('25','04') then nvl(amt1,0)
            else 0
          end +
          case
            when type2 in ('25','04') then nvl(amt2,0)
            else 0
          end +
          case
            when type3 in ('25','04') then nvl(amt3,0)
            else 0
          end +
          case
            when type4 in ('25','04') then nvl(amt4,0)
            else 0
          end +
          case
            when type5 in ('25','04') then nvl(amt5,0)
            else 0
          end +
          case
            when type6 in ('25','04') then nvl(amt6,0)
            else 0
          end copay
    from  test_detail
  /
  
  CASE       ITEM      CO      COPAY
  ---------- --------- -- ----------
  EML3371015 133761570 10        355
  EML3371015 133761570 10         20
  EML3371015 133761570 10          5
  EMC6369600 140328551 10         54
  EMH6353995 140328551 11      26.04
  
  SQL> 
  

  SY.

• Security requirements - please help!

  Hello Experts,
  
  One of my clients is to have the line of questioning. It would be a great help if you share your suggestions to meet the following:
  
  For authentication issues on the client side:
  1. the credentials stored in the client session state?
  2. the credentials stored in any type of data store (database, flat file)?
  3. the credentials are never available to be written to the log files?
  4. is secure transport that is used for all communication between the connection and the back-end server? Or is the password encrypted on a non secure channel?
  5. How are treated invalid credentials?
  6. How are expired passwords be managed?
  7. the users redirected to the idM of password resets managed? IDM is our application, so whne user has attempted to change password in excel is sort of redirect to our Application.
  For the LDAP bind
  1. is the integration with LDAP for authentication?
  2. what information will be pulled back from the directory and how often?
  3 you need to rewrite all the data in the directory?
  4. how many connections (number of) will be open to the application directory?
  5. the number of connections may be limited to a specific number?
  6. a connection pool will be used?
  7. the document and run tests to understand the Directory performance implications.
  8 the application does support of research filtered to pull back only users who have access to the application?
  9 must. the application maintain all groups in the directory?
  
  
  Thanks in advance.
  
  Kind regards
  
  Jingle

  I can't respond to all of this, but some general information can help a lot.

  The answer to many of them also depends on the version you are using. My knowledge ends with version 7, and I have 'some' details on the new versions, but in general:

  (1) No, the handles are used to represent a qualified user (credentialled)
  (2) the Essbase.sec file contains this information in an encrypted form for authenticated internal users (using DES/Blowfish IIRC), external authentication is, thus, outwardly authenticate... (couldn't resist that).
  (3) there is no API or internally the internal mechanism to expose the stored password. I suspect that a sum of control (or one-way hash) is used, this information is not yet available.
  Note 3 (a): there are two security vulnerabilities in passwords, but I give these details on a forum public (it would probably take a lot to find, but still).
  (4) N ° credentials are completely secure, data requests are not. However, from the safety point of view, intercept an excerpt of companies by sniffing the network traffic is much harder hacking an account of essbase as one so-called spy would be silly to use the network traffic as a way to learn about a competitor. In general, if the server has access to the public, a VPN connection must prevent the unauthorized public access, and this would provide the security of the traffic. A public server with internet access is a little risky, but not a great threat.
  (5) simple refusal of connection for the first attempts at "n", then the account lockout. Here, we give 3 attempts, which means I have reset many accounts.
  (6) locking of account when the connection attempt (no grace period).
  (7) n ° 'See your Essbase Administrator' (or equivalent message Hyperion/Oracle).

  For LDAP, commissioning is more complicated and I don't have enough experience with it to address more, so I leave you with the above.

  I think that I know a couple of responses, which means that answering them will ensure only that I'm wrong.

• output required - please help

  declare
  abc cursor's select empname from emp;
  out varchar2 (2000);
  Start
  I'm looping CBA
  output: output = | " ' || i.EmpName | ',';
  end loop;
  
  dbms_output.put_line (output);
  end;
  
  I want that all the name of the employee of the emp table are saved in variable exit that way
  
  "Rene', 'Kumar',"AEK","Sachin. "
  
  I'm trying to add the name of the employee with the output variable.
  
  The cursor is incomplete the name of an employee in each itaration.
  
  in the 1st itaration the production value will be-"René".
  in the 2nd itaration the production value will be - "Rene', 'Kumar '.
  
  and so on.
  
  But when I try to add the '(single cotes) before and after the name he's in trouble.
  
  What I did is;
  
  I'm looping CBA
  output: output = | » ' '|| i.EmpName | ',';
  end loop;
  
  but it does not work or can tell you how to disable the central point "'(this one)" | i.EmpName | " (this one).
  In java, we do this in.
  
  can you tell me how can I get the output deserve.
  
  Concerning
  Rajat
  
  Published by: user10235767 on 21 Sep, 2008 01:14

  To print a quote that you must double and calls then that the double quotes. So 4 citations in a row:

  output := output || '''' || i.empname || ''',';
  

  Also note, that for the aggregation of the chain, you don't need PL/SQL. A single SQL can do. For example: http://rwijk.blogspot.com/2008/05/string-aggregation-with-model-clause.html
  If you follow the link, you will find another - but more slowly - the alternatives.

  Kind regards
  Rob.

• I want to buy adobe cc costume Middle East version for mac, please advice

  I want to buy adobe cc costume Middle East version for mac, please advice

  Hello

  Please visit Troubleshooting FAQ: what should I do if I have a subscription, but my application acts as if I had a trial? for the plans and prices.

  Hope that helps!

  Kind regards

  Sheena