aggregate queries - view the right output

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• by using the analytical function to get the right output.

  Hello all;
  
  I have the following date of sample below
  

  create table temp_one
  (
         id number(30),   
        placeid varchar2(400),
        issuedate  date,
        person varchar2(400),
        failures number(30),
        primary key(id)
  );
  
  insert into temp_one values (1, 'NY', to_date('03/04/2011', 'MM/DD/YYYY'), 'John', 3);
  
  insert into temp_one values (2, 'NY', to_date('03/03/2011', 'MM/DD/YYYY'), 'Adam', 7);
  
  insert into temp_one values (3, 'Mexico', to_date('03/04/2011', 'MM/DD/YYYY'), 'Wendy', 3);
  
  insert into temp_one values (4, 'Mexico', to_date('03/14/2011', 'MM/DD/YYYY'), 'Gerry', 3);
  
  insert into temp_one values (5, 'Mexico', to_date('03/15/2011', 'MM/DD/YYYY'), 'Zick', 9);
  
  insert into temp_one values (6, 'London', to_date('03/16/2011', 'MM/DD/YYYY'), 'Mike', 8);

  It's the output I want
  

  placeid       issueperiod                               failures
  NY              02/28/2011 - 03/06/2011          10
  Mexico       02/28/2011 - 03/06/2011           3
  Mexico        03/14/2011 - 03/20/2011          12
  London        03/14/2011 - 03/20/2011          8

  Any help is appreciated. I'll post my request as soon as I can think of a good logic for this...

  Hello

  user13328581 wrote:
  ... Please note, I'm still learning how to use analytical functions.

  It doesn't matter; analytical functions will not help in this problem. The SUM aggregate function is all you need.
  But what do you need to GROUP BY? What is the value of each row of the result will represent? A placeid? Yes, each line will represent only placedid, but it will be divided further. You want a separate line of the output for each placeid and every week, then you'll want of the week and GROUP BY placeid. You don't want to GROUP BY the raw issuedate; that would put on 3 March and 4 March in separate groups. And you don't want to GROUP BY failures; This would mean that a line with 3 failures could never be in the same group in line with 9 failures.

  This becomes the output you posted from the sample data you posted:

  SELECT       placeid
  ,             TO_CHAR ( TRUNC (issuedate, 'IW')
                , 'MM/DD/YYYY'
              ) || ' - '|| TO_CHAR ( TRUNC (issuedate, 'IW') + 6
                                           , 'MM/DD/YYY'
                             )     AS issueperiod
  ,       SUM (failures)                  AS sumfailures
  FROM        temp_one
  GROUP BY  placeid
  ,            TRUNC (issuedate, 'IW')
  ;
  

  You can use a subquery to calculate TRUNC (issuedate, 'IW') once. The code would be of about as complicated, efficiency probably will not improve substantially and the results would be the same.

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  end;
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  SQL >

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  Published by: DBA115102 on June 10, 2011 17:27